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JEE Main 2020 Question Paper with Solution PDF

JEE Main 2020 Question Paper with Solution PDF

#JEE Main
Team Careers360Updated on 04 Nov 2024, 04:57 PM IST

JEE Main 2020 Question Paper with Solution PDF is provided here for the ease of students who are preparing for the upcoming JEE Mains exam. The question paper of JEE Main 2020 is available with the answer key in PDF format. Solving the JEE Main 2020 question paper gives insight into the JEE Main exam difficulty level, important topics, marking scheme and more. Solving or reviewing the JEE Mains 2020 question paper with solutions within 3 hours (i.e. real exam duration) helps you improve your problem-solving skills. Aspirants can also download the previous year's JEE Mains question paper from Careers360. Download the JEE Main 2020 question paper with the solution pdf below.

This Story also Contains

  1. JEE Main 2020 Question Paper PDF
  2. JEE Main 2020 Question Paper With Solution (January Session)
  3. JEE Main 2020 Question Paper with Solution (September Session)
  4. JEE Main Sample Paper PDF
  5. Benefits of Solving JEE Main 2020 Question Paper with Solution PDF
  6. JEE Main 2020 Vs JEE Main 2025
  7. Few Solved Questions from JEE Main 2020 Paper
JEE Main 2020 Question Paper with Solution PDF
JEE Main 2020 Question Paper

JEE Main 2020 Question Paper PDF

JEE Main 2020 paper was conducted in 2 sessions (i.e. January and September) where a total number of 1200 questions were asked including all three subjects (i.e. Physics, Maths and Chemistry) from all 16 shifts. This number of questions is sufficient for aspirants aiming for JEE Main 2025 preparations for practising questions of JEE Main difficulty level. If needed candidates can also go through others JEE Main previous years questions for better understanding.

JEE Main 2020 Question Paper With Solution (January Session)

JEE Main 2020 Question Paper with Solution (September Session)

In the year 2020 session 2 of JEE Main, which is usually held in April, was postponed due to the Covid 19 pandemic and was conducted in the month of September. Click the link below to download the official JEE Main Question Paper 2020 with solutions.

Direct link for JEE Main September 2020 Official Question Papers With Detailed Solutions

Careers360 provides the question paper of JEE Main 2020 for both sessions on this page itself. We have also provided solutions to the questions asked in JEE Main question paper 2020. After attempting the JEE Main question paper, candidates can check their answers by using the solutions provided.

Since these are free resources, candidates must download them to make the most of them. JEE Main 2020 question paper when combined with other resources such as mock tests, sample papers and more practice questions makes an effective preparation strategy. Students can find the links for all the preparation resources on this page itself.

Careers360 provides the question paper of JEE Main 2020 for both sessions on this page itself. We have also provided solutions to the questions asked in JEE Main question paper 2020. After attempting the JEE Main question paper, candidates can check their answers by using the solutions provided.

Aspirants preparing for upcoming exams can gain valuable insights into the paper pattern, difficulty level, and frequently appearing questions by referring to the JEE Main question paper pdf. Experts have explained the jee main question paper 2020 with solutions in great detail.

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JEE Main Important Formulas

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JEE Main Sample Paper PDF

We have provided direct links for downloading the JEE Main sample paper pdf. Candidates must download the sample papers and practise them to strengthen their preparation for the upcoming JEE Main examination.

Download JEE Main Sample Paper Link

JEE Main Syllabus: Subjects & Chapters
Select your preferred subject to view the chapters

Benefits of Solving JEE Main 2020 Question Paper with Solution PDF

Students who complete the JEE Mains 2020 question paper will gain the following advantages:

  • Candidates will be able to revise the concepts learned during preparation by practising the JEE Main exam question paper pdf. Students can then identify topics that need more practice and strengthen their grasp on the particular subject topics.

  • Students can gain an understanding of the JEE Main exam pattern, the weighting of topics, and more by solving the question paper of JEE Main 2020. This acts as a better preparation strategy for the exam.

  • Candidates can improve their time management and exam familiarity by completing the JEE Mains question paper 2020. They can also use it to determine which sections to concentrate on to increase their accuracy and speed.

