JEE Main 2024 Question Paper With Solutions PDF

JEE Main 2024 Question Paper With Solutions PDF

Team Careers360Updated on 08 Dec 2025, 12:21 PM IST

JEE Main 2024 Question Paper - The National Testing Agency has released the JEE Main question paper 2024 on the official website, jeemain.nta.nic.in. Candidates can download the JEE Main 2024 question paper along with solutions on this page. Solving the previous year's JEE Mains paper helps students improve time management, boost confidence and make their preparation more structured focused and efficient. These JEE Main previous year question PDFs allow applicants to analyze questions, compare answers, and understand the exam pattern and difficulty level. Aspirants can find the direct link to download the JEE Main 2024 question paper with solutions PDF for both sessions. It is necessary to check the JEE Main question paper to cross-check the answers.

JEE Main 2024 Question Paper With Solutions PDF
JEE Main 2024 Question Paper PDF With Solution

The authority had released the JEE Main answer key along with the question paper at jeemain.nta.ac.in. To download the official JEE Mains 2024 question paper pdf, candidates can go through this article and download the corresponding pdf by clicking on the corresponding links provided in the article.

JEE Main 2024 Question Paper Session 1

Below are links to download the JEE Main question paper pdf download 2024. Using these links you can easily access the question paper and answer key. Below is the link for the JEE Main Question Paper 2024 pdf.

JEE Main 2024 Questions Paper Analysis with Answers

JEE Main 2024 paper was conducted in 2 sessions. Let's have a look at the detailed analysis of both session question papers by experts of careers360. JEE Main 2024 question paper based on the latest syllabus and latest pattern which was changed by NTA.

JEE Main 2024 Questions and Paper Analysis (April Session)

JEE Main 2024 Questions and Paper Analysis (January Session)

How to download the JEE Main 2024 Question Papers With Solutions?

Here are the steps to download the JEE Mains 2024 previous year paper with solutions.

  • Click on the links provided in the tables above.

  • Register using your email ID.

  • The JEE question paper pdf download link will be sent to the registered email ID.

  • Simply download it and view the file.

Also Check:

JEE Main Last 10 Years Question Papers with Solutions

JEE Main Question Paper with Solutions and Answer Keys

JEE Main Syllabus: Subjects & Chapters
Select your preferred subject to view the chapters

Benefits of Solving JEE Main 2024 Question Paper

The previous year's JEE Main question papers are an important resource for exam preparation. The JEE Main 2024 question paper based on the latest syllabus and latest pattern offers the following benefits-

  • Helps in revising and identifying topics that need more practice and conceptual clarity.

  • Students gain a better understanding of the JEE Main exam pattern, frequently appearing topics and more. It acts as an effective preparation strategy for the exam.

  • Candidates can improve their time management skills. They can also use it to determine which sections to concentrate on for better accuracy and speed.

  • Regular practice of JEE Main question paper pdf with solutions can help aspirants gain confidence and reduce anxiety before the exam.

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JEE Main Previous Year Questions 2024

Chemistry

1. Cyclohexene 1721277874250is __________ type of an organic compound.

a)Benzenoid non-aromatic

b)Benzenoid aromatic

c)Alicyclic

d)Acyclic

Solution : 1721277874171 is alicyclic compound

2. Which of the following statements are correct?

A. Glycerol is purified by vacuum distillation because it decomposes at its normal boiling point.

B. Aniline can be purified by steam distillation as aniline is miscible in water.

C. Ethanol can be separated from the ethanol-water mixture by azeotropic distillation because it forms azeotrope.

D. An organic compound is pure, if mixed M.P. remains the same.

Choose the most appropriate answer from the options given below :

Solution: Option (B) is incorrect because aniline is immiscible in water.


Physics

1. By what percentage will the illumination of the lamp decrease if the current drops by 20%?

a)56% b) 26% c) 36% d)46%

Solution: Heat and Power developed in a resistor

Heat developed in a resistor: When a steady current flows through a resistance R for time t, the loss in electric potential energy appears as increased thermal energy(Heat H) of the resistor and H=i^2RtThe power developed = \frac{energy}{time}=i^2R=iR=\frac{V^2}{R} (from Ohm's law)

The unit of heat is the joule (J)

The unit of power is the watt (W)

2. A block of mass 5 kg is there on a smooth inclined plane which is making 30 degrees angle with the horizontal, And a hanging mass of 6 kg is attached with it by a string which passes through a pulley; the acceleration of the system is

  1. 4m/s-2 b)1.8m.s-2 c) 4.5m/s-2 d) 5m/s-2

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Solution: Let us see the fbd for the system


1721277875916

For acceleration, we can write the equation as


a=\frac{6g-5gsin30^{o}}{6+5}

\Rightarrow a=\frac{60-(50\times \frac{1}{2})}{11}=3.18ms^{-2}

Maths

1. If the mean and variance of five observations are \frac{24}{5} and \frac{194}{25} respectively and the mean of the first four observations is \frac{7}{2}, then the variance of the first four observations in equal to

a)\frac{4}{5} b)\frac{5}{4} c)\frac{3}{5} d)\frac{105}{4}

Solution: MEAN (Arithmetic Mean)

The mean is the sum of the value of each observation in a dataset divided by the number of observations.

