JEE Main 2020 Question Paper with Solution PDF

JEE Main 2020 Question Paper with Solution PDF

Team Careers360Updated on 11 Oct 2025, 01:36 PM IST

JEE Main 2020 Question Paper with Solution PDF - NTA uploaded the JEE Main 2020 question paper on the official website, jeemain.nta.nic.in. Candidates can check the question paper of JEE Main 2020 in this article. Solving the JEE Main 2020 question paper PDF is important to understand the difficulty level of the JEE Main exam, important topics, marking scheme and more. Solving or reviewing the JEE Mains 2020 question paper with solutions within 3 hours (i.e. real exam duration) helps you improve your problem-solving skills. Aspirants can also download the previous year's JEE Mains question paper from Careers360. Download the JEE Main 2020 question paper with the solution pdf below.

LiveJEE Mains 2026 Registration LIVE: NTA to begin application process soon at jeemain.nta.nic.in; exam date, feeOct 16, 2025 | 10:39 PM IST

Based on the registration trends from previous years, the JEE Main 2026 registration process is expected to begin in October, with the first session likely in January and the second session in April. The JEE Main previous years registration trend is given in the table below.

Exam Year

Registration start date

2025

October 28, 2024 

2024

November 1, 2023 

2023

December 15, 2022 

2022

March 1, 2022 

2021

December 16, 2020

Read More

This Story also Contains

  1. JEE Main 2020 Question Paper PDF
  2. JEE Main 2020 Question Paper with Solution (September Session)
  3. JEE Main Sample Paper PDF
  4. Benefits of Solving JEE Main 2020 Question Paper with Solution PDF
  5. Changes in JEE Main Question Paper
  6. Few Solved Questions from JEE Main 2020 Paper
JEE Main 2020 Question Paper with Solution PDF
JEE Main 2020 Question Paper

JEE Main 2020 Question Paper PDF

JEE Main 2020 paper was conducted in 2 sessions (i.e. January and September) where a total number of 1200 questions were asked including all three subjects (i.e. Physics, Maths and Chemistry) from all 16 shifts. This number of questions is sufficient for aspirants aiming for JEE Main 2025 preparations for practising questions of JEE Main difficulty level. If needed candidates can also go through others JEE Main previous years questions for better understanding.

JEE Main Question Paper PDF 2020

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JEE Main 2020 Question Paper Day Wise

JEE Main 2026: Preparation Tips & Study Plan
Download the JEE Main 2026 Preparation Tips PDF to boost your exam strategy. Get expert insights on managing study material, focusing on key topics and high-weightage chapters.
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JEE Main 2020 Question Paper with Solution (September Session)

In the year 2020 session 2 of JEE Main, which is usually held in April, was postponed due to the Covid 19 pandemic and was conducted in the month of September. Candidates can click the link above to download the official JEE Main Question Paper 2020 with solutions. Careers360 provides the question paper of JEE Main 2020 for both sessions on this page itself. We have also provided solutions to the questions asked in JEE Main question paper 2020. After attempting the JEE Main question paper, candidates can check their answers by using the solutions provided.

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Since these are free resources, candidates must download them to make the most of them. JEE Main 2020 question paper when combined with other resources such as mock tests, sample papers and more practice questions makes an effective preparation strategy. Students can find the links for all the preparation resources on this page itself.

Aspirants preparing for upcoming exams can gain valuable insights into the paper pattern, difficulty level, and frequently appearing questions by referring to the JEE Main question paper pdf. Experts have explained the jee main question paper 2020 with solutions in great detail.

JEE Main Sample Paper PDF

We have provided direct links for downloading the JEE Main sample paper pdf. Candidates must download the sample papers and practise them to strengthen their preparation for the upcoming JEE Main examination.

Download JEE Main Sample Paper Link

Benefits of Solving JEE Main 2020 Question Paper with Solution PDF

Students who complete the JEE Mains 2020 question paper will gain the following advantages:

  • Candidates will be able to revise the concepts learned during preparation by practising the JEE Main exam question paper pdf. Students can then identify topics that need more practice and strengthen their grasp on the particular subject topics.

  • Students can gain an understanding of the JEE Main exam pattern, the weighting of topics, and more by solving the question paper of JEE Main 2020. This acts as a better preparation strategy for the exam.

  • Candidates can improve their time management and exam familiarity by completing the JEE Mains question paper 2020. They can also use it to determine which sections to concentrate on to increase their accuracy and speed.

  • Regular practice of JEE Main Question Paper 2020 pdf with solutions can help candidates gain confidence and reduce anxiety before the exam. It will allow candidates to get the feel of the exam and get accustomed to its time limit and challenging questions.

