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Refraction Of Light - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Refraction is considered one of the most asked concept.

  • 35 Questions around this concept.

Solve by difficulty

A transparent solid cylindrical rod has a refractive index of $\frac{2}{\sqrt{3}}$. It is surrounded by air. A light ray is incident at the mid-point of one end of the rod as shown in the figure.

The incident angle $\theta$ for which the light ray grazes along the wall of the rod is

A ray of light is incident on a medium with angle of incidence $i$ and refracted into a second medium with angle of refraction $r$. The graph of $\sin \mathrm{i}$ vs $\sin r$ is shown in the figures. Then the velocity of light in the first medium is $n$ times the velocity of light in the second medium. The value of $n$ should be.

Consider a light ray travelling in air is incident into a medium of refractive index $\sqrt{2} n$. The incident angle is twice that of the refracting angle. Then, the angle of incidence will be :

Time taken by light to travel in two different materials A and B of refractive indices $\mu_{\mathrm{A}}$ and $\mu_B$ of same thickness is $t_1$ and $t_2$ respectively. If $t_2-t_1=5 \times 10^{-10} \mathrm{~s}$ and the ratio of $\mu_{\mathrm{A}}$ to $\mu_{\mathrm{B}}$ is $1: 2$. Then, the thickness of material, in meter is: (Given $v_{\mathrm{A}}$ and $v_{\mathrm{B}}$ are velocities of light in A and B materials respectively.)

A ray of laser of a wavelength 630 nm is incident at an angle of $30^{\circ}$ at the diamond-air interface. It is going from diamond to air. The refractive index of diamond is 2.42 and that of air is 1 . Choose the correct option.

The following figure represents a wavefront AB that passes from air to another transparent medium and produces a new wavefront CD after refraction. The refractive index of the medium is (PQ is the boundary between air and the medium).       

Which of the following graphs represents the angle of deviation vs angle of incidence (i) for light ray going from rarer to denser?

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Concepts Covered - 1

Refraction

Refraction

Deviation or bending of light rays from their original path while passing from one medium to another is called refraction. It is due to change in the speed of light as light passes from one medium to another medium. If the light is incident normally then it goes to the second medium without bending, but still, it is called refraction. When a light ray passes from one medium to another such that
it undergoes a change in velocity, refraction takes place. Hence, the wavelength of light changes, but frequency remains the same.

Types of medium: 

  1.  Rarer medium: Medium in which the speed of light is more is called optically Rarer medium. 
  2.  Denser medium: Medium in which light travels more slowly is called optically denser medium.

Refractive index: Refractive index of a medium is defined as the factor by which speed of light reduces as compared to the speed of light in vacuum.

                                 $\mu=\frac{c}{v}=\frac{\text { speed of light in vacuum }}{\text { speed of light in medium }}$

 When light moves from denser to a rarer medium, it bends away from the normal.

              

 When light moves from rarer to denser medium, it bends towards the normal.

                

Laws of refraction: 

  1. The incident ray, the normal to any refracting surface at the point of incidence, and the refracted ray all lie in the same plane called the plane of incidence or plane of refraction.
  2. The ratio of sine of angle of incidence to the angle of refraction is always constant. 

                           $\frac{\sin i}{\sin r}=$ constant

                         

     

Also, $\frac{\sin i}{\sin r}=\frac{\mu_2}{\mu_1}=\frac{v_1}{v_2}=\frac{\lambda_1}{\lambda_2}$
For applying in problems remember

$$
\begin{aligned}
& \mu_1 \sin i=\mu_2 \sin r \\
& \frac{\sin (i)}{\sin (r)}=\mu_{21} \quad=\text { refractive index of the second medium with respect to the first medium. }
\end{aligned}
$$


Deviation due to refraction:
Deviation $(\delta)$ of ray incident at $\angle i$ and refracted at $\angle r$ is given by :

$$
\delta=|i-r|
$$
 

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Refraction

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