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Which JEE Main 2025 score will NTA use for common rank list? - NTA conducts the most important entrance examination JEE Main for admission into undergraduate engineering colleges in India. The National Testing Agency administers the exam twice a year: January and April sessions. For JEE Main 2025 exam the January session will take place from January 22 to 31, while the April session will be conducted from April 1 to 8, 2025. Candidates' best scores from the two sessions will be used for ranking purposes, which plays a crucial role in securing admissions. Despite NTA outlining the criteria for selecting the best score, some confusion remains among students regarding the preparation of the common rank list.
The last three years’ closing ranks of all NITs for CSE courses are given below.
NIT JEE Mains cut-off | 2025 | 2024 | 2023 | |||
Institute | Opening Rank | Closing Rank | Opening Rank | Closing Rank | Opening Rank | Closing Rank |
NIT Tiruchirappalli | 659 | 1449 | 299 | 1224 | 176 | 1509 |
NIT Karnataka, Surathkal | 1191 | 1827 | 14 | 1615 | 966 | 1984 |
NIT Warangal | 1521 | 2409 | 1043 | 2186 | 889 | 2413 |
NIT Rourkela | 2442 | 3431 | 591 | 2940 | 2529 | 3786 |
Motilal Nehru National Institute of Technology Allahabad | 2730 | 4594 | 2417 | 4191 | 2758 | 4777 |
NIT Calicut | 3651 | 5222 | 2614 | 4482 | 2483 | 5256 |
Malaviya National Institute of Technology Jaipur | 3027 | 5601 | 1501 | 4711 | 2684 | 4909 |
Visvesvaraya National Institute of Technology, Nagpur | 4442 | 6359 | 4555 | 5795 | 4920 | 7087 |
NIT Kurukshetra | 5180 | 7037 | 4472 | 6000 | – | – |
NIT Delhi | 2363 | 7651 | 2438 | 8018 | 4278 | 9930 |
Sardar Vallabhbhai National Institute of Technology, Surat | 6343 | 8130 | 5587 | 7113 | 5052 | 7741 |
NIT Jamshedpur | 6378 | 8902 | 4935 | 7944 | 3260 | 9204 |
Maulana Azad National Institute of Technology Bhopal | 5942 | 9249 | 6217 | 8830 | 6409 | 9370 |
NIT Durgapur | 6565 | 9836 | 5973 | 8765 | 6848 | 10070 |
Dr. B R Ambedkar National Institute of Technology, Jalandhar | 7991 | 11262 | 6330 | 10957 | 9028 | 11017 |
NIT Hamirpur | 9637 | 12586 | 8376 | 12236 | 9929 | 12426 |
NIT Silchar | 8010 | 12665 | 5736 | 11930 | 8606 | 12818 |
NIT Raipur | 8140 | 13559 | 10323 | 13177 | 10110 | 12773 |
NIT Goa | 10279 | 13640 | 7914 | 12511 | 8584 | 12604 |
NIT Patna | 10529 | 14996 | 9288 | 14442 | 8125 | 13964 |
Indian Institute of Engineering Science and Technology, Shibpur | 13917 | 16765 | 6068 | 14635 | 8043 | 13711 |
NIT Andhra Pradesh | 11739 | 18183 | 10309 | 18548 | 11839 | 17272 |
NIT Uttarakhand | 16359 | 18491 | 14598 | 18039 | 14432 | 18447 |
NIT Puducherry | 11429 | 19758 | 6318 | 18515 | 12546 | 17305 |
NIT Agartala | 13104 | 22013 | 8121 | 20298 | 14010 | 20102 |
NIT Meghalaya | 20712 | 24074 | 14656 | 20039 | 15911 | 19175 |
NIT Srinagar | 15080 | 26171 | 12751 | 21839 | 12931 | 22814 |
NIT Sikkim | 15389 | 26616 | 23245 | 28284 | 19566 | 24093 |
NIT Arunachal Pradesh | 27500 | 30607 | 22046 | 28514 | 25273 | 29087 |
NIT Manipur | 26617 | 33098 | 15616 | 30611 | 17658 | 29644 |
NIT Mizoram | 35504 | 37751 | 31598 | 33181 | 28938 | 31336 |
NIT Nagaland | 32717 | 39594 | 22429 | 31391 | 24324 | |
JEE Main 2026: NIT Tiruchirappalli, Surathkal, Warangal retain highest BTech cut-offs among NITs
Aspirants who are planning to appear for the JEE Main 2025 exam should keep a close eye on the official website of NTA to get the latest updates about the exam dates and other details. Understanding the selection criteria and preparing accordingly can significantly increase the chances of success in the exam and securing admission into the top engineering colleges in India.
The National Testing Agency will release the JEE Main 2025 rank list after the JEE Main result. Due to the large number of candidates appearing for the JEE Main exam, the rank/merit list is prepared based on the JEE Mains cutoff 2025 percentile score of the candidate. To calculate the percentile score, if a candidate has appeared for both exam sessions, the better of the two scores will be considered. The score used by NTA to prepare the JEE Main common rank list will prioritize the better score obtained by the candidate from the two sessions.
Appearing in JEE Main 2025? Scores of the respective test will be used.
