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    JEE Main 2020 Question Paper with Solution PDF

    JEE Main 2020 Question Paper with Solution PDF

    #JEE Main
    Team Careers360Updated on 08 Dec 2025, 11:53 AM IST

    JEE Main 2020 Question Paper with Solution PDF - The National Testing Agency uploaded the JEE Main question paper with solution 2020 on the official website, jeemain.nta.nic.in. Candidates can check the question paper of JEE Main 2020 in this article. Solving the JEE Main 2020 question paper PDF is important to understand the difficulty level of the JEE Main exam, important topics, marking scheme and more. Reviewing or slovinf the JEE Mains 2020 question paper within the 3 hours (i.e. real exam duration) helps you improve your problem-solving skills. Aspirants can also download the previous year's JEE Mains question paper from Careers360. Download the JEE Main 2020 question paper with the solution pdf below.

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    An 87.5 percentile in JEE Main is a good score and is usually not enough to get top NITs or IITs in popular branches like CSE.

    This Story also Contains

    1. JEE Main 2020 Question Paper PDF
    2. JEE Main 2020 Question Paper with Solution (September Session)
    3. JEE Main Sample Paper PDF
    4. Benefits of Solving JEE Main 2020 Question Paper with Solution PDF
    5. Changes in JEE Main Question Paper
    6. Few Solved Questions from JEE Main 2020 Paper
    JEE Main 2020 Question Paper with Solution PDF
    JEE Main 2020 Question Paper

    JEE Main 2020 Question Paper PDF

    JEE Main 2020 paper was conducted in 2 sessions (i.e. January and September) where a total number of 1200 questions were asked including all three subjects (i.e. Physics, Maths and Chemistry) from all 16 shifts. This number of questions is sufficient for aspirants aiming for JEE Main 2025 preparations for practising questions of JEE Main difficulty level. If needed candidates can also go through others JEE Main previous years questions for better understanding. The JEE Main 2020 question paper with solution pdf free download link is provided below.

    JEE Main Question Paper PDF 2020

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    JEE Main 2020 Question Paper Day Wise

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    JEE Main 2020 Question Paper with Solution (September Session)

    In the year 2020 session 2 of JEE Main, which is usually held in April, was postponed due to the Covid 19 pandemic and was conducted in the month of September. Candidates can click the link above to download the official JEE Main Question Paper 2020 with solutions. Careers360 provides the question paper of JEE Main 2020 for both sessions on this page itself. We have also provided solutions to the questions asked in JEE Main question paper 2020. After attempting the JEE Main question paper, candidates can check their answers by using the solutions provided.

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    Since these are free resources, candidates must download them to make the most of them. JEE Main 2020 question paper when combined with other resources such as mock tests, sample papers and more practice questions makes an effective preparation strategy. Students can find the links for all the preparation resources on this page itself.

    Aspirants preparing for upcoming exams can gain valuable insights into the paper pattern, difficulty level, and frequently appearing questions by referring to the JEE Main question paper pdf. Experts have explained the jee main question paper 2020 with solutions in great detail.

    JEE Main Paper 1

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    JEE Main Sample Paper PDF

    We have provided direct links for downloading the JEE Main sample paper pdf. Candidates must download the sample papers and practise them to strengthen their preparation for the upcoming JEE Main examination.

    Download JEE Main Sample Paper Link

    Benefits of Solving JEE Main 2020 Question Paper with Solution PDF

    Students who complete the JEE Mains 2020 question paper will gain the following advantages:

    • Candidates will be able to revise the concepts learned during preparation by practising the JEE Main exam question paper pdf. Students can then identify topics that need more practice and strengthen their grasp on the particular subject topics.

    • Students can gain an understanding of the JEE Main exam pattern, the weighting of topics, and more by solving the question paper of JEE Main 2020. This acts as a better preparation strategy for the exam.

    • Candidates can improve their time management and exam familiarity by completing the JEE Mains question paper 2020. They can also use it to determine which sections to concentrate on to increase their accuracy and speed.

    • Regular practice of JEE Main Question Paper 2020 pdf with solutions can help candidates gain confidence and reduce anxiety before the exam. It will allow candidates to get the feel of the exam and get accustomed to its time limit and challenging questions.

    JEE Main Syllabus: Subjects & Chapters
    Select your preferred subject to view the chapters

    Changes in JEE Main Question Paper

    There is a significant difference between JEE Main question papers as compared to previous years, with respect to exam syllabus, exam pattern, number of questions etc for Paper 1 (i.e. for B.E./ B. Tech). Let's discuss them one by one

    • JEE Main Syllabus:- Major chapters from all three subjects have been deleted from the current JEE Main Syllabus with respect to previous year JEE Main Syllabus.

