JEE Mains 2025 Qualifying Percentile: Expected Cutoff and Latest Updates

JEE Mains 2025 Qualifying Percentile: Expected Cutoff and Latest Updates

Edited By Jalla Venkatesh | Updated on Feb 11, 2025 05:24 PM IST | #JEE Main
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JEE Mains 2025 for Qualifying Percentile: Candidates can access the qualifying percentile data for JEE Main through this page. The National Testing Agency will release the JEE Mains 2025 cutoff on the official website, jeemain.nta.nic.in. To qualify for JEE Advance participants need to meet the minimum percentile specified by JEE Mains 2025. The cutoff marks to qualify in JEE Main 2025 varies every year based on the factors like difficulty level of exam, number of candidates and seats available. The authority conducted the JEE Main entrance exam on January 22 to 30, 2025.

This Story also Contains
  1. JEE Main Result 2025 - Percentile Calculation
  2. NTA Score And Overall Merit /Rank List
  3. NTA Percentile For JEE Main 2025
JEE Mains 2025 Qualifying Percentile: Expected Cutoff and Latest Updates
JEE Mains 2025 Qualifying Percentile: Expected Cutoff and Latest Updates

JEE Mains 2025 qualifying percentile is calculated using the normalisation process for all the exam shifts. Securing the JEE Main qualifying percentile allows students to appear for JEE advance, but to secure admission into the NITs, IIIT’s and GFTI’s, candidates must score the respective institute cutoff and marks. In case of General category candidates, the cutoff percentile ranges from 88 to 92. In case of OBC, it is around 72 to 76, and for SC/ST the cutoff falls between 30 to 55. For more details regarding what is the qualifying percentile for JEE Mains, candidates can refer to the article given below.

JEE Main Result 2025 - Percentile Calculation

The National Testing Agency evaluates JEE Main 2025 scores for percentile across three distinct subject categories (Physics, Chemistry, Mathematics) and a combined overall scheme using this normalization formula.

Calculating JEE Main Percentile

Total Percentile (T1P)

(100 x No. of candidates from the session with a raw score equal to or less than T1 score) / Total No. of candidates who appeared in the session

Mathematics Percentile (M1P)

(100 x No. of candidates appeared from the session with a raw score equal to or less than than M1 score in Mathematics)

/ Total No. of candidates who appeared in the session

Chemistry Percentile (C1P):

(100 x No. of candidates appeared from the session with a raw score equal to or less than C1 score in Chemistry) / Total No. of candidates who appeared in the session

Physics Percentile (P1P)

(100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates who appeared in the session

JEE Main percentile calculation

NTA Score And Overall Merit /Rank List

Candidates can check the Top 10 NTA Score and Overall Rank List in the table below.

RAW SCORE

NTA SCORE (Percentile)

RANK

Math

PHY

CHE

Total

Math

PHY

CHE

Total

120

110

101

331

100.0000

100.000

99.9201471

100.0000

1

120

101

111

332

100.0000000

99.9778342

99.9926114

100.0000000

2

115

115

105

335

99.9964301

99.9750107

99.9571612

100.0000000

3

115

116

115

346

99.9692695

99.9938539

99.9938539

100.0000000

4

115

95

111

321

99.9903209

99.9080482

99.9975802

99.9975802

5

106

110

105

321

99.9007888

100.0000000

99.9661230

22051995

6

120

110

100

330

99.9975371

100.0000000

100.0000000

99.8916336

7

115

110

120

345

99.9969270

99.9692695

99.9600504

100.0000000

8

106

115

111

332

99.9964301

99.9500214

99.9750107

99.9750107

9

120

100

100

320

99.9950743

100.0000000

99.9704455

99.8916336

10

NTA Percentile For JEE Main 2025

Compilation and display of Result for multi session Papers of JEE(Main) For examinations conducted twice (First and Second attempt) before admissions to the next academic session.

1. Compilation of Result for First attempt:

Since, the first attempt will be conducted in multi-sessions, NTA scores will be calculated corresponding to the raw marks obtained by a candidate in each session as per above procedure. The calculated NTA scores for all the sessions will be merged for declaration of result. The result shall comprise the four NTA scores for each of the three subjects (Mathematics, Physics, and Chemistry) and the total for the first attempt.

2. Compilation of Result for Second attempt:

Similarly, the second attempt will be conducted in multi-sessions, NTA scores will be calculated corresponding to the raw marks obtained by a candidate in each session as per above procedure. The calculated NTA scores for all the sessions will be merged for declaration of result.The result shall comprise the four NTA scores for each of the three subjects (Mathematics, Physics, and Chemistry) and the total for the second attempt.