Appearing in both JEE Main 2025? The better of the two scores will be used. The lower score will be ignored.
| Marks out of 300 | Rank |
| 288- 294 | 20-11 |
| 280-284 | 44-22 |
| 270- 279 | 107-63 |
| 252- 268 | 522-106 |
| 231-249 | 1385-546 |
| 215-230 | 2798-1421 |
| 202-214 | 4666-2862 |
| 190-200 | 6664- 4830 |
| 175-189 | 10746-7151 |
| 161-174 | 16163-11018 |
| 149-159 | 21145-16495 |
| 132-148 | 32826-22238 |
| 120-131 | 43174-33636 |
| 110-119 | 54293-44115 |
| 102-109 | 65758-55269 |
| 95-101 | 76260-66999 |
| 89-94 | 87219-78111 |
| 79-88 | 109329-90144 |
| 64-87 | 169542-92303 |
| 44-62 | 326517-173239 |
| 1-42 | 1025009-334080 |
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The JEE Main score 2025 for Paper-1 and Paper-2 will be calculated differently. Mentioned below is the procedure for the calculation for both the papers.
Score of JEE Main = Number of correct answers x 4 – number of incorrect answers x 1
The percentile score will be the normalized score for JEE Main exam 2025 (instead of the raw marks of the candidate). The JEE Main 2025 percentile scores will be calculated up to 7 decimal places. NTA will use the following method to calculate the percentile score of a candidate:
100 * Number of candidates appeared in the ‘Session’ with raw score ‘Equal To Or Less’ than the candidate/Total number of the candidates appeared in the ‘Session'.
Ranks will be prepared based on the percentile scores of the candidates in JEE Main 2025 as mentioned above. However, there may be instances where more than two candidates may score the same marks. In such a case the inter-se-merit guidelines will be enforced to allot the rank.
JEE Main paper-2 is conducted in two shifts, the raw marks obtained by all the candidates who appeared in the first attempt will be declared. This shall comprise the actual marks obtained in Paper 2 of JEE (Main) 2025 for the first attempt.
The rank list will be prepared by merging the raw scores of the first and the second attempt. Candidates who have appeared in both the attempts; their best of the two raw marks will be considered. The total raw marks of both the attempts and rank of Paper-2 for all candidates will be declared. This shall comprise the total raw marks obtained by the candidate in the first attempt as well as in the second attempt along with All India rank and All India category rank. In case of a tie, inter-se merit will be determined in the following order.
Important Points of JEE Main Common Rank List
The common rank list of JEE Main will include candidates given ranks as per their performance but with a tag of GEN, GEN-PwD, OBC-NCL, OBC-NCL-PwD, SC, SC-PwD, ST or ST-PwD.
The category ranks will be separate from the JEE Main 2025 common rank list where the list will consist of the same category candidates assigned ranks based on their performance in JEE Main 2025.
Allotment will be based on CRL which is also called as the common rank list.
JEE Main 2025 new official website is jeemain.nta.nic.in.
As with the previous year, Section B does not contain any more optional questions. Applicants must sit for all 5 numerical questions in each subject.
The details of JEE Main 2025 exam pattern for Mathematics: Section A consists of 20 MCQs, Section B has 10 numerical problems. As mentioned earlier five numerical questions will be asked in section B wherein none of the questions will be covered in other questions of the same type. This pattern holds good for both Paper 1 (B.E./B.Tech) and Paper 2 (B.Arch/B.Planning).
JEE Main is held by the National Testing Agency which was set up in November 2017 exclusively for conducting entrance exams pertaining to higher education.
JEE Main 2025 will be a computer-based test and will be held twice a year
JEE Main Mock tests will be available on the official website.
As recommended by the Council of Architecture to NTA regarding JEE Main Paper II, candidates must secure at least 50% marks in the qualifying examination and 50% marks in PCM individually.
3400 Schools/ Engineering Colleges as Test Practice Centres (TPCs) are open for practice on the mock tests for free.
Each student will be assigned a unique paper from a large data bank prepared by experts.
Rank List will be prepared in May for JoSAA Counselling.
On Question asked by student community
Hello,
Yes, attendance is compulsory in Class XI and XII.
As per school and board rules, students must maintain minimum attendance, usually around 75%. Schools can stop students from appearing in board exams if attendance is short.
Even if a student is preparing for JEE or any other competitive exam
Hello,
You can find here the direct links to download the JEE Main last 10 years PYQ PDFs from the Official Careers360 website.
Kindly visit this link to access the question papers : Last 10 Years JEE Main Question Papers with Solutions PDF
Hope it helps !
Hello Harika,
Firstly, you cannot prepare for JEE in 8 days if you havent studied before. But still, You can try solving the previous year question papers. Here's a Link for the same
HELLO,
If you are from General category with 57 percent in 12th then to appear for JEE Advanced you need to be in top percentile of your board as the eligibility for JEE advanced you need at least 75 percent in 12th or in the top 20 percentile of your
Hello aspirant,
The JEE Main 2026 admission card will include information about the exam location. On the other hand, students can use the JEE Main 2026 city notification slip, which was made available on January 8, 2026, to check the exam city beforehand. The second week of January 2026 is
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