JEE Main 2020 Question Paper with Solution PDF

JEE Main 2020 Question Paper with Solution PDF

Team Careers360Updated on 08 Dec 2025, 11:53 AM IST

JEE Main 2020 Question Paper with Solution PDF - The National Testing Agency uploaded the JEE Main question paper with solution 2020 on the official website, jeemain.nta.nic.in. Candidates can check the question paper of JEE Main 2020 in this article. Solving the JEE Main 2020 question paper PDF is important to understand the difficulty level of the JEE Main exam, important topics, marking scheme and more. Reviewing or slovinf the JEE Mains 2020 question paper within the 3 hours (i.e. real exam duration) helps you improve your problem-solving skills. Aspirants can also download the previous year's JEE Mains question paper from Careers360. Download the JEE Main 2020 question paper with the solution pdf below.

This Story also Contains

  1. JEE Main 2020 Question Paper PDF
  2. JEE Main 2020 Question Paper with Solution (September Session)
  3. JEE Main Sample Paper PDF
  4. Benefits of Solving JEE Main 2020 Question Paper with Solution PDF
  5. Changes in JEE Main Question Paper
  6. Few Solved Questions from JEE Main 2020 Paper
JEE Main 2020 Question Paper with Solution PDF
JEE Main 2020 Question Paper

JEE Main 2020 Question Paper PDF

JEE Main 2020 paper was conducted in 2 sessions (i.e. January and September) where a total number of 1200 questions were asked including all three subjects (i.e. Physics, Maths and Chemistry) from all 16 shifts. This number of questions is sufficient for aspirants aiming for JEE Main 2025 preparations for practising questions of JEE Main difficulty level. If needed candidates can also go through others JEE Main previous years questions for better understanding. The JEE Main 2020 question paper with solution pdf free download link is provided below.

JEE Main Question Paper PDF 2020

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JEE Main 2020 Question Paper Day Wise

JEE Main 2026: Preparation Tips & Study Plan
Download the JEE Main 2026 Preparation Tips PDF to boost your exam strategy. Get expert insights on managing study material, focusing on key topics and high-weightage chapters.
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JEE Main 2020 Question Paper with Solution (September Session)

In the year 2020 session 2 of JEE Main, which is usually held in April, was postponed due to the Covid 19 pandemic and was conducted in the month of September. Candidates can click the link above to download the official JEE Main Question Paper 2020 with solutions. Careers360 provides the question paper of JEE Main 2020 for both sessions on this page itself. We have also provided solutions to the questions asked in JEE Main question paper 2020. After attempting the JEE Main question paper, candidates can check their answers by using the solutions provided.

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Since these are free resources, candidates must download them to make the most of them. JEE Main 2020 question paper when combined with other resources such as mock tests, sample papers and more practice questions makes an effective preparation strategy. Students can find the links for all the preparation resources on this page itself.

Aspirants preparing for upcoming exams can gain valuable insights into the paper pattern, difficulty level, and frequently appearing questions by referring to the JEE Main question paper pdf. Experts have explained the jee main question paper 2020 with solutions in great detail.

JEE Main Sample Paper PDF

We have provided direct links for downloading the JEE Main sample paper pdf. Candidates must download the sample papers and practise them to strengthen their preparation for the upcoming JEE Main examination.

Download JEE Main Sample Paper Link

Benefits of Solving JEE Main 2020 Question Paper with Solution PDF

Students who complete the JEE Mains 2020 question paper will gain the following advantages:

  • Candidates will be able to revise the concepts learned during preparation by practising the JEE Main exam question paper pdf. Students can then identify topics that need more practice and strengthen their grasp on the particular subject topics.

  • Students can gain an understanding of the JEE Main exam pattern, the weighting of topics, and more by solving the question paper of JEE Main 2020. This acts as a better preparation strategy for the exam.

  • Candidates can improve their time management and exam familiarity by completing the JEE Mains question paper 2020. They can also use it to determine which sections to concentrate on to increase their accuracy and speed.

  • Regular practice of JEE Main Question Paper 2020 pdf with solutions can help candidates gain confidence and reduce anxiety before the exam. It will allow candidates to get the feel of the exam and get accustomed to its time limit and challenging questions.

JEE Main Syllabus: Subjects & Chapters
Select your preferred subject to view the chapters

Changes in JEE Main Question Paper

There is a significant difference between JEE Main question papers as compared to previous years, with respect to exam syllabus, exam pattern, number of questions etc for Paper 1 (i.e. for B.E./ B. Tech). Let's discuss them one by one

  • JEE Main Syllabus:- Major chapters from all three subjects have been deleted from the current JEE Main Syllabus with respect to previous year JEE Main Syllabus.

Here are the details about the syllabus that is removed.

Subject

Chapter Name

Physics

Communication System

Physical Chemistry

States of Matter

Surface Chemistry

Inorganic Chemistry

General Principles and Processes of Isolation of Metals

Hydrogen

S-Block Elements (Alkali and Alkaline Earth Metals)

Environmental Chemistry

Organic Chemistry

Polymers

Chemistry in Everyday Life

Mathematics

Mathematical Inductions

Mathematical Reasoning

The above-mentioned chapters are completely removed from the JEE Main Syllabus along with major topics from other remaining chapters also reduced.

