How to calculate JEE Main 2026 rank based on Percentile score? - Candidates can check this page for the way to calculate the JEE Main rank from percentile score. Careers360 has derived the JEE Main 2026 rank from the percentile based on the previous year's statistics. The percentile score is a measure to know the percentage of candidates who have marks equal to or less than. NTA uses a JEE normalisation method to get the percentile from raw marks. Those with higher percentile are assigned higher rank in JEE Main. By knowing how to calculate the JEE Main rank based on percentile, candidates get a chance to judge their test performance. Also, they can use the JEE Main rank predictor tool. Note that the final JEE Main result 2026 will mention the rank.
Also Check: JEE Main marks vs percentile
NTA has revised the JEE Main 2026 number of exam cities. This year, the number of exam cities has increased from 284 to 323.
With the help of expected rank, aspirants can also check the chances of admission to desired colleges through JEE Main college predictor. Candidates can check this article to know how to calculate JEE Main 2026 rank based on percentile score.
JEE Main 2026 result date will be released online. Since the authority conducts two sessions of JEE Main exam, the final ranks announced through JEE Main 2026 session will be final. The institutes consider this rank during the JoSAA counselling. Below is the process of calculating rank from percentile using a formula provided by coaching institutes and an example. As per the previous year's NTA JEE Main statistics, 14,75,103 students appeared for JEE Main in the January session. NTA had announced that 24 students have scored 100 percentile in 2025 and have declared them as JEE Main Toppers.
To calculate the JEE Main rank, you first need to know the percentage of candidates with higher percentile scores than you. To calculate that, the formula would be-
100 (highest score) - your percentile score.
Since the percentile is calculated from 100 to 0 for each session of examinees, the formula applies the total number of students in the session which is-
14,75,103 /100 * percentage of people ahead of you to arrive at the rank.
Therefore, the formula to calculate the JEE Main rank through percentile is-
JEE Main rank (probable) = (100- NTA percentile score ) X 14,75,103 /100
*This formula would not be for a 100 percentile score as those are the top ranks.
Suppose the total number of candidates who appeared for JEE Main exam are 823967, and then the approximate JEE Main rank can be-
If the NTA percentile score is 99.999, JEE Main rank will be (100-99.999 ) X 823967/100 = 914 (approx.)
Consider the NTA score of 80.60 then JEE Main rank = (100-80.60) X 823967/100. The rank will be 159849
Note: It should be undertood that the formula given for the calculation of percentile in JEE Main is indicative and should not be taken as accurate as the actual ranks will vary on account of many factors. For the actual rank, candidates should check the alloted rank on the JEE Main 2026 scorecard.
Until the result is declared, aspirants can go through the expected JEE Mains percentile vs rank based on the previous year statistics to get an idea of how to calculate the JEE Main rank from the percentile.
JEE Main Percentile | JEE Main Rank |
100 | 1 |
99.994681 - 99.997394 | 56-25 |
99.988780 - 99.994681 | 115-55 |
99.956404 - 99.988551 | 402-115 |
99.901123 - 99.956364 | 978-401 |
99.795063 - 99.901123 | 2001 — 978 |
99.573193 - 99.782472 | 3901 - 2001 |
99.239937 - 99.782472 | 7003 - 3901 |
98.732389 - 99.239937 | 12200 - 7003 |
96.978108 - 98.7322 | 210010 -12200 |
96.064850 - 96.978108 | 35000 - 21010 |
Candidates can take a probable calculation of percentile in JEE Main January 2026 session and check the rank. Based on your performance in the JEE Main January session, you can decide if you want to attempt the April session or not.
According to the total number of registrations in JEE Main 2026 session 1, the expected number of candidates who may appeared for the JEE Main January session are around 14 Lakhs. Using this as a basis, use the NTA score and see what is the JEE Main rank.
The reason is that the authority will consider the better of the two session's scores is to provide benefit to aspirants. So if any candidate performs badly in January, they can take another attempt in April. The January NTA score will be counted for determiing the rank if they would have performed better in that session or vice-versa.
General category candidates with an NTA percentile score of 89 and above are expected to have better chances to qualify for JEE Advanced if one takes a look at the JEE Main cutoff from last year. It is a fact that IITs are dream institutions for most engineering aspirants. So a student who has done exceptionally well in January session of JEE Main may wish to skip the JEE Main April session to concentrate on JEE Advanced preparation. Another student may have scored well enough and feels that another session is too strenuous so may wish to skip it if only he/she has a fair chance of a seat in one good NIT or IIIT. Others may wish to know if they have the chance for any admissions based on their January JEE Main percentile scores or if should they appear for the April exam to better this.
We hope that the decision to write or skip can be made a bit easier using the calculation methods mentioned in this article.
Frequently Asked Questions (FAQs)
Aspirants can use a formula to convert a percentile to rank in JEE Mains as given in the article. However, the said formula provides only a probable rank.
JEE Main 2026 normalisation process will be done by the authority to ensure all candidates' scores are at an equal level, regardless of the difficulty level of the session.
The JEE Main 2026 result date will be announced.
On Question asked by student community
HELLO,
For the JEE Mains 2026 the high weightage topics include Modern Physics , Heat and Thermodynamics , Optics in Physics :- Integral Calculus , Limits and Continuity in Math and Coordination Compounds , Organic Chemistry.
For more detailed information like to know everything about every topic in detail You
Yes, absolutely! If you score 98 percentile in MHT-CET, you have excellent chances of securing admission to good engineering colleges in Maharashtra, even if your JEE Mains percentile is 60. MHT-CET is the primary entrance exam for admissions to engineering colleges in Maharashtra. A 98 percentile in MHT-CET is considered
Here are the chapters which contains high weightage in your exam and are also easy to prepare.
* PHYSICS:-
current electricity - 2 to 3 questions
Modern physics - 3 to 4 ques
Semiconductor - 1 to 2 ques
Electrostatics - 2 ques
Magnetic effects of current - 2 ques
Hello,
The link to the short notes is attached here. Solutions to the notes are also uploaded on the website. You can access the preparation tips, previous year question paper and answer key that can help you analyse your performance and increase your score.
https://engineering.careers360.com/articles/jee-main-2026-revision-notes-solutions
Careers360 conducted a free mock
JEE Main aspirants should prepare short notes for quick revision of important concepts and formulas from Physics Chemistry and Mathematics. Short notes help in revising topics like kinematics laws of motion current electricity chemical bonding periodic table quadratic equations trigonometry and coordinate geometry in less time. Regular revision of these
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