JEE Mains 2025 for Qualifying Percentile: Candidates can access the qualifying percentile data for JEE Main through this page. The National Testing Agency will release the JEE Mains 2025 cutoff on the official website, jeemain.nta.nic.in. To qualify for JEE Advance participants need to meet the minimum percentile specified by JEE Mains 2025. The cutoff marks to qualify in JEE Main 2025 varies every year based on the factors like difficulty level of exam, number of candidates and seats available. The authority conducted the JEE Main entrance exam on January 22 to 30, 2025.
The NTA in 2024 revised the tie-breaking process for Paper 1 to determine ranks of candidates with identical total NTA scores. The criteria used were applied in the following order:
If the tie persisted even after applying all these parameters, candidates were allotted the same rank.
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JEE Mains 2025 qualifying percentile is calculated using the normalisation process for all the exam shifts. Securing the JEE Main qualifying percentile allows students to appear for JEE advance, but to secure admission into the NITs, IIIT’s and GFTI’s, candidates must score the respective institute cutoff and marks. In case of General category candidates, the cutoff percentile ranges from 88 to 92. In case of OBC, it is around 72 to 76, and for SC/ST the cutoff falls between 30 to 55. For more details regarding what is the qualifying percentile for JEE Mains, candidates can refer to the article given below.
The National Testing Agency evaluates JEE Main 2025 scores for percentile across three distinct subject categories (Physics, Chemistry, Mathematics) and a combined overall scheme using this normalization formula.
Total Percentile (T1P) | (100 x No. of candidates from the session with a raw score equal to or less than T1 score) / Total No. of candidates who appeared in the session |
Mathematics Percentile (M1P) | (100 x No. of candidates appeared from the session with a raw score equal to or less than than M1 score in Mathematics) / Total No. of candidates who appeared in the session |
Chemistry Percentile (C1P): | (100 x No. of candidates appeared from the session with a raw score equal to or less than C1 score in Chemistry) / Total No. of candidates who appeared in the session |
Physics Percentile (P1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates who appeared in the session |

Candidates can check the Top 10 NTA Score and Overall Rank List in the table below.
RAW SCORE | NTA SCORE (Percentile) | RANK | ||||||
Math | PHY | CHE | Total | Math | PHY | CHE | Total | |
120 | 110 | 101 | 331 | 100.0000 | 100.000 | 99.9201471 | 100.0000 | 1 |
120 | 101 | 111 | 332 | 100.0000000 | 99.9778342 | 99.9926114 | 100.0000000 | 2 |
115 | 115 | 105 | 335 | 99.9964301 | 99.9750107 | 99.9571612 | 100.0000000 | 3 |
115 | 116 | 115 | 346 | 99.9692695 | 99.9938539 | 99.9938539 | 100.0000000 | 4 |
115 | 95 | 111 | 321 | 99.9903209 | 99.9080482 | 99.9975802 | 99.9975802 | 5 |
106 | 110 | 105 | 321 | 99.9007888 | 100.0000000 | 99.9661230 | 22051995 | 6 |
120 | 110 | 100 | 330 | 99.9975371 | 100.0000000 | 100.0000000 | 99.8916336 | 7 |
115 | 110 | 120 | 345 | 99.9969270 | 99.9692695 | 99.9600504 | 100.0000000 | 8 |
106 | 115 | 111 | 332 | 99.9964301 | 99.9500214 | 99.9750107 | 99.9750107 | 9 |
120 | 100 | 100 | 320 | 99.9950743 | 100.0000000 | 99.9704455 | 99.8916336 | 10 |
Compilation and display of Result for multi session Papers of JEE(Main) For examinations conducted twice (First and Second attempt) before admissions to the next academic session.
1. Compilation of Result for First attempt:
Since, the first attempt will be conducted in multi-sessions, NTA scores will be calculated corresponding to the raw marks obtained by a candidate in each session as per above procedure. The calculated NTA scores for all the sessions will be merged for declaration of result. The result shall comprise the four NTA scores for each of the three subjects (Mathematics, Physics, and Chemistry) and the total for the first attempt.
2. Compilation of Result for Second attempt:
Similarly, the second attempt will be conducted in multi-sessions, NTA scores will be calculated corresponding to the raw marks obtained by a candidate in each session as per above procedure. The calculated NTA scores for all the sessions will be merged for declaration of result.The result shall comprise the four NTA scores for each of the three subjects (Mathematics, Physics, and Chemistry) and the total for the second attempt.
3. Compilation of Result and Preparation of Merit List / Ranking:
The four NTA scores for each of the candidates for the first attempt as well as for the second attempt will be merged for compilation of result and preparation of overall Merit List / Ranking.Those appeared in both the attempts; their best of the two NTA scores will be considered further for preparation of Merit List /Rankings as explained in the following example:
Roll No | First Attempt – NTA Score | Second Attempt-NTA Score | Final NTA Score for compilation of result (best of the two in Total) | |
C20045511 | Total | 99.8620723 | 99.8740051 | 99.8740051 |
Mathematics | 99.6249335 | 100.0000000 | 100.0000000 | |
Physics | 99.7338237 | 99.2102271 | 99.2102271 | |
Chemistry | 99.8572327 | 99.7203528 | 99.7203528 | |
C20045512 | Total | Did not Appear | 99.8620723 | 99.8620723 |
Mathematics | 99.6249335 | 99.6249335 | ||
Physics | 99.7338237 | 99.7338237 | ||
Chemistry | 99.8572327 | 99.8572327 | ||
C20045513 | Total | 99.8740051 | Did not Appear | 99.8740051 |
Mathematics | 100.0000000 | 100.0000000 | ||
Physics | 99.2102271 | 99.2102271 | ||
Chemistry | 99.7203528 | 99.7203528 | ||
C20045514 | Total | 99.8740051 | 99.8620723 | 99.8740051 |
Mathematics | 100.0000000 | 99.6249335 | 100.0000000 | |
Physics | 99.2102271 | 99.7338237 | 99.2102271 | |
Chemistry | 99.7203528 | 99.8572327 | 99.7203528 |
IIT JEE aspirants can refer to the JEE Mains Marks vs Percentile vs Rank for 2025, which will be provided here. According to the JEE Main 2025 marks vs percentile vs rank data, candidates need to score above 250 marks to achieve a percentile greater than 90.
