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    JEE Main 2020 Question Paper with Solution PDF

    JEE Main 2020 Question Paper with Solution PDF

    #JEE Main
    Team Careers360Updated on 08 Dec 2025, 11:53 AM IST

    JEE Main 2020 Question Paper with Solution PDF - The National Testing Agency uploaded the JEE Main question paper with solution 2020 on the official website, jeemain.nta.nic.in. Candidates can check the question paper of JEE Main 2020 in this article. Solving the JEE Main 2020 question paper PDF is important to understand the difficulty level of the JEE Main exam, important topics, marking scheme and more. Reviewing or slovinf the JEE Mains 2020 question paper within the 3 hours (i.e. real exam duration) helps you improve your problem-solving skills. Aspirants can also download the previous year's JEE Mains question paper from Careers360. Download the JEE Main 2020 question paper with the solution pdf below.

    This Story also Contains

    1. JEE Main 2020 Question Paper PDF
    2. JEE Main 2020 Question Paper with Solution (September Session)
    3. JEE Main Sample Paper PDF
    4. Benefits of Solving JEE Main 2020 Question Paper with Solution PDF
    5. Changes in JEE Main Question Paper
    6. Few Solved Questions from JEE Main 2020 Paper
    JEE Main 2020 Question Paper with Solution PDF
    JEE Main 2020 Question Paper

    JEE Main 2020 Question Paper PDF

    JEE Main 2020 paper was conducted in 2 sessions (i.e. January and September) where a total number of 1200 questions were asked including all three subjects (i.e. Physics, Maths and Chemistry) from all 16 shifts. This number of questions is sufficient for aspirants aiming for JEE Main 2025 preparations for practising questions of JEE Main difficulty level. If needed candidates can also go through others JEE Main previous years questions for better understanding. The JEE Main 2020 question paper with solution pdf free download link is provided below.

    JEE Main Question Paper PDF 2020

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    JEE Main 2020 Question Paper with Solution (September Session)

    In the year 2020 session 2 of JEE Main, which is usually held in April, was postponed due to the Covid 19 pandemic and was conducted in the month of September. Candidates can click the link above to download the official JEE Main Question Paper 2020 with solutions. Careers360 provides the question paper of JEE Main 2020 for both sessions on this page itself. We have also provided solutions to the questions asked in JEE Main question paper 2020. After attempting the JEE Main question paper, candidates can check their answers by using the solutions provided.

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    Since these are free resources, candidates must download them to make the most of them. JEE Main 2020 question paper when combined with other resources such as mock tests, sample papers and more practice questions makes an effective preparation strategy. Students can find the links for all the preparation resources on this page itself.

    Aspirants preparing for upcoming exams can gain valuable insights into the paper pattern, difficulty level, and frequently appearing questions by referring to the JEE Main question paper pdf. Experts have explained the jee main question paper 2020 with solutions in great detail.

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    JEE Main Sample Paper PDF

    We have provided direct links for downloading the JEE Main sample paper pdf. Candidates must download the sample papers and practise them to strengthen their preparation for the upcoming JEE Main examination.

    Download JEE Main Sample Paper Link

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    Benefits of Solving JEE Main 2020 Question Paper with Solution PDF

    Students who complete the JEE Mains 2020 question paper will gain the following advantages:

    • Candidates will be able to revise the concepts learned during preparation by practising the JEE Main exam question paper pdf. Students can then identify topics that need more practice and strengthen their grasp on the particular subject topics.

    • Students can gain an understanding of the JEE Main exam pattern, the weighting of topics, and more by solving the question paper of JEE Main 2020. This acts as a better preparation strategy for the exam.

    • Candidates can improve their time management and exam familiarity by completing the JEE Mains question paper 2020. They can also use it to determine which sections to concentrate on to increase their accuracy and speed.

    • Regular practice of JEE Main Question Paper 2020 pdf with solutions can help candidates gain confidence and reduce anxiety before the exam. It will allow candidates to get the feel of the exam and get accustomed to its time limit and challenging questions.

    JEE Main Syllabus: Subjects & Chapters
    Select your preferred subject to view the chapters

    Changes in JEE Main Question Paper

    There is a significant difference between JEE Main question papers as compared to previous years, with respect to exam syllabus, exam pattern, number of questions etc for Paper 1 (i.e. for B.E./ B. Tech). Let's discuss them one by one

    • JEE Main Syllabus:- Major chapters from all three subjects have been deleted from the current JEE Main Syllabus with respect to previous year JEE Main Syllabus.

