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JEE Main, BITSAT Compared: What Your Preparation Strategy Should Be

JEE Main, BITSAT Compared: What Your Preparation Strategy Should Be

Edited By Ramraj Saini | Updated on Apr 19, 2024 07:06 PM IST | #JEE Main

Birla Institute of Technology and Science Aptitude Test (BITSAT) is conducted for the admissions in the campuses of Birla Institute of Technology and Science (BITS) at Pilani, Goa and Hyderabad. Almost all the candidates who appear for BITSAT sit for the Joint Entrance Examination Main (JEE Main) as well, which makes the former more competitive than the latter. This article will throw light on the commonalities and the differences between JEE Main and BITSAT which will help the candidates to prepare well for both the examinations simultaneously.

JEE Main, BITSAT Compared: What Your Preparation Strategy Should Be
JEE Main, BITSAT Compared: What Your Preparation Strategy Should Be

JEE Main: Introduction

The Joint Entrance Examination Main (JEE Main) is the first of the two stages of JEE Advanced, a national-level entrance examination. JEE Main serves as a gateway for admission into National Institutes of Technology (NITs) Indian Institutes of Information Technology (IIITs) and government-funded technical institutions (GFTIs). JEE Main is written by students who intend to study engineering, basic sciences or architecture in some of the top colleges of the country. It also serves as a screening stage for JEE Advanced which is a gateway for admission in the undergraduate (BTech) and integrated postgraduate (BTech-MTech) programmes in the Indian Institutes of Technology (IITs).

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JEE Main is conducted by the National Testing Agency and JEE Advanced by one of the IITs each year, under the aegis of the Joint Admission Board (JAB). In 2023, the organising institute for JEE Advanced was IIT Guwahati and for 2024, it will be IIT Madras.

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BITSAT: Introduction

BITSAT is a national-level entrance examination conducted by the Birla Institute of Technology and Science for admission to undergraduate and integrated postgraduate programmes such as BE, BPharma, and Integrated MSc at BITS Pilani and other campuses. In this article the comparison is done only for BE programmes.

JEE Main, BITSAT: Exam Patterns

The JEE Main pattern was modified recently and numerical answer questions (questions having no options and numerical value of answer has to be entered in the input box using an on-screen keyboard) have been introduced in the examination.

In JEE Main, there are a total of 90 questions in which students have to attempt 75 questions in 3 hours. The JEE Main has three subjects:

  • Physics

  • Chemistry

  • Maths

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JEE Main contains two sections for every subject. Section 1 contains 20 Multiple Choice Questions (MCQs) while Section 2 contains 10 Numerical response questions out of which only 5 have to be attempted.

As per the latest exam pattern 2024, BITSAT is a three-hour long examination with a total of 130 questions. There are four sections in the paper:

  • Part I : Physics
  • Part II : Chemistry
  • Part III : (a) English Proficiency and (b) Logical Reasoning
  • Part IV : Mathematics or Biology (For B.Pharm. candidates)
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A student appearing for the BITSAT examination has to choose between Biology and Mathematics for the last section. There are 30 questions on Physics; 30 on Chemistry; 20 on Logical Reasoning and 10 questions on English Proficiency; and 40 questions on Maths or Biology.

The BITSAT paper also includes 12 bonus questions, four from each in Physics, Chemistry, Maths or Biology and logical reasoning. These additional questions can be attempted only after the candidate has attempted all the 130 questions. If a candidate opts for the bonus questions, he/she cannot edit the answers to the first 130 questions. No extra time is given for attempting the bonus questions.

Almost all who want to score 390 or higher on the BITSAT — necessary for a seat in Computer Science in any of the BITS — (CS in any of the BITS) attempt the 12 bonus questions. These 12 additional questions are only available after you've completed the main part.

JEE Main, BITSAT: Differences And Similarities

Both JEE Main and BITSAT exams are now computer-based. Candidates have to write them at designated exam centres. JEE Main was held twice in the years 2021, 2023, and 2024 and the best score out of the attempts was taken into consideration for the merit or rank list. BITSAT is organized in two session in 2024, the higher of the two scores will be considered for admission.

While JEE Main is for admission in government engineering colleges, central and also for several states. BITSAT is only for the various campuses of one of the private colleges in India.

Over 11.62 lakh candidates registered for the two sessions of JEE Main in 2023 and about 11.13 lakh appeared in the examination. As per the JoSAA seat matrix, the total seats are 49085 including 17385 in IITs, while the number of seats in NITs and IIITs are 23954 and 7746 respectively in 2024. In comparison, BITSAT 2023 attracted around 2 lakh aspirants who competed for around 2000 seats.

The level of difficulty of JEE Main is higher than that of BITSAT since the questions in JEE Main are more concept-based. However, the BITSAT contains more questions and its candidates are usually more pressed for time.

The marking schemes are also different. In JEE Main, each correct answer fetches 4 marks and each wrong answer leads to the candidate losing one mark in negative marking. In BITSAT, each correct answer fetches 3 marks and each incorrect answer leads to the docking of one mark in negative marking.

In the case of JEE Main, the paper and solution are published on the official website for students to examine. Students can also ask for a review of the answer key once it has been posted on the official website, jeemain.nta.nic.in. In the case of BITSAT, the scores are displayed immediately once the exam is over.

BITSAT Vs JEE Main: Subject-Wise Preparation Strategy

BITSAT questions are easier than JEE Main and require recollection of the appropriate formulae. The questions asked in JEE Main are more conceptual and require deep knowledge of concepts and techniques. So, a student preparing for JEE Main can easily appear for the BITSAT exam as well. The major difference in the syllabus of the two exams is the presence of English Proficiency and Logical Reasoning in the BITSAT.

Given below are comparisons of questions in the two exams by subject.

PHYSICS

Syllabus Comparison

The syllabus for Physics is almost the same for BITSAT and JEE Main except that the chapter Experimental Lab Skills are present in JEE Main but absent in BITSAT. All remaining chapters from Class 11 and Class 12 Physics textbooks of the National Council for Educational Research and Training (NCERT) are relevant to both the examinations. Students preparing for BITSAT and appearing for JEE Main should prepare these topics well.

Weightage Comparison

For BITSAT, focus more on Mechanics as a huge percentage of the questions are from that topic. Topics such as Modern Physics, Current, Optics, and Electrostatics also claim considerable weightage. One should refer to a good reference book for Physics to get a good grip on the concepts and formulae.

Following is the detailed chapter-wise comparison between the two exams.

JEE Main Vs BITSAT Physics Chapter Wise Comparison

Physics - Class 11 NCERT

JEE Main

BITSAT

Units And Measurements

Motion In A Straight Line

Motion In A Plane

Laws Of Motion

Work, Energy And Power

System Of Particles And Rotational Motion

Gravitation

Mechanical Properties Of Solids

Mechanical Properties Of Fluids

Thermal Properties Of Matter

Thermodynamics

Kinetic Theory

Oscillations

Waves

Physics - Class 12 NCERT

JEE Main
BITSAT

Electric Charges And Fields

Electrostatic Potential And Capacitance

Current Electricity

Moving Charges And Magnetism

Magnetism And Matter

Electromagnetic Induction

Alternating Current

Electromagnetic Waves

Ray Optics And Optical Instruments

Wave Optics

Dual Nature Of Radiation And Matter

Atoms

Nuclei

Semiconductor Electronics

Communication Systems

Experimental Skills

CHEMISTRY

Syllabus Comparison

The Chemistry syllabus of both exams includes all the topics and chapters included in the NCERT textbooks of Classes 11 and 12. A few chapters such as Solid State, Surface Chemistry and Environmental Chemistry etc. are present in BITSAT but absent from JEE Main. The level of questions asked in the examinations may vary as questions in JEE Main require more conceptual strength and BITSAT requires more application of formulae.

Weightage Comparison

In BITSAT, Organic Chemistry has a good weightage followed by Inorganic Chemistry. Some additional topics such as Biomolecules, Chemistry in Everyday Life, and Metallurgy should be studied in depth.

In the following table, the detailed syllabus comparison between the two exams is mentioned.

JEE Main Vs BITSAT Chemistry Chapter Wise Comparison

Chemistry - Class 11 NCERT

JEE Main

BITSAT

Some Basic Concepts Of Chemistry

Structure Of Atom

Classification Of Elements And Periodicity In Properties

Chemical Bonding And Molecular Structure

States Of Matter

Thermodynamics

Equilibrium

Redox Reactions

Hydrogen

The s - Block Elements

The p - Block Elements

Organic Chemistry Some Basic Principles And Techniques

Hydrocarbons

Environmental Chemistry

Chemistry - Class 12 NCERT

JEE Main

BITSAT

Solid States

Solutions

Electrochemistry

Chemical Kinetics

Surface Chemistry

General Principle And Processes Of Isolation Of Elements

The p-Block Elements

The d-And f-Block Elements

Coordination Compounds

Haloalkanes And Haloarenes

Alcohols, Phenols And Ethers

Aldehydes, Ketones And Carboxylic Acids

Amines

Biomolecules

Polymers

Chemistry In Everyday Life

MATHEMATICS

Syllabus Comparison

A few chapters such as Linear Programming, Mathematical modeling and Linear Inequalities are not included in the JEE Main syllabus but are asked in BITSAT.

Weightage Comparison

Students should focus on Calculus, Complex Numbers, Statistics, Vectors, and Trigonometry as these chapters and topics constitute a large section of the Mathematics section of BITSAT.

In the following table, the detailed chapter wise compassion is being done.

JEE Main Vs BITSAT Maths Chapter Wise Comparison

Maths - Class 11 NCERT

JEE Main

BITSAT

Sets

Relations And Functions

Trigonometric Functions

Principle Of Mathematical Induction

Complex Numbers And Quadratic Equations

Linear Inequalities

Permutations And Combinations

Binomial Theorem

Sequence And Series

Straight Lines

Conic Sections

Introduction To Three Dimensional Geometry

Limits And Derivatives

Mathematical Reasoning

Statistics

Probability

Maths - Class 12 NCERT

JEE Main

BITSAT

Relations And Functions

Inverse Trigonometric Functions

Matrices

Determinants

Continuity And Differentiability

Application Of Derivatives

Integrals

Application Of Integrals

Differential Equations

Vector Algebra

Three Dimensional Geometry

Linear Programming

Probability

Is BITSAT Easier Than JEE Main?

Yes, studying for JEE Main is sufficient for BITSAT. The syllabi of both exams are nearly the same as that of Class 11 and Class 12 Science stream.

The sole distinction to be kept in mind during JEE and BITSAT preparation is the pattern of question papers. The candidate should extensively practice questions from different reference books. Practicing mock question papers will familiarise a student with different types of questions, the marking method, and significant themes. A decent grasp of English and logical reasoning are required for the BITSAT.

A good BITSAT score of 312 out of 390 (80%) is considered satisfactory. In 2023, 331 was the cutoff for B.E. Computer Science in Pilani campus. where as cut of for JEE main 2022 and 2023 given below.

Category/Year

General(%)

OBC(%)

SC(%)

ST(%)

202390.778864273.611422751.977602737.2348772
202288.412138367.009029743.082095426.7771328

How Should One Prepare?

BITSAT consists of more questions to be attempted within three hours, which makes it more of a speed test. One must attempt mock test papers for both the exams as their paper patterns are different. Students should follow accuracy and time management practices to perform better in the examinations. Prepare a strategy of attempting the paper in an order that suits you and helps you in maximizing the score.

Some suggestions are:

a) Make a study timetable and stick to it

b) Study the concepts thoroughly from NCERT books

c) Use good reference books to gain knowledge and practise problems

d) Do regular self-study and analyze your strengths and weaknesses

e) Make revision notes so that it is easier to revise the concepts just before the examination

f) Prepare English and Logical Reasoning for BITSAT as the other subjects are also covered in JEE Main syllabus.

g) Attempt mock tests

h) Improve time management skills

i) Prepare a strategy to attempt the paper.

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Questions related to JEE Main

Have a question related to JEE Main ?

There is no requirement to have Physics, Chemistry, and Math (PCM) in 12th to appear for JEE Mains 2025. You must have passed the class 12 exam in 2023, 2024, or 2025 .You need to have studied at least five subjects in your qualifying exam, with Physics, Chemistry, and Mathematics being mandatory. This means your PCB combination fulfills the Physics and Chemistry requirement.

Since you haven't studied Math in 12th, you need to put in extra effort to build a strong foundation in Mathematics, which is a crucial subject for JEE Mains.Qualifying for JEE Advanced, which allows admission to IITs, requires Mathematics at the 12th-grade level.

https://engineering.careers360.com/download/ebooks/jee-main-2022-preparation-tips

I hope it helps!


Alliance University Bangalore doesn't specify a single entrance exam for this program on their official website. Here are the possibilities:

  • Alliance University Scholastic Aptitude Test (AUSAT): This is the university's own entrance exam. It's a possibility for admission to various undergraduate programs, including engineering.

  • JEE Main/Advanced: These national-level engineering entrance exams are widely accepted by many universities in India. While not explicitly mentioned, Alliance might consider JEE scores for B.Tech. programs.

  • Other State or National Level Engineering Entrance Exams: Some states might have their own engineering entrance exams, and Alliance could potentially accept scores from those as well.

  • Merit-Based Admission: In some cases, Alliance might grant admission based solely on your Class 12th marks (depending on availability of seats).

    https://www.careers360.com/university/alliance-university-bangalore

    I hope it helps!

A simple refresh of the page can sometimes resolve temporary glitches causing the session to expire. Try refreshing the webpage and see if you can regain access.

Sometimes, accumulated cache and cookies in your browser can interfere with website functionality. Try clearing your browser's cache and cookies, then restarting your browser and logging back in to the JoSAA portal.

If refreshing and clearing cache don't work, you can try logging out completely and then logging back in with your JoSAA credentials. This can sometimes reset your session and allow you to continue.


Occasionally, the JoSAA portal might undergo scheduled maintenance, which could cause temporary inaccessibility. Check the JoSAA website for any announcements about maintenance periods.

If none of the above solutions work immediately, there might be a temporary technical issue with the JoSAA portal. Wait for a while (maybe an hour or two) and try logging in again later.

https://engineering.careers360.com/download/ebooks/josaa-what-you-need-to-know

I hope it helps!

No, directly floating your choices to get a higher preference in subsequent JoSAA counselling rounds isn't guaranteed.

JoSAA uses a demand-filling process. In each round, it allocates seats based on candidate preferences, institute/branch choices, and candidate ranks.

If you don't get any of your higher choices (including your 1st choice) in a round, and a seat is available in one of your lower choices (like your 4th choice), JoSAA might allocate that seat to you.

However, there is no guarantee that your 1st choice will become available in later rounds.

During the second round (or any subsequent round), you'll have the option to either freeze your allocated seat (4th choice) or float it. Floating means you're willing to give up your current seat for a chance at a higher preference in the next round.

If you are happy with your allocated seat (4th choice) and don't mind attending that college/branch, you can lock it (freeze). Consider how likely it is for your 1st choice to become available in the next rounds. If the seats for your 1st choice are filling quickly, floating might be a gamble. You might end up with no seat at all in the next round. Floating involves some risk. You might lose your current seat (4th choice) and not get your 1st choice either. Locking secures your current seat but eliminates the possibility of getting your 1st choice.

I hope it helps