MHT CET 2026 May 14 Question Paper and Answer Key with Solutions PDF

Download MHT CET 2026 May 14 Question Paper with Solutions PDF

The MHT CET 2026 May 14 question paper PDF for both shifts has been uploaded below. Students can go through each question, match it with the solutions, and calculate their expected scores. The download links given in the table below are now active.

MHT CET 2026 May 14 Question Paper

The memory-based questions from the MHT CET 2026 May 14 Shift 1 and Shift 2 papers are provided below. These papers have been prepared using student feedback collected immediately after the exam. Students can use the question papers and solutions to review the types of questions asked, understand important topics, and analyse the overall exam pattern.

MHT CET May 14 Shift 1 Questions

Question 1: If $|a+b|=|a-b|$, then the angle between $a$ and $b$ is:

1. $0^{\circ}$

2. 45

3. $90^{\circ}$

4. 180

Question 2: $M$ is the foot of drawn from $A(4,3,2)$ on line joining the point $\mathrm{B}(2,4,1)$ and $\mathrm{C}(4,5,3)$.

The co-ordinate of M are

Question 3: $\triangle \mathrm{ABC}$, with usual notation, the value of $\csc \left(\frac{\mathrm{A}}{2}\right) \csc \left(\frac{\mathrm{B}}{2}\right) \csc \left(\frac{\mathrm{C}}{2}\right)$ is

Question 4: Approximate value of $\sin ^{-1}(0.51)$ is [Given

$\left.\pi=3.1416, \frac{2}{\sqrt{3}}=1.15\right]$

Question 5: $\int_0^1 \tan ^{-1}\left[\frac{1}{1-x+x^2}\right] d x=2 k$. Then value of $k$ i

MHT CET 2026 May 14 Answer Key

The MHT CET 2026 answer key has been provided on this page. Students can use the unofficial memory-based answer key to match their responses and estimate their expected scores. The official MHT CET 2026 answer key will be released later by the Maharashtra State CET Cell on the official website after all exam shifts are completed.

How to Calculate MHT CET 2026 Score using Answer Key

After you have access to the answer key, here’s how you can calculate your MHT CET 2026 score using the answer key.

• Step 1: Download the Answer key: Download the answer key provided on our page.

• Step 2: Follow the marking scheme: you must know about the marking scheme before you start calculating your score.

  • Correct answer: As per the marking scheme, +1 for physics and chemistry, and +2 marks will be awarded for Maths.

  • Incorrect answer: 0 marks will be deducted for a wrong answer, as there is no negative marking in the MHT CET exam.

  • Unattempted answer: 0 marks will be given for an unattempted answer.

• Step 3: Count and Compute: Verify your answers with the answer key on this page and record correct and incorrect answers. Apply the marking scheme and then use the following formula to calculate your total score:

• Total Score = (No. of correct answers (mathematics) * 2) + (No. of correct answers (physics and chemistry) * 1)

MHT CET 2026 May 14 Paper Analysis

The detailed MHT CET 2026 May 14 paper analysis for both shifts is provided below. The analysis includes the overall difficulty level of the paper along with subject-wise difficulty for Mathematics, Physics, and Chemistry based on student feedback and expert reviews.

MHT CET 14 May Shift 1 Question Paper

The MHT CET 14 May shift 1 question paper analysis is updated below.

MHT CET 14 May Shift 2 Question Paper

The MHT CET 14 May Shift 2 question paper analysis will be updated here.

MHT CET 2026 PCM 14 May Exam Overview

Here is a quick look at all the important details of the exam pattern for the 14 May MHT CET question paper exam:

MHT CET Previous Year Question Paper

Students can refer to the MHT CET previous year question papers given below to understand the exam pattern, important chapters, question trends, and difficulty level of the exam.

MHT CET 2026 Marks vs Percentile (Expected)

After the exam is over, the first question that comes to the student’s mind is what percentile they might get with their estimated score. If you also have the same question in your mind, then the Marks vs. Percentile table is here for you. The data provided in the table is approximate and is based on the previous year’s trends. So these figures might vary depending on the difficulty level of the exam and the number of students appearing for the exam this year.