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JEE Main 2024 Question Paper With Solutions PDF

JEE Main 2024 Question Paper With Solutions PDF

#JEE Main
Vikash Kumar VishwakarmaUpdated on 01 Nov 2024, 09:28 AM IST

JEE Main 2024 question paper - Download the 2024 question paper with the solution in pdf format from this article. JEE Main ( Joint Entrance Examination) is one of the most common exams of engineering. JEE Main Exam is conducted in two sessions one in January and the other In April. Herein, in this article, we provide a link to download the JEE Main 2024 question paper with solutions for both sessions. NTA will publish the JEE Main Question Paper 2025 within a week of the JEE Main exam conclusion. The JEE Main answer key along with the question paper will be released at jeemain.nta.ac.in.

JEE Main 2024 Question Paper With Solutions PDF
JEE Main 2024 Question Paper PDF With Solution

To download the official JEE Mains 2024 question paper pdf, candidates can go through this article and download the corresponding pdf by clicking on the corresponding links provided in the article.

JEE Main Question Paper 2024 Session 1

Below are links to download the 2024 session 1 question paper with the answer key. Using these links you can easily access the question paper and answer key. Below is the link for the JEE Main Question Paper 2024 pdf.

JEE Main Question Paper 2024 Session 2

JEE Main 2024 Questions Paper Analysis with Answers

JEE Main 2024 paper was conducted in 2 sessions. Let's have a look at the detailed analysis of both session question papers by experts of careers360. JEE Main 2024 question paper based on the latest syllabus and latest pattern which was changed by NTA.

JEE Main 2024 Questions and Paper Analysis (April Session)

JEE Main 2024 Questions and Paper Analysis (January Session)

JEE Main 2024 Papers: Questions and Analysis for 27, 29,30,31 January and 1 February

JEE Main 2024 Paper: Questions and Analysis of 27th January Morning Shift

JEE Main 2024 Paper: Questions and Analysis of 27th January Evening Shift

JEE Main 2024 Paper: Questions and Analysis of 29th January Morning Shift

JEE Main 2024 Paper: Questions and Analysis of 29th January Evening Shift

JEE Main 2024 Paper: Questions and Analysis of 30th January Morning Shift

JEE Main 2024 Paper: Questions and Analysis of 30th January Evening Shift

JEE Main 2024 Paper: Questions and Analysis of 31st January Morning Shift

JEE Main 2024 Paper: Questions and Analysis of 31st January Evening Shift

JEE Main 2024 Paper: Questions and Analysis of 1st February Morning Shift

JEE Main 2024 Paper: Questions and Analysis of 1st February Evening Shift

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How to download the JEE Main 2024 Question Papers With Solutions?

Here are the steps to download the JEE Mains 2024 previous year paper with solutions.

  • Click on the links provided in the tables above.

  • Register using your email ID.

  • The JEE question paper pdf download link will be sent to the registered email ID.

  • Simply download it and view the file.

Also Check:

JEE Main Last 10 Years Question Papers with Solutions

JEE Main Question Paper with Solutions and Answer Keys

JEE Main Syllabus: Subjects & Chapters
Select your preferred subject to view the chapters

Benefits of Solving JEE Main 2024 Question Paper

The previous year's JEE Main question papers are an important resource for exam preparation. The JEE Main 2024 question paper based on the latest syllabus and latest pattern offers the following benefits-

  • Helps in revising and identifying topics that need more practice and conceptual clarity.

  • Students gain a better understanding of the JEE Main exam pattern, frequently appearing topics and more. It acts as an effective preparation strategy for the exam.

  • Candidates can improve their time management skills. They can also use it to determine which sections to concentrate on for better accuracy and speed.

  • Regular practice of JEE Main question paper pdf with solutions can help aspirants gain confidence and reduce anxiety before the exam.

