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The sample Physics paper has been created for JEE Main 2026, following the NTA pattern, to help students become familiar with the types of questions they will encounter on exam day. The sample consists of several types of questions that present students with both questions about Concepts, Application of Formulas, and Applications of real-life experiences as they will encounter them on exam day, while also providing questions to check core knowledge as well as the ability to think quickly.
99.93 percentile in JEE Main 2026 means an All India Rank (AIR) between about 800 and 1,200, as per the last year’s trends.
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We will provide a complete JEE Main 2026 physics sample paper with an answer key so that students can check their preparation and know the areas of improvement. This will help you to do the proper practice. With regular practice of such papers, students can boost confidence and accuracy for the final exam.
The JEE Main 2026 Physics Sample Paper with Answer Key is created to help students solve real exam-level questions and strengthen their concepts. We are also sharing the link so you can access and solve them easily.
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JEE Main 2026 Sample Papers | |
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JEE Main 2026 Physics Sample Paper |
For More Sample papers, students can go through this Careers360 Free product, in which you can find many mock tests, sample papers, chapter-wise tests, subject-wise tests and study material, JEE Main Free Study Material.
We have given some questions from the Physics sample paper for reference. Here you can check the JEE Main 2026 Physics sample paper with answer key:
Question 1: In a Young's double slit experiment, the source is white light. One of the slits is covered by a red filter and another by a green filter. In this case
1. There shall be an interference pattern for red distinct from that for green.
2. There shall be no interference fringes.
3. There shall be alternate interference fringes of red and green.
4. There shall be an interference pattern, where each fringe's pattern centre is green, and the outer edges are red.
Solution: The Frequency of Green and the frequency of Red will be different. No interference pattern is observed for two lights of different frequencies, as the phase difference does not remain constant.
Hence, the answer is option (2).
Question 2: A convex lens of focal length 30 cm is placed in contact with a concave lens of focal length 20 cm. An object is placed at 20 cm to the left of this lens system. The distance of the image from the lens in cm is _____
30
45
$\frac{60}{7}$
15
Solution: Equivalent focal length
$
\begin{aligned}
& \frac{1}{\mathrm{f}}=\frac{1}{\mathrm{f}_1}+\frac{1}{\mathrm{f}_2} \\
& =\frac{1}{30}+\frac{1}{-20}=\frac{2-3}{60}=-\frac{1}{60} \\
& \mathrm{f}=-60 \mathrm{~cm}
\end{aligned}
$
Lens formula
$
\begin{aligned}
& \frac{1}{v}-\frac{1}{u}=\frac{1}{f} \\
& \frac{1}{v}-\frac{1}{-20}=\frac{1}{-60} \\
& v=-15 \mathrm{~cm}
\end{aligned}
$
Hence, the answer is option (4).
Question 3: For a nucleus of mass number A and radius R , the mass density of nucleus can be represented as
1.$A^3$
2.$\mathrm{A}^{\frac{1}{3}}$
3. $\mathrm{A}^{\frac{2}{3}}$
4. Independent of A
Solution: $\begin{aligned} & R=R_0 A^{1 / 3} \\ & \text { Density }=\frac{\text { Mass }}{\text { Volume }}=\frac{mA}{\frac{4}{3} \pi R_0^3 A}=\text { constant }\end{aligned}$
Hence, the answer is option (4).
Question 4: A plane electromagnetic wave propagates along the $+x$ direction in free space. The components of the electric field, $\vec{E}$ and magnetic field, $\vec{B}$ vectors associated with the wave in Cartesian frame are :
1.$\mathrm{E}_y, \mathrm{~B}_{\mathrm{x}}$
2.$\mathrm{E}_{\mathrm{y}}, \mathrm{B}_{\mathrm{z}}$
3.$E_x, B_y$
4.$\mathrm{E}_z, \mathrm{~B}_y$
Solution:

Direction of propagation$
=\overrightarrow{\mathrm{E}} \times \overrightarrow{\mathrm{B}}
$
$E \rightarrow y, B \rightarrow z, c \rightarrow x$
$\hat{\mathrm{E}} \times \hat{\mathrm{B}}=\hat{\mathrm{j}} \times \hat{\mathrm{k}}=\hat{\mathrm{i}}=\hat{\mathrm{c}}$
Hence, the answer is option (2).
