JEE Mains 2025 Qualifying Percentile: Expected Cutoff and Latest Updates

JEE Mains 2025 Qualifying Percentile: Expected Cutoff and Latest Updates

Edited By Jalla Venkatesh | Updated on Feb 11, 2025 05:24 PM IST | #JEE Main
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JEE Mains 2025 for Qualifying Percentile: Candidates can access the qualifying percentile data for JEE Main through this page. The National Testing Agency will release the JEE Mains 2025 cutoff on the official website, jeemain.nta.nic.in. To qualify for JEE Advance participants need to meet the minimum percentile specified by JEE Mains 2025. The cutoff marks to qualify in JEE Main 2025 varies every year based on the factors like difficulty level of exam, number of candidates and seats available. The authority conducted the JEE Main entrance exam on January 22 to 30, 2025.

This Story also Contains
  1. JEE Main Result 2025 - Percentile Calculation
  2. NTA Score And Overall Merit /Rank List
  3. NTA Percentile For JEE Main 2025
JEE Mains 2025 Qualifying Percentile: Expected Cutoff and Latest Updates
JEE Mains 2025 Qualifying Percentile: Expected Cutoff and Latest Updates

JEE Mains 2025 qualifying percentile is calculated using the normalisation process for all the exam shifts. Securing the JEE Main qualifying percentile allows students to appear for JEE advance, but to secure admission into the NITs, IIIT’s and GFTI’s, candidates must score the respective institute cutoff and marks. In case of General category candidates, the cutoff percentile ranges from 88 to 92. In case of OBC, it is around 72 to 76, and for SC/ST the cutoff falls between 30 to 55. For more details regarding what is the qualifying percentile for JEE Mains, candidates can refer to the article given below.

JEE Main Result 2025 - Percentile Calculation

The National Testing Agency evaluates JEE Main 2025 scores for percentile across three distinct subject categories (Physics, Chemistry, Mathematics) and a combined overall scheme using this normalization formula.

Calculating JEE Main Percentile

Total Percentile (T1P)

(100 x No. of candidates from the session with a raw score equal to or less than T1 score) / Total No. of candidates who appeared in the session

Mathematics Percentile (M1P)

(100 x No. of candidates appeared from the session with a raw score equal to or less than than M1 score in Mathematics)

/ Total No. of candidates who appeared in the session

Chemistry Percentile (C1P):

(100 x No. of candidates appeared from the session with a raw score equal to or less than C1 score in Chemistry) / Total No. of candidates who appeared in the session

Physics Percentile (P1P)

(100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates who appeared in the session

JEE Main percentile calculation

NTA Score And Overall Merit /Rank List

Candidates can check the Top 10 NTA Score and Overall Rank List in the table below.

RAW SCORE

NTA SCORE (Percentile)

RANK

Math

PHY

CHE

Total

Math

PHY

CHE

Total

120

110

101

331

100.0000

100.000

99.9201471

100.0000

1

120

101

111

332

100.0000000

99.9778342

99.9926114

100.0000000

2

115

115

105

335

99.9964301

99.9750107

99.9571612

100.0000000

3

115

116

115

346

99.9692695

99.9938539

99.9938539

100.0000000

4

115

95

111

321

99.9903209

99.9080482

99.9975802

99.9975802

5

106

110

105

321

99.9007888

100.0000000

99.9661230

22051995

6

120

110

100

330

99.9975371

100.0000000

100.0000000

99.8916336

7

115

110

120

345

99.9969270

99.9692695

99.9600504

100.0000000

8

106

115

111

332

99.9964301

99.9500214

99.9750107

99.9750107

9

120

100

100

320

99.9950743

100.0000000

99.9704455

99.8916336

10

NTA Percentile For JEE Main 2025

Compilation and display of Result for multi session Papers of JEE(Main) For examinations conducted twice (First and Second attempt) before admissions to the next academic session.

