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How To Calculate JEE Main Percentile - NTA will release the JEE Main 2025 score in the form of the JEE Main percentile. Hence, candidates need to be aware of how to calculate the JEE Main percentile. The NTA JEE Main percentile is the normalised score of candidates attempting the JEE Main exam. The percentile score can be calculated by multiplying the total number of candidates who scored lower or less than the candidate multiplied by 100. Candidates can know their percentile score through the JEE Mains exam result. National Testing Agency will announce the JEE Main 2025 result for the January session on February 12, 2025.
Also Check: JEE Main Rank Predictor 2025 | JEE Main College Predictor 2025
NTA is yet to announce the JEE Main 2026 registration schedule. Once the JEE Mains 2026 registration schedule is announced, candidates will know about the registration and application fee payment last date soon.
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Candidates can calculate the JEE Main percentile for the practice papers and the JEE main exam they have given. This will help them analyse their performance in the JEE Main 2025 exam. Candidates can then decide if they want to attempt the JEE Main April session to improve their performance
NTA JEE Main Percentile refers to the percentage of candidates that scored equal to or below a certain score in the JEE Main 2025 exam. Calculating the JEE Main 2025 percentile is called the JEE Main normalisation process. To calculate the JEE Main percentile, the authority converts the raw scores of the candidates into a percentage score(out of 100). This ensures that all candidates attempting the JEE Main exam have an equal score despite the varied difficulties of the multi-session papers.
The process of calculating the JEE Main 2025 percentile is mentioned below
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The calculation for the Raw scores, the subject-wise and the total NTA score in the JEE Main result are given below.
Raw Scores: Marks obtained in each session and subject (Maths, Physics, Chemistry) of the JEE Main exam calculated for all correct and incorrect answers, totalled up to obtain a total raw JEE Main 2025 score.
Percentile score | Calculation | |
---|---|---|
Total Percentile (T1P): | (100 x No. of candidates from the session with raw score equal to or less than T1 score) / Total No. of candidates appeared in the session | |
Mathematics Percentile (M1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than than M1 score in Mathematics) / Total No. of candidates appeared in the session | |
Physics Percentile (P1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates appeared in the session | |
Chemistry Percentile (C1P): | (100 x No. of candidates appeared from the session with raw score equal to or less than C1 score in Chemistry) / Total No. of candidates appeared in the session |
The expected JEE Main marks vs rank vs percentile is specified below.
Marks out of 300 | Rank | Percentile |
---|---|---|
288- 294 | 20-11 | 99.99826992- 99.99890732 |
280-284 | 44-22 | 99.99617561 - 99.99790569 |
270-279 | 107-63 | 99.99034797 - 99.99417236 |
252- 268 | 522-106 | 99.95228621- 99.99016586 |
231-249 | 1385-546 | 99.87388626-99.95028296 |
215-230 | 2798-1421 | 99.74522293-99.87060821 |
202-214 | 4666-2862 | 99.57503767- 99.73930423 |
190-200 | 6664- 4830 | 99.39319714- 99.56019541 |
175-189 | 10746-7151 | 99.02150308 - 99.3487614 |
161-174 | 16163-11018 | 98.52824811-98.99673561 |
149-159 | 21145-16495 | 98.07460288-98.49801724 |
132-148 | 32826-22238 | 97.0109678-97.97507774 |
120-131 | 43174-33636 | 96.0687115-96.93721175 |
110-119 | 54293-44115 | 95.05625037-95.983027 |
102-109 | 65758-55269 | 94.01228357-94.96737888 |
95-101 | 76260-66999 | 93.05600452 -93.89928202 |
89-94 | 87219-78111 | 92.05811248 -92.88745828 |
79-88 | 109329-90144 | 90.0448455 -91.79177119 |
62-87 | 169542-92303 | 84.56203931-91.59517945 |
41-61 | 326517-173239 | 70.26839007-84.22540213 |
1-42 | 1025009-334080 | 66.6590786-69.5797271 |
NTA will release the JEE Main 2025 score in the form of a percentile. Hence, knowing how to calculate the JEE Main NTA percentile will help candidates determine their performance in the exam. Candidates who are attempting the JEE Main 2025 January session can analyse their scores. This helps them to determine if they need to attempt the JEE Main April 2025 session.
Frequently Asked Questions (FAQs)
The JEE Main 2025 result for the session 1 exam will be released on february 12, 2025.
Candidates can find the formula for JEE Main Percentile calculation in the article above.
On Question asked by student community
Hello,
You cannot "renew" your September 2025 certificate. You must apply for a completely new EWS certificate after April 1, 2026.
EWS certificates are linked to a specific financial year.
Your certificate issued in September 2025 is valid for the financial year 2025-26. It is based on your family's income from the previous financial year (i.e., 2024-25).
The certificate required for JEE counselling in mid-2026 must be valid for the financial year 2026-27. This certificate must be based on your family's income from the financial year 2025-26 and must be issued on or after April 1, 2026.
Since they are based on two different income periods, they are considered completely different documents.
Hope it's helpful to you.
Hi! Don’t worry, you can correct your category this year while filling out the JEE Main 2025 application form. If you belong to BC/OBC category and have the valid caste certificate, you can apply under OBC NCL now. It will not be a problem if last year you had applied as General/EWS, since each year’s application is considered separately.
OBC NCL is for candidates from socially and educationally backward communities (non creamy layer) with income below 8 lakh, while EWS is for students from the general category (not SC/ST/OBC) with family income below 8 lakh. Since your family income is less than 2 lakh and you are BC, applying under OBC NCL is the right choice and will give you reservation benefits.
Hello,
To get below AIR 100 in JEE Advanced 2027, you need a strong and focused plan. Here’s a simple guide:
Clear Concepts : Make sure all NCERT basics are strong. Focus on Physics, Chemistry, and Maths concepts deeply.
Advanced Practice : Solve previous years’ JEE Advanced papers and high-level questions from books like HC Verma, I.E. Irodov, OP Tandon, and Cengage.
Regular Mock Tests : Take full-length tests every week. Analyse mistakes and improve weak areas.
Time Management : Learn to solve questions quickly and accurately. Work on speed and accuracy together.
Short Notes : Make notes/formulas for quick revision.
Consistency : Study daily and avoid long breaks. Consistent practice is key.
Focus on Weak Areas : Identify topics you struggle with and spend extra time on them.
Stress Management : Stay healthy, sleep well, and avoid last-minute panic.
If you follow a structured plan and stay consistent, AIR below 100 is achievable.
Hope it helps !
Helloaspirant,
The JEE Main 2026 syllabus, which is broken down into Physics, Chemistry, and Mathematics, is based on the NCERT curriculum for Classes 11 and 12. Calculus, Algebra, and Coordinate Geometry in Mathematics; Organic, Inorganic, and Physical Chemistry; and Mechanics, Thermodynamics, and Optics in Physics are important subjects.
To know the syllabus, you can visit our site through following link:
https://engineering.careers360.com/articles/jee-main-syllabus
Thank you
You will get last 10 years JEE Mains papers in hindi below
JEE MAIN 10 YEAR PAPER IN HINDI
Practising these papers will increase your confidence and you will be better prepared for the exam.
Good luck!!
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