JEE Main April 7 Shift 2 Question Paper with Solutions 2025 Released - Download PDF
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JEE Main is a highly significant examination for students wishing to pursue engineering in India. This JEE Main 2025 April 7 Shift 2 question paper article is giving detailed information about the type of questions, difficulty level, and effective methods of tackling various subjects. As the JEE Main exam for April 7 Shift 2 is finished, the question paper and the solutions is updated below. You can also download the JEE Main 2025 April 7 Shift 2 Question Paper PDF. You can check JEE Mains April 7 shift 2 answer key also.
This Story also Contains
- Watch JEE Mains Live Analysis April 7 Shift 2
- JEE Main 2025 April 7 Shift 2 Question Paper with Solution
- Chemistry
- Physics
- Maths
- JEE Main 2025 April 7 Shift 2 Answer Key & Solution PDF Download
- JEE Main 2025 Previous Year Question Paper
Watch JEE Mains Live Analysis April 7 Shift 2
JEE Main 2025 April 7 Shift 2 Question Paper with Solution
As the JEE Main 2025 April 7 Shift 2 test is concluded, the question paper and solutions is updated here on this webpage. The students who are appearing for the next shifts can utilize these resources since they provide an overall picture of the structure and difficulty of the exam. By studying the JEE Main 2025 Shift 2 Question Paper with Solutions PDF, candidates can grasp important concepts, solve problems efficiently, and prepare well for future exams.
Chemistry
Q.1 Consider the following oxides
$$
\mathrm{V}_2 \mathrm{O}_5, \mathrm{Cr}_2 \mathrm{O}_3, \mathrm{Mn}_2 \mathrm{O}_7, \mathrm{~V}_2 \mathrm{O}_3, \mathrm{VO}_2
$$
Number of oxides which are acidic is $\mathbf{x}$.
Consider the following complex compound $\left[\mathrm{Co}\left(\mathrm{NH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NH}_2\right)_3\right]_2\left(\mathrm{SO}_4\right)_3$ the primary valency of comple $x$ is $y$
The value of $x+y$ is
Q.2. Which of the following is the correct Hybridisation of $\mathrm{XeF}_4$ ?
$1\quad sp^3 d$
$2 \quad \mathrm{sp}^3$
$3 \quad s p^3 d^2$
$4 \quad s p^3 d^3$
Q.3. Which of the following is correct order of acidic character of oxides of vanadium?
$1 \quad \mathrm{~V}_2 \mathrm{O}_5>\mathrm{VO}_2>\mathrm{V}_2 \mathrm{O}_3$
$2 \quad \mathrm{~V}_2 \mathrm{O}_3>\mathrm{VO}_2>\mathrm{V}_2 \mathrm{O}_5$
$3 \quad \mathrm{~V}_2 \mathrm{O}_5>\mathrm{V}_2 \mathrm{O}_3>\mathrm{VO}_3$
$4 \quad \mathrm{VO}_2>\mathrm{V}_2 \mathrm{O}_3>\mathrm{V}_2 \mathrm{O}_5$
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Physics
Q 1. Given below are two statements. One is labelled as Assertion (A) and the other is labelled as reason (R).
Assertion (A) : Refractive index of glass is more than air.
Reason (R) : Optical density of a medium is directly related to its mass density.
In the light of the above statements, choose the correct answer from the options given below
1. (A) is false but (R) is true
2. (A) is true but (R) is false
3. Both $(A)$ and $(R)$ are true but $(R)$ is NOT the correct explanation of $(A)$
4. Both $(A)$ and $(R)$ are true and $(R)$ is the correct explanation of $(A)$
Q 2. The figure shows a circular portion of radius $R / 2$ removed from a disc of mass $m$ and radius $R$. The moment of inertia about an axis passing through the centre of mass the disc and perpendicular to the plane is
$\begin{aligned} 1) & \frac{13}{32} m R^2 \\ 2)& \frac{m R^2}{2} \\ 3) & \frac{m R^2}{4} \\ 4)& \frac{13}{64} m R^2\end{aligned}$
Q 3. Give below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) : A magnetic monopole does not exist.
Reason (R) : Magnetic lines are continuous and form closed loops.
