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How to calculate JEE Main 2025 rank based on Percentile score? - Many candidates wish to know how to calculate their JEE Main 2025 rank based on the percentile score. This helps them predict their rank before the release of the JEE 2025 result. As we know, NTA has released the JEE Main score in the form of percentile. JEE Main rank is based on the percentile score of both sessions of NTA JEE Mains. So, why would students ask about JEE Main 2025 rank based on the NTA percentile score? Well, the reasons are many and varied like not appearing for JEE Main April session or judging whether a better score would fetch a seat. Check out how to calculate the JEE Main 2025 rank using the percentile score below in this article.
Also Check: JEE Main marks vs percentile table
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NTA will conduct the JEE Main normalisation process session-wise so the percentile score you got would be relative to the others in your session. This score denotes the percentage of candidates who have scored equal to or below (same or lower raw scores) that particular Percentile in that examination. So the 9 toppers are students who have got 100 NTA Scores and have got the highest scores which is 100 percentile after normalisation in their respective sessions. The marks obtained in between the highest and lowest scores will also been converted to appropriate Percentiles.
Note: It may be noted that the formula given for the calculation of percentile in JEE Main is indicative and should not be taken as accurate as the actual ranks will vary on account of many factors. For the actual rank, candiadtes should check the alloted rank on the JEE Main 2025 scorecard.
JEE Main 2025 exam dates will be announced on the official website. Candiadtes can follow the previous year statistics to get an idea of how to calculate the JEE Main rank from the percentile. Below is the process of calculating rank from percentile with last year's example.
As per the previous year NTAJEE Main statistics, 823967 students appeared for JEE Main in the January session. NTA announced that 20 students have scored 100 percentile in the previous year sessions and has declared them as JEE Main Toppers.
To calculate the JEE Main rank, you first need to know the percentage of candidates with higher percentile scores than you. To calculate that, the formula would be 100 (highest score) - your percentile score.
Since the percentile is calculated from 100 to 0 for each session of examinees, the formula applies the total number of students in the January session which is 8,22,000 /100 * percentage of people ahead of you to arrive at the rank.
Therefore, the formula to calculate the JEE Main rank through percentile for January is
JEE Main rank (probable) = (100- NTA percentile score ) X 823967 /100
If the NTA percentile score is 90.70, JEE Main rank will be (100-90.70 ) X 823967/100 = 76628
Consider the NTA score of 80.60 then JEE Main 2023 rank = (100-80.60) X 823967 /100. The rank will be 159849
** This formula would not be for a 100 percentile score as those are the top ranks.
Candidates can also use the JEE Main Rank Predictor to check their rank.
Candidates can take a probable calculation of percentile in JEE Main January 2025 session and check the rank. Based on your performance in the JEE Main January session, you can decide if you want to attempt the April session or not.
According to the previous year statistics, the total number of candidates that appeared for the JEE Main April session are 10,67,959. Using this as a basis, use the NTA score and see what is the JEE Main rank.
Why the January NTA score? The reason is that the authority will consider the better of the two session's scores. So if you perform badly in April, the January NTA score will be counted and if you perform better, then the rank will only be better.
So what will be the April JEE Main rank from the NTA Percentile Score of January?
Using the same formula,
If the NTA percentile score is 90.70, JEE Main rank will be (100-90.70) X 10,67,959/100 = 99320
In this case, you have a good chance of qualifying for JEE Advanced (as 2,50,000 students qualify for it) and can check the JEE Main cutoff from previous years to understand which institute you can apply for admissions.
Consider the NTA score of 80.60 then JEE Main rank = (100-80.60) X 10,67,959 /100. The rank will be 207184 which means may not have a chance of qualifying for JEE Advanced.
The NTA percentile score of 89.7548849 will stand a chance at JEE Advanced if one takes a look at the JEE Main cutoff from last year.
It is a fact that IITs are dream institutions for most engineering aspirants. So a student who has done exceptionally well in January session of JEE Main may wish to skip the JEE Main April session to concentrate on JEE Advanced preparation. Another student may have scored well enough and feels that another session is too strenuous so may wish to skip it if only he/she has a fair chance of a seat in one good NIT or IIIT. Others may wish to know if they have the chance for any admissions based on their January JEE Main percentile scores or if should they appear for the April exam to better this.
