How To Calculate JEE Main 2026 Percentile - The National Testing Agency has released the JEE Main 2026 score in the form of a percentile. Candidates can learn how to calculate the JEE Main 2026 percentile on this page. To calculate JEE Main percentile, use the formula: The total number of candidates who scored lower than or equal to a candidate is multiplied by 100 and divided appropriately. The percentile represents the normalised score of candidates appearing for the JEE Main exam. Applicants can use the JEE Main percentile calculators for both the practice papers and the actual exam.
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This will allow them to evaluate their performance in the JEE Main 2026 exam. Based on this analysis, candidates can then decide whether to attempt the JEE Main January session to enhance their scores.
NTA JEE Main Percentile refers to the percentage of candidates that scored equal to or below a certain score in the exam. Calculating the percentile is called the JEE Main normalisation process. To calculate the JEE Main percentile, the authority converts the raw scores of the candidates into a percentage score(out of 100). This ensures that all candidates attempting the JEE Main exam have an equal score despite the varied difficulties of the multi-session papers.
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The process of calculating the JEE Main 2026 percentile is mentioned below.
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The calculation for the Raw scores, the subject-wise and the total NTA score in the JEE Main result are given below.
Raw Scores: Marks obtained in each session and subject (Maths, Physics, Chemistry) of the JEE Main exam calculated for all correct and incorrect answers, totalled up to obtain a total raw JEE Main 2026 score.
| Percentile score | Calculation | |
|---|---|---|
Total Percentile (T1P): | (100 x No. of candidates from the session with raw score equal to or less than T1 score) / Total No. of candidates appeared in the session | |
Mathematics Percentile (M1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than than M1 score in Mathematics) / Total No. of candidates appeared in the session | |
Physics Percentile (P1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates appeared in the session | |
Chemistry Percentile (C1P): | (100 x No. of candidates appeared from the session with raw score equal to or less than C1 score in Chemistry) / Total No. of candidates appeared in the session | |
| Percentile | 2 Apr S1 | 2 Apr S2 | 4 Apr S1 | 4 Apr S2 | 5 Apr S1 | 5 Apr S2 | 6 Apr S1 | 6 Apr S2 | 8 Apr S2 |
|---|---|---|---|---|---|---|---|---|---|
99 | 176–180 | 181–185 | 186–190 | 191–195 | 171–175 | 166–170 | 151–155 | 161–165 | 156–160 |
98 | 156–160 | 161–165 | 166–170 | 171–175 | 151–155 | 146–150 | 131–135 | 141–145 | 136–140 |
95 | 121–125 | 126–130 | 131–135 | 136–140 | 116–120 | 111–115 | 96–100 | 106–110 | 101–105 |
90 | 86–90 | 91–95 | 96–100 | 101–105 | 81–85 | 76–80 | 61–65 | 71–75 | 66–70 |
The expected JEE Main marks vs rank vs percentile is specified below.
| Marks | JEE Main Percentile | JEE Main Rank |
|---|---|---|
300-299 | 100 - 99.99989 | 1 - 15 |
289-280 | 99.99908 - 99.99745 | 16 - 36 |
279-270 | 99.99417 - 99.99347 | 37 - 100 |
269-260 | 99.99016 - 99.98881 | 101 - 160 |
259-250 | 99.97720 - 99.96976 | 161 - 428 |
249-240 | 99.95028 - 99.94664 | 429 - 755 |
239-230 | 99.91595 - 99.93498 | 756 - 1,189 |
229-220 | 99.86623 - 99.90111 | 1,190 - 1,893 |
219-210 | 99.80777 - 99.85161 | 1,894 - 2,720 |
209-200 | 99.73129 - 99.79506 | 2,721 - 3,803 |
NTA releases the JEE Main 2026 score in the form of a percentile. Hence, knowing how to calculate the JEE Main NTA percentile will help candidates determine their performance in the exam. Candidates who are attempting the JEE Main 2026 January session can analyse their scores. This helps them to determine if they need to attempt the JEE Main April 2026 session.
Frequently Asked Questions (FAQs)
Candidates can find the formula for JEE Main Percentile calculation in the article above.
The JEE Main 2026 result for the session 2 exam will be declared on April 20, 2026.
The JEE Main 2026 percentile predictor works by comparing your calculated raw score from the answer key with past year's percentile trends and adjusting for difficulty levels to estimate your expected percentile and rank.
JEE Main marks 150 is equal to 98 percentile.
JEE Main 2026 cutoff will be release along with the exam result.
To calculate your JEE Main 2026 rank, use the formula: Rank = (100 - Percentile) × Total Candidates / 100, where the total number of candidates is based on how many appeared for the exam. This gives you an approximate rank based on your percentile
On Question asked by student community
Hello,
Based on your JEE Main Paper 2 percentile (96.3), CRL 2566, NATA percentile (88.69), and Class 12 score (88.8%), you have a good academic profile for B.Arch admissions.
Since COMEDK has its own merit preparation for B.Arch admissions, your exact rank cannot be predicted before the merit list is
Hello Student,
With your rank og 129537 as an OBC candidate, it is highly unlikely that you will get a seat in core branches. There is a possibility, though, that you might get a seat in lower-tier NITs or GFTIs, in branches such as Biotechnology , Mining, Metallurgy and Civil
Hello Dear Student,
Neither branch is universally "better"; it depends entirely on your interests.
Computer Science Engineering (CSE) focuses on software, coding, and algorithms, and generally yields higher immediate IT salaries. Electronics and Communication Engineering (ECE) focuses on hardware, microchips, and circuits, offering a dual-advantage of core hardware jobs +
Hey there,
With 94.95 percentile in JEE Main, Rajasthan home state, and REAP OBC-NCL merit rank 202, you have a very good chance of getting B.Tech CSE at MBM University, Jodhpur. While admission cannot be guaranteed until the official seat allotment is announced, your profile is competitive based on previous
Hello Dear Student,
You will not be able to secure a seat (CS or core branches) at the COEP Technological University with your current score. COEP is highly competitive, and closing ranks for the SC category normally range between \(\approx 10{,}000\) to (20,000), well below your (38,647) category rank.
Hope
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