Mean of the Ungrouped Data

If n observations in data are x1, x2, x3, ……, xn, then arithmetic mean \mathit{\bar x} is given by

\mathit{\bar x}=\frac{x_1+x_2+x_3+\ldots\dots +x_n }{n}=\frac{1}{n}\sum^{n}_{i=1}x_i

Variance and Standard Deviation

The mean of the squares of the deviations from the mean is called the variance and is denoted by σ2 (read as sigma square).

Variance is a quantity that leads to a proper measure of dispersion.

The variance of n observations x1 , x2 ,..., xn is given by

\sigma^{2}=\frac{1}{n} \sum_{i=1}^{n}\left(x_{i}-\bar{x}\right)^{2}

\bar{X}=\frac{24}{5} ; \sigma^2=\frac{194}{25}

Let the first four observations be \mathrm{x}_1, \mathrm{x}_2, \mathrm{x}_3, \mathrm{x}_4

Here, \frac{x_1+x_2+x_3+x_4+x_5}{5}=\frac{24}{5}

Also, \frac{\mathrm{x}_1+\mathrm{x}_2+\mathrm{x}_3+\mathrm{x}_4}{4}=\frac{7}{2}\Rightarrow \mathrm{x}_1+\mathrm{x}_2+\mathrm{x}_3+\mathrm{x}_4=14

Now from eqn -1

\mathrm{x}_5=10 Now, \sigma^2=\frac{194}{25}

\begin{aligned} & \frac{x_1^2+x_2^2+x_3^2+x_4^2+x_5^2}{5}-\frac{576}{25}=\frac{194}{25} \\ & \Rightarrow x_1^2+x_2^2+x_3^2+x_4^2=54 \end{aligned}

Now, the variance of the first 4 observations

\mathrm{Var}=\frac{\sum_{\mathrm{i}=1}^4 \mathrm{x}_{\mathrm{i}}^2}{4}-\left(\frac{\sum_{\mathrm{i}=1}^4 \mathrm{x}_{\mathrm{i}}}{4}\right)^2=\frac{54}{4}-\frac{49}{4}=\frac{5}{4}

2. If the general term of the first AP = 3n-5 and that of the second AP is 3n+5. Then the 50th term of AP where both the AP are added

a)155 b) 145 c) 300 d)150

Solution: As we learned,

Properties of an AP:

If a_{1},a_{2},a_{3}\: \: and\: b_{1},b_{2},b_{3} are two APs,

then a_{1}+ b_{1},a_{2}+ b_{2,}a_{3}+ b_{3} is also an AP.

In this Question,

T_n=3n+5+3n-5= 6n

T_{50}=6\times 50=300

Frequently Asked Questions (FAQs)

Q: Upto which year should I solve the question paper of JEE Main?
A:

It is advised to candidates that they should solve at least 10 previous year's question papers to know more about the exam pattern.

Q: Is it necessary to attempt all 75 questions in JEE Mains?
A:

Yes, candidates must attempt all the 75 questions in JEE Mains. However, candidates should only attempt the questions if they are confident about the answer.

Q: Is there a negative marking in the JEE Main Exam?
A:

Yes, there is a negative marking in the JEE Main Exam in both sections for each subject.

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Questions related to JEE Main

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Hello

If you want to get admission in IIT Delhi, then you will score well in JEE Advanced. Only the JEE Mains score is not sufficient to get admission in the IIT Delhi. You need to score 250+ marks for the general category in CSE. For the reservation category, you also need to score much higher marks and give your best performance. If you score quite well in JEE Advanced, then you will have a chance to get admission through JOSAA counselling.

Thank you

To score good marks in JEE Mains, you need a strong plan, consistent study habits and smart practice. First, finish the entire JEE syllabus from NCERT Class 11 and 12 textbooks, because these are the foundation for questions asked in the exam. After completing the basics, choose good quality reference books for Physics, Chemistry and Mathematics to build problem-solving skills and deepen your understanding. Make a weekly study plan where each day is divided into theory study, problem practice and revision of earlier topics.