    Here are the details about the syllabus that is removed.

    Subject

    Chapter Name

    Physics

    Communication System

    Physical Chemistry

    States of Matter

    Surface Chemistry

    Inorganic Chemistry

    General Principles and Processes of Isolation of Metals

    Hydrogen

    S-Block Elements (Alkali and Alkaline Earth Metals)

    Environmental Chemistry

    Organic Chemistry

    Polymers

    Chemistry in Everyday Life

    Mathematics

    Mathematical Inductions

    Mathematical Reasoning

    The above-mentioned chapters are completely removed from the JEE Main Syllabus along with major topics from other remaining chapters also reduced.

    For detailed analysis have a look at JEE Main Syllabus

    • Exam patterns:-

    1. Total marks- The total marks are the same. I.e Students can achieve a maximum of 300 marks in the main exam.

    2. No of Questions- Let's have a look at Subject wise distribution of the total number of questions for the JEE Main exams.

    Subject

    No of Questions

    No of Questions

    Mathematics

    (20 MCQs+ 5 NAT)

    (20 MCQs+ 5 NAT)

    Physics

    (20 MCQs+ 5 NAT)

    (20 MCQs+ 5 NAT)

    Chemistry

    (20 MCQs+ 5 NAT)

    (20 MCQs+ 5 NAT)

    Here MCQs mean Multiple-Choice Questions and NTA means questions whose answers are to be filled in as a numerical value. So to summarize in JEE Main for section B in each subject 5 NTA-type questions are there, but candidates have to attempt all 5 of them.

    Few Solved Questions from JEE Main 2020 Paper

    1. (Subject - Physics, Chapter - Optics, Shift - 06 Sep - Evening Shift)

    Question:- A double convex lens has power P and the same radii of curvature R of both surfaces. The radius of curvature of the surface of a planoconvex lens made of the same material with power 1.5 P is :

    1. 2R

    2. \frac{R}{2}

    3. \frac{3R}{2}

    4. \frac{R}{3}

    Answer- 4) \frac{R}{3}

    Solution:-

    1720600855410

    \mathrm{R}_{1}=\mathrm{R}_{2}=\mathrm{R} \\ Power= P \\ \text{Refractive index is assume} (\mu_{l})

    \mathrm{P}=\frac{1}{\mathrm{f}}=\left(\mu_{l}-1\right)\left(\frac{2}{\mathrm{R}}\right)

    1720600856679

    \begin{aligned} &\mathrm{P}^{\prime}=\frac{1}{\mathrm{f}^{\prime}}=\left(\mu_{\ell}-1\right)\left(\frac{1}{\mathrm{R}^{\prime}}\right)\\ &P^{\prime}=\frac{3}{2} P \end{aligned}

    \begin{array}{l} \left(\mu_{\ell}-1\right)\left(\frac{1}{\mathrm{R}^{\prime}}\right)= \frac{3}{2}\left(\mu_{\ell}-1\right)\left(\frac{2}{\mathrm{R}}\right) \\ \\ \therefore \quad \mathrm{R}^{\prime}=\frac{\mathrm{R}}{3} \end{array}


    Hence, The correct option is (4)


    2. (Subject - Maths, Chapter - Integral Calculus, Shift - 03 Sep - Evening Shift )

    Question:- If \int \sin ^{-1}\left ( \sqrt{\frac{x}{1+x}} \right )dx=A(x)\tan ^{-1}(\sqrt{x})+B(x)+C, where C is a constant of integration, then the ordered pair (A(x),\; B(x)) can be?

    1. (x+1,\; -\sqrt{x})

    2. (x+1,\; \sqrt{x})

    3. (x-1,\; -\sqrt{x})

    4. (x-1,\; \sqrt{x})

    Answer- 1) (x+1,\; -\sqrt{x})

    Solution:-

    Given,

    \int \sin ^{-1}\left ( \sqrt{\frac{x}{1+x}} \right )dx=A(x)\tan ^{-1}(\sqrt{x})+B(x)+C,

    \begin{array}{l} \text { Put } x=\tan ^{2} \theta \Rightarrow d x=2 \tan \theta \sec ^{2} \theta d \theta \\ \int \theta \cdot\left(2 \tan \theta \cdot \sec ^{2} \theta\right) d \theta \end{array}

