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6 Questions around this concept.
A plane mirror is placed at origin parallel to y-axis facing the positive x-axis. An object starts from (2,0 ,0) with a velocity $(2 \hat{i}+2 \hat{j})$ m/s. The relative velocity of the image with respect to object is along:
An object and a plane mirror are shown in the figure. The mirror is moved with velocity.
V as shown. The velocity of the image is :
The - plane separates two media and with refractive indices and , respectively. A ray of light travels from and . Its directions in the two media are given by the unit vectors and respectively, where and are unit vectors in the and - directions. Then;
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An object is placed at a distance of 12 cm in front of a plane mirror. The virtual and erect image is formed by the mirror. Now the mirror is moved by 4 cm towards the stationary object. The distance by which the position of image would be shifted, will be
In the given diagram the mirror and object is moving with a speed 2 m/s as shown then the velocity of image with respect to object
The relation between the velocity of the object and mirror in-plane mirror:
In case of plane mirror, distance of the object from the mirror is equal to distance of image from the mirror.
i.e Distance of Image formed in the mirror is same as the distance of the object formed the surface of the mirror.
Hence, from the mirror property:
$$
x_{\mathrm{im}}=-x_{\mathrm{on}}, y_{\mathrm{im}}=y_{\mathrm{om}} \text { and } z_{\mathrm{im}}=z_{\mathrm{om}}
$$
Here $x_{i m}$ means " x coordinate of image with respect to mirror.
Differentiating w.r.t time, we get,
$$
v_{(\mathrm{im}) x}=-v_{(\mathrm{om}) x} ; \quad v_{(\mathrm{im}) y}=v_{(\mathrm{om}) y} ; \quad v_{(\mathrm{im}) \mathrm{z}}=v_{(\mathrm{orn}) z}
$$
Here,
$v_i=$ velocity of the image with respect to the ground.
$v_0=$ velocity of the object with respect to the ground.
$v_{\text {om }}=$ velocity of the object with respect to the mirror.
$v_{i m}=$ velocity of the object with respect to the mirror.
i.e $\vec{v}_{\text {om }}=\vec{v}_{\mathrm{o}}-\vec{v}_{\mathrm{m}} \quad$ and $\quad \vec{v}_{\mathrm{im}}=\vec{v}_{\mathrm{i}}-\vec{v}_{\mathrm{m}}$
For x-axis-
$$
\begin{aligned}
& v_{(i m) x}=-v_{(\mathrm{om}) x} \\
& \Rightarrow \quad v_i-v_{\mathrm{m}}=-\left(v_{\mathrm{o}}-v_{\mathrm{m}}\right) \quad(\text { for } x \text {-axis })
\end{aligned}
$$
- I.e When the object moves with speed $v$ towards (or away) from the plane mirror then image also moves toward (or away) with speed $v$. But the relative speed of image w.r.t. the object is $2 v$.
For y -axis and z -axis
$$
v_{(\mathrm{im}) y}=v_{(\mathrm{om}) y} ; \quad v_{(\mathrm{im}) \mathrm{z}}=v_{(\mathrm{om}) z}
$$
| Relative velocity of image w.r.t. mirror | = | Relative velocity of object w.r.t. mirror |
$\begin{array}{ll}\text { But } & v_1-v_{\mathrm{m}}=\left(v_{\mathrm{o}}-v_{\mathrm{m}}\right) \\ \text { or } & v_{\mathrm{i}}=v_{\mathrm{o}}\end{array} \quad$ for $y$-and $z$-axis.
Here, $v_i=$ velocity of the image with respect to the ground.
$v_0=$ velocity of the object with respect to the ground.
i.e Velocity of the object is equal to the velocity of the image when the object is moving to parallel to the mirror surface.
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