HBTU Kanpur JEE Mains Cutoff 2025: Expected Ranks and Trends

Centripetal Force For Non-uniform Circular Motion - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • 4 Questions around this concept.

Solve by difficulty

A body of mass m= 1kg is moving in a circular path of radius 50m. Its speed is increasing with the rate of 2m/s2.Then what is the rate of  work done when speed of body is 5m/s:

 

Concepts Covered - 1

Force in non-uniform Circular Motion

$\begin{aligned} & F_c=m a_c=\frac{m v^2}{r} \quad\left(\vec{F}_c \perp \vec{v}\right) \\ & \mathrm{F}_{\mathrm{t}}=m \mathrm{a}_{\mathrm{t}} \\ & F_{n e t}=m \sqrt{a_c^2+a_t^2} \\ & \mathrm{~m}=\text { mass } \\ & \mathrm{a}_{\mathrm{c}}=\text { centripetal acceleration } \\ & \mathrm{a}_{\mathrm{t}}=\text { tangential acceleration } \\ & \mathrm{F}_{\mathrm{c}}=\text { centripetal force }\end{aligned}$

Study it with Videos

Force in non-uniform Circular Motion

"Stay in the loop. Receive exam news, study resources, and expert advice!"

Get Answer to all your questions

Back to top