  • Regular practice of JEE Main Question Paper 2020 pdf with solutions can help candidates gain confidence and reduce anxiety before the exam. It will allow candidates to get the feel of the exam and get accustomed to its time limit and challenging questions.

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JEE Main 2020 Vs JEE Main 2025

There is a significant difference between JEE Main 2020 and JEE Main 2025 question papers with respect to exam syllabus, exam pattern, number of questions etc for Paper 1 (i.e. for B.E./ B. Tech). Let's discuss them one by one

  • JEE Main Syllabus:- Major chapters from all three subjects have been deleted from JEE Main 2025 Syllabus with respect to JEE Main 2020 Syllabus.

JEE Main 2026: Preparation Tips & Study Plan
Download the JEE Main 2026 Preparation Tips PDF to boost your exam strategy. Get expert insights on managing study material, focusing on key topics and high-weightage chapters.
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Here are the details about the syllabus that is removed.

Subject

Chapter Name

Physics

Communication System

Physical Chemistry

States of Matter

Surface Chemistry

Inorganic Chemistry

General Principles and Processes of Isolation of Metals

Hydrogen

S-Block Elements (Alkali and Alkaline Earth Metals)

Environmental Chemistry

Organic Chemistry

Polymers

Chemistry in Everyday Life

Mathematics

Mathematical Inductions

Mathematical Reasoning

The above-mentioned chapters are completely removed from the JEE Main 2025 Syllabus along with major topics from other remaining chapters also reduced.

For detailed analysis have a look at JEE Main 2025 Syllabus

  • Exam patterns:-

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  1. Total marks- For both JEE Main 2025 and JEE Main 2020 total marks are the same. I.e Students can achieve a maximum of 300 marks in the main exam.

  2. No of Questions- Let's have a look at Subject wise distribution of the total number of questions for the JEE Main 2025 and JEE Main 2020 exams.

Subject

No of Questions

No of Questions

Mathematics

(20 MCQs+ 5 NAT)

(20 MCQs+ 5 NAT)

Physics

(20 MCQs+ 5 NAT)

(20 MCQs+ 5 NAT)

Chemistry

(20 MCQs+ 5 NAT)

(20 MCQs+ 5 NAT)

Here MCQs mean Multiple-Choice Questions and NTA means questions whose answers are to be filled in as a numerical value. So to summarize in JEE Main 2025 for section B in each subject 5 NTA-type questions are there, but candidates have to attempt all 5 of them.

Few Solved Questions from JEE Main 2020 Paper

1. (Subject - Physics, Chapter - Optics, Shift - 06 Sep - Evening Shift)

Question:- A double convex lens has power P and the same radii of curvature R of both surfaces. The radius of curvature of the surface of a planoconvex lens made of the same material with power 1.5 P is :

  1. 2R

  2. \frac{R}{2}

  3. \frac{3R}{2}

  4. \frac{R}{3}

Answer- 4) \frac{R}{3}

Solution:-

1720600855410

\mathrm{R}_{1}=\mathrm{R}_{2}=\mathrm{R} \\ Power= P \\ \text{Refractive index is assume} (\mu_{l})

\mathrm{P}=\frac{1}{\mathrm{f}}=\left(\mu_{l}-1\right)\left(\frac{2}{\mathrm{R}}\right)

1720600856679

\begin{aligned} &\mathrm{P}^{\prime}=\frac{1}{\mathrm{f}^{\prime}}=\left(\mu_{\ell}-1\right)\left(\frac{1}{\mathrm{R}^{\prime}}\right)\\ &P^{\prime}=\frac{3}{2} P \end{aligned}

\begin{array}{l} \left(\mu_{\ell}-1\right)\left(\frac{1}{\mathrm{R}^{\prime}}\right)= \frac{3}{2}\left(\mu_{\ell}-1\right)\left(\frac{2}{\mathrm{R}}\right) \\ \\ \therefore \quad \mathrm{R}^{\prime}=\frac{\mathrm{R}}{3} \end{array}

Hence, The correct option is (4)

2. (Subject - Maths, Chapter - Integral Calculus, Shift - 03 Sep - Evening Shift )

Question:- If \int \sin ^{-1}\left ( \sqrt{\frac{x}{1+x}} \right )dx=A(x)\tan ^{-1}(\sqrt{x})+B(x)+C, where C is a constant of integration, then the ordered pair (A(x),\; B(x)) can be?

