JEE Main 2025 Session 2 Important Questions - Students who enroll in JEE Main 2025 Session 2 have to be thoroughly prepared because they need a high percentile score to enter their chosen engineering institution. Preparing for JEE Main 2025 Session 2 involves strategic, practicable methods through the study of important questions that match the current syllabus and examination pattern.
While BTech in Computer Science Engineering (CSE) remains the top choice among JEE Advanced toppers, the JIC report shows a growing popularity of new-gen courses such as artificial intelligence (AI) and data science in IIT Madras, IIT Kharagpur, IIT Hyderabad, IIT Gandhinagar among others.
JEE 2026: IIT admissions show major shift toward AI, data science, away from core engineering course
Studying the JEE Main important questions helps students both develop a clearer understanding of concepts and speed up their problem-solving ability while learning typical types of problems that appear in the exam. Solving the critical questions in Session 2 of JEE Main 2025 offers an opportunity to understand prominent exam topics.
To ensure a comprehensive revision, focus on high-priority topics in Physics, Chemistry, and Mathematics. Below are some of the critical areas:
Physics: Mechanics, Electrostatics, Magnetism, Optics, Modern Physics
Chemistry: Organic Reactions, Chemical Bonding, Thermodynamics, Coordination Compounds
Mathematics: Calculus, Algebra, Probability, Coordinate Geometry, Vectors & 3D Geometry
Practicing JEE Mains important questions with solutions PDF can significantly enhance accuracy and efficiency in solving problems.
1. A person traveling on a straight line moves with a uniform velocity $\mathrm{v}_1$ for a distance x and with a uniform velocity $\mathrm{v}_2$ for the next $\frac{3}{2} \mathrm{x}$ distance. The average velocity in this motion is $\frac{50}{7} \mathrm{~m} / \mathrm{s}$. If $\mathrm{v}_1$ is $5 \mathrm{~m} / \mathrm{s}$ then $\mathrm{v}_2=$ _____ $\mathrm{m} / \mathrm{s}$.
2. The moment of inertia of a rod of mass ' M ' and length 'L' about an axis passing through its center and normal to its length is ' $\alpha$ '. Now the rod is cut into two equal parts and these parts are joined symmetrically to form a cross shape. The moment of inertia of a cross about an axis passing through its center and normal to the plane containing the cross is :
1) $\alpha$2
2) $\alpha / 4$
3) $\alpha / 8$
4) $\alpha / 2$
3. A river is flowing from west to east direction with a speed of $9 \mathrm{~km} \mathrm{~h}^{-1}$. If a boat capable of moving at a maximum speed of $27 \mathrm{~km} \mathrm{~h}^{-1}$ in still water, crosses the river in half a minute, while moving with maximum speed at an angle of $150^{\circ}$ to direction of river flow, then the width of the river is :
1) 300 m
2) 112.5 m
3) 75 m
4) $112.5 \times \sqrt{3} \mathrm{~m}$
4. The equation for real gas is given by $\left(\mathrm{P}+\frac{\mathrm{a}}{\mathrm{V}^2}\right)(\mathrm{V}-\mathrm{b})=\mathrm{RT}$, where $\mathrm{P}, \mathrm{V}, \mathrm{T}$ and R are the pressure, volume, temperature, and gas constant, respectively. The dimension of $\mathrm{ab}^{-2}$ is equivalent to that of:
1) Planck's constant
2) Compressibility
3) Strain
4) Energy density
5. Let $B_1$ be the magnitude of the magnetic field at the center of a circular coil of radius R carrying current I . Let $\mathrm{B}_2$ be the magnitude of magnetic field at an axial distance ' $x$ ' from the center. For $x: R=3: 4, \frac{B_2}{B_1}$ is :
1) $4: 5$
2) $16: 25$
3) $64: 125$
4) $25: 16$
1.
