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JEE Mains 2018 Question Paper- NTA uploaded the JEE Main question paper 2018. Candidates can cross-check the answers and get an insight into the background and pattern of the paper. By solving JEE Main previous year question papers, aspirants can analyse the difficulty level and weightage given to a concept/topic that requires more attention. NTA conducted the JEE Main exam in online mode. The JEE Main 2018 question paper pdf with the answer key can be downloaded from this page using the links given below. Follow the JEE Main preparation tips and books referred by NTA IIT JEE toppers. Check the page for JEE Main 2018 question papers.
The JEE Main 2026 percentile predictor is available on Careers360 and helps students easily estimate their expected percentile based on their exam performance, so they can understand their chances and plan what to do next.
Candidates can check the question paper of JEE Main 2018 here. The direct links for JEE Main 2018 question paper with solution PDF are given below.
JEE Main Question Paper 2018 PDF
JEE Main Question Paper 2018 can be downloaded by using the links provided above. Candidates are required to provide their necessary details for downloading the question paper. Once, they register with their details a link will be sent to their registered email address for downloading the question paper of JEE main 2018.
Below is the benefit of solving the JEE Main question paper below
Frequently Asked Questions (FAQs)
Candidates can download the JEE Main 2018 paper without solutions pdf through the link provided on this page.
The overall difficulty level of JEE 2018 for sessions 1 and 2 was moderate to difficult level.
Mathematics is considered to be a tough paper due to lengthy questions and a number of numerical questions.
NTA conducted the JEE Main 2018 exam.
Candidates will be able to download the JEE 2018 question paper online at jeemain.nta.nic.in.
On Question asked by student community
JEE Main 28 Jan shift 2 exam will end at 6 PM. The complete analysis and memory-based questions will solution will be updated in the below article. Keep checking the page-
Math and Chemistry was difficult and Physics was moderate. The complete analysis is available here- https://engineering.careers360.com/articles/jee-main-2026-january-28-shift-1-question-paper-with-solutions-pdf
You can also check the memory-based questions and detailed solutions for JEE Main Jan 28 shift 1 paper.
Hi Lucky,
Please refer to this link and you can download the free pdf.
HI Manisha Maharana
You can download the JEE Mains 10 Free Mock Test with Detailed solutions. Its a feely downloadable pdf.
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Also, you can check ad attemp the online mock test on our platform.
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A general equation of a circle is
$
x^2+y^2+2 g x+2 f y+c=0
$
Since it passes through $(0,0)$,
$
c=0
$
So the equation becomes
$
x^2+y^2+2 g x+2 f y=0
$
It cuts the x -axis at ( $a, 0$ ).
Substituting:
$
a^2+2 g a=0
$
g=-a/2
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