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    Acceleration Of Block On Horizontal Smooth Surface - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • 13 Questions around this concept.

    Solve by difficulty

    A body of mass 0.3 kg is being pulled by a horizontal force P= 4 N. If the body is just tending to move then what is the value of the resultant force exerted by the surface on block?

    A rocket is fired vertically from the earth with an acceleration of 2g, where g is the gravitational acceleration.  On an inclined plane inside the rocket, making an angle θ with the horizontal, a point object of mass m is kept.  The minimum coefficient of friction µmin between the mass and the inclined surface such that the mass does not move is :

    A body of mass m is placed on a weighing machine placed in lift is moving upward with acceleration a then the apparent weight of the body is  

    In the arrangement shown in the figure, the strings are light and inextensible.

    Find the acceleration of each block.

    Concepts Covered - 1

    Acceleration of Block on horizontal smooth surface
    • Free Body Diagram (FBD)

    In this diagram, the object of interest is isolated from its surroundings and the interactions between the object and the surroundings are represented in terms of forces.

    After drawing FBD, Choose the axes and write the equation of motion. This is very helpful while solving questions.

    Example- 

    1. When the pull is horizontal, and no friction

                       

    Balance forces

    the body is moving along the $x$-axis

    $
    \begin{aligned}
    & \because F_y=0 \\
    & R=m g \quad \& \quad F=m a \\
    & a=\frac{F}{m}
    \end{aligned}
    $
     


     

    1. Pull Acting at Angle (Upward)

                        

    Balancing forces in both X and Y directions,

    $
    \begin{aligned}
    & R+F \sin \theta=m g \\
    & R=m g-F \sin \theta \text { along } \mathrm{Y} \text {-axis } \\
    & F \cos \theta=m a \text { along } \mathrm{X} \text {-axis } \\
    & a=\frac{F \cos \theta}{m}
    \end{aligned}
    $
     

    1. Push Acting at Angle (Downward)

                        

    Balancing forces in both X and Y directions, $R=m g+F \sin \theta$ along Y -axis $a=\frac{F \cos \theta}{m}$ along X -axis

     

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    Acceleration of Block on horizontal smooth surface

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