3. Compilation of Result and Preparation of Merit List / Ranking:

The four NTA scores for each of the candidates for the first attempt as well as for the second attempt will be merged for compilation of result and preparation of overall Merit List / Ranking.Those appeared in both the attempts; their best of the two NTA scores will be considered further for preparation of Merit List /Rankings as explained in the following example:

Roll No


First Attempt – NTA Score

Second Attempt-NTA Score

Final NTA Score for compilation of result (best of the two in Total)

C20045511

Total

99.8620723

99.8740051

99.8740051

Mathematics

99.6249335

100.0000000

100.0000000

Physics

99.7338237

99.2102271

99.2102271

Chemistry

99.8572327

99.7203528

99.7203528

C20045512

Total

Did not Appear

99.8620723

99.8620723

Mathematics

99.6249335

99.6249335

Physics

99.7338237

99.7338237

Chemistry

99.8572327

99.8572327

C20045513

Total

99.8740051

Did not Appear

99.8740051

Mathematics

100.0000000

100.0000000

Physics

99.2102271

99.2102271

Chemistry

99.7203528

99.7203528

C20045514

Total

99.8740051

99.8620723

99.8740051

Mathematics

100.0000000

99.6249335

100.0000000

Physics

99.2102271

99.7338237

99.2102271

Chemistry

99.7203528

99.8572327

99.7203528

JEE Mains 2025 Expected Marks Vs Percentile Vs Rank

IIT JEE aspirants can refer to the JEE Mains Marks vs Percentile vs Rank for 2025, which will be provided here. According to the JEE Main 2025 marks vs percentile vs rank data, candidates need to score above 250 marks to achieve a percentile greater than 90.

JEE Main Marks vs Rank vs Percentile 2025

Marks Out of 300

Percentile

Overall Rank

290- 280

99.99908943 - 99.99745041

13 - 36

280 - 250

99.99745041 - 99.96976913

36 - 428

250 - 240

99.96976913 - 99.94664069

428 - 755

240 - 230

99.94664069 - 99.91595453

755 - 1189

230 - 220

99.91595453 - 99.86623749

1189 - 1893

220 - 210

99.86623749 - 99.80777899

1893 - 2720

210 - 200

99.80777899 - 99.73129123

2720 - 3803

200 - 190

99.73129123 - 99.62402626

3803 - 5320

190 - 180

99.62402626 - 99.48033855

5320 - 7354

180 - 170

99.48033855 - 99.2955842

7354 - 9968

170 - 160

99.2955842 - 99.06985426

9968 - 13163

160 - 150

99.06985426 - 98.77819917

13163 - 17290

150 - 140

98.77819917 - 98.40768884

17290 - 22533

140 - 130

98.40768884 - 97.94047614

22533 - 29145

130 - 120

97.94047614 - 97.35425213

29145 - 37440

120 - 110

97.35425213 - 96.60949814

37440 - 47979

110 - 100

96.60949814 - 95.64338495

47979 - 61651

100 - 90

95.64338495 - 94.39636137

61651 - 79298

90 - 80

94.39636137 - 92.76234617

79298 - 102421

80 - 70

92.76234617 - 90.4109851

102421 - 135695

70 - 60

90.4109851 - 87.06073037

135695 - 183105

60 - 50

87.06073037 - 81.57582987

183105 - 260722

50 - 40

81.57582987 - 73.08140938

260722 - 380928

40 - 30

73.08140938 - 59.84001311

380928 - 568308

30 - 20

59.84001311 - 40.3469266

568308 - 844157

20 - 10

40.3469266 - 20.95045141

844157 - 1118638

10 - 0

20.95045141 - 6.599800585

1118638 - 1321716

JEE Main 2025 Session 1 Cutoff Expected

The National Testing Agency will release the JEE Main 2025 cutoff on the official website. Candidates can check the expected cutoff for various categories: 95+ for General, 83+ for OBC, 85+ for EWS, 65+ for SC, and 50+ for ST.

Frequently Asked Questions (FAQs)

1. How to calculate percentile in JEE Mains 2025?

To calculate the JEE Mains percentile for 2025, candidates should use the following formula: Percentile = (100 × Number of candidates in the session with a raw score equal to or lower than the T1 score) / Total number of candidates who appeared in the session.

2. What is the top 5 percentile?

A score that reaches beyond 95% of all observed data points belongs to the 5th percentile group. The top 5 percentile indicates your test score surpasses what 95% of test-takers achieved. Becoming part of the top 5 means your ranking surpasses 95% of potential candidates thus sitting at the 95th percentile position.

3. what is the cutoff for jee mains 2025?
CategoryExpected cut off
General91-95
EWS77-85
OBC NCL77-85
SC58-65
ST44-50

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Questions related to JEE Main

Have a question related to JEE Main ?

