VIT - VITEEE 2025
National level exam conducted by VIT University, Vellore | Ranked #11 by NIRF for Engg. | NAAC A++ Accredited | Last Date to Apply: 31st March | NO Further Extensions!
16 Questions around this concept.
There are two forces; their magnitude’s summation is 40 N and the resultant of them is 20N; The resultant force is perpendicular to the smaller force; The magnitudes of their forces are :
Assertion: When two perpendicular forces are there and the sum of their magnitude is 20N; Then the resultant of these forces is 14.42 N
Reason: Value of two forces 12 and 8
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If external force a system is zero then which of the following is not true
The point where net force is assumed to be acting is defined as
In which of the following cases forces are not required to keep the
WHich of the following is conservative force
National level exam conducted by VIT University, Vellore | Ranked #11 by NIRF for Engg. | NAAC A++ Accredited | Last Date to Apply: 31st March | NO Further Extensions!
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A vertical spring with force constant 'k' is fixed on a table. A ball of mass 'm' at height 'h' above the free upper end of the spring falls vertically on the spring so that the spring is compressed by a distance d. The net work done in the process is.
Definition- Force is defined as an effect which causes a body to change its state.
Force on 1 kg mass in the presence of gravity $\left(g=9.8 \mathrm{~m} / \mathrm{s}^2\right)$ is 1 kg-f=9.8 N
Unit of force-
1 Newton(N) is the force needed to accelerate an object with a mass of 1 kg at a rate of 1 m/s2 (1 N = 1 kg · m/s2)
2. Types of forces-
a) Contact forces-
Contact forces are due to direct physical contact between objects.
Types of contact forces-
b) Non-contact forces-
These forces act without the necessity of physical contact between objects.
They depend on the presence of a “field” in the region of space surrounding the body under consideration.
Types of non-contact forces-
Note:- Gravitational and Electrostatic force have infinite range
c) Weak forces-
Vanderwaal force
d) Nuclear forces
$
\begin{aligned}
& F_{\text {nuclear }}>F_{\text {electro }}>F_{\text {gravitation }} \\
& F_e / F_g=10^{43}
\end{aligned}
$
Therefore, $F_e \gg F_g$
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