    Now do the integration by parts

    \\\mathrm{\theta\rightarrow 1st\;function}\\\mathrm{2\tan\theta\sec^2\theta\rightarrow 2nd\;function}

    \begin{array}{l} =\theta \cdot \tan ^{2} \theta-\int \tan ^{2} \theta \mathrm{d} \theta \\ =\theta \cdot \tan ^{2} \theta-\int\left(\sec ^{2} \theta-1\right) \mathrm{d} \theta \\ =\theta\left(1+\tan ^{2} \theta\right)-\tan \theta+\mathrm{C} \\ =\tan ^{-1}(\sqrt{\mathrm{x}})(1+\mathrm{x})-\sqrt{\mathrm{x}}+\mathrm{C} \end{array}

    A(x)=1+x,\;\;B(x)=-\sqrt x

    Hence, the answer is the option 1.


    3. (Subject - Chemistry, Chapter - Hydrocarbons, Shift - 08 Jan - Morning Shift)

    Question:- The major products A and B in the following reactions are:

    1720600856029


    1. 1720600856074

    2. 1720600854949

    3. 1720600855903

    4. 1720600855239


    Answer- 1) 1720600856126

    Solution:-

    The given reaction occurs as :

    \mathrm{R-O-O-R\xrightarrow[]{\Delta}2R\dot{O}}

    1720600856280

    Therefore, Option(1) is correct.

    Frequently Asked Questions (FAQs)

    Q: Is the JEE Main 2020 question paper a reliable resource for practice?
    A:

    Yes, the JEE Main 2020 question paper is a reliable resource for practice as it is the official examination paper.

    Q: Where can I find the JEE Main 2020 question paper?
    A:

    Candidates can find the JEE Main question papers with solutions pdf of all years and sessions on Careers360 website.

    Q: How effective was solving the previous year's JEE Main question papers for exam preparation?
    A:

    Solving the previous year's JEE Main question papers was a highly effective preparation strategy. It allowed candidates to familiarise themselves with the exam pattern, question types, and concepts. It also helped assess their readiness and improve problem-solving skills.

    Q: What is the mode of examination for JEE Main 2020?
    A:

    JEE Mains 2020 examination was conducted as a computer based test and held in online mode.

    Q: What are the advantages of practising previous years' JEE Main question papers?
    A:

    Solving previous years' question papers can help candidates identify the exam pattern, important topics, frequently asked topics, and increase their speed and accuracy.

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    I can not download ebooks JEE MAINS CHAPTER WISE PYQ after clicking in the link

    Hi Fahim,

    If you are facing issues downloading, please use this direct Careers360 link for JEE Mains Chapter-wise PYQ eBooks:

    https://engineering.careers360.com/articles/jee-mains-chapterwise-pyq-previous-year-questions-solutions-pdf

    Read Complete Answer
    S
    Saniya Khatri
    26 Mar'26
    hindi medium jee mains question

    Hi Narendra,

    Please download the Hindi medium JEE Mains question paper with solution from the link given below:

    https://engineering.careers360.com/hi/articles/jee-main-question-paper-hindi-medium

    Read Complete Answer
    S
    Saniya Khatri
    26 Mar'26
    sir, i am a general pwbd student and i get 84.89 percentile in jee mains, can i get nit with this score.

    Hi Manish Saraswat,

    Yes, you can get NIT seat with 84.89 percentile in JEE Mains. Your's JEE Main rank is expected to be 2 lakh 22 thousand plus. See the list of NITs from the link below in which you may get an NIT seat.

    Link 1: https://engineering.careers360.com/articles/jee-main-marks-vs-rank

    Link 2:

    Read Complete Answer
    C
    Chintakuntla Sai Gnan
    24 Mar'26
    The concept of high weightage chapter for jee mains is real or not ???

    Hi,

    High - weightage chapters in JEE Mains are based on past paper analysis, not official NTA rules. Some topics come up more often, so students use them for smart revision. You can refer to this link for details:

    JEE Main Chapter-wise Weightage 2026: Important Topics & Marks Distribution

    Read Complete Answer
    S
    Saniya Khatri
    25 Mar'26
    Study material for jee Preparing

    Hi Sasika,

    Careers360 provides JEE study material, including books, notes, previous year papers, and revision PDFs for Physics, Chemistry, and Maths.

    You can check subject-wise study material here:

    https://engineering.careers360.com/exams/jee-main/study-material

    Read Complete Answer
    S
    Saniya Khatri
    25 Mar'26
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