Consider the following half cell reaction
$$
\mathrm{Cr}_2 \mathrm{O}_7^{2-}(\mathrm{aq})+6 \mathrm{e}^{-}+14 \mathrm{H}^{+}(\mathrm{aq}) \rightarrow 2 \mathrm{Cr}^{3+}(\mathrm{aq})+7 \mathrm{H}_2 \mathrm{O}(\mathrm{l})
$$
The reaction was conducted with the ratio of $\frac{\left[\mathrm{Cr}^{3+}\right]^2}{\left[\mathrm{Cr}_2 \mathrm{O}_7^{2-}\right]}=10^{-6}$. The pH value at which the EMF of the half cell will become zero is $\_\_\_\_$ . (nearest integer value)
[Given : standard half cell reduction potential
$$
\left.\mathrm{E}_{\mathrm{C}_2 \mathrm{O}_{-}^2+\mathrm{H}^* / \mathrm{Cr}^{3+}}^{\mathrm{o}}=1.33 \mathrm{~V}, \frac{2.303 \mathrm{RT}}{\mathrm{~F}}=0.059 \mathrm{~V}\right]
$$
2. The equilibrium constant for decomposition of $\mathrm{H}_2 \mathrm{O}(\mathrm{g})$
$$
\mathrm{H}_2 \mathrm{O}(\mathrm{~g}) \rightleftharpoons \mathrm{H}_2(\mathrm{~g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g})\left(\Delta \mathrm{G}^{\circ}=92.34 \mathrm{~kJ} \mathrm{~mol}^1\right)
$$
is $8.0 \times 10^{-3}$ at 2300 K and total pressure at equilibrium is 1 bar . Under this condition, the degree of dissociation ( $\alpha$ ) of water is $\_\_\_\_$ $\times 10^{-2}$ (nearest integer value).
[Assume $\alpha$ is negligible with respect to 1 ]
3. 20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is $\_\_\_\_$ M. (Nearest Integer value)
$$
\left(\text { Given : } \mathrm{Na}=23, \mathrm{I}=127, \mathrm{Ag}=108, \mathrm{~N}=14, \mathrm{O}=16 \mathrm{~g} \mathrm{~mol}^{-1}\right)
$$
4. The energy of an electron in first Bohr orbit of H -atom is -13.6 eV . The magnitude of energy value of electron in the first excited state of $\mathrm{Be}^{3+}$ is $\_\_\_\_$ eV . (nearest integer value)
1. If the set of all $\mathrm{a} \in \mathrm{R}-\{1\}$, for which the roots of the equation $(1-a) x^2+2(a-3) x+9=0$ are positive is $(-\infty,-\alpha] \cup[\beta, \gamma)$, then $2 \alpha+\beta+\gamma$ is equal to $\_\_\_\_$
2. Let $\mathrm{A}(4,-2), \mathrm{B}(1,1)$ and $\mathrm{C}(9,-3)$ be the vertices of a triangle $A B C$. Then the maximum area of the parallelogram $A F D E$, formed with vertices $\mathrm{D}, \mathrm{E}$ and F on the sides $\mathrm{BC}, \mathrm{CA}$ and AB of the triangle ABC respectively, is $\_\_\_\_$
3. If $y=\cos \left(\frac{\pi}{3}+\cos ^{-1} \frac{x}{2}\right)$, then $(x-y)^2+3 y^2$ is equal to $\_\_\_\_$
4. If the sum of the first 10 terms of the series $\frac{4.1}{1+4.1^4}+\frac{4.2}{1+4.2^4}+\frac{4.3}{1+4.3^4}+\ldots$ is $\frac{m}{n}$, where $\operatorname{gcd}(m, n)=1$, then $m+n$ is equal to $\_\_\_\_$ .
5. Let $y=y(x)$ be the solution of the differential equation $\frac{d y}{d x}+2 y \sec ^2 x=2 \sec ^2 x+3 \tan x \cdot \sec ^2 x$ such that $y(0)=\frac{5}{4}$. Then $12\left(y\left(\frac{\pi}{4}\right)-e^{-2}\right)$ is equal to
Your performance will be improved by solving previous year examinations along with expert-created problems. Some illustrative topics that will be discussed include:
Kinematics-based motion problems with detailed solutions
Stoichiometry and mole concept numerical questions
Definite Integration and Differential Equations.