JEE Main Paper 2 SC rank of 1181 , you have a strong chance of securing admission in some of the top government colleges in India through counseling . Here’s an estimate of the colleges you may get based on previous years' cutoff trends:

Expected NITs & Other Top Govt Colleges (B.Arch)

  1. NIT Trichy (National Institute of Technology, Tiruchirappalli) – Likely
    (Previous SC cutoffs around 1000-1500 )

  2. NIT Calicut – Good Chance
    (SC cutoff usually 1200-2000 )

  3. NIT Hamirpur – Very Likely
    (SC cutoff around 1500-2500 )

  4. NIT Jaipur (MNIT) – Possible
    (SC cutoff around 1000-2000 )

  5. NIT Patna – Safe Option
    (SC cutoff around 2000-3000 )

  6. NIT Raipur – Safe
    (SC cutoff around 2500-4000 )

  7. SPA Vijayawada (School of Planning & Architecture) – Possible
    (SC cutoff around 1000-2000 )

  8. CEPT Ahmedabad (if eligible via JEE Main) – Possible
    (Depends on state quota)

IIITs & Other Options

  • IIITDM Jabalpur (B.Arch) – Possible
    (SC cutoff around 1500-2500 )

State Govt Colleges

  • College of Engineering, Trivandrum (CET)

  • Jadavpur University (if appearing for WBJEE)

  • School of Planning & Architecture, Bhopal/Delhi (via JEE Main + CEED/separate exam

Your rank is competitive, so you should aim for NIT Trichy, NIT Calicut, or SPA Vijayawada as top preferences. (https://josaa.nic.in/)

Hello there,

PES University in Bangalore admits students to its B.Tech programs through both the JEE Main and PESSAT (PES Scholastic Aptitude Test) exams. The closing ranks for JEE Main vary by branch and category. For instance, in 2023, the closing rank for Computer Science and Engineering was 4,618, while for OBC candidates, it ranged between 1,463 and 7,937, and for SC candidates, between 15,675 and 36,289.

It's important to note that PES University primarily fills its seats through PESSAT, and only a limited number of seats are available via JEE Main. Therefore, competition is high, and securing admission through JEE Main requires a strong rank.

For the most accurate and up-to-date information, it's recommended to consult the official PES University admissions portal or contact their admissions office directly.


I hope this answer helps you. If you have more queries, feel free to share your questions with us, and we will be happy to assist you.

Thank you, and I wish you all the best in your bright future.

The closing rank for JEE Mains cutoff at PES University for B.Tech programs varies by program and year. In 2024, the closing rank for B.Tech in Computer Science and Engineering was 2009, while for B.Tech in Electrical and Electronics Engineering it was 10345. For more specific details, you can refer HERE

B.Tech in Computer Science and Engineering: The closing rank in 2024 was 2009.

B.Tech in Electrical and Electronics Engineering: The closing rank in 2024 was 10345.

B.Tech in Electronics and Communication Engineering: The closing rank in 2024 was 5451.

B.Tech in Mechanical Engineering: The closing rank in 2024 was 26275.

B.Tech in Biotechnology Engineering: The closing rank in 2024 was 18040.

B.Tech in Computer Science and Engineering (Artificial Intelligence and Machine Learning): The closing rank in 2024 was 3119.

Ranks for PES University (Bangalore) in JEE Main vary depending on the branch, category, and quota . Here’s an overview based on recent trends (2023-2024):

PES University JEE Main Cutoff (2023)

B.Tech (Through JEE Main)

Branch General (Round 1) General (Last Round) SC/ST/OBC
Computer Science (CSE) ~25,000 - 35,000 ~40,000 - 50,000 ~80,000 - 1.2L
Artificial Intelligence (AI) ~30,000 - 45,000 ~50,000 - 70,000 ~1L - 1.5L
Electronics (ECE) ~50,000 - 70,000 ~80,000 - 1.2L ~1.5L+
Mechanical (ME) ~1L - 1.5L ~1.5L - 2L ~2L+

2024 Expected Cutoff

  • Cutoffs may increase slightly (~5-10%) due to rising competition.

  • Safe Ranks :

    • CSE : < 40,000 (General)

    • ECE/AI : < 80,000

    • Mechanical : < 1.5L

Hello there,

Yes, if you got 61 percentile in JEE Mains, you may be eligible to apply under B-Category counselling in some private engineering colleges or deemed universities.

Key points to note:

  1. B-Category seats are usually filled through JEE Mains score but do not have a high cutoff like NITs or IITs.

  2. Colleges offering B-Category admissions mostly focus on:

    • Availability of seats

    • JEE percentile (minimum required varies by college)

    • State rules and college reputation

At 61 percentile, you might not get top branches like CSE or ECE in top private colleges, but you can get options in other branches or in mid-level institutions.

You should directly check with the colleges you're interested in, as B-Category admission rules and cutoffs vary from college to college.


I hope this answer helps you. If you have more queries, feel free to share your questions with us, and we will be happy to assist you.

Thank you, and I wish you all the best in your bright future.

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