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JEE Main Previous Year Questions 2024

Chemistry

1. Cyclohexene 1721277874250is __________ type of an organic compound.

a)Benzenoid non-aromatic

b)Benzenoid aromatic

c)Alicyclic

d)Acyclic

Solution : 1721277874171 is alicyclic compound

2. Which of the following statements are correct?

A. Glycerol is purified by vacuum distillation because it decomposes at its normal boiling point.

B. Aniline can be purified by steam distillation as aniline is miscible in water.

C. Ethanol can be separated from the ethanol-water mixture by azeotropic distillation because it forms azeotrope.

D. An organic compound is pure, if mixed M.P. remains the same.

Choose the most appropriate answer from the options given below :

Solution: Option (B) is incorrect because aniline is immiscible in water.


Physics

1. By what percentage will the illumination of the lamp decrease if the current drops by 20%?

a)56% b) 26% c) 36% d)46%

Solution: Heat and Power developed in a resistor

Heat developed in a resistor: When a steady current flows through a resistance R for time t, the loss in electric potential energy appears as increased thermal energy(Heat H) of the resistor and H=i^2RtThe power developed = \frac{energy}{time}=i^2R=iR=\frac{V^2}{R} (from Ohm's law)

The unit of heat is the joule (J)

The unit of power is the watt (W)

2. A block of mass 5 kg is there on a smooth inclined plane which is making 30 degrees angle with the horizontal, And a hanging mass of 6 kg is attached with it by a string which passes through a pulley; the acceleration of the system is

  1. 4m/s-2 b)1.8m.s-2 c) 4.5m/s-2 d) 5m/s-2

JEE Main 2026: Preparation Tips & Study Plan
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Solution: Let us see the fbd for the system


1721277875916

For acceleration, we can write the equation as


a=\frac{6g-5gsin30^{o}}{6+5}

\Rightarrow a=\frac{60-(50\times \frac{1}{2})}{11}=3.18ms^{-2}

Maths

1. If the mean and variance of five observations are \frac{24}{5} and \frac{194}{25} respectively and the mean of the first four observations is \frac{7}{2}, then the variance of the first four observations in equal to

a)\frac{4}{5} b)\frac{5}{4} c)\frac{3}{5} d)\frac{105}{4}

Solution: MEAN (Arithmetic Mean)

The mean is the sum of the value of each observation in a dataset divided by the number of observations.

Mean of the Ungrouped Data

If n observations in data are x1, x2, x3, ……, xn, then arithmetic mean \mathit{\bar x} is given by

\mathit{\bar x}=\frac{x_1+x_2+x_3+\ldots\dots +x_n }{n}=\frac{1}{n}\sum^{n}_{i=1}x_i

Variance and Standard Deviation

The mean of the squares of the deviations from the mean is called the variance and is denoted by σ2 (read as sigma square).

Variance is a quantity that leads to a proper measure of dispersion.

The variance of n observations x1 , x2 ,..., xn is given by

\sigma^{2}=\frac{1}{n} \sum_{i=1}^{n}\left(x_{i}-\bar{x}\right)^{2}

\bar{X}=\frac{24}{5} ; \sigma^2=\frac{194}{25}

Let the first four observations be \mathrm{x}_1, \mathrm{x}_2, \mathrm{x}_3, \mathrm{x}_4

Here, \frac{x_1+x_2+x_3+x_4+x_5}{5}=\frac{24}{5}

Also, \frac{\mathrm{x}_1+\mathrm{x}_2+\mathrm{x}_3+\mathrm{x}_4}{4}=\frac{7}{2}\Rightarrow \mathrm{x}_1+\mathrm{x}_2+\mathrm{x}_3+\mathrm{x}_4=14

Now from eqn -1

\mathrm{x}_5=10 Now, \sigma^2=\frac{194}{25}

\begin{aligned} & \frac{x_1^2+x_2^2+x_3^2+x_4^2+x_5^2}{5}-\frac{576}{25}=\frac{194}{25} \\ & \Rightarrow x_1^2+x_2^2+x_3^2+x_4^2=54 \end{aligned}