Regularly solve previous years’ JEE Main papers and take timed mock tests to improve your speed and accuracy. Analyse every test you take, understand your mistakes and work on weak areas instead of only doing new questions. In subjects like Physics and Mathematics, practising a variety of numerical problems is important, while in Chemistry focus on concepts and reactions that are frequently asked. Revision is crucial, so dedicate time every week to revisit older topics and short notes that you make while preparing.

Stay consistent, avoid last-minute cramming, and maintain good health with adequate sleep and breaks during study. With disciplined planning, regular practice and careful revision, you can significantly improve your JEE Main score. All the best.

Achieving a JEE Rank of below 100 in JEE Main and Advanced 2027 requires a disciplined, two-year preparation strategy starting from Class 11. Your study plan must integrate competitive exam preparation with your school academics:

Phase 1: Class 11 (Foundation Building and Conceptual Clarity)

  • Syllabus Completion: Dedicate this year to rigorously completing the entire Class 11 NCERT syllabus for Physics, Chemistry, and Mathematics (PCM). Focus heavily on fundamental topics like Mechanics (Physics), General Organic Chemistry (GOC) and Chemical Bonding (Chemistry), and Calculus basics (Maths).

  • Concept Mastery: Do not rush. Master concepts thoroughly before moving to problems. Use standard JEE reference books and ensure you solve all NCERT examples and exercises first.

  • Practice: Allocate 60% of your study time to concept building and 40% to problem-solving. Practice JEE Main Previous Year Questions (PYQs) immediately after completing a chapter to gauge the exam pattern.

Phase 2: Class 12 (Advanced Problem Solving and Revision)

  • Advanced Topics: Complete the Class 12 syllabus by November 2026, focusing on high-weightage topics like Electrostatics, Modern Physics, and Electrochemistry.

  • Revision & Mocks: Reserve the period from December 2026 to January 2027 solely for mock tests and revision. Start taking full-length JEE Main mock tests (3 per week) under strict timed conditions. Analyze each mock test thoroughly to eliminate repeated errors.

  • Target JEE Advanced: After the JEE Main attempts in early 2027, shift focus entirely to JEE Advanced PYQs and challenging, multi-concept problems, taking at least 2 JEE Advanced mock tests per week.

A detailed subject-wise study plan and additional tips on effective JEE preparation starting from Class 11 can be found here: https://engineering.careers360.com/articles/jee-preparation-from-class-11

The last 30 days before the JEE Main exam should be dedicated entirely to revision, practice, and error analysis, shifting focus away from learning new concepts.

Here is a concise, 30-day study plan to maximize your score:

1. Revision Strategy (Weeks 1-3)

  • Prioritize High-Weightage Topics: Spend 70% of your revision time reviewing the most scoring and frequently tested chapters (e.g., Modern Physics, Chemical Kinetics, p-Block elements, Vectors & 3D Geometry). Use your short notes and flashcards for quick review, focusing on formulas, key mechanisms, and definitions.

  • Physics & Maths: Master all formulas and derivations. Practice at least 20 numerical problems daily, emphasizing speed and calculation accuracy.

  • Chemistry: Dedicate 50% of your Chemistry time to Inorganic (NCERT-based) and Organic (name reactions, reagents, mechanisms) concepts.

2. Mock Tests & Analysis (Daily)

  • Daily Mock Test: Solve one full-length JEE Main Mock Test every day (3 hours) under strict exam conditions (9 AM–12 PM or 3 PM–6 PM).

  • Error Analysis (Crucial): Immediately after the test, spend 2-3 hours analyzing your performance:

    • Identify every incorrect or unattempted question.

    • Determine the reason for the error (Conceptual mistake, calculation error, or time pressure).

    • Revisit the concept from your notes/NCERT text to correct the mistake permanently.

3. Final Week Focus (Last 7 Days)

  • Stop Learning New Topics: Absolutely avoid picking up new, complex chapters.

  • PYQ Sprint: Revisit only the last 3 years' JEE Main Previous Year Questions (PYQs). Mark any previously incorrect questions and solve them again.

  • Mindset: Focus on maintaining confidence, getting proper sleep, and using the revision breaks for physical activity to keep your mind fresh.

You can find more detailed subject-wise tips and psychological strategies here: https://engineering.careers360.com/articles/jee-main-preparation-tips

The most effective way to prepare for JEE Main 2026 is by focusing on the most important Previous Year Question Papers (PYQs), which highlight high-weightage and frequently repeated questions across Physics, Chemistry, and Mathematics. Since the exam strongly tests NCERT concepts, mastering these PYQs is essential for predicting the question pattern and improving your time management. https://engineering.careers360.com/articles/jee-mains-chapterwise-pyq-previous-year-questions-solutions-pdf