1. Compilation of Result for First attempt:

Since, the first attempt will be conducted in multi-sessions, NTA scores will be calculated corresponding to the raw marks obtained by a candidate in each session as per above procedure. The calculated NTA scores for all the sessions will be merged for declaration of result. The result shall comprise the four NTA scores for each of the three subjects (Mathematics, Physics, and Chemistry) and the total for the first attempt.

2. Compilation of Result for Second attempt:

Similarly, the second attempt will be conducted in multi-sessions, NTA scores will be calculated corresponding to the raw marks obtained by a candidate in each session as per above procedure. The calculated NTA scores for all the sessions will be merged for declaration of result.The result shall comprise the four NTA scores for each of the three subjects (Mathematics, Physics, and Chemistry) and the total for the second attempt.

3. Compilation of Result and Preparation of Merit List / Ranking:

The four NTA scores for each of the candidates for the first attempt as well as for the second attempt will be merged for compilation of result and preparation of overall Merit List / Ranking.Those appeared in both the attempts; their best of the two NTA scores will be considered further for preparation of Merit List /Rankings as explained in the following example:

Roll No


First Attempt – NTA Score

Second Attempt-NTA Score

Final NTA Score for compilation of result (best of the two in Total)

C20045511

Total

99.8620723

99.8740051

99.8740051

Mathematics

99.6249335

100.0000000

100.0000000

Physics

99.7338237

99.2102271

99.2102271

Chemistry

99.8572327

99.7203528

99.7203528

C20045512

Total

Did not Appear

99.8620723

99.8620723

Mathematics

99.6249335

99.6249335

Physics

99.7338237

99.7338237

Chemistry

99.8572327

99.8572327

C20045513

Total

99.8740051

Did not Appear

99.8740051

Mathematics

100.0000000

100.0000000

Physics

99.2102271

99.2102271

Chemistry

99.7203528

99.7203528

C20045514

Total

99.8740051

99.8620723

99.8740051

Mathematics

100.0000000

99.6249335

100.0000000

Physics

99.2102271

99.7338237

99.2102271

Chemistry

99.7203528

99.8572327

99.7203528

JEE Mains 2025 Expected Marks Vs Percentile Vs Rank

IIT JEE aspirants can refer to the JEE Mains Marks vs Percentile vs Rank for 2025, which will be provided here. According to the JEE Main 2025 marks vs percentile vs rank data, candidates need to score above 250 marks to achieve a percentile greater than 90.

