JEE Main 2025 April 4 Shift 1 Question Paper with Solutions Available - Download PDF

JEE Main 2025 April 4 Shift 1 Question Paper with Solutions Available - Download PDF

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Shivani PooniaUpdated on 04 Apr 2025, 07:08 PM IST
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JEE Main 2025 April 4 Shift 1 question paper gives valuable insights into the kind of questions, difficulty level, and effective methodologies to tackle different subjects. Students can find the JEE Main 2025 April 4 question paper and step-by-step solutions to judge their performance, understand the test format, measure the difficulty level, and check crucial topics included. This overall JEE Main 2025 April 4 Question Paper review comprises subject-wise difficulty levels, weightage proportion, and professional solutions, providing a good platform for students studying for upcoming shifts and days. JEE Main exam is over, the JEE Main 2025 April 4 Shift 1 question paper with solutions is updated and made available for practice and viewing.

LiveJEE Main 2026 Registration LIVE: NTA session 1 application link active at jeemain.nta.nic.in; apply by Nov 27Nov 12, 2025 | 8:33 PM IST

The table below lists the opening and closing All India Ranks for BTech programmes at the National Institute of Technology (NIT) Durgapur under the Open (PwD) category for both Home State (HS) and Other State (OS) quotas. It provides a detailed view of admissions across key engineering disciplines.

Academic Program NameQuotaOpening RankClosing Rank
B.Tech in Mathematics and Computing (4 Years, Bachelor of Technology)HS10271027
Bio Technology (4 Years, Bachelor of Technology)HS17681768
Bio Technology (4 Years, Bachelor of Technology)OS20402040
Chemical Engineering (4 Years, Bachelor of Technology)HS18271827
Chemical Engineering (4 Years, Bachelor of Technology)OS19491949
Civil Engineering (4 Years, Bachelor of Technology)HS12381238
Computer Science and Engineering (4 Years, Bachelor of Technology)HS151151
Computer Science and Engineering (4 Years, Bachelor of Technology)OS406406
Electrical Engineering (4 Years, Bachelor of Technology)HS588588
Electrical Engineering (4 Years, Bachelor of Technology)OS14781478
Electronics and Communication Engineering (4 Years, Bachelor of Technology)HS613613
Electronics and Communication Engineering (4 Years, Bachelor of Technology)OS506506
Mechanical Engineering (4 Years, Bachelor of Technology)HS12961296
Mechanical Engineering (4 Years, Bachelor of Technology)OS19641964
Metallurgical and Materials Engineering (4 Years, Bachelor of Technology)HS32463246
Metallurgical and Materials Engineering (4 Years, Bachelor of Technology)OS23312331

The last date for submission of JEE Main application form 2026 is November 27.NIT Durgapur BTech Seats: PwD category rank. (Image: Official Website) 

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This Story also Contains

  1. JEE Main 2025 April 4 Shift 1 Question Paper Pattern and Structure
  2. JEE Main 2025 Marking Scheme
  3. JEE Main 2025 April 4 Shift 1 Question Paper with Solutions
  4. Memory Based questions
  5. JEE Main 2025 April 4 Shift 1 Answer Key & Solution PDF Download
  6. JEE Main 2025 Previous Year Question Paper
JEE Main 2025 April 4 Shift 1 Question Paper with Solutions Available - Download PDF
JEE Main 2025 April 4 Shift 1 Question Paper with Solutions

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JEE Main is perhaps the most important exam for Indian engineering aspirants.The JEE Main 2025 April 4 shift 1 question paper after completion will be updated on the page below. The JEE Main 2025 April 4 shift 1 question paper is based on students' responses and memory-based questions. You can also go for the JEE Main 2025 April 4 Question Paper PDF download

Watch Live 4 April Shift 1


JEE Main 2025 April 4 Shift 1 Question Paper Pattern and Structure

Details

Information

Total Time

3 hours (180 minutes)

Total Questions

75 questions

Maximum Marks

300 marks

Exam Medium

Available in 13 languages

Exam Mode

Computer Based Test (CBT)

Question Type

MCQs and Numerical Value-Based

JEE Main 2025 Marking Scheme

Aspect

Details

Marking Scheme

- MCQs: +4 marks for correct answers, -1 mark for incorrect answers.

- Numerical Value-Based Questions: No negative marking.

