Careers360 Logo
ask-icon
share
    JEE Main 2024 Question Paper With Solutions PDF

    JEE Main 2024 Question Paper With Solutions PDF

    Team Careers360Updated on 31 Mar 2026, 12:42 PM IST

    JEE Main 2024 Question Paper - The National Testing Agency releases the JEE Main question paper 2024 on the official website, jeemain.nta.nic.in. Download the 2024 question paper PDF for free from the website. No login credentials are required to download the JEE Main 2024 question paper. Careers360 has also provided the JEE Main 2024 question paper PDF along with solutions on this page. With the help of the previous year’s question paper, analyse questions, compare answers, and understand the JEE Main exam pattern and difficulty level. To download the official JEE Mains 2024 question paper PDF, candidates can go through this article and download the PDF by clicking on the links provided in the article.

    JEE Main 2024 Question Paper With Solutions PDF
    JEE Main 2024 Question Paper PDF With Solution

    JEE Main 2024 Question Paper Session 1

    Candidates preparing for the upcoming Joint Entrance Examination can download the JEE Main question paper PDF 2024 via the links. Just click on the link to easily access the question paper and answer key. Check the table below with the link for the JEE Main Question Paper 2024 PDF.

    Confused About College Admissions?

    Get expert advice on college selection, admission chances, and career path in a personalized counselling session.

    Book a Counselling Slot
    Select Date
    Pick a Slot

    JEE Main 2024 Questions Paper Analysis with Answers

    The JEE Main 2024 exam was conducted in two sessions and in two shifts. Candidates can check a thorough analysis of the session and sheet-wise question paper by experts of careers360. The JEE Main 2024 question paper is based on the latest syllabus and the latest pattern, which was changed by NTA. Candidates will find out the paper analysis here to see what they can expect fro the upcoming exam.

    JEE Main 2024 Questions and Paper Analysis (April Session)

    JEE Main 2024 Questions and Paper Analysis (January Session)

    How to download the JEE Main 2024 Question Papers With Solutions?

    To download the question paper from the official website, candidates just have o follow the steps:

    • Visit the official website of the National Testing Agency, nta.ac.in/Home.

    • On the home page, click on the ‘Downloads’ option.

    • Candidates will now be directed to the previous year's exam paper window.

    • Now, on the search option, enter the exam year (select 2024) and the exam type (select JEE Main),

    • Click ‘Search’ and the JEE Main 2024 question paper download link will be displayed in table format.

    • Candidaets can click on the question paper 2024 type and download in PDF format.

    Also Check:

    JEE Main Last 10 Years Question Papers with Solutions

    JEE Main Question Paper with Solutions and Answer Keys

    JEE Main Syllabus: Subjects & Chapters
    Select your preferred subject to view the chapters

    Benefits of Solving the JEE Main 2024 Question Paper

    For JEE Main exam preparation, the previous year's JEE Main question papers are an important resource. The JEE Main 2024 question paper, based on the latest syllabus and latest pattern, offers the following benefits-

    • Helps in revising and identifying topics that need more practice and conceptual clarity.

    • Students gain a better understanding of the JEE Main exam pattern, frequently appearing topics and more. It acts as an effective preparation strategy for the exam.

    • Candidates can improve their time management skills. They can also use it to determine which sections to concentrate on for better accuracy and speed.

    • Regular practice of JEE Main question paper pdf with solutions can help aspirants gain confidence and reduce anxiety before the exam.

    Amity University B.Tech Admissions 2026

    Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026

    UPES B.Tech Admissions 2026

    Last Date to Apply: 18th May | Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements

    JEE Main Previous Year Questions 2024

    Chemistry

    1. Cyclohexene 1721277874250is __________ type of an organic compound.

    a)Benzenoid non-aromatic

    b)Benzenoid aromatic

    c)Alicyclic

    d)Acyclic

    Solution : 1721277874171 is alicyclic compound

    2. Which of the following statements are correct?

    A. Glycerol is purified by vacuum distillation because it decomposes at its normal boiling point.

    B. Aniline can be purified by steam distillation as aniline is miscible in water.

    C. Ethanol can be separated from the ethanol-water mixture by azeotropic distillation because it forms azeotrope.

    D. An organic compound is pure, if mixed M.P. remains the same.

    Choose the most appropriate answer from the options given below :

    Solution: Option (B) is incorrect because aniline is immiscible in water.

    Physics

    1. By what percentage will the illumination of the lamp decrease if the current drops by 20%?

    a)56% b) 26% c) 36% d)46%

    Solution: Heat and Power developed in a resistor

    Heat developed in a resistor: When a steady current flows through a resistance R for time t, the loss in electric potential energy appears as increased thermal energy(Heat H) of the resistor and H=i^2RtThe power developed = \frac{energy}{time}=i^2R=iR=\frac{V^2}{R} (from Ohm's law)

    The unit of heat is the joule (J)

    The unit of power is the watt (W)

    2. A block of mass 5 kg is there on a smooth inclined plane which is making 30 degrees angle with the horizontal, And a hanging mass of 6 kg is attached with it by a string which passes through a pulley; the acceleration of the system is

    1. 4m/s-2 b)1.8m.s-2 c) 4.5m/s-2 d) 5m/s-2

    JEE Main 2026 College Predictor
    Check your college admission chances based on your JEE Main percentile with the JEE Main 2026 College Predictor.
    Try Now

    Solution: Let us see the fbd for the system

    1721277875916

    For acceleration, we can write the equation as

    a=\frac{6g-5gsin30^{o}}{6+5}

    \Rightarrow a=\frac{60-(50\times \frac{1}{2})}{11}=3.18ms^{-2}

    Maths

    1. If the mean and variance of five observations are \frac{24}{5} and \frac{194}{25} respectively and the mean of the first four observations is \frac{7}{2}, then the variance of the first four observations in equal to

    a)\frac{4}{5} b)\frac{5}{4} c)\frac{3}{5} d)\frac{105}{4}

    Solution: MEAN (Arithmetic Mean)

    The mean is the sum of the value of each observation in a dataset divided by the number of observations.