Downloading JEE Mains important questions with solutions PDF ensures easy access to high-quality resources for systematic preparation.
Daily question-solving leads to improved speed and accuracy within the workplace.
Test conditions can be made by using timers to practice during simulation sessions.
Students should review solutions completely to understand concepts in weak areas.
Testing with full-length assessments allows students to evaluate their performance by measuring improvement as well as discovering weaknesses.
100% Placement Record | Highest CTC 54 LPA | NAAC A++ Accredited | Ranked #62 in India by NIRF Ranking 2025 | JEE & JET Scores Accepted
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
Mastering the most important questions for JEE Mains 2025 Session 2 is essential for achieving a competitive score. Strengthen your comprehension and problem-solving skills by referring to the JEE Main session 2 important questions and answers. Students who access JEE Mains important questions with solutions in PDF format will experience simplified revision while boosting their exam confidence level.
Frequently Asked Questions (FAQs)
Keep regular practice and solve all difficulty-level questions consistently.
You will get 3 hours.
On Question asked by student community
Hello,
Your OBC-NCL certificate issued in June 2024 will not be accepted for JEE Main or JEE Advanced reservation. For these exams, the OBC-NCL certificate must be issued on or after 1 April 2025 . So yes, there will be an issue if you use the June 2024 certificate.
What you should do:
Apply for a new OBC-NCL certificate with an issue date of 1 April 2025 or later.
At the time of form filling, if the portal asks for the certificate and you do not have the new one yet, you can upload the self-declaration format (the exam authorities usually allow this). Later, during counselling or document verification, you must show the updated certificate.
Since your Aadhaar has mistakes in name and DOB, make sure it gets updated before the exam application and counselling. Wrong Aadhaar details can cause mismatch issues.
So, get your Aadhaar corrected and plan to get a fresh OBC-NCL certificate after 1 April 2025. This will prevent any problem during verification.
Hope it helps !
Hello Satyam,
Yes, your EWS certificate is valid.
In Bihar, the EWS certificate can be issued by the Circle Officer, BDO, SDO, or DM. So a certificate signed by the Circle Officer (Revenue Officer) is acceptable.
If the format of your certificate is the same as the Central Government EWS format, then it is valid for JEE Main registration and also for JoSAA counselling. The heading “Government of Bihar” does not create any problem.
Just remember one point:
For
JoSAA 2026
, you will need an EWS certificate issued on or after 1 April 2025. Even if your current certificate works for registration, you must update it before counselling.
Hope it helps !
Hello murali
No, your son is not eligible for OBC NCL for IIT JEE because you fall in the "creamy layer" occupational category, regardless of your current employment status or family income. Students whose family income is less than Rs. 8 lakhs annually and they are not belong to the "creamy layer".
Note -
Thank You
Hello,
You can fill the JEE Main form even if you are a private candidate
Write the
name of the school/board from where you are appearing as a private candidate
.
If your Class 12 admit card or registration slip shows a school/centre name, use that exactly.
If your board lists you as a “Private Candidate” under the board name , then write:
CBSE – Private Candidate
(or your board name – Private Candidate)
Use the pin code of the examination centre/school mentioned on your Class 12 private candidate admit card or registration details.
If your board does not give any school address and only shows the regional office address, then use the regional office address pin code given by your board.
Hope it helps !
Hello Aspirant
You should not leave the OBC-NCL certificate ID blank in the JEE Main form it can create problems later.
NTA wants the certificate details while filling the form, not just at counselling. If you can, apply for the OBC-NCL certificate immediately so you get the ID on time.
If you fail to submit the certificate during counselling, your category will shift to General. It’s safer to enter OBC-NCL only if you’re sure you’ll get the certificate before counselling.
Hope it will help you
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
Recognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships
Attempt JEE Main online mock test based on the updated syllabus. Check your preparation and identify your weak points.
Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements
NAAC A++ Grade | Recognized as Category-1 Deemed to be University by UGC | 41,000 + Alumni Imprints Globally
60+ Years of Education Legacy | UGC & AICTE Approved | Scholarship Worth 6 Crores | H-CTC 35 LPA