    Here are the details about the syllabus that is removed.

    Subject

    Chapter Name

    Physics

    Communication System

    Physical Chemistry

    States of Matter

    Surface Chemistry

    Inorganic Chemistry

    General Principles and Processes of Isolation of Metals

    Hydrogen

    S-Block Elements (Alkali and Alkaline Earth Metals)

    Environmental Chemistry

    Organic Chemistry

    Polymers

    Chemistry in Everyday Life

    Mathematics

    Mathematical Inductions

    Mathematical Reasoning

    The above-mentioned chapters are completely removed from the JEE Main Syllabus along with major topics from other remaining chapters also reduced.

    For detailed analysis have a look at JEE Main Syllabus

    • Exam patterns:-

    1. Total marks- The total marks are the same. I.e Students can achieve a maximum of 300 marks in the main exam.

    2. No of Questions- Let's have a look at Subject wise distribution of the total number of questions for the JEE Main exams.

    Subject

    No of Questions

    No of Questions

    Mathematics

    (20 MCQs+ 5 NAT)

    (20 MCQs+ 5 NAT)

    Physics

    (20 MCQs+ 5 NAT)

    (20 MCQs+ 5 NAT)

    Chemistry

    (20 MCQs+ 5 NAT)

    (20 MCQs+ 5 NAT)

    Here MCQs mean Multiple-Choice Questions and NTA means questions whose answers are to be filled in as a numerical value. So to summarize in JEE Main for section B in each subject 5 NTA-type questions are there, but candidates have to attempt all 5 of them.

    Few Solved Questions from JEE Main 2020 Paper

    1. (Subject - Physics, Chapter - Optics, Shift - 06 Sep - Evening Shift)

    Question:- A double convex lens has power P and the same radii of curvature R of both surfaces. The radius of curvature of the surface of a planoconvex lens made of the same material with power 1.5 P is :

    1. 2R

    2. \frac{R}{2}

    3. \frac{3R}{2}

    4. \frac{R}{3}

    Answer- 4) \frac{R}{3}

    Solution:-

    1720600855410

    \mathrm{R}_{1}=\mathrm{R}_{2}=\mathrm{R} \\ Power= P \\ \text{Refractive index is assume} (\mu_{l})

    \mathrm{P}=\frac{1}{\mathrm{f}}=\left(\mu_{l}-1\right)\left(\frac{2}{\mathrm{R}}\right)

    1720600856679

    \begin{aligned} &\mathrm{P}^{\prime}=\frac{1}{\mathrm{f}^{\prime}}=\left(\mu_{\ell}-1\right)\left(\frac{1}{\mathrm{R}^{\prime}}\right)\\ &P^{\prime}=\frac{3}{2} P \end{aligned}

    \begin{array}{l} \left(\mu_{\ell}-1\right)\left(\frac{1}{\mathrm{R}^{\prime}}\right)= \frac{3}{2}\left(\mu_{\ell}-1\right)\left(\frac{2}{\mathrm{R}}\right) \\ \\ \therefore \quad \mathrm{R}^{\prime}=\frac{\mathrm{R}}{3} \end{array}


    Hence, The correct option is (4)


    2. (Subject - Maths, Chapter - Integral Calculus, Shift - 03 Sep - Evening Shift )

    Question:- If \int \sin ^{-1}\left ( \sqrt{\frac{x}{1+x}} \right )dx=A(x)\tan ^{-1}(\sqrt{x})+B(x)+C, where C is a constant of integration, then the ordered pair (A(x),\; B(x)) can be?

