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JEE Main 2020 Question Paper with Solution PDF

JEE Main 2020 Question Paper with Solution PDF

#JEE Main
Team Careers360Updated on 11 Oct 2025, 01:36 PM IST

JEE Main 2020 Question Paper with Solution PDF - NTA uploaded the JEE Main 2020 question paper on the official website, jeemain.nta.nic.in. Candidates can check the question paper of JEE Main 2020 in this article. Solving the JEE Main 2020 question paper PDF is important to understand the difficulty level of the JEE Main exam, important topics, marking scheme and more. Solving or reviewing the JEE Mains 2020 question paper with solutions within 3 hours (i.e. real exam duration) helps you improve your problem-solving skills. Aspirants can also download the previous year's JEE Mains question paper from Careers360. Download the JEE Main 2020 question paper with the solution pdf below.

LiveJEE Main 2026 Registration LIVE: NTA session 1 applications close on November 27; apply at jeemain.nta.nic.inNov 18, 2025 | 11:33 PM IST

Yes, droppers will have to reapply for the JEE Main exam for each session they plan to attend. Candidates who passed Class 12 in 2024, 2025 or are going to appear for the exam in 2026 can apply for JEE Mains 2026.

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This Story also Contains

  1. JEE Main 2020 Question Paper PDF
  2. JEE Main 2020 Question Paper with Solution (September Session)
  3. JEE Main Sample Paper PDF
  4. Benefits of Solving JEE Main 2020 Question Paper with Solution PDF
  5. Changes in JEE Main Question Paper
  6. Few Solved Questions from JEE Main 2020 Paper
JEE Main 2020 Question Paper with Solution PDF
JEE Main 2020 Question Paper

JEE Main 2020 Question Paper PDF

JEE Main 2020 paper was conducted in 2 sessions (i.e. January and September) where a total number of 1200 questions were asked including all three subjects (i.e. Physics, Maths and Chemistry) from all 16 shifts. This number of questions is sufficient for aspirants aiming for JEE Main 2025 preparations for practising questions of JEE Main difficulty level. If needed candidates can also go through others JEE Main previous years questions for better understanding.

JEE Main Question Paper PDF 2020

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JEE Main 2020 Question Paper Day Wise

JEE Main 2026: Preparation Tips & Study Plan
Download the JEE Main 2026 Preparation Tips PDF to boost your exam strategy. Get expert insights on managing study material, focusing on key topics and high-weightage chapters.
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JEE Main 2020 Question Paper with Solution (September Session)

In the year 2020 session 2 of JEE Main, which is usually held in April, was postponed due to the Covid 19 pandemic and was conducted in the month of September. Candidates can click the link above to download the official JEE Main Question Paper 2020 with solutions. Careers360 provides the question paper of JEE Main 2020 for both sessions on this page itself. We have also provided solutions to the questions asked in JEE Main question paper 2020. After attempting the JEE Main question paper, candidates can check their answers by using the solutions provided.

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Since these are free resources, candidates must download them to make the most of them. JEE Main 2020 question paper when combined with other resources such as mock tests, sample papers and more practice questions makes an effective preparation strategy. Students can find the links for all the preparation resources on this page itself.

Aspirants preparing for upcoming exams can gain valuable insights into the paper pattern, difficulty level, and frequently appearing questions by referring to the JEE Main question paper pdf. Experts have explained the jee main question paper 2020 with solutions in great detail.

JEE Main Sample Paper PDF

We have provided direct links for downloading the JEE Main sample paper pdf. Candidates must download the sample papers and practise them to strengthen their preparation for the upcoming JEE Main examination.

Download JEE Main Sample Paper Link

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Related eBooks & Sample Papers

JEE Main 2026 Paper 2 (B.Arch) Syllabus

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Benefits of Solving JEE Main 2020 Question Paper with Solution PDF

Students who complete the JEE Mains 2020 question paper will gain the following advantages:

  • Candidates will be able to revise the concepts learned during preparation by practising the JEE Main exam question paper pdf. Students can then identify topics that need more practice and strengthen their grasp on the particular subject topics.

  • Students can gain an understanding of the JEE Main exam pattern, the weighting of topics, and more by solving the question paper of JEE Main 2020. This acts as a better preparation strategy for the exam.

  • Candidates can improve their time management and exam familiarity by completing the JEE Mains question paper 2020. They can also use it to determine which sections to concentrate on to increase their accuracy and speed.

  • Regular practice of JEE Main Question Paper 2020 pdf with solutions can help candidates gain confidence and reduce anxiety before the exam. It will allow candidates to get the feel of the exam and get accustomed to its time limit and challenging questions.