JEE Main Syllabus: Subjects & Chapters
Select your preferred subject to view the chapters

Changes in JEE Main Question Paper

There is a significant difference between JEE Main question papers as compared to previous years, with respect to exam syllabus, exam pattern, number of questions etc for Paper 1 (i.e. for B.E./ B. Tech). Let's discuss them one by one

  • JEE Main Syllabus:- Major chapters from all three subjects have been deleted from the current JEE Main Syllabus with respect to previous year JEE Main Syllabus.

Here are the details about the syllabus that is removed.

Subject

Chapter Name

Physics

Communication System

Physical Chemistry

States of Matter

Surface Chemistry

Inorganic Chemistry

General Principles and Processes of Isolation of Metals

Hydrogen

S-Block Elements (Alkali and Alkaline Earth Metals)

Environmental Chemistry

Organic Chemistry

Polymers

Chemistry in Everyday Life

Mathematics

Mathematical Inductions

Mathematical Reasoning

The above-mentioned chapters are completely removed from the JEE Main Syllabus along with major topics from other remaining chapters also reduced.

For detailed analysis have a look at JEE Main Syllabus

  • Exam patterns:-

  1. Total marks- The total marks are the same. I.e Students can achieve a maximum of 300 marks in the main exam.

  2. No of Questions- Let's have a look at Subject wise distribution of the total number of questions for the JEE Main exams.

Subject

No of Questions

No of Questions

Mathematics

(20 MCQs+ 5 NAT)

(20 MCQs+ 5 NAT)

Physics

(20 MCQs+ 5 NAT)

(20 MCQs+ 5 NAT)

Chemistry

(20 MCQs+ 5 NAT)

(20 MCQs+ 5 NAT)

Here MCQs mean Multiple-Choice Questions and NTA means questions whose answers are to be filled in as a numerical value. So to summarize in JEE Main for section B in each subject 5 NTA-type questions are there, but candidates have to attempt all 5 of them.

Few Solved Questions from JEE Main 2020 Paper

1. (Subject - Physics, Chapter - Optics, Shift - 06 Sep - Evening Shift)

Question:- A double convex lens has power P and the same radii of curvature R of both surfaces. The radius of curvature of the surface of a planoconvex lens made of the same material with power 1.5 P is :

  1. 2R

  2. \frac{R}{2}

  3. \frac{3R}{2}

  4. \frac{R}{3}

Answer- 4) \frac{R}{3}

Solution:-

1720600855410

\mathrm{R}_{1}=\mathrm{R}_{2}=\mathrm{R} \\ Power= P \\ \text{Refractive index is assume} (\mu_{l})

\mathrm{P}=\frac{1}{\mathrm{f}}=\left(\mu_{l}-1\right)\left(\frac{2}{\mathrm{R}}\right)

1720600856679

\begin{aligned} &\mathrm{P}^{\prime}=\frac{1}{\mathrm{f}^{\prime}}=\left(\mu_{\ell}-1\right)\left(\frac{1}{\mathrm{R}^{\prime}}\right)\\ &P^{\prime}=\frac{3}{2} P \end{aligned}

\begin{array}{l} \left(\mu_{\ell}-1\right)\left(\frac{1}{\mathrm{R}^{\prime}}\right)= \frac{3}{2}\left(\mu_{\ell}-1\right)\left(\frac{2}{\mathrm{R}}\right) \\ \\ \therefore \quad \mathrm{R}^{\prime}=\frac{\mathrm{R}}{3} \end{array}


Hence, The correct option is (4)


2. (Subject - Maths, Chapter - Integral Calculus, Shift - 03 Sep - Evening Shift )

Question:- If \int \sin ^{-1}\left ( \sqrt{\frac{x}{1+x}} \right )dx=A(x)\tan ^{-1}(\sqrt{x})+B(x)+C, where C is a constant of integration, then the ordered pair (A(x),\; B(x)) can be?

  1. (x+1,\; -\sqrt{x})

  2. (x+1,\; \sqrt{x})

  3. (x-1,\; -\sqrt{x})

  4. (x-1,\; \sqrt{x})

Answer- 1) (x+1,\; -\sqrt{x})

Solution:-

Given,

\int \sin ^{-1}\left ( \sqrt{\frac{x}{1+x}} \right )dx=A(x)\tan ^{-1}(\sqrt{x})+B(x)+C,

\begin{array}{l} \text { Put } x=\tan ^{2} \theta \Rightarrow d x=2 \tan \theta \sec ^{2} \theta d \theta \\ \int \theta \cdot\left(2 \tan \theta \cdot \sec ^{2} \theta\right) d \theta \end{array}

Now do the integration by parts

\\\mathrm{\theta\rightarrow 1st\;function}\\\mathrm{2\tan\theta\sec^2\theta\rightarrow 2nd\;function}

\begin{array}{l} =\theta \cdot \tan ^{2} \theta-\int \tan ^{2} \theta \mathrm{d} \theta \\ =\theta \cdot \tan ^{2} \theta-\int\left(\sec ^{2} \theta-1\right) \mathrm{d} \theta \\ =\theta\left(1+\tan ^{2} \theta\right)-\tan \theta+\mathrm{C} \\ =\tan ^{-1}(\sqrt{\mathrm{x}})(1+\mathrm{x})-\sqrt{\mathrm{x}}+\mathrm{C} \end{array}

A(x)=1+x,\;\;B(x)=-\sqrt x

Hence, the answer is the option 1.


