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Acceleration Of Block On Smooth Inclined Plane - Practice Questions & MCQ
Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main
Quick Facts
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Acceleration of Block on Smooth Inclined Plane is considered one of the most asked concept.
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33 Questions around this concept.
Solve by difficulty
Two fixed frictionless inclined planes making an angle 30° and 60° with the vertical are shown in the figure. Two blocks A and B are placed on the two planes. What is the relative vertical acceleration of A with respect to B?
In the figure shown the acceleration of A is $\vec{a}_A=15 i+15 j$ then the acceleration of $B$ is: (A remains in contact with B)
For no friction to act on a block kept on an accelerating wedge as shown in figure, acceleration of the wedge should be
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in above case, what is Component of acceleration along y or perpendicular to inclined plane?
The system shown in figure are in equilibrium . What is the reading of spring balance . (g = 10 m/s 2)
Concepts Covered - 1
Acceleration of Block on Smooth Inclined Plane
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When an Inclined Plane is at rest
$R=m g \cos \theta$ along with normal to the incline $m g \sin \theta=m a$ along the incline $a=g \sin \theta$
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When an Inclined Plane is given Acceleration 'b'
$
\begin{aligned}
& R=m g \cos \theta+m b \sin \theta \\
& m a=m g \sin \theta-m b \cos \theta \\
& a=g \sin \theta-b \cos \theta
\end{aligned}
$
* Condition for the body to be at rest relative to the inclined plane.
$
\begin{aligned}
a & =g \sin \theta-b \cos \theta=0 \\
b & =g \tan \theta
\end{aligned}
$
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