Careers360 Logo
ask-icon
share
    JEE Main: Differentiation and How To Calculate ‘e’

    JEE Main: Differentiation and How To Calculate ‘e’

    Ramraj SainiUpdated on 19 Apr 2024, 07:49 PM IST

    We all have come across the number ‘e’ while studying logarithm and calculus. This number is an irrational number like π, and is called Euler’s Number. Its value is 2.71828… and this sequence of digits never ends. So, how can we find this number and what is so special about this number?

    JEE Main: Differentiation and How To Calculate ‘e’
    Exponential-graph(Image:Wikimedia commons)

    A property that you must have studied in differentiation that stands out among all differentiation formulae is

    \frac{d}{dx}e^x=e^x

    So, the differentiation of the function f(x) = ex, is this function itself. This makes this function unique. We will be using this property to calculate the number ‘e’. So, in all the calculations below, we will not use ‘e’ directly.

    Let us start with the differentiation of a general exponential function, f(x) = 2x.

    Using First Principle of Differentiation, we know that the differentiation of a function f(x) is

    f'(x)=\lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}

    So, differentiation of f(x) = 2x will be

    \\f'(x)=\lim_{h\rightarrow 0}\frac{2^{x+h}-2^x}{h}\\\\f'(x)=\frac{2^x.2^h-2^x}{h}\\\\f'(x)=2^x\lim_{h\rightarrow 0}\frac{2^h-1}{h}.......equation(1)

    Now, when the value of the limit h→0 [(2h-1)/h] is calculated by putting different values of h that are very close to 0, we can see that the value of this expression approaches 0.693147…(Note that we are not directly using the value of this limit as ln(2), as the number ‘e’ and thus ln(x), which is log with the base ‘e’, is not yet known).

    Also Read,

    Let us see what values of [(2h-1)/h] we get by putting different values of h that are close to 0. We can use a calculator to find these values

    When h = 0.001, [(2h-1)/h] = 0.6933…

    When h = 0.0001, [(2h-1)/h] = 0.6931…

    When h = 0.00000001, [(2h-1)/h] = 0.6931…

    We can see that [(2h-1)/h] value approaches 0.6931…and hence

    limit h→0 [(2h-1)/h]= 0.6931…

    From equation (i):

    f'(x) = 2x.(0.6931…)

    So, differentiation of f(x) = 2x is of the form

    f'(x) =  Some constant. f(x)

    Now if we do the same procedure with f(x) = 4x

    \\f'(x)=\lim_{h\rightarrow 0}\frac{4^{x+h}-4^x}{h}\\\\f'(x)=\frac{4^x.4^h-4^x}{h}\\\\f'(x)=4^x\lim_{h\rightarrow 0}\frac{4^h-1}{h}.......equation(2)

    When h = 0.001, [(4h-1)/h] = 1.3872…..

    When h = 0.0001, [(4h-1)/h] = 1.38631…

    When h = 0.00000001, [(4h-1)/h] = 1.38629…

    So, limit h→0 [(4h-1)/h] = 1.38629…

    And from (ii),

    f'(x) =  4x . (1.38629…)

    So, differentiation of f(x) = 4x is again of the form

    f'(x) =  Some constant. f(x)

    In fact, we can do the same exercise for any positive real number a, and we will find that the differentiation of f(x) = ax equals some constant times ax

    It can also be seen that the value of this constant keeps on increasing as the value of ‘a’ increases. For example

    For a = 2, the constant we calculated was 0.6931…

    For a = 4, the constant we calculated was 1.38629…

    Similarly, for a = 5, the constant can be calculated to be 1.6094…

    For a = 6, the constant is 1.7917…

    So naturally we can ask ourselves the question that can we find a number ‘a’ for which this constant value equals 1, and thus differentiation of ax is 1. ax, meaning that the differentiation of the function ax is this function itself ( = ax)

    After doing multiple hits and trials, this number can be found to be 2.71828. That is why we have the unique property,

    d/dx(ex)= ex

    Euler’s Number also finds applications in fields of mathematics other than calculus. One of the most important applications is in Complex Numbers. You must have come across the relation eiπ = - 1. Imaginary powers of e help us get the values of many trigonometric series which would otherwise be very difficult to prove using only the trigonometric relations. The number is also used in Finance (to calculate compound interest), to explain population growth of humans or microbes, to explain radioactive decay (which in turn is used to tell the age of ancient objects), etc.

    Due to numerous applications, ‘e’ is the second most famous mathematical constant after π. We also celebrate ‘e-day’ on 7 February. This date is chosen as it is written as 2/7 in month/date format and the digits 2,7 represent the first two digits used in the value of ‘e’ (2.71…).

    Articles
    |
    Upcoming Engineering Exams
    Certifications By Top Providers
    Online Certificate Course on Cyber Laws
    Via Indian Law Institute, New Delhi
    Basic Programming using Python
    Via Indian Institute of Technology Bombay
    Software Engineering Essentials
    Via Technical University of Munich, Munich
    Material Science
    Via Indira Gandhi National Open University, New Delhi
    B.Tech Engineering Technology
    Via Birla Institute of Technology and Science, Pilani
    Principles of Digital Communications
    Via Indian Institute of Technology Delhi
    Udemy
     1525 courses
    Swayam
     817 courses
    NPTEL
     773 courses
    Coursera
     697 courses
    Edx
     608 courses
    Explore Top Universities Across Globe

    Questions related to JEE Main

    On Question asked by student community

    Have a question related to JEE Main ?

    Yes, with a rank of 1 to 3 lakh in OBC-NCL, you may elligible for to participate in OJEE 2026 counselling . OJEE counselling primarily uses the JEE Main Common Rank List for seat allocation; it also considers OBC-NCL category ranks for state reservation benefits. If your OBC-NCL rank is

    The result date for JEE Main session 2 is April 20, 2026.

    Both the coaching institutions are well known for their JEE classes. Based on online reviews, Vibrant Academy is known to offer classes with a higher focus on JEE Advanced, meaning tougher maths and physics questions. Whereas Motion is known for a balanced approach between JEE Main and JEE Advanced.
    You

    Hi Bhanu Pratap,

    You can get JEE Mains 2026 Hindi Medium memory based question and answers from the link provided below.

    Link: https://engineering.careers360.com/hi/articles/jee-main-question-paper-hindi-medium

    The expected rank on 100 marks in JEE Advanced 2018 was 8000-12000 rank. You can check the JEE Advanced rank predictors to know better - https://engineering.careers360.com/jee-advanced-rank-predictor