Total Marks per Correct Answer

+4 marks for each correct response

Negative Marking

- For MCQs: -1 mark for an incorrect answer

- For Numerical Value-Based Questions: No negative marking

Unanswered Questions

No marks are awarded for unanswered questions and no penalty for leaving them blank.

Subjects Covered

Physics, Mathematics, and Chemistry (including Organic Chemistry, Mechanics, Calculus, etc.)

JEE Main 2025 April 4 Shift 1 Question Paper with Solutions

JEE Main 2025 April 4 Shift 1 exam, the question paper and solutions is made available on this webpage. These materials is prove helpful for the aspirants appearing for subsequent shifts, providing them with a complete overview of the structure and difficulty of the exam. By going through the JEE Main 2025 April 4 Shift 1 Question Paper with Solutions PDF they can spot critical concepts, attempt problem-solving techniques, and prepare well for future exams. You can also download JEE Main 2025 April 4 Shift 1 Paper PDF.

Memory Based questions

Chemistry

4 April shift 1

Q.1 In the following, the number of paramagnetic molecules are : $\mathrm{O}_2, \mathrm{~N}_2, \mathrm{~F}_2, \mathrm{~B}_2, \mathrm{Cl}_2$

Q.2 Which of the following is the ratio of $5^{\text {th }}$ Bohr orbit $\left(r_5\right)$ of $\mathrm{He}^{+} \& \mathrm{Li}^{2+}$ ?
1) $\frac{2}{3}$
2) $\frac{3}{2}$
3) $\frac{9}{4}$
4) $\frac{4}{9}$

Q.3 Which of the following pair of ions have equal number of unpaired electrons
$1 \quad\mathrm{~V}^{2+}$ and $\mathrm{Ni}^{2+}$
$2\quad \mathrm{Cr}^{2+}$ and $\mathrm{Mn}^{2+}$
$3 \quad \mathrm{Fe}^{2+}$ and $\mathrm{Sc}^{2+}$
$4 \quad\mathrm{Mn}^{3+}$ and $\mathrm{Fe}^{2+}$

Q.4. Incorrect order of atomic radius is
1 $\mathrm{~B}<\mathrm{Al}$
2 $\ln <\mathrm{TI}$
3 $\mathrm{Al}<\mathrm{Ga}$
4 $\mathrm{Ga}<\ln$

Maths

4th April Shift 1 Maths

Q 1. Solve $\int_{-1}^1 \frac{1+2 x}{e^{-x}+e x} d x$.

1) $2\left(\tan ^{-1} e-\frac{\pi}{4}\right)$
2) $2\left(\tan ^{-1} e-\frac{\pi}{3}\right)$
3) $2\left(\tan ^{-1} e-\frac{\pi}{2}\right)$
4) $2\left(\frac{\pi}{2}-\tan ^{-1} \pi\right)$

Q 2. If the equation of an ellipse $E$ is $\frac{x^2}{9}+\frac{y^2}{16}=1$, then the length of latus rectum of $E$ is

$\begin{aligned} 1) & \frac{32}{5} \\ 2) & \frac{9}{2} \\ 3) & \frac{16}{3} \\ 4) & \frac{9}{5}\end{aligned}$

Q 3. The sum of the series $1+3+5^2+7+9^2+\ldots$ upto 80 terms is

1) 328160

2) 338160

3) 339400

4) 326870

Q 4. Foci of ellipse are (2,5) and (2,-3), eccentricity is 4/5. Find the length of the latus rectum.

Q 5. Let there be two A.P.'s with each having 2025 terms. Find the number of distinct terms in union of these two A.P.'s, i.e., AUB if first A.P. is $1,6,11, \ldots$ and second A.P. is $9,16,23, \ldots$

Physics

Q 1) A ring and a solid sphere were released from rest from the same height on enough rough inclined surface. Ratio of their speed when they reach at bottom is $\sqrt{\frac{7}{x}} \mathrm{~m} / \mathrm{s}$, then $x$ is $\qquad$

Q 2) Mean free path for an ideal gas is to be observed $20 \mu \mathrm{~m}$ while average speed of molecules of gas is observed to be $600 \mathrm{~m} / \mathrm{s}$, then frequency of collision is near by

Q.3) Find the equivalent capacitance between $A$ and $B$, where $C=16 \mu F$


JEE Main Syllabus: Subjects & Chapters
Select your preferred subject to view the chapters

JEE Main 2025 April 4 Shift 1 Answer Key & Solution PDF Download

Once the answer key is officially published, candidates can verify their answers and assess their performance through the direct link to the JEE Main 2025 April 3 Answer Key PDF Download. After all the shifts are completed, the question paper of JEE Main 2025 April 3 All Shifts will be posted here. The JEE Main 2025 April 3 Answer Key Download and solutions from each expert will be posted on this page.

