How to calculate JEE Main 2019 rank based on NTA Percentile score?
Prabha Dhavala, 20 Jan 2019, #JEE Main
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How to calculate JEE Main 2019 rank based on NTA Percentile score? Now that the JEE Main 2019 result for January session is declared, the big question in the mind of every JEE Main aspirant is - How to calculate JEE Main 2019 rank based on NTA Percentile score? The fact is that NTA score released is the percentile score for the January session of JEE Main. The JEE Main 2019 ranks will be declared based on the percentile scores of the students in both the sessions with the better of the two scores used in case the candidate has appeared for both January and April sessions. So, why would students ask about JEE Main 2019 rank based on NTA percentile score? Well the reasons are many and varied like not appearing for JEE Main April or to judge whether a better score would fetch a seat. Check out how to calculate the JEE Main 2019 rank using the NTA percentile score below in this article.

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NTA has announced that normalization will be session wise so the percentile score you got would be relative to the others in your session. This score denotes the percentage of candidates who have scored equal to or below (same or lower raw scores) that particular Percentile in that examination. So the 15 toppers are students who have all got the highest scores of 100 percentile after normalization in their respective sessions. The marks obtained in between the highest and lowest scores have also been converted to appropriate Percentiles.

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Note: It may be noted that the formula given is indicative in nature and should not be taken as accurate as the actual ranks will vary on account of many factors.

How to calculate my JEE Main 2019 rank based on my NTA Percentile score?

Let’s take this for the January session of JEE Main 2019 first. As per the NTA declared result statistics, 8,74,469 students appeared for the exam across four days with two sessions each making that a total of eight sessions. There are 15 students who have scored 100 percentile in these sessions.

To calculate the JEE Main 2019 rank, you first need to know the percentage of people ahead of you with higher percentile scores. To calculate that, the formula would be 100 which is the highest score minus your percentile score.

Since the percentile is calculated from a scale ranging from 100 to 0 for each session of examinees, the formula applies the total number of students in the January session which is 874469 /100 multiplied by the percentage of people who are ahead of you to arrive at the rank.

Therefore, the formula to calculate the JEE Main 2019 rank for January 2019 is

JEE Main 2019 rank (probable) = (100- NTA percentile score ) X 874469 /100

If NTA percentile score is 90.70, JEE Main rank will be (100-90.70 ) X 874469/100 = 81325

Consider the NTA score of 80.60 then JEE Main 2019 rank = (100-80.60) X 874469 /100. The rank will be 169646.

** This formula would not be for a 100 percentile score as those are the top ranks.

To use the JEE Main 2019 Rank Predictor tool, click here

How to decide whether to go for JEE Main 2019 April?

You could take a probable calculation and see where you stand. This means that you take a hypothetical number of the candidates who will appear in April. If you go by past trends, the figures are somewhat between 11 lakhs to 12 lakhs. Using this as a basis, use the NTA score and see which JEE Main rank you will get.

Why the January NTA score? The reason is that the better of the two scores will be used. So if you perform badly in April, the January NTA score still holds good and if you perform better, then the rank will only be better.

So what will be the April JEE Main 2019 rank with the NTA Percentile Score of January?

Using the same formula,

If NTA percentile score is 90.70, JEE Main rank will be (100-90.70) X 1200000/100 = 1,11,600

In this case you have a good chance of qualifying for JEE Advanced (as 2,24,000 students qualify for it) and can check the JEE Main cutoff from previous years to understand which institute you can apply for admissions.

Consider the NTA score of 80.60 then JEE Main 2019 rank = (100-80.60) X 1200000 /100. The rank will be 2,32,800 which means may not have a chance of qualifying for JEE Advanced.

What is the minimum NTA percentile that may stand a chance to qualify for JEE Advanced?

As per experts from various leading coaching centres, an NTA percentile score of 85 will stand a chance at JEE Advanced but this is still not clear. Until April 30, there is also no hard fast means to know the minimum cutoff to qualify for JEE Advanced 2019.

It is a fact that IITs are dream institutions for most engineering aspirants. So a student who has done exceptionally well in January may be wishing to skip the JEE Main 2019 April session to concentrate on JEE Advanced 2019 preparation. Another student may have scored well enough and feels that another session is too strenuous so may wish to skip it if only he/she has a fair chance of a seat in one good NIT or IIIT. Others may wish to know if they have the chance for any admissions on the basis of their January JEE Main 2019 percentile scores or should they appear for the April exam to better this?

We hope that the decision to write or skip can be made a bit easier using the calculation methods mentioned in this article.

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