JEE Main Marks vs Rank vs Percentile 2025

Marks Out of 300

Percentile

Overall Rank

290- 280

99.99908943 - 99.99745041

13 - 36

280 - 250

99.99745041 - 99.96976913

36 - 428

250 - 240

99.96976913 - 99.94664069

428 - 755

240 - 230

99.94664069 - 99.91595453

755 - 1189

230 - 220

99.91595453 - 99.86623749

1189 - 1893

220 - 210

99.86623749 - 99.80777899

1893 - 2720

210 - 200

99.80777899 - 99.73129123

2720 - 3803

200 - 190

99.73129123 - 99.62402626

3803 - 5320

190 - 180

99.62402626 - 99.48033855

5320 - 7354

180 - 170

99.48033855 - 99.2955842

7354 - 9968

170 - 160

99.2955842 - 99.06985426

9968 - 13163

160 - 150

99.06985426 - 98.77819917

13163 - 17290

150 - 140

98.77819917 - 98.40768884

17290 - 22533

140 - 130

98.40768884 - 97.94047614

22533 - 29145

130 - 120

97.94047614 - 97.35425213

29145 - 37440

120 - 110

97.35425213 - 96.60949814

37440 - 47979

110 - 100

96.60949814 - 95.64338495

47979 - 61651

100 - 90

95.64338495 - 94.39636137

61651 - 79298

90 - 80

94.39636137 - 92.76234617

79298 - 102421

80 - 70

92.76234617 - 90.4109851

102421 - 135695

70 - 60

90.4109851 - 87.06073037

135695 - 183105

60 - 50

87.06073037 - 81.57582987

183105 - 260722

50 - 40

81.57582987 - 73.08140938

260722 - 380928

40 - 30

73.08140938 - 59.84001311

380928 - 568308

30 - 20

59.84001311 - 40.3469266

568308 - 844157

20 - 10

40.3469266 - 20.95045141

844157 - 1118638

10 - 0

20.95045141 - 6.599800585

1118638 - 1321716

JEE Main 2025 Session 1 Cutoff Expected

The National Testing Agency will release the JEE Main 2025 cutoff on the official website. Candidates can check the expected cutoff for various categories: 95+ for General, 83+ for OBC, 85+ for EWS, 65+ for SC, and 50+ for ST.

Frequently Asked Questions (FAQs)

1. How to calculate percentile in JEE Mains 2025?

To calculate the JEE Mains percentile for 2025, candidates should use the following formula: Percentile = (100 × Number of candidates in the session with a raw score equal to or lower than the T1 score) / Total number of candidates who appeared in the session.

2. What is the top 5 percentile?

A score that reaches beyond 95% of all observed data points belongs to the 5th percentile group. The top 5 percentile indicates your test score surpasses what 95% of test-takers achieved. Becoming part of the top 5 means your ranking surpasses 95% of potential candidates thus sitting at the 95th percentile position.

3. what is the cutoff for jee mains 2025?
CategoryExpected cut off
General91-95
EWS77-85
OBC NCL77-85
SC58-65
ST44-50

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Questions related to JEE Main

Have a question related to JEE Main ?

Hello Gangaram

First of all, you must cover your NCERTs of Physics, Mathematics and Chemistry of Class 11th and 12th as they are the building blocks of your JEE Mains preparation specially for Chemistry (as direct questions come from NCERT in JEE Mains).

After that, here are my recommendations:

1. Physics
HC Verma Volume 1 & 2 (For theory and conceptual problems)
DC Pandey (For practice)
Cengage (Better if you want to go for JEE Advance)

2. Chemistry
Physical Chemistry: N Avasthi
Organic Chemistry: M.S. Chauhan
Inorganic Chemistry: 11th and 12th NCERTs are enough but if you want to, you can go for JD LEE

3. Mathematics
Objective Mathematics by RD Sharma (Volume 1 & 2)
Arihant Publications Series (Good for Advance)
Cengage (Better if you want to go for JEE Advance)

You also need to give emphasis on PYQs so buy any PYQ serious book like Arihant, Disha etc.

Hope this answer helps! Thank You!!!

Usually, UPTAC counselling considers either JEE or CUET, but you cannot register twice. You need to contact UPTAC officials for correction or withdrawal before deadlines.


Yes, based on her AIR of 3424 in General and 970 in OBC category in JEE Main Paper 2 (B.Arch), your daughter has a good chance of getting admission in Architecture to MNIT Jaipur under the OBC category. In previous years, the closing ranks for OBC category at MNIT Jaipur for B.Arch have gone to around1500-1600, so a rank of 970 is comfortably at the lower part of that bracket. However, the final allotment will depend on yearly cutoffs, matrix of the seats and choices filled for JoSAA counseling. Check here for more information: MNIT jaipur

Hello Aspirant,

you can study b.tech in computer science without giving JEE exam by taking admission through management quota or spot admission or in private institutes that accept 12th marks only. entrance exam is not mandatory in many private colleges . you should focus now on building coding skills and gaining practical knowledge for future placements.

It's amazing that you're already thinking about JEE 2027.

As of now, the official notifications for JEE 2027 haven't been released (they usually come out a few months before the exam), but you can still plan your preparation based on the usual pattern and schedule that's been followed in the last few years.

The syllabus is based on class 11 and class 12 NCERT topics. In recent years, NTA has allowed some flexibility in question patterns by offering optional questions in each section, so staying updated with the official brochure is important.

Since you're aiming for 2027, now is the perfect time to build your foundation strong. Focus on clarity of concepts, regular revisions, and solving a lot of mock tests. Starting early gives you time to learn at a steady pace without pressure.

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