    Mean of the Ungrouped Data

    If n observations in data are x1, x2, x3, ……, xn, then arithmetic mean \mathit{\bar x} is given by

    \mathit{\bar x}=\frac{x_1+x_2+x_3+\ldots\dots +x_n }{n}=\frac{1}{n}\sum^{n}_{i=1}x_i

    Variance and Standard Deviation

    The mean of the squares of the deviations from the mean is called the variance and is denoted by σ2 (read as sigma square).

    Variance is a quantity that leads to a proper measure of dispersion.

    The variance of n observations x1 , x2 ,..., xn is given by

    \sigma^{2}=\frac{1}{n} \sum_{i=1}^{n}\left(x_{i}-\bar{x}\right)^{2}

    \bar{X}=\frac{24}{5} ; \sigma^2=\frac{194}{25}

    Let the first four observations be \mathrm{x}_1, \mathrm{x}_2, \mathrm{x}_3, \mathrm{x}_4

    Here, \frac{x_1+x_2+x_3+x_4+x_5}{5}=\frac{24}{5}

    Also, \frac{\mathrm{x}_1+\mathrm{x}_2+\mathrm{x}_3+\mathrm{x}_4}{4}=\frac{7}{2}\Rightarrow \mathrm{x}_1+\mathrm{x}_2+\mathrm{x}_3+\mathrm{x}_4=14

    Now from eqn -1

    \mathrm{x}_5=10 Now, \sigma^2=\frac{194}{25}

    \begin{aligned} & \frac{x_1^2+x_2^2+x_3^2+x_4^2+x_5^2}{5}-\frac{576}{25}=\frac{194}{25} \\ & \Rightarrow x_1^2+x_2^2+x_3^2+x_4^2=54 \end{aligned}

    Now, the variance of the first 4 observations

    \mathrm{Var}=\frac{\sum_{\mathrm{i}=1}^4 \mathrm{x}_{\mathrm{i}}^2}{4}-\left(\frac{\sum_{\mathrm{i}=1}^4 \mathrm{x}_{\mathrm{i}}}{4}\right)^2=\frac{54}{4}-\frac{49}{4}=\frac{5}{4}

    2. If the general term of the first AP = 3n-5 and that of the second AP is 3n+5. Then the 50th term of AP where both the AP are added

    a)155 b) 145 c) 300 d)150

    Solution: As we learned,

    Properties of an AP:

    If a_{1},a_{2},a_{3}\: \: and\: b_{1},b_{2},b_{3} are two APs,

    then a_{1}+ b_{1},a_{2}+ b_{2,}a_{3}+ b_{3} is also an AP.

    In this Question,

    T_n=3n+5+3n-5= 6n

    T_{50}=6\times 50=300

    Frequently Asked Questions (FAQs)

    Q: Upto which year should I solve the question paper of JEE Main?
    A:

    It is advised to candidates that they should solve at least 10 previous year's question papers to know more about the exam pattern.

    Q: Is it necessary to attempt all 75 questions in JEE Mains?
    A:

    Yes, candidates must attempt all the 75 questions in JEE Mains. However, candidates should only attempt the questions if they are confident about the answer.

    Q: Is there a negative marking in the JEE Main Exam?
    A:

    Yes, there is a negative marking in the JEE Main Exam in both sections for each subject.

    Articles
    |
    Upcoming Engineering Exams
    Ongoing Dates
    IEMJEE Exam Date

    5 Jan'26 - 30 May'26 (Online)

    Ongoing Dates
    CITKEE Application Date

    9 Mar'26 - 25 May'26 (Online)

    Certifications By Top Providers
    Online Certificate Course on Cyber Laws
    Via Indian Law Institute, New Delhi
    Basic Programming using Python
    Via Indian Institute of Technology Bombay
    Software Engineering Essentials
    Via Technical University of Munich, Munich
    Material Science
    Via Indira Gandhi National Open University, New Delhi
    B.Tech Engineering Technology
    Via Birla Institute of Technology and Science, Pilani
    Principles of Digital Communications
    Via Indian Institute of Technology Delhi
    Udemy
     1525 courses
    Swayam
     817 courses
    NPTEL
     773 courses
    Coursera
     697 courses
    Edx
     608 courses
    Explore Top Universities Across Globe

    Questions related to JEE Main

    On Question asked by student community

    Have a question related to JEE Main ?

    Hi Raj Kumar,
    As you have not mentioned an approximate or particular JEE Mains rank, you can view the colleges by using the JEE Main college predictor , a simple and direct tool to predict colleges!

    Link for Everything you might need:
    Comprehensive Guide

    1. IIT's
    2. NIT's
    3. IIIT's

    Also Don't miss

    Hello Student,

    I am sharing the college predictor tool with you that will help you determine which are the possible colleges you can get based on your rank in both exams.

    Link - JEE Main 2026 College Predictor

    Link - AP EAMCET 2026 College Predictor

    Hello Student,

    You have a good percentile in JEE Main, and there is a strong chance of getting of you securing a seat at ISI BSDS. This is especially advantageous if you are from a reserved category.


    What you need to remember is that the final admission will still depend

    Hello Student,

    With your rank, getting a seat in mechanical engineering in a top-tier or even a mid-tier NIT or an IIIT is extremely difficult, through JoSAA rounds, because the mechanical engineering cut-off rank at NITs is much before the 50K - 60K rank for OBC candidates.

    However, there can