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    How to Prepare for 12th Board Exams, JEE Main & JEE Advanced Simultaneously?

    Equilibrium Of Concurrent Forces - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • Equilibrium of concurrent forces is considered one of the most asked concept.

    • 24 Questions around this concept.

    Solve by difficulty

    A light spring balance hangs from the hook of the other light spring balance and a block of mass M Kg hangs from the former one. Then the true  statement about the scale reading is :

    Three forces start acting simultaneously on a particle moving with velocity $\vec{v}$. These forces are represented in magnitude and direction by the three sides of a triangle ABC (as shown ). The particle will now move with velocity

    A car is moving on a plane inclined at $30^a$ to the horizontal with an acceleration of $10 \mathrm{~ms}^{-2}$ parallel to the plane upward. A bob is suspended by a string from the roof of the car. The angle in degrees which the string makes with the vertical is: (Take $\mathrm{g}=10 \mathrm{~ms}^{-2}$ )

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    When a body is in equilibrium 

     

    A body of mass $m$ is suspended by two strings making angles $\theta_1$ and $\theta_2$ with the horizontal ceiling with tensions $\mathrm{T}_1$ and $\mathrm{T}_2$ simultaneously. $\mathrm{T}_1$ and $\mathrm{T}_2$ are related by $T_1=\sqrt{3} T_2$. the angles $\theta_1$ and $\theta_2$ are


     


    A body of mass 1 kg is suspended with the help of two strings making angles as shown in figure. Magnitude of tensions $T_1$ and $T_2$, respectively, are (in N ):

    Concepts Covered - 1

    Equilibrium of concurrent forces

     

    • Concurrent Forces-If all the forces working on a body are acting on the same point then they are said to be concurrent. 

    • Three forces will be in equilibrium if they are represented by three sides of a triangle taken in order.

           

    • For equilibrium, 

    $\begin{aligned} & \sum \overrightarrow{F_{n e t}}=0 \\ & \text { or } \sum \vec{F}_x=0, \sum \vec{F}_y=0, \sum \vec{F}_z=0\end{aligned}$

    • Lami’s theorem: It states that for three concurrent forces in equilibrium,

                                    

                         $\frac{F_1}{\sin \alpha}=\frac{F_2}{\sin \beta}=\frac{F_3}{\sin \gamma}$

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    Equilibrium of concurrent forces

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