How to calculate JEE Main 2026 rank based on Percentile score? - Candidates can check this page for the way to calculate the JEE Main rank from percentile score. Careers360 has derived the JEE Main 2026 rank from the percentile based on the previous year's statistics. The percentile score is a measure to know the percentage of candidates who have marks equal to or less than. NTA uses a JEE normalisation method to get the percentile from raw marks. Those with higher percentile are assigned higher rank in JEE Main. By knowing how to calculate the JEE Main rank based on percentile, candidates get a chance to judge their test performance. Also, they can use the JEE Main rank predictor tool. Note that the final JEE Main result 2026 will mention the rank.
Also Check: JEE Main marks vs percentile
With the help of expected rank, aspirants can also check the chances of admission to desired colleges through JEE Main college predictor. Candidates can check this article to know how to calculate JEE Main 2026 rank based on percentile score.
JEE Main 2026 result date will be released online. Since the authority conducts two sessions of JEE Main exam, the final ranks announced through JEE Main 2026 session will be final. The institutes consider this rank during the JoSAA counselling. Below is the process of calculating rank from percentile using a formula provided by coaching institutes and an example. As per the previous year's NTA JEE Main statistics, 14,75,103 students appeared for JEE Main in the January session. NTA had announced that 24 students have scored 100 percentile in 2025 and have declared them as JEE Main Toppers.
To calculate the JEE Main rank, you first need to know the percentage of candidates with higher percentile scores than you. To calculate that, the formula would be-
100 (highest score) - your percentile score.
Since the percentile is calculated from 100 to 0 for each session of examinees, the formula applies the total number of students in the session which is-
14,75,103 /100 * percentage of people ahead of you to arrive at the rank.
Therefore, the formula to calculate the JEE Main rank through percentile is-
JEE Main rank (probable) = (100- NTA percentile score ) X 14,75,103 /100
*This formula would not be for a 100 percentile score as those are the top ranks.
Suppose the total number of candidates who appeared for JEE Main exam are 823967, and then the approximate JEE Main rank can be-
If the NTA percentile score is 99.999, JEE Main rank will be (100-99.999 ) X 823967/100 = 914 (approx.)
Consider the NTA score of 80.60 then JEE Main rank = (100-80.60) X 823967/100. The rank will be 159849
Note: It should be undertood that the formula given for the calculation of percentile in JEE Main is indicative and should not be taken as accurate as the actual ranks will vary on account of many factors. For the actual rank, candidates should check the alloted rank on the JEE Main 2026 scorecard.
Until the result is declared, aspirants can go through the expected JEE Mains percentile vs rank based on the previous year statistics to get an idea of how to calculate the JEE Main rank from the percentile.
JEE Main Percentile | JEE Main Rank |
100 | 1 |
99.994681 - 99.997394 | 56-25 |
99.988780 - 99.994681 | 115-55 |
99.956404 - 99.988551 | 402-115 |
99.901123 - 99.956364 | 978-401 |
99.795063 - 99.901123 | 2001 — 978 |
99.573193 - 99.782472 | 3901 - 2001 |
99.239937 - 99.782472 | 7003 - 3901 |
98.732389 - 99.239937 | 12200 - 7003 |
96.978108 - 98.7322 | 210010 -12200 |
96.064850 - 96.978108 | 35000 - 21010 |
Candidates can take a probable calculation of percentile in JEE Main January 2026 session and check the rank. Based on your performance in the JEE Main January session, you can decide if you want to attempt the April session or not.
According to the total number of registrations in JEE Main 2026 session 1, the expected number of candidates who may appeared for the JEE Main January session are around 14 Lakhs. Using this as a basis, use the NTA score and see what is the JEE Main rank.
The reason is that the authority will consider the better of the two session's scores is to provide benefit to aspirants. So if any candidate performs badly in January, they can take another attempt in April. The January NTA score will be counted for determiing the rank if they would have performed better in that session or vice-versa.
General category candidates with an NTA percentile score of 89 and above are expected to have better chances to qualify for JEE Advanced if one takes a look at the JEE Main cutoff from last year. It is a fact that IITs are dream institutions for most engineering aspirants. So a student who has done exceptionally well in January session of JEE Main may wish to skip the JEE Main April session to concentrate on JEE Advanced preparation. Another student may have scored well enough and feels that another session is too strenuous so may wish to skip it if only he/she has a fair chance of a seat in one good NIT or IIIT. Others may wish to know if they have the chance for any admissions based on their January JEE Main percentile scores or if should they appear for the April exam to better this.
We hope that the decision to write or skip can be made a bit easier using the calculation methods mentioned in this article.
Frequently Asked Questions (FAQs)
JEE Main 2026 normalisation process will be done by the authority to ensure all candidates' scores are at an equal level, regardless of the difficulty level of the session.
On Question asked by student community
Hello,
Since the NTA conducts exams in Tamil, these official papers will have a Tamil language option. Kindly check the following link to get the question papers.
https://engineering.careers360.com/articles/jee-main-question-papers
I hope this helps you.
Hello there,
Understanding and solving different question papers is one of the best practice for the preparation specially when it comes to JEE mains. It gives you proper understanding of the exam pattern, important topics to cover and marking scheme.
Here is the link attached from the official website of Careers360 which will provide you with the link of previous year question papers on chemistry in PDF format. Hope it helps!
https://engineering.careers360.com/articles/jee-mains-chemistry-questions-in-last-year-exam-premium
thank you!
Hello,
Yes, you can be eligible , but it depends on how you passed Mathematics.
JEE Main
You are eligible if:
You passed Class 12 with Physics and Mathematics.
Mathematics was passed as a full subject from NIOS.
NIOS is a recognized board.
Having two marksheets is allowed.
You are not eligible if:
Mathematics was taken only as an improvement or additional without passing it as a full subject.
MHT-CET
You are eligible if:
You passed Class 12 with Physics and Mathematics.
Mathematics from NIOS is shown as a passed subject.
NIOS is recognized for Maharashtra admissions.
Mathematics was passed before the admission year.
You are not eligible if:
Mathematics is not shown as a passed subject.
Important
Mathematics must be a separate and passed subject.
Keep both marksheets during counselling.
Always check the current year information brochure before applying.
Hope it helps !
The marks needed for a 99+ percentile in the JEE Main January attempt depend on the difficulty of the paper and the total number of candidates. Generally, you need roughly *180–200* marks out of 300 to hit the 99+ percentile. The exact cutoff varies each session, so checking the official NTA percentile score calculator or previous year cutoffs gives a more precise idea.
Hello aspirant
JEE Main accepts NIOS, so you can appear if you meet the basic eligibility.
BITS does not accept marks from two different boards, so this option won’t work for BITS.
VIT and SRM generally accept NIOS, but having two separate mark sheets can be an issue. You should check their official eligibility rules before applying.
Thankyou I hope this help
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