Frequently Asked Questions (FAQs)

Q: Where can I get JEE Main 2025 April 4 Answer Key PDF?
A:

You can get  JEE Main 2025 April 4 Answer Key PDF on this article after the exam.

Q: What is the marking pattern or distribution for the JEE Main 2025 April 4 Shift 1 examination?
A:

For MCQs, 4 marks were given for a correct response and 1 mark was deducted for an incorrect one. For Numerical Value-Based Questions, no negative marking provision was made.

Q: How long is the JEE Main 2025 April 4 Shift 1 examination?
A:

The examination lasted 3 hours (180 minutes).

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Questions related to JEE Main

On Question asked by student community

Have a question related to JEE Main ?

HELLO,

The JEE Main application verification system uses the name you enter in the application form at the time of Aadhar Card verification so if you your Aadhaar was updated but still it is showing name not verifies then it means the new details have not been reflected in the online system use by NTA

Now what you can do is :-

1. First check the status of your Aadhaar card updates on the official UIDAI website by using your Update request Number.

2. Verify the details you have entered in application form like ensure that the name that you have entered in the JEE main application form exactly matches your newly updated Aadhaar card

3. You can use the NTA Mismatch Advisory like if a name mismatch pop up appears during the application process so for this NTA has provided the solution first close the pop up then a new window will appear that will allow you to enter the name exactly as it is on your Aadhaar card

4. If still the problem does not solve then you can contact the NTA Helpdesk

Visit the link to know more :- https://engineering.careers360.com/articles/how-correct-aadhaar-name-mismatch-in-jee-mains

Hope this Helps!

While filling the form of JEE Mains 2026 January session, upload the improvement marksheet, as your improvement marksheet is your final marksheet of class 12th AISSCE exams. The one that you got before the improvement doesn't matter now as you appeared for the compartment exam to increase your overall score. So, use the marksheet given to you after appearing for your improvement exam everywhere as that is your finalized class 12th marksheet.

Hello, Yes, this mismatch will absolutely cause a problem during your JEE Mains 2026 registration, but there is a clear solution.

You must enter your father's name "Girisharadya" (without the 'a') in the main application form, as it appears on your 10th-grade marksheet. The 10th marksheet is the primary, non-changeable document for all NTA applications.

When the system tries to verify this with your Aadhaar, it will detect a mismatch ("Girisharadya" vs. "Girisharadhya") and will show a pop-up warning. NTA has created a process for this: you will be given an option to enter your father's name as per your Aadhaar in a separate field. The system will then capture both spellings, allowing you to complete the registration.

However, since you have time before 2026, the safest and most highly recommended solution is to get your Aadhaar card (and your father's) corrected to match the spelling on your 10th marksheet ("Girisharadya"). This will prevent any confusion or problems later during JoSAA counselling and final document verification.

I hope you found this information helpful and for any study related queries you can ask in careers360 app, Have a great day!

Hello Aspirant,

Jee main's high scoring chapters:

For mathematics : Coordinate Geometry, Calculus (especially Integral Calculus), and Algebra (Complex Numbers, Quadratic Equations, Matrices, Determinants) .

For physics:  Thermodynamics, Current Electricity, Electrostatics, and Optics.

For Chemistry: Periodic Table, Chemical Bonding, Hydrocarbons, and Chemical Kinetics.

This chapters are the highest scoring in jee main. Hope this will help u. Wish u good luck.

Hello,

If you are currently studying in Class 12 and haven’t yet received your registration number or roll number from your board, you can leave that field blank or enter “NA” (Not Applicable) in the JEE Main application form.

Once your board issues the official registration or roll number, you don’t need to worry, NTA verifies your board details later during counselling or admission, not during registration.

So, do not enter random numbers, use “NA” or skip if optional.

Hope you understand.