Marks Out of 300 | Percentile | Overall Rank |
|---|---|---|
290- 280 | 99.99908943 - 99.99745041 | 13 - 36 |
280 - 250 | 99.99745041 - 99.96976913 | 36 - 428 |
250 - 240 | 99.96976913 - 99.94664069 | 428 - 755 |
240 - 230 | 99.94664069 - 99.91595453 | 755 - 1189 |
230 - 220 | 99.91595453 - 99.86623749 | 1189 - 1893 |
220 - 210 | 99.86623749 - 99.80777899 | 1893 - 2720 |
210 - 200 | 99.80777899 - 99.73129123 | 2720 - 3803 |
200 - 190 | 99.73129123 - 99.62402626 | 3803 - 5320 |
190 - 180 | 99.62402626 - 99.48033855 | 5320 - 7354 |
180 - 170 | 99.48033855 - 99.2955842 | 7354 - 9968 |
170 - 160 | 99.2955842 - 99.06985426 | 9968 - 13163 |
160 - 150 | 99.06985426 - 98.77819917 | 13163 - 17290 |
150 - 140 | 98.77819917 - 98.40768884 | 17290 - 22533 |
140 - 130 | 98.40768884 - 97.94047614 | 22533 - 29145 |
130 - 120 | 97.94047614 - 97.35425213 | 29145 - 37440 |
120 - 110 | 97.35425213 - 96.60949814 | 37440 - 47979 |
110 - 100 | 96.60949814 - 95.64338495 | 47979 - 61651 |
100 - 90 | 95.64338495 - 94.39636137 | 61651 - 79298 |
90 - 80 | 94.39636137 - 92.76234617 | 79298 - 102421 |
80 - 70 | 92.76234617 - 90.4109851 | 102421 - 135695 |
70 - 60 | 90.4109851 - 87.06073037 | 135695 - 183105 |
60 - 50 | 87.06073037 - 81.57582987 | 183105 - 260722 |
50 - 40 | 81.57582987 - 73.08140938 | 260722 - 380928 |
40 - 30 | 73.08140938 - 59.84001311 | 380928 - 568308 |
30 - 20 | 59.84001311 - 40.3469266 | 568308 - 844157 |
20 - 10 | 40.3469266 - 20.95045141 | 844157 - 1118638 |
10 - 0 | 20.95045141 - 6.599800585 | 1118638 - 1321716 |
The National Testing Agency will release the JEE Main 2025 cutoff on the official website. Candidates can check the expected cutoff for various categories: 95+ for General, 83+ for OBC, 85+ for EWS, 65+ for SC, and 50+ for ST.
Frequently Asked Questions (FAQs)
| Category | Expected cut off |
|---|---|
| General | 91-95 |
| EWS | 77-85 |
| OBC NCL | 77-85 |
| SC | 58-65 |
| ST | 44-50 |
A score that reaches beyond 95% of all observed data points belongs to the 5th percentile group. The top 5 percentile indicates your test score surpasses what 95% of test-takers achieved. Becoming part of the top 5 means your ranking surpasses 95% of potential candidates thus sitting at the 95th percentile position.
To calculate the JEE Mains percentile for 2025, candidates should use the following formula: Percentile = (100 × Number of candidates in the session with a raw score equal to or lower than the T1 score) / Total number of candidates who appeared in the session.
On Question asked by student community
Hello Aspirant
As you are preparing for JEEMains and you want to practice the PYQs, it is a good choice as NTA mainly follows the same pattern, and some questions are repeatedly asked. To get the most repeated question, just visit the link I'm attaching below.
The form requires the candidates to upload the signature in JPEG format within 10-100KB format, if this condition is not fulfilled the photo will not get uploaded. Assistance from an e-mitra might be needed or you may choose to convert the sizes and the types of your documents from various converting applications available
to get details about registration and avoid getting confused follow the link below from careers360 How to fill JEE Main Application Form 2026? – Steps to Apply Online
You can look up to the syllabus released by the NTA for the 2026 examination available in pdf form at careers360 from the link given below, you will get all the deleted syllabus and the additional added syallabus in the pdf itself JEE Main 2026 Syllabus (Out): Download Paper 1, 2 PDF Here
Hello, You want to get 99 percentile in JEE Mains, for this you should prepare very well.
I am providing you the link of a book to help you in your preparation, you will get everything in it to score well in JEE Mains.
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You can download the ebook directly by clicking on "CLICK HERE".
I hope you found this information helpful and for any study related problems you can ask in careers360 app, Have a great day!
Hello,
JEE Main ke 75% eligibility ke liye marks calculation board ke total marks (as printed on marksheet) par based hoti hai, best of 5 nahi.
Agar aapke marksheet me total 355/500 likha hai, to wahi valid mana jayega.
Isliye agar ye 75% se kam hai, to aap JEE Main de sakte ho, par NIT, IIIT, ya GFTI admission ke liye eligible nahi hoge, unless aap SC/ST category se ho (unke liye 65% required hai).
Hope you understand.
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