In the light of the above statements, choose the correct answer from the options given below:
1. (A) is false but (R) is true
2. (A) is true but (R) is false
3. Both $(A)$ and $(R)$ are true but $(R)$ is NOT the correct explanation of $(A)$
4. Both $(A)$ and $(R)$ are true and $(R)$ is the correct explanation of $(A)$
Maths
Q 1. If $x|x-3|+3|x-2|+1=0$, then the number of real solution is
1) 2
2) 4
3) 1
4) 6
Q 2. $\operatorname{Re}\left(\frac{2 z+i}{z+i}\right)+\operatorname{Re}\left(\frac{2 \bar{z}-i}{\bar{z}-i}\right)=2$ is a circle of radius $r$ and centre $(a, b)$, then $\frac{15 a b}{r^2}$ is equal to
Q 3. If two vectors $\vec{a}$ and $\vec{b}$ satisfies $\frac{|\vec{a}+\vec{b}|+|\vec{a}-\vec{b}|}{|\vec{a}+\vec{b}|-|\vec{a}-\vec{b}|}=\sqrt{2}+1$, then the value of $\frac{|\vec{a}+\vec{b}|^2}{|\vec{a}-\vec{b}|^2}$ is equal to
$\begin{aligned} 1) & 1+\sqrt{2} \\ 2) & 2+4 \sqrt{2} \\ 3) & 1+2 \sqrt{2} \\ 4)& 3+2 \sqrt{2}\end{aligned}$
Q 4. Let $f(x)=\frac{x-5}{x^2-3 x+2}$, if range of $f(x)$ is $(-\infty, \alpha) \cup(\beta, \infty)$. Then $\alpha^2+\beta^2$ equals to?
JEE Main April 7 Shift 2 Question Paper with Solution |
JEE Main 2025 April 7 Shift 2 Answer Key & Solution PDF Download
The JEE Main 2025 April 7 All Shifts Question and answer key will be uploaded on the Careers360 website after the exam. With these, the candidates will have a clear idea of their performance and areas where they must improve. Referring to the JEE Main 2025 April 3 answer key and solutions is crucial for candidates to be able to accurately determine their performance by matching their answers with the correct ones. This helps in the identification of strengths and areas for improvement, allowing for specific study strategies.
JEE Main 2025 Previous Year Question Paper
Working through past years' question papers is a strategic method of exam preparation, with a number of important advantages. Going through these papers familiarizes students with the format and structure of future exams, including the mark distribution and question types that are usually set. This enables students to prepare for the layout of the exam and organize their study time accordingly. You can also refer to the following:
Frequently Asked Questions (FAQs)
Q: Is JEE Main held in various shifts?
A:
Yes, JEE Main is held in various shifts (usually two shifts a day) for a few days within the exam window.
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Have a question related to JEE Main ?
With your JEE Main CRL 476199 and OBC rank 173160, admission to Civil Engineering at Indira Gandhi Institute of Technology (IGIT), Sarang under JoSAA counseling is highly unlikely, since even civil branch closing ranks in IGIT usually remain within 50k–80k CRL (general) and much lower for OBC. However, you may try through state counseling (Odisha JEE) where cutoffs are sometimes more flexible, but chances are still very low. You should keep other private/state colleges as backup.
Hey! With a JEE Main rank of around 1 lakh, you still have a good chance to get admission in several engineering colleges that provide quality education at a reasonable fee. For government colleges, you can aim for NITs or GFTIs in branches like Civil, Mechanical, or Chemical Engineering, as these usually have slightly higher closing ranks. For example, colleges like NIT Goa, NIT Puducherry, and NIT Srinagar might have seats available in certain branches.
Apart from NITs, state government engineering colleges are also a good option, especially under home state quota. They often have lower tuition fees and good faculty, so you can get a solid education without spending much.
If you are open to private colleges, there are options like VIT Vellore, KIIT Bhubaneswar, or Amity University that provide decent infrastructure and placements. However, the fees may be higher than government colleges.
My advice is to focus on branches that are less competitive, check all counseling rounds, and make use of state quotas if applicable. With proper planning, a rank of 1 lakh can still help you get a good college and start your engineering career success
fully.
No, you can’t use a previous year’s JEE rank for the current year’s WBJEE counselling. Only the JEE Main rank of the same admission year is valid along with that year’s WBJEE rank.
Hello Aspirant,
Finding specific JEE exam centers for Whitefield is difficult as they vary each year. The list is released on the admit card . However, many centers are usually iON Digital Zones. For coaching, top centers near Whitefield include Aakash Institute , Narayana Institute , and Allen Career Institute . These centers have branches in and around the Whitefield area to help you prepare for the exam.
Its okay if you missed jee this year you can drop year for JEE to get into a government institute like IET Lucknow to get better placement here and fees is also less in comparison with SRMU but it also means delaying a year with no guarantee success.
Joining a private college like SRMU now avoids losing a year,but it comes with higher costs and generally lower placement statistics compared to top government institutions.
ultimately Your decision should be based on your skill whether you can significantly improve your JEE score versus accepting a faster, but potentially more expensive, path to your B.Tech.
Hope it helps..
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