Now, the variance of the first 4 observations

\mathrm{Var}=\frac{\sum_{\mathrm{i}=1}^4 \mathrm{x}_{\mathrm{i}}^2}{4}-\left(\frac{\sum_{\mathrm{i}=1}^4 \mathrm{x}_{\mathrm{i}}}{4}\right)^2=\frac{54}{4}-\frac{49}{4}=\frac{5}{4}

2. If the general term of the first AP = 3n-5 and that of the second AP is 3n+5. Then the 50th term of AP where both the AP are added

a)155 b) 145 c) 300 d)150

Solution: As we learned,

Properties of an AP:

If a_{1},a_{2},a_{3}\: \: and\: b_{1},b_{2},b_{3} are two APs,

then a_{1}+ b_{1},a_{2}+ b_{2,}a_{3}+ b_{3} is also an AP.

In this Question,

T_n=3n+5+3n-5= 6n

T_{50}=6\times 50=300

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Have a question related to JEE Main ?
Hi my name is Disha and currently I am in 12 th I am not prepared for jee literally I am from 0 So what to do i can't prepare now with boards and prelim should I take drop ???

Hi aspirant,

If you are willing to give jee and you are in 12 th then it is best to focus from now on as u have to give your boards this year as well . And according to the exam pattern you can prepare for your jee prelims with you boards at the same time it is hardly differ from each other . But if you have 0 preparation and even your basics are not clear then i suggest u to take a drop and prepare to the fullest for next year thankyou .

Read Complete Answer
P
Pragati Mehrotra
4 Sep'25
Jee main last 10 years question with detailed solution

Hello Hari

You can find JEE Mains last 10 year Previous Year Questions (PYQs) with detailed solution at CAREERS360 website . CAREERS360 provide JEE Mains as well as JEE Advance questions with solutions in many languages like English and Hindi.

Here's the link: JEE Mains Last 10 Years PYQs by CAREERS360

Hope this link helps! Thank You!!!


Read Complete Answer
Y
Yash Teotia
3 Sep'25
I passed my class 12 form NIOS Board with 67% marks in April 2025 ,So I admission FOR re exam in class 12 Fom BOSSE BOARD, SIKKIM october 2025 to met 75% the criteria . what I fill jee mains applicatn form appearing or passed , passing year and which marksheet i use in jossa counseling

Hello Aspirant,

If you already have a Class 12 from NIOS in April 2025 with 67%, you are technically considered a “pass”. But, now since you are reappearing for Class 12 through BOSSE (Sikkim) in October 2025, in order to increase your percentage to 75% (for eligibility) here is how it works:

In the JEE Main Application Form:

  • Choose "Appearing" for Class 12 (you will be giving the BOSSE oct 2025 exam).
  • Enter the passing year as 2025.

For JoSAA Counselling:

  • You must submit the latest valid marksheet, that states you have obtained more than 75%.
  • If your result from BOSSE (oct 2025) comes before counselling/document verification, then to submit BOSSE marksheet.
  • If you only submit NIOS marksheet (67%), you will not then meet the criteria for 75%, so you may be excluded from admission
Read Complete Answer
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gopi
3 Sep'25
Jee mains 2026 is in 4 months Need a plan to finish class 12 and class 11 revision

Here’s a plan for JEE Mains 2026 in 4 months:

1. Divide time: 2 months for Class 12 syllabus, 1 month for Class 11, 1 month for full revision & mock tests.

2. Daily schedule: 6–7 hours study; 50% for theory & problem-solving, 50% for practice & revision.

3. Topic-wise focus: Prioritize high-weightage chapters and weak areas first.

4. Daily problem practice: Solve previous year questions and chapter-wise exercises.

5. Weekly tests: Take 1 full-length test weekly, analyze mistakes, and revise weak concepts.

6. Consistency: Avoid skipping days; maintain notes and formula sheets for quick revision.


Read Complete Answer
A
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How to crack jee in first attempt

If you want to crack JEE exam you read to dedicatedly prepared for that from the scratch to the advance focus on high weightage topic and prepare question in the time based and continuously practice the previous question this will help to know the pattern of JEE exam questions

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