34 Percentile Means How Many Marks in JEE Mains 2026 - Candidates can go through this page to know what 34 percentile means how many marks in JEE Main 2026. NTA declares the JEE Main result in the form of a percentile score. 34 percentile in JEE Main will be around 23 to 25 marks. Since the authority does not publish the raw marks, the Careers360 team has compiled the details based on previous years' trends of JEE Main. Note that the value of 34 percentile in JEE Main 2026 in marks will vary for each year. JEE Main 2026 aspirants can scroll down the article to know about the significance of 34 percentile for JEE Main 2026.
Candidates can use the JEE Main college predictor 2026 to determine the type of college that may provide admission based on 34 percentile.
The JEE Main Marks vs Percentile depends on exam difficulty level, total number of applicants, seats, and more. However, based on previous years’ trends, a 34 percentile will be 23 to 25 marks (out of 300). Check the table for detailed data.
JEE Main Marks | JEE Main Percentile |
300 | 100 |
299 – 240 | 99.9999803 – 99.975028 |
161 – 239 | 99.272084 – 99.956340 |
141 – 160 | 98.732389 – 99.239737 |
121 – 140 | 97.811260 – 98.666935 |
101 – 120 | 96.204550 – 96.978272 |
81 – 100 | 93.471231 – 96.064850 |
71 – 80 | 91.8 – 93.2 |
61 – 70 | 87.0 – 91.7 |
51 – 60 | 78.0 – 86.9 |
36 – 45 | 58.0 – 68.9 |
31 – 35 | 47.0 – 56.7 |
21 – 30 | 32.0 – 46.9 |
11 – 20 | 17.0 – 31.9 |
0 – 10 | 0.8435177 – 16.9 |
Keep in mind that these figures are not accurate and might change depending on the JEE Mains session. For example, if the exam is harder in one year than in another one, an applicant may need to score slightly higher for the same percentile.
The term "percentile" refers to a candidate's performance relative to others. It depicts the number of applicants who received a score less than or equal to the candidate's. According to the JEE Main percentile vs. rank, a candidate scoring in the 90th percentile outperformed 90% of all contenders. With a percentile of 34, the candidate outperformed 34% of the other contenders.
The JEE Main percentile 2026 score is calculated by the formula:
Percentile = (Number of candidates with a score ≤ your score ÷ Total number of candidates in that session) × 100.
The NTA applies this formula to calculate percentile scores following the JEE Main 2026 results. JEE percentile score does not equal the percentage of marks. It is a normalized score used to compare candidates' performance. To account for the difference in difficulty between JEE Main exam 2026 shifts, the NTA will use a JEE Main 2026 normalization process. As a result, the percentile-corresponding scores may differ across exam sessions.
General category candidates with a 34 percentile will be unable to meet the qualifying JEE Main cut-off 2026 for admission to top engineering colleges in India. However, candidates belonging ot certain reserved categories will be be evan eligible for taking the JEE Advanced. Candidates with this percentile should only consider going to a private college. What makes up a good JEE Main score greatly depends on the college or institute to which a student wishes to apply. Some reserved categories might be able to get in with a 34 percentile, but general category applicants need a much higher percentile to get a place in good colleges.
Frequently Asked Questions (FAQs)
Due to the low JEE Main score of 32, admission to NITs, IIITs, and GFTIs is not possible.
As per past year trends, an NTA percentile score in the 99–98 range will be seen as a good percentile for JEE Main 2026.
JEE Main 2026 cut off will be announced after the JEE Main 2026 result in April.
On Question asked by student community
Good Evening,
Yes, you are eligible for both JEE Mains and Advanced, as you completed your 12th with physics, chemistry and biology. Moreover, you passed mathematics in 2025, which makes you fit the eligibility criteria of both exams.
Aspirant, I would like to inform you that Careers360 recently launched a free mock test series for JEE students. The last date of registration is 8th January, 2026. Enroll and solve chapter wise question papers and improve you concept and assess your learning. The link to the mock test series is attached herewith. https://learn.careers360.com/test-series-jee-main-free-mock-test/
Best regards.
Hello,
Since the NTA conducts exams in Tamil, these official papers will have a Tamil language option. Kindly check the following link to get the question papers.
https://engineering.careers360.com/articles/jee-main-question-papers
I hope this helps you.
Hello there,
Understanding and solving different question papers is one of the best practice for the preparation specially when it comes to JEE mains. It gives you proper understanding of the exam pattern, important topics to cover and marking scheme.
Here is the link attached from the official website of Careers360 which will provide you with the link of previous year question papers on chemistry in PDF format. Hope it helps!
https://engineering.careers360.com/articles/jee-mains-chemistry-questions-in-last-year-exam-premium
thank you!
Good Morning, Candidate,
The 30-day study plan for JEE is now available on the website of Careers360. The link is attached herewith.
https://engineering.careers360.com/download/ebooks/jee-main-study-plan-30-days
There is an option for free download, which will help to proceed further.
Careers360 would like to inform you that you can have an opportunity to analyse your in-depth performance. Careers360 is conducting a free all-India online JEE mock test series on 11th January. It will provide you with a proper question pattern with chapter-wise questions and answers.
Registration is closed on 8th January. Registered and assessed your learning.
Thank You
Hello,
Yes, you can be eligible , but it depends on how you passed Mathematics.
JEE Main
You are eligible if:
You passed Class 12 with Physics and Mathematics.
Mathematics was passed as a full subject from NIOS.
NIOS is a recognized board.
Having two marksheets is allowed.
You are not eligible if:
Mathematics was taken only as an improvement or additional without passing it as a full subject.
MHT-CET
You are eligible if:
You passed Class 12 with Physics and Mathematics.
Mathematics from NIOS is shown as a passed subject.
NIOS is recognized for Maharashtra admissions.
Mathematics was passed before the admission year.
You are not eligible if:
Mathematics is not shown as a passed subject.
Important
Mathematics must be a separate and passed subject.
Keep both marksheets during counselling.
Always check the current year information brochure before applying.
Hope it helps !
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