3. (Subject - Chemistry, Chapter - Hydrocarbons, Shift - 08 Jan - Morning Shift)

Question:- The major products A and B in the following reactions are:

1720600856029


  1. 1720600856074

  2. 1720600854949

  3. 1720600855903

  4. 1720600855239


Answer- 1) 1720600856126

Solution:-

The given reaction occurs as :

\mathrm{R-O-O-R\xrightarrow[]{\Delta}2R\dot{O}}

1720600856280

Therefore, Option(1) is correct.

Frequently Asked Questions (FAQs)

Q: Is the JEE Main 2020 question paper a reliable resource for practice?
A:

Yes, the JEE Main 2020 question paper is a reliable resource for practice as it is the official examination paper.

Q: Where can I find the JEE Main 2020 question paper?
A:

Candidates can find the JEE Main question papers with solutions pdf of all years and sessions on Careers360 website.

Q: How effective was solving the previous year's JEE Main question papers for exam preparation?
A:

Solving the previous year's JEE Main question papers was a highly effective preparation strategy. It allowed candidates to familiarise themselves with the exam pattern, question types, and concepts. It also helped assess their readiness and improve problem-solving skills.

Q: What is the mode of examination for JEE Main 2020?
A:

JEE Mains 2020 examination was conducted as a computer based test and held in online mode.

Q: What are the advantages of practising previous years' JEE Main question papers?
A:

Solving previous years' question papers can help candidates identify the exam pattern, important topics, frequently asked topics, and increase their speed and accuracy.

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Questions related to JEE Main

On Question asked by student community

Have a question related to JEE Main ?

Hello,

JEE has two exams:

  1. JEE Main : for NITs and eligibility for JEE Advanced.
  2. JEE Advanced: For IITs

The percentage or marks needed to get seat in NITs and IITs are:

  • For NITs, aim for 150+ marks in JEE Main.
  • For IITs, aim for 50-60% marks in JEE Advanced.
  • Focus on concepts, practice, and take mock tests for best results.

Go through the link for more details:

https://engineering.careers360.com/articles/jee-main-cutoff

I hope this answer helps you, All the best!



Heya,

Yes, you can refill your category again. In the case of the April session JEE Main registration, you have the option to change your category while registering your details only once. You can switch from General to EWS if you have a proper certificate. Just be certain that the EWS certificate is granted before the last date of the April session form and complies with the NTA's requirements of validity.

Hope it helps!!!

Hello,

You can certainly get admission at DTU (Delhi Technological University) as the minimum requirement there is 60% aggregate in PCM. In such a case, you will be given admission to the top branches of CSE/ECE. Nevertheless, the case is totally different for IIT Hyderabad.

Admission into IITs is through JEE Advanced, and they require either a minimum of 75% in boards or to be in the top 20th percentile of the board for eligibility. But, if you fail to get 75% and happen to not be in the top 20th percentile, you can't get admission at IIT even if you have a good rank in JEE Mains.

Hope it helps!!!

Hello Tanishka,

Although i believe your attempting strategy and sequence depends entirely on your stage of preparation and your personal progress, i would suggest you sit for your January attempt even if you aim to seriously prepare for April.

Whatever stage of syllabus completion you are at, i suggest you give it a try to get an estimate of the exam difficulty and see roughly where you stand among the applicants that year. No matter how many mock tests you attempt, the actual examination environment happens to be very different from mock tests. The first attempt is going to give you an idea of the exam environment so you can prepare for your April attempt better.

All the best for your exams!

Hello Swati

Yes, your EWS certificate will be valid for JEE Main 2026 and counselling if it’s issued after April 1, 2025.
This is because EWS certificates are valid for one financial year from April to March.
So, a certificate made in October 2025 will be for FY 2025–26, which covers both JEE and counselling. You’ll need the certificate number during JEE registration in October 2025.
Even if you don’t have it yet, you can still register and upload it later during counselling. Just make sure the certificate clearly mentions the correct financial year.
Always keep a few extra copies and the original ready for verification.
You're good to go if it’s issued after April 1, 2025