We hope that the decision to write or skip can be made a bit easier using the calculation methods mentioned in this article.
JEE Main 2025 normalisation process is done by the authority to ensure all candidates scores are at an equal level regardless of the difficulty level of the session.
Application Date:03 September,2024 - 31 December,2024
Application Date:16 September,2024 - 04 December,2024
Hello,
Here’s a step-by-step guide to help resolve this issue:
Contact School Authorities : Reach out to your school immediately. Explain the discrepancy in your name between your Aadhaar card and board registration. Schools usually have a process to handle name corrections.
Submit Correction Application : Schools may ask for a written application, so provide one along with proof of your correct name (e.g., Aadhaar card). Request that they initiate the correction in your board records.
Check with Board Office : If needed, contact your state or central board’s regional office directly to understand the procedure and required documents for name corrections.
Update JEE Application : Once the name is corrected in the board records, you may need to update your JEE registration. Check with the National Testing Agency (NTA) helpline on how to proceed.
Stay Calm and Follow Up : Keeping calm and staying proactive with regular follow-ups is essential. This is a common issue, and boards have processes to handle it.
For more details about JEE MAINS registration, visit : https://engineering.careers360.com/articles/how-to-fill-jee-main-application-form
Hope it helps !
Hello,
In case you have no surname mentioned on your Class 10th marksheet but every other document has it, make sure the name is correctly uniform everywhere and also while appearing for exams like JEE Mains. Here is how you can do:
This will see you well through to JEE Mains and any further admission processes.
Yes, you will be eligible for JEE Main and JEE Advanced in 2025 and 2026.
JEE Main allows candidates to attempt the exam in three consecutive years following their Class 12th examination. Since you are reappearing for the Class 12th board in 2024-25 due to medical reasons, your eligibility will start from 2025. This means you can take JEE Main in 2025, 2026, and 2027.
For JEE Advanced, candidates can appear in the exam twice in consecutive years, beginning the year they complete their Class 12th. Since your Class 12th completion year will be 2025, you can take JEE Advanced in 2025 and 2026.
Your gap year, caused by health challenges, does not affect your eligibility. The examination authorities recognize that candidates might face unforeseen circumstances and determine eligibility based on the year of completion of Class 12th, not initial enrollment. Just ensure you meet the other basic requirements, such as minimum marks in the required subjects, when applying.
Focus on your preparation and health, and when you're ready, you’ll have the opportunity to pursue JEE with full eligibility.
Hello,
If a candidate uses a certificate issued through EWS on false grounds for entrance into JEE Mains or college admissions, things can go quite serious at the time of discovery. Here's what might follow:
Cancellation of Admission: If the false certificate issued is detected in the course of verification or later when the course has started running, the candidate's admission may be cancelled immediately.
Legal Action: In this activity, he shall be fraud when he use a false certificate. His punishment will be done via fines or further action against him, as per state-institutional rules on committing such an offense.
Candidate may get disqualified for such competitive exams in the near future because of this action that directly affects the field of education and career.
This leaves the candidate with a great loss in reputation, where they may not be in a position to continue with their studies or seek employment.
Use valid and genuine documents to avoid these risks.
Hello Pritam
It seems difficult for you to get NIT seat in west Bengal with 64 marks in jee mains 2025.
If you are from general category, you must get 95+ percentile in jee mains . You should be in top the top 20 percentile.
Also you must get minimum 75 % marks in class xii. You must have passed class xii with physics, chemistry and mathematics as main subjects .
For sc/ st , minimum marks in class xii should be 65% .
Cut off changes every year and it depends upon certain factors such as number of candidates appeared in exam, previous year's cut off, number of seats available etc.
For college prediction you may visit the link given below
https://engineering.careers360.com/jee-main-college-predictor
For previous year's cut off you must follow the below given link
https://engineering.careers360.com/articles/jee-main-cutoff-for-top-nits
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