Question 5: Two balls with the same mass and initial velocity are projected at different angles in such a way that the maximum height reached by the first ball is 8 times higher than that of the second ball. $T_1$ and $T_2$ are the total flying times of first and second ball, respectively, then the ratio of $T_1$ and $T_2$ is :
1.$2 \sqrt{2}: 1$
2.$2: 1$
3.$\sqrt{2}: 1$
4.$4: 1$
Solution: Given, $\left(\mathrm{H}_{\max }\right)_1=8 \times\left(\mathrm{H}_{\max }\right)_2$
$
\begin{aligned}
& \frac{\mathrm{u}^2 \sin ^2 \theta_1}{2 \mathrm{~g}}=8 \times \frac{\mathrm{u}^2 \sin ^2 \theta_2}{2 \mathrm{~g}} \\
& \Rightarrow \sin \theta_1=2 \sqrt{2} \sin \theta_2 \\
& \frac{\mathrm{~T}_1}{\mathrm{~T}_2}=\frac{2 \mathrm{u} \sin \theta_1 / \mathrm{g}}{2 \mathrm{u} \sin \theta_2 / \mathrm{g}}=\frac{\sin \theta_1}{\sin \theta_2}=2 \sqrt{2}
\end{aligned}
$
Hence, the answer is option (1).
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By practising with JEE Mains Physics Sample Paper with Solutions 2026 at timed intervals, you learn how to solve questions quickly. When you practice with sample papers, you also become aware of the variety of shortcuts, formulas, and question styles you will encounter in the actual test. The knowledge and skills acquired through practice with sample papers will translate to increased accuracy and overall higher test scores in the real exam.
JEE Mains Physics Sample Paper with Solutions 2026 includes experience-based questions that require you to get an understanding of the concepts rather than just memorising what you have been taught. By performing the sample paper questions, you will learn how to connect different chapters of the study material together. As you begin to connect your conceptual understanding across the entire course material for and from both numerical and theoretical problems, your conceptual development becomes stronger.
You will better understand how much time you can save using multiple-choice questions and calculations. By practising on sample papers, you will develop a skill for skipping difficult calculations and focusing on the easier computations. The ability to do this will alleviate anxiety and improve your efficiency during the test.
When you practice under conditions similar to an actual exam, you feel more comfortable and confident on the actual day of your exam. Seeing your improvement from taking the same sample papers multiple times will help instil confidence and reduce anxiety on test day. You will feel relaxed because you will be sure that you have prepared well and will feel confident when taking the actual test.
Practicing sample papers will help you identify the areas in which you repeatedly make mistakes. Knowing these areas will let you get ready for the exam more efficiently.
Let us understand the marking Scheme of the JEE Main 2026 physics sample paper with answers. The JEE Main 2026 exam marking Scheme helps students understand the structure and types of questions asked in the exam. Check it below:
|
Subject |
Total Marks Per Subject |
Total No. of Questions |
|
Physics |
100 |
20MCQs+ 5NAT |
|
Chemistry |
100 |
20MCQs+ 5NAT |
|
Maths |
100 |
20MCQs+ 5NAT |
|
Total |
300 |
60 MCQs +15 NAT = 75 |
Frequently Asked Questions (FAQs)
After finishing the Physics syllabus once, begin working on sample papers. For better progress, keep writing one paper every two to three days.
Before the test, try to finish 15–20 full papers. This gives enough practice and builds confidence for all types of questions.
When you solve sample papers, it helps you to be familiar with the exam pattern, question difficulty, and time management. It enhances the accuracy and gives you a way to study multiple problem types similar to actual JEE papers.
On Question asked by student community
A score of 110 in JEE Mains is expected to be equal to 94 to 95th percentile. This score may not secure your admission in top NIT institutes for the general category, but candidates from OBC, SC, ST, and EWS categories have a good chance of getting into NITs and
Here are the best engineering colleges for 35,000-50,000 rank in JEE Main 2026 examination -
No, JEE Main Answer Key for 2026 session 1 is not out yet. NTA will release the JEE answer key 2026 on February 4.
With 100 marks in JEE Main exam, you can apply for several IIITs depending upon the branch of the course. Candidates with 100 marks in JEE Main are likely to secure seat in IIITs like IIIT Manipur , IIIT Nagpur, IIIT Dharwad, IIIT Sri City , IIIT Trichy and other
With 77 marks in JEE Main, you can expect engineering colleges like NIT Mizoram, NIT Meghalaya , and NIT Arunachal Pradesh. Consider private colleges like GITAM, Lovely Professional University, SRM Institute of Science and Technology , Chandigarh University, and Amity University for better branch options.
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