42 Percentile in JEE Mains Means How Many Marks?- Candidates can check data about how many marks is 42 percentile in JEE Mains in this article. The National Testing Agency declares the JEE Mains result in the form of a percentile. Hence, 42 percentile in JEE Main 2026 means a range of 25-28 marks. The marks required for 42 percentile in JEE Main is based on the difficulty level of the shift and the performance of other candidates. Candiadtes can check their percentile in the JEE Main 2026 result. The authority uses a normalisation process for the JEE Main 2026 percentile calculation.
Also check: JEE Main Rank Predictor | JEE Main College Predictor
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Most of the JEE aspirants have a query about how many marks make 42 percentile. Experts at Careers360 have determined 42 percentile means how many marks in JEE Main 2026 based on previous year analysis. Read the article to know how many marks you will get with 42 percentile in JEE Mains.
Read more: What is percentile in JEE Mains?
The JEE Main marks vs percentile depends on several factors like difficulty level of the JEE Mains exam, the total number of appeared candidates and more. However, based on previous years’ trends, a 42 percentile will be 25-28 marks (out of 300).
181 - 190 | 99.597399 - 99.688579 |
171 - 180 | 99.456939 - 99.573193 |
161 - 170 | 99.272084 - 99.431214 |
151 - 160 | 99.028614 - 99.239737 |
141 - 150 | 98.732389 - 98.990296 |
131 - 140 | 98.317414 - 98.666935 |
121 - 130 | 97.811260 - 98.254132 |
111 - 120 | 97.142937 - 97.685672 |
101 - 110 | 96.204550 - 96.978272 |
91 - 100 | 94.998594 - 96.064850 |
81 - 90 | 93.471231 - 94.749479 |
71 - 80 | 91.072128 - 93.152971 |
61 - 70 | 87.512225 - 90.702200 |
51 - 60 | 82.016062 - 86.907944 |
41 - 50 | 73.287808 - 80.982153 |
31 - 40 | 58.151490 - 71.302052 |
21 - 30 | 37.694529 - 56.569310 |
20 - 11 | 13.495849 - 33.229128 |
0 - 10 | 0.8435177 - 9.6954066 |
It is important to note that these marks are approximations and can vary depending on the specific session of the JEE Mains. For example, if the exam is tougher in one year compared to another, a candidate might need to score slightly higher to achieve the same percentile.
Percentile refers to a candidate's relative performance compared to others. It shows the percentage of candidates who have scored below or equal to the candidate's score. As per JEE Main percentile vs rank, a percentile of 90 means the candidate has outperformed 90% of the total candidates. A percentile of 42 means the candidate has outperformed 42% of the total candidates.
The JEE Main percentile score is calculated using the formula:
Percentile = (Number of candidates with a score ≤ your score ÷ Total number of candidates in that session) × 100.
The NTA uses the above formula to calculate the percentile scores after the JEE Main results 2026. JEE percentile score is not the same as the percentage of marks. It is a normalized score used to compare candidates based on their performance. The NTA will use a JEE Main 2026 normalization process to account for the difference in difficulty across different shifts of the JEE Main exam. As a result, the marks corresponding to percentiles may vary across different sessions of the exam.
Candidates with 42 percentile will not be able to clear the qualifying JEE cut-off 2026 for admission into top engineering colleges in India. With this percentile, candidates can aim for a good private college only.
Frequently Asked Questions (FAQs)
The marks required for 42 percentile typically range between 25-28 marks, though this can vary each year.
No, a 42 percentile is generally not sufficient to get admission into top IIT colleges in India, as their cut-off percentiles are much higher.
If the exam is tougher, fewer candidates may score high marks, which can make the marks required for a particular percentile lower.
A 42 percentile does not guarantee admission to top colleges, but it might be enough for admission to some lesser-known colleges or specific programs.
On Question asked by student community
Hello aspirant,
If your syllabus is completed with theory , use the next 30 days only for smart revision . Make short notes and revise formulas daily for Physics , Chemistry and Maths . Solve previous year JEE Main questions topic-wise and then full mock tests every 3-4 days. Analyse mistakes properly and revise weak areas again . Avoid new topics and focus on accuracy , speed and confidence building during revision.
FOR REFERENCE : https://engineering.careers360.com/articles/jee-main-revision-strategy
Hope the details will help you.
THANK YOU
Preparing for the JEE Main in just 30 days is a challenging but achievable task if you follow a highly disciplined and strategic approach. According to the Careers360 30-day study plan , the key is to shift your focus from learning everything to mastering high-weightage topics and practicing rigorously.
During the first 15 days, prioritize topics that frequently appear in the exam.
Physics: Modern Physics, Heat & Thermodynamics, Optics, and Current Electricity.
Chemistry: GOC (General Organic Chemistry), Chemical Bonding, p-Block elements, and Solutions.
Maths: Matrices & Determinants, Sequences & Series, Coordinate Geometry, and Vector & 3D Geometry.
Study Strategy: Use NCERT for Chemistry and simplified notes for Physics/Maths. Spend 3-4 hours on each subject daily.
Short Notes: Go through the short notes you made during the first two weeks.
Flashcards: Use flashcards for inorganic chemistry reactions and physics formulas.
Mock Tests: Start giving one full-length mock test every alternate day. Analyze your mistakes immediately to avoid repeating them.
Previous Year Papers (PYQs): Solve the last 3-5 years of JEE Main papers in the actual exam time slot (9 AM–12 PM or 3 PM–6 PM) to sync your body clock.
No New Topics: Stop picking up new chapters. Focus solely on what you already know to build confidence.
Accuracy over Speed: Focus on getting the questions right rather than attempting all of them, as negative marking can significantly lower your percentile.
You can download the comprehensive day-by-day schedule, which includes specific topics to cover each morning and evening, by visiting the link : https://engineering.careers360.com/download/ebooks/jee-main-study-plan-30-days
Hello
I think your question sounds like this: "Can a candidate who passed Class 12 in 2025 and filled JEE Main Session 1 apply for Session 2 as 'Appearing' in 2026 as a fresh board candidate, and will both sessions have the same details? "
So yes, you can fill the JEE Main Session 2 as "Appearing". The information filled in Session 1 will remain exactly as it was and will not change.
Session 1 and Session 2 are treated as separate applications. There is no issue if the qualifying status is different in both sessions. During counselling, the board marks that meet the 75 rule will be considered.
Hello,
If you filled the JEE Main January form with Class 12 passed in 2025 and are planning to appear again for the Class 12 exam through HOS, there is usually no serious issue. You were eligible to apply since you had already passed Class 12. Reappearing through HOS for improvement or requalification is allowed, provided HOS is a recognized board. During counselling, your latest valid Class 12 result will be considered. Make sure you meet the 75% marks or top 20 percentile requirement where applicable. If a correction window opens, update details if needed.
Hope this has solved your query. Thank You.
Good Evening,
Yes, you are eligible for both JEE Mains and Advanced, as you completed your 12th with physics, chemistry and biology. Moreover, you passed mathematics in 2025, which makes you fit the eligibility criteria of both exams.
Aspirant, I would like to inform you that Careers360 recently launched a free mock test series for JEE students. The last date of registration is 8th January, 2026. Enroll and solve chapter wise question papers and improve you concept and assess your learning. The link to the mock test series is attached herewith. https://learn.careers360.com/test-series-jee-main-free-mock-test/
Best regards.
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