2 Questions around this concept.
Image seen by a person using lens as simple microscope will be -
Magnifying power: It is defined as the ratio between the dimensions of the image and the object.
Magnifying power of an optical instrument is given by,
$
m=\frac{\text { Visual angle with instrument }(\beta)}{\text { Visual angle when object is placed at least distance of distinct vision }(\alpha)}
$

Simple Microscope
Case 1: Magnification's, when the final image is formed at $D$ and $\infty$.
$
\begin{aligned}
& \text { (i.e. } m_D \text { and } m_{\infty} \text { ) } \\
& m_D=\left(1+\frac{D}{f}\right)_{\max \text { and }} \\
& m_{\infty}=\left(\frac{D}{f}\right)_{\min }
\end{aligned}
$
Case 2: If lens is kept at a distance a from the eye then
$
\begin{aligned}
& m_D=1+\frac{D-a}{f} \text { and } \\
& m_{\infty}=\frac{D-a}{f}
\end{aligned}
$
"Stay in the loop. Receive exam news, study resources, and expert advice!"
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Last Date to Apply: 18th May | Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements
Recognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships
NAAC A+ Accredited | Among top 2% Universities Globally (QS World University Rankings 2026)
NAAC A++ Grade | Highest Package-30 LPA | 400+ Recruiters
NAAC A++ Grade | Recognized as Category-1 Deemed to be University by UGC | 41,000 + Alumni Imprints Globally
Explore on Careers360
Student Community: Where Questions Find Answers