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3 Questions around this concept.
Image seen by a person using lens as simple microscope will be -
Magnifying power: It is defined as the ratio between the dimensions of the image and the object.
Magnifying power of an optical instrument is given by,
$
m=\frac{\text { Visual angle with instrument }(\beta)}{\text { Visual angle when object is placed at least distance of distinct vision }(\alpha)}
$
Simple Microscope
Case 1: Magnification's, when the final image is formed at $D$ and $\infty$.
$
\begin{aligned}
& \text { (i.e. } m_D \text { and } m_{\infty} \text { ) } \\
& m_D=\left(1+\frac{D}{f}\right)_{\max \text { and }} \\
& m_{\infty}=\left(\frac{D}{f}\right)_{\min }
\end{aligned}
$
Case 2: If lens is kept at a distance a from the eye then
$
\begin{aligned}
& m_D=1+\frac{D-a}{f} \text { and } \\
& m_{\infty}=\frac{D-a}{f}
\end{aligned}
$
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