For detailed analysis have a look at JEE Main Syllabus

  • Exam patterns:-

  1. Total marks- The total marks are the same. I.e Students can achieve a maximum of 300 marks in the main exam.

  2. No of Questions- Let's have a look at Subject wise distribution of the total number of questions for the JEE Main exams.

Subject

No of Questions

No of Questions

Mathematics

(20 MCQs+ 5 NAT)

(20 MCQs+ 5 NAT)

Physics

(20 MCQs+ 5 NAT)

(20 MCQs+ 5 NAT)

Chemistry

(20 MCQs+ 5 NAT)

(20 MCQs+ 5 NAT)

Here MCQs mean Multiple-Choice Questions and NTA means questions whose answers are to be filled in as a numerical value. So to summarize in JEE Main for section B in each subject 5 NTA-type questions are there, but candidates have to attempt all 5 of them.

Few Solved Questions from JEE Main 2020 Paper

1. (Subject - Physics, Chapter - Optics, Shift - 06 Sep - Evening Shift)

Question:- A double convex lens has power P and the same radii of curvature R of both surfaces. The radius of curvature of the surface of a planoconvex lens made of the same material with power 1.5 P is :

  1. 2R

  2. \frac{R}{2}

  3. \frac{3R}{2}

  4. \frac{R}{3}

Answer- 4) \frac{R}{3}

Solution:-

1720600855410

\mathrm{R}_{1}=\mathrm{R}_{2}=\mathrm{R} \\ Power= P \\ \text{Refractive index is assume} (\mu_{l})

\mathrm{P}=\frac{1}{\mathrm{f}}=\left(\mu_{l}-1\right)\left(\frac{2}{\mathrm{R}}\right)

1720600856679

\begin{aligned} &\mathrm{P}^{\prime}=\frac{1}{\mathrm{f}^{\prime}}=\left(\mu_{\ell}-1\right)\left(\frac{1}{\mathrm{R}^{\prime}}\right)\\ &P^{\prime}=\frac{3}{2} P \end{aligned}

\begin{array}{l} \left(\mu_{\ell}-1\right)\left(\frac{1}{\mathrm{R}^{\prime}}\right)= \frac{3}{2}\left(\mu_{\ell}-1\right)\left(\frac{2}{\mathrm{R}}\right) \\ \\ \therefore \quad \mathrm{R}^{\prime}=\frac{\mathrm{R}}{3} \end{array}


Hence, The correct option is (4)


2. (Subject - Maths, Chapter - Integral Calculus, Shift - 03 Sep - Evening Shift )

Question:- If \int \sin ^{-1}\left ( \sqrt{\frac{x}{1+x}} \right )dx=A(x)\tan ^{-1}(\sqrt{x})+B(x)+C, where C is a constant of integration, then the ordered pair (A(x),\; B(x)) can be?

  1. (x+1,\; -\sqrt{x})

  2. (x+1,\; \sqrt{x})

  3. (x-1,\; -\sqrt{x})

  4. (x-1,\; \sqrt{x})

Answer- 1) (x+1,\; -\sqrt{x})

Solution:-

Given,

\int \sin ^{-1}\left ( \sqrt{\frac{x}{1+x}} \right )dx=A(x)\tan ^{-1}(\sqrt{x})+B(x)+C,

\begin{array}{l} \text { Put } x=\tan ^{2} \theta \Rightarrow d x=2 \tan \theta \sec ^{2} \theta d \theta \\ \int \theta \cdot\left(2 \tan \theta \cdot \sec ^{2} \theta\right) d \theta \end{array}

Now do the integration by parts

\\\mathrm{\theta\rightarrow 1st\;function}\\\mathrm{2\tan\theta\sec^2\theta\rightarrow 2nd\;function}

\begin{array}{l} =\theta \cdot \tan ^{2} \theta-\int \tan ^{2} \theta \mathrm{d} \theta \\ =\theta \cdot \tan ^{2} \theta-\int\left(\sec ^{2} \theta-1\right) \mathrm{d} \theta \\ =\theta\left(1+\tan ^{2} \theta\right)-\tan \theta+\mathrm{C} \\ =\tan ^{-1}(\sqrt{\mathrm{x}})(1+\mathrm{x})-\sqrt{\mathrm{x}}+\mathrm{C} \end{array}

A(x)=1+x,\;\;B(x)=-\sqrt x

Hence, the answer is the option 1.


3. (Subject - Chemistry, Chapter - Hydrocarbons, Shift - 08 Jan - Morning Shift)

Question:- The major products A and B in the following reactions are:

1720600856029


  1. 1720600856074

  2. 1720600854949

  3. 1720600855903

  4. 1720600855239


Answer- 1) 1720600856126

Solution:-

The given reaction occurs as :

\mathrm{R-O-O-R\xrightarrow[]{\Delta}2R\dot{O}}

1720600856280

Therefore, Option(1) is correct.

