जेईई मेन 2025 सिलेबस वेटेज (JEE Main 2025 Syllabus wise Weightage in hindi) - फिजिक्स, केमिस्ट्री, मैथ्स

Hello there,

Yes, Thapar Institute of Engineering and Technology (TIET) accepts students from the National Institute of Open Schooling (NIOS) for admission to its B.Tech Computer Science and Engineering (CSE) program, provided they meet the eligibility criteria.

Eligibility Criteria for B.Tech CSE at TIET:

• Educational Qualification : Completion of 10+2 or equivalent examination with at least 60% aggregate marks (55% for SC/ST candidates) in Physics, Mathematics, and any one of the following subjects: Chemistry, Biology, Biotechnology, or a Technical Vocational subject.
  
  

• Entrance Exam : A valid score in JEE Main 2024 is required for admission to B.Tech CSE at TIET.
  
  

• Age Limit : Candidates must be born on or after 1st October 2000 .
  
  Admission Process for B.Tech CSE without JEE Main:

While JEE Main is the primary entrance exam for B.Tech admissions at TIET, there is an alternative pathway:

• Mode-2 Admission : For candidates who have not appeared in JEE Main, admission is based on the merit of marks secured in 10+2 or equivalent examination in the aggregate of three subjects: Physics, Mathematics, and any one subject out of Chemistry, Biology, Biotechnology, or a Technical Vocational subject.
  
  

• Eligibility for Mode-2 : Candidates must have passed 10+2 or equivalent examination with at least 70% marks (65% for SC/ST candidates) in the aggregate of the specified subjects.

I hope this answer helps you. If you have more queries, then feel free to share your questions with us, we will be happy to assist you.

Thank you, and I wish you all the best in your bright future.

Hello there,

Yes, TIET (Thapar Institute of Engineering and Technology) accepts NIOS (National Institute of Open Schooling) students for B.Tech CSE as long as the student meets the eligibility criteria.

Admission Process for B.Tech CSE at TIET without JEE Main:

1. Eligibility Criteria :

   • Educational Qualification : You must have completed your 12th or equivalent with a minimum of 60% aggregate in Physics, Chemistry, and Mathematics (for CSE) from a recognized board, including NIOS.
     
     

   • Age Limit : Candidates must be born on or after 1st October 2000 .
     
     

2. Admission Without JEE Main :

   • TIET provides admission to B.Tech courses based on Thapar University’s Entrance Exam (THAPAR Entrance Test) or Direct Admission (based on merit).
     
     

   • For Direct Admission (without JEE Main), students with good academic performance (generally 80% and above) in 12th grade may be eligible. However, this depends on the cutoff for the specific year.
     
     

3. Application Process :

   • Visit the official TIET website and fill out the online application form.
     
     

   • You may have to appear for the Thapar University Entrance Exam (if applicable) . For direct admission, the process is based on merit or marks obtained in 12th.
     
     

4. Important Dates : Keep track of the application dates and exam schedules on the official TIET website.
   
   

5. Admission Fee : After clearing the entrance exam or merit list, the next step will be counseling and document verification , where you'll submit your 12th-grade marks and other relevant documents.
   
   

If you don’t wish to take JEE, direct admission (based on merit) is an option, but it depends on your academic performance and availability of seats.

I hope this answer helps you. If you have more queries, then feel free to share your questions with us, we will be happy to assist you.

Thank you, and I wish you all the best in your bright future.

Hello there,

With a 74.82 percentile in JEE Main , getting CS , IT , or AI in top Mumbai colleges might be challenging. However, here are some options:

1. University of Mumbai Colleges :

• VJTI : Highly competitive for top branches, but possible for others.

• SVKM NMIMS (private): May accept JEE Main scores.

• DJ Sanghvi : Competitive for CS/IT, but possible for other branches.
  
  2. Private Colleges :

• L&T Institute of Technology and KJ Somaiya : They accept JEE Main scores but competition is high.
  
  3. Other Considerations :

• MHT CET : As you're from Maharashtra, applying for MHT CET can improve your chances in top colleges.
  
  

• Management Quota : Some private colleges may have lower entry requirements through this route.

You may also consider related branches like Electronics to increase your chances.

I would recommend you to use JEE Mains College Predictor Tool by Careers360 to get the list of possible colleges you can get with your rank or percentile.

I hope this answer helps you. If you have more queries, then feel free to share your questions with us, we will be happy to assist you.

Thank you, and I wish you all the best in your bright future.

Hello there,

With a 94 percentile in JEE Mains, you have several options:

1. NITs : You may get branches like Mechanical, Civil, or Electrical in lower-ranked NITs, especially under the Home State Quota .
   
   

2. IIITs : You could secure a seat in newer IIITs like IIIT Pune or IIIT Vadodara .
   
   

3. State Government Colleges : Apply through state counseling for good chances, especially in non-circuit branches .
   
   

4. Private Colleges : Institutions like VIT , SRM , and Manipal may offer opportunities based on your JEE score.
   
   Suggestion: Participate in JoSAA counseling and explore state and private universities for better chances of admission. Focus on branches like Mechanical , Civil , and Electrical .
   
   
   

   I hope this answer helps you. If you have more queries, then feel free to share your questions with us, we will be happy to assist you.

   Thank you, and I wish you all the best in your bright future.

   
   
   
   
   

Hello there,

With an 82.63 percentile in JEE Mains 2025 under the OBC-NCL category, you are not eligible to appear for JEE Advanced 2025 .

Eligibility Criteria for JEE Advanced 2025

To qualify for JEE Advanced, candidates must be among the top 2,50,000 performers in JEE Mains. The distribution is as follows:

• OBC-NCL : 27% of 2,50,000 = 67,500 candidates

Your percentile of 82.63 suggests that your rank is beyond the cutoff for the OBC-NCL category. Therefore, you are not among the top 67,500 candidates in your category and thus do not qualify for JEE Advanced.

Next Steps

• Focus on NITs and IIITs : With your percentile, you can aim for admission to NITs and IIITs through JoSAA counseling .
  
  

• Consider State Engineering Colleges : Explore admission opportunities in state government engineering colleges .
  
  

• Explore Private Universities : Institutions like VIT Vellore , SRM Chennai , and Manipal University may also be viable options.

I hope this answer helps you. If you have more queries, then feel free to share your questions with us, we will be happy to assist you.

Thank you, and I wish you all the best in your bright future.