  1. (x+1,\; -\sqrt{x})

  2. (x+1,\; \sqrt{x})

  3. (x-1,\; -\sqrt{x})

  4. (x-1,\; \sqrt{x})

Answer- 1) (x+1,\; -\sqrt{x})

Solution:-

Given,

\int \sin ^{-1}\left ( \sqrt{\frac{x}{1+x}} \right )dx=A(x)\tan ^{-1}(\sqrt{x})+B(x)+C,

\begin{array}{l} \text { Put } x=\tan ^{2} \theta \Rightarrow d x=2 \tan \theta \sec ^{2} \theta d \theta \\ \int \theta \cdot\left(2 \tan \theta \cdot \sec ^{2} \theta\right) d \theta \end{array}

Now do the integration by parts

\\\mathrm{\theta\rightarrow 1st\;function}\\\mathrm{2\tan\theta\sec^2\theta\rightarrow 2nd\;function}

\begin{array}{l} =\theta \cdot \tan ^{2} \theta-\int \tan ^{2} \theta \mathrm{d} \theta \\ =\theta \cdot \tan ^{2} \theta-\int\left(\sec ^{2} \theta-1\right) \mathrm{d} \theta \\ =\theta\left(1+\tan ^{2} \theta\right)-\tan \theta+\mathrm{C} \\ =\tan ^{-1}(\sqrt{\mathrm{x}})(1+\mathrm{x})-\sqrt{\mathrm{x}}+\mathrm{C} \end{array}

A(x)=1+x,\;\;B(x)=-\sqrt x

Hence, the answer is the option 1.

3. (Subject - Chemistry, Chapter - Hydrocarbons, Shift - 08 Jan - Morning Shift)

Question:- The major products A and B in the following reactions are:

1720600856029

  1. 1720600856074

  2. 1720600854949

  3. 1720600855903

  4. 1720600855239

Answer- 1) 1720600856126

Solution:-

The given reaction occurs as :

\mathrm{R-O-O-R\xrightarrow[]{\Delta}2R\dot{O}}

1720600856280

Therefore, Option(1) is correct.

Frequently Asked Questions (FAQs)

Q: Is the JEE Main 2020 question paper a reliable resource for practice?
A:

Yes, the JEE Main 2020 question paper is a reliable resource for practice as it is the official examination paper.

Q: Where can I find the JEE Main 2020 question paper?
A:

Candidates can find the JEE Main question papers with solutions pdf of all years and sessions on Careers360 website.

Q: How effective was solving the previous year's JEE Main question papers for exam preparation?
A:

Solving the previous year's JEE Main question papers was a highly effective preparation strategy. It allowed candidates to familiarise themselves with the exam pattern, question types, and concepts. It also helped assess their readiness and improve problem-solving skills.

Q: What is the mode of examination for JEE Main 2020?
A:

JEE Mains 2020 examination was conducted as a computer based test and held in online mode.

Q: What are the advantages of practising previous years' JEE Main question papers?
A:

Solving previous years' question papers can help candidates identify the exam pattern, important topics, frequently asked topics, and increase their speed and accuracy.

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there is no fixed marks requirement to appear JEE Mains exams you just need to complete your 12th with

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Is p block elements included in jee mains syllabus for 2026 examination

Hey ,

If you are preparing for you jee mains 2026 then yes P block holds a good weightage in your exams as it is a part of chemistry . And yes P block elements is included in jee mains 2026 syllabus so it is good for you to prepare for the exams accordingly and does not leave this leave for the same thankyou .

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Hello,

you can appear for the TALLENTEX or StarNxt test while in class 10.The offline exams for TALLENTEX 2026 are scheduled for October 5 and October 12 in 2025.you can register online at tallentex.com.

You can also take the ALLEN Scholarship Admission Test (ASAT) and if you score 85% and above in it, you will definitely get a scholarship. Also you get one of the best batches too.

If you're a NTSE scholar, good at National and state Olympiads. You can enlist yourself for Allen Champ.


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Hello,

JEE Main 2026 will be held in two sessions. Session 1 is expected in the last week of January 2026 and Session 2 in the first week of April 2026 .

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