JEE Main Syllabus: Subjects & Chapters
Select your preferred subject to view the chapters

Changes in JEE Main Question Paper

There is a significant difference between JEE Main question papers as compared to previous years, with respect to exam syllabus, exam pattern, number of questions etc for Paper 1 (i.e. for B.E./ B. Tech). Let's discuss them one by one

  • JEE Main Syllabus:- Major chapters from all three subjects have been deleted from the current JEE Main Syllabus with respect to previous year JEE Main Syllabus.

Here are the details about the syllabus that is removed.

Subject

Chapter Name

Physics

Communication System

Physical Chemistry

States of Matter

Surface Chemistry

Inorganic Chemistry

General Principles and Processes of Isolation of Metals

Hydrogen

S-Block Elements (Alkali and Alkaline Earth Metals)

Environmental Chemistry

Organic Chemistry

Polymers

Chemistry in Everyday Life

Mathematics

Mathematical Inductions

Mathematical Reasoning

The above-mentioned chapters are completely removed from the JEE Main Syllabus along with major topics from other remaining chapters also reduced.

For detailed analysis have a look at JEE Main Syllabus

  • Exam patterns:-

  1. Total marks- The total marks are the same. I.e Students can achieve a maximum of 300 marks in the main exam.

  2. No of Questions- Let's have a look at Subject wise distribution of the total number of questions for the JEE Main exams.

Subject

No of Questions

No of Questions

Mathematics

(20 MCQs+ 5 NAT)

(20 MCQs+ 5 NAT)

Physics

(20 MCQs+ 5 NAT)

(20 MCQs+ 5 NAT)

Chemistry

(20 MCQs+ 5 NAT)

(20 MCQs+ 5 NAT)

Here MCQs mean Multiple-Choice Questions and NTA means questions whose answers are to be filled in as a numerical value. So to summarize in JEE Main for section B in each subject 5 NTA-type questions are there, but candidates have to attempt all 5 of them.

Few Solved Questions from JEE Main 2020 Paper

1. (Subject - Physics, Chapter - Optics, Shift - 06 Sep - Evening Shift)

Question:- A double convex lens has power P and the same radii of curvature R of both surfaces. The radius of curvature of the surface of a planoconvex lens made of the same material with power 1.5 P is :

  1. 2R

  2. \frac{R}{2}

  3. \frac{3R}{2}

  4. \frac{R}{3}

Answer- 4) \frac{R}{3}

Solution:-

1720600855410

\mathrm{R}_{1}=\mathrm{R}_{2}=\mathrm{R} \\ Power= P \\ \text{Refractive index is assume} (\mu_{l})

\mathrm{P}=\frac{1}{\mathrm{f}}=\left(\mu_{l}-1\right)\left(\frac{2}{\mathrm{R}}\right)

1720600856679

\begin{aligned} &\mathrm{P}^{\prime}=\frac{1}{\mathrm{f}^{\prime}}=\left(\mu_{\ell}-1\right)\left(\frac{1}{\mathrm{R}^{\prime}}\right)\\ &P^{\prime}=\frac{3}{2} P \end{aligned}

\begin{array}{l} \left(\mu_{\ell}-1\right)\left(\frac{1}{\mathrm{R}^{\prime}}\right)= \frac{3}{2}\left(\mu_{\ell}-1\right)\left(\frac{2}{\mathrm{R}}\right) \\ \\ \therefore \quad \mathrm{R}^{\prime}=\frac{\mathrm{R}}{3} \end{array}


Hence, The correct option is (4)


2. (Subject - Maths, Chapter - Integral Calculus, Shift - 03 Sep - Evening Shift )

Question:- If \int \sin ^{-1}\left ( \sqrt{\frac{x}{1+x}} \right )dx=A(x)\tan ^{-1}(\sqrt{x})+B(x)+C, where C is a constant of integration, then the ordered pair (A(x),\; B(x)) can be?

  1. (x+1,\; -\sqrt{x})

  2. (x+1,\; \sqrt{x})

  3. (x-1,\; -\sqrt{x})

  4. (x-1,\; \sqrt{x})

Answer- 1) (x+1,\; -\sqrt{x})

Solution:-

Given,

\int \sin ^{-1}\left ( \sqrt{\frac{x}{1+x}} \right )dx=A(x)\tan ^{-1}(\sqrt{x})+B(x)+C,

\begin{array}{l} \text { Put } x=\tan ^{2} \theta \Rightarrow d x=2 \tan \theta \sec ^{2} \theta d \theta \\ \int \theta \cdot\left(2 \tan \theta \cdot \sec ^{2} \theta\right) d \theta \end{array}