    1. (x+1,\; -\sqrt{x})

    2. (x+1,\; \sqrt{x})

    3. (x-1,\; -\sqrt{x})

    4. (x-1,\; \sqrt{x})

    Answer- 1) (x+1,\; -\sqrt{x})

    Solution:-

    Given,

    \int \sin ^{-1}\left ( \sqrt{\frac{x}{1+x}} \right )dx=A(x)\tan ^{-1}(\sqrt{x})+B(x)+C,

    \begin{array}{l} \text { Put } x=\tan ^{2} \theta \Rightarrow d x=2 \tan \theta \sec ^{2} \theta d \theta \\ \int \theta \cdot\left(2 \tan \theta \cdot \sec ^{2} \theta\right) d \theta \end{array}

    Now do the integration by parts

    \\\mathrm{\theta\rightarrow 1st\;function}\\\mathrm{2\tan\theta\sec^2\theta\rightarrow 2nd\;function}

    \begin{array}{l} =\theta \cdot \tan ^{2} \theta-\int \tan ^{2} \theta \mathrm{d} \theta \\ =\theta \cdot \tan ^{2} \theta-\int\left(\sec ^{2} \theta-1\right) \mathrm{d} \theta \\ =\theta\left(1+\tan ^{2} \theta\right)-\tan \theta+\mathrm{C} \\ =\tan ^{-1}(\sqrt{\mathrm{x}})(1+\mathrm{x})-\sqrt{\mathrm{x}}+\mathrm{C} \end{array}

    A(x)=1+x,\;\;B(x)=-\sqrt x

    Hence, the answer is the option 1.


    3. (Subject - Chemistry, Chapter - Hydrocarbons, Shift - 08 Jan - Morning Shift)

    Question:- The major products A and B in the following reactions are:

    1720600856029


    1. 1720600856074

    2. 1720600854949

    3. 1720600855903

    4. 1720600855239


    Answer- 1) 1720600856126

    Solution:-

    The given reaction occurs as :

    \mathrm{R-O-O-R\xrightarrow[]{\Delta}2R\dot{O}}

    1720600856280

    Therefore, Option(1) is correct.

    Frequently Asked Questions (FAQs)

    Q: Is the JEE Main 2020 question paper a reliable resource for practice?
    A:

    Yes, the JEE Main 2020 question paper is a reliable resource for practice as it is the official examination paper.

    Q: Where can I find the JEE Main 2020 question paper?
    A:

    Candidates can find the JEE Main question papers with solutions pdf of all years and sessions on Careers360 website.

    Q: How effective was solving the previous year's JEE Main question papers for exam preparation?
    A:

    Solving the previous year's JEE Main question papers was a highly effective preparation strategy. It allowed candidates to familiarise themselves with the exam pattern, question types, and concepts. It also helped assess their readiness and improve problem-solving skills.

    Q: What is the mode of examination for JEE Main 2020?
    A:

    JEE Mains 2020 examination was conducted as a computer based test and held in online mode.

    Q: What are the advantages of practising previous years' JEE Main question papers?
    A:

    Solving previous years' question papers can help candidates identify the exam pattern, important topics, frequently asked topics, and increase their speed and accuracy.

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    Hello Dear Student,
    With a JEE rank of 71,251 (approx. 95.5 percentile), you are unlikely to secure a mainstream Computer Science and Engineering (CSE) seat through the general counselling quotas at VNR Vignana Jyothi Institute of Engineering and Technology (VNR VJIET), Hyderabad.

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    Hello,

    With a JEE Main score of around 100 marks, your admission chances depend on your percentile, category, state quota, and counselling process.

    You can consider B.Tech through your state counselling (such as GUJCET), private engineering colleges, or branches like Civil, Mechanical, Electrical, Electronics, or emerging fields depending on your

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    If you are looking for the best online JEE coaching with excellent faculty, high quality lectures, doubt supporting and regular mock test. Some of the most trusted options are Allen digital, Competishun, unacademy, Physics Wala (PW) and Vedantu.

    The right choice depend on your preparation level and budget

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    King Singh
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    JEE mains: 91.48 percentile obc ncl rank : 44480 , Female CRL: 132000 home state: Bihar Which NITs can I get for Core branch?

    Hello Dear Student,

    With a 91.48 percentile (OBC-NCL rank 44,480; CRL 132,000) and Bihar home state quota, your strong female supernumerary quota makes you highly competitive for core branches (Mechanical, Civil, and Electrical) at NIT Patna and NIT Jamshedpur.

    You can get directly find, check, get more information here:

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    2 Jul'26
    I got 60 percentile in mhtcet and jee mains i want to take b tech cse or it which clg should I get

    Hello Dear Student,
    With a 60 percentile in both JEE Main and MHT CET, securing B.Tech CSE or IT in top-tier government colleges is highly unlikely. However, you have excellent options available at reputable private engineering universities and can explore state-affiliated private colleges through decentralized counselling.

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