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6 Questions around this concept.
A ball of mass $0.20 kg$ hits a wall at an angle of $45^{\circ}$ with a velocity of $25 \mathrm{~m} / \mathrm{s}$. If the ball rebounds at $90^{\circ}$ to the direction of incidence with the same speed. Calculate the magnitude of change in momentum of the ball.
A ball is thrown vertically up (taken as + z-axis) from the ground . The correct momentum -height (p-h) diagram is :
Linear momentum of a body is the quantity of motion contained in the body.
It is measured in terms of the force required to stop the body in unit time.
. If a body of mass $m$ is moving with velocity $\vec{v}$, then its linear momentum $\vec{p}$ is given by $\vec{p}=m \vec{v}$.
4. It is a vector quantity and its direction is the same as the direction of the velocity of the body.
5. S.I. Unit : kg-m/sec
6. Dimension- $\mathrm{MLT}^{-1}$
7. If two objects of different masses have the same momentum, the lighter body possesses greater velocity.
As $\mathrm{p}=\mathrm{m}_1 \mathrm{v}_1=\mathrm{m}_2 \mathrm{v}_2=$ constant
$$
\therefore \frac{V_1}{V_2}=\frac{m_2}{m_1} \Rightarrow V \alpha \frac{1}{m}
$$
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