Now do the integration by parts

\\\mathrm{\theta\rightarrow 1st\;function}\\\mathrm{2\tan\theta\sec^2\theta\rightarrow 2nd\;function}

\begin{array}{l} =\theta \cdot \tan ^{2} \theta-\int \tan ^{2} \theta \mathrm{d} \theta \\ =\theta \cdot \tan ^{2} \theta-\int\left(\sec ^{2} \theta-1\right) \mathrm{d} \theta \\ =\theta\left(1+\tan ^{2} \theta\right)-\tan \theta+\mathrm{C} \\ =\tan ^{-1}(\sqrt{\mathrm{x}})(1+\mathrm{x})-\sqrt{\mathrm{x}}+\mathrm{C} \end{array}

A(x)=1+x,\;\;B(x)=-\sqrt x

Hence, the answer is the option 1.


3. (Subject - Chemistry, Chapter - Hydrocarbons, Shift - 08 Jan - Morning Shift)

Question:- The major products A and B in the following reactions are:

1720600856029


  1. 1720600856074

  2. 1720600854949

  3. 1720600855903

  4. 1720600855239


Answer- 1) 1720600856126

Solution:-

The given reaction occurs as :

\mathrm{R-O-O-R\xrightarrow[]{\Delta}2R\dot{O}}

1720600856280

Therefore, Option(1) is correct.

Frequently Asked Questions (FAQs)

Q: What are the advantages of practising previous years' JEE Main question papers?
A:

Solving previous years' question papers can help candidates identify the exam pattern, important topics, frequently asked topics, and increase their speed and accuracy.

Q: What is the mode of examination for JEE Main 2020?
A:

JEE Mains 2020 examination was conducted as a computer based test and held in online mode.

Q: How effective was solving the previous year's JEE Main question papers for exam preparation?
A:

Solving the previous year's JEE Main question papers was a highly effective preparation strategy. It allowed candidates to familiarise themselves with the exam pattern, question types, and concepts. It also helped assess their readiness and improve problem-solving skills.

Q: Where can I find the JEE Main 2020 question paper?
A:

Candidates can find the JEE Main question papers with solutions pdf of all years and sessions on Careers360 website.

Q: Is the JEE Main 2020 question paper a reliable resource for practice?
A:

Yes, the JEE Main 2020 question paper is a reliable resource for practice as it is the official examination paper.

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Is OBC certificate required for JEE Main?

Hello,

Yes, you need an OBC-NCL certificate if you want to claim the OBC-NCL reservation in JEE Main .

Here are the key points:

  • If you want the OBC-NCL quota, you must upload a valid OBC-NCL certificate.

  • The certificate should be issued by the government and must follow the latest format.

  • It should usually be issued on or after 1 April of the current admission year.

  • If you do not have a valid certificate, you will be treated as a General (Unreserved) candidate.

If you apply under General category, then no OBC certificate is needed.

Hope it helps !

Read Complete Answer
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17 Nov'25
Is transistor in JEE syallbus 2026?

Hello,

Yes, transistor is included in the JEE Main 2026 Physics syllabus .

Topics generally covered are:

  • Junction transistor and its working

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  • Transistor as a switch

  • Basic use of transistor in simple circuits

Hope it helps !

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17 Nov'25
What is the closing jee advance rank in iit madras

Hello,

In 2025, IIT Madras JEE Advanced, closing ranks are around 171 for CSE, 306 for AI & Data Analytics, 849 for Electrical, about 1300 for Computational Engineering, around 1440 for Engineering Physics, 2468 for Mechanical, and about 6112 for Civil.

To know more access below mentioned link:

https://engineering.careers360.com/articles/jee-advanced-cutoff-for-iit-madras

Hope it helps.

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16 Nov'25
Can you give jee advance college predictor for obc ncl category

Hello,

JEE Advanced College Predictor 2026 is an AI driven tool created by Careers360.

This JEE Adv college predictor tool uses the latest rank vs college details to give the most accurate information on best available colleges based on JEE Advanced ranks.

Here is the link where you can access the tool : JEE Advanced College Predictor 2026

Hope it helps !

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In the jee application form,in the identity details section i gave my old adhaar card,the details are the same but photo is of my younger version, unfortunately i am not able to change it, i have also updated adhaar and not yet clicked on final submission but but will my form get rehected???

Hello,

No, your form will not get rejected because of this.

If the Aadhaar number and personal details match , the photo on your old Aadhaar is not a problem . Many students use Aadhaar with an old photo, and NTA accepts it as long as the details are correct.

Since you have not done final submission yet , you can try once more to edit the Aadhaar number. If the portal still does not allow changes, just continue with the form. It will not cause rejection.

For the exam day, carry:

  • Your updated Aadhaar (new one)

  • The JEE admit card

This is enough. There is no risk of rejection.

Hope it helps !

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