Frequently Asked Questions (FAQs)

Q: What are the advantages of practising previous years' JEE Main question papers?
A:

Solving previous years' question papers can help candidates identify the exam pattern, important topics, frequently asked topics, and increase their speed and accuracy.

Q: What is the mode of examination for JEE Main 2020?
A:

JEE Mains 2020 examination was conducted as a computer based test and held in online mode.

Q: How effective was solving the previous year's JEE Main question papers for exam preparation?
A:

Solving the previous year's JEE Main question papers was a highly effective preparation strategy. It allowed candidates to familiarise themselves with the exam pattern, question types, and concepts. It also helped assess their readiness and improve problem-solving skills.

Q: Where can I find the JEE Main 2020 question paper?
A:

Candidates can find the JEE Main question papers with solutions pdf of all years and sessions on Careers360 website.

Q: Is the JEE Main 2020 question paper a reliable resource for practice?
A:

Yes, the JEE Main 2020 question paper is a reliable resource for practice as it is the official examination paper.

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Questions related to JEE Main

On Question asked by student community

Have a question related to JEE Main ?

Hello aspirant,

If your syllabus is completed with theory , use the next 30 days only for smart revision . Make short notes and revise formulas daily for Physics , Chemistry and Maths . Solve previous year JEE Main questions topic-wise and then full mock tests every 3-4 days. Analyse mistakes properly and revise weak areas again . Avoid new topics and focus on accuracy , speed and confidence building during revision.

FOR REFERENCE : https://engineering.careers360.com/articles/jee-main-revision-strategy

Hope the details will help you.

THANK YOU

Preparing for the JEE Main in just 30 days is a challenging but achievable task if you follow a highly disciplined and strategic approach. According to the Careers360 30-day study plan , the key is to shift your focus from learning everything to mastering high-weightage topics and practicing rigorously.

Phase 1: Week 1 & 2 – Focus on High-Weightage Chapters

During the first 15 days, prioritize topics that frequently appear in the exam.

  • Physics: Modern Physics, Heat & Thermodynamics, Optics, and Current Electricity.

  • Chemistry: GOC (General Organic Chemistry), Chemical Bonding, p-Block elements, and Solutions.

  • Maths: Matrices & Determinants, Sequences & Series, Coordinate Geometry, and Vector & 3D Geometry.

  • Study Strategy: Use NCERT for Chemistry and simplified notes for Physics/Maths. Spend 3-4 hours on each subject daily.

Phase 2: Week 3 – Revision and Formula Memorization

  • Short Notes: Go through the short notes you made during the first two weeks.

  • Flashcards: Use flashcards for inorganic chemistry reactions and physics formulas.

  • Mock Tests: Start giving one full-length mock test every alternate day. Analyze your mistakes immediately to avoid repeating them.

Phase 3: Final Week – Full Simulation and Relaxation

  • Previous Year Papers (PYQs): Solve the last 3-5 years of JEE Main papers in the actual exam time slot (9 AM–12 PM or 3 PM–6 PM) to sync your body clock.

  • No New Topics: Stop picking up new chapters. Focus solely on what you already know to build confidence.

  • Accuracy over Speed: Focus on getting the questions right rather than attempting all of them, as negative marking can significantly lower your percentile.

Downloadable Resources:

You can download the comprehensive day-by-day schedule, which includes specific topics to cover each morning and evening, by visiting the link : https://engineering.careers360.com/download/ebooks/jee-main-study-plan-30-days

Hello

I think your question sounds like this: "Can a candidate who passed Class 12 in 2025 and filled JEE Main Session 1 apply for Session 2 as 'Appearing' in 2026 as a fresh board candidate, and will both sessions have the same details? "

So yes, you can fill the JEE Main Session 2 as "Appearing". The information filled in Session 1 will remain exactly as it was and will not change.
Session 1 and Session 2 are treated as separate applications. There is no issue if the qualifying status is different in both sessions. During counselling, the board marks that meet the 75 rule will be considered.

Hello,

If you filled the JEE Main January form with Class 12 passed in 2025 and are planning to appear again for the Class 12 exam through HOS, there is usually no serious issue. You were eligible to apply since you had already passed Class 12. Reappearing through HOS for improvement or requalification is allowed, provided HOS is a recognized board. During counselling, your latest valid Class 12 result will be considered. Make sure you meet the 75% marks or top 20 percentile requirement where applicable. If a correction window opens, update details if needed.

Hope this has solved your query. Thank You.

Good Evening,

Yes, you are eligible for both JEE Mains and Advanced, as you completed your 12th with physics, chemistry and biology. Moreover, you passed mathematics in 2025, which makes you fit the eligibility criteria of both exams.

Aspirant, I would like to inform you that Careers360 recently launched a free mock test series for JEE students. The last date of registration is 8th January, 2026. Enroll and solve chapter wise question papers and improve you concept and assess your learning. The link to the mock test series is attached herewith. https://learn.careers360.com/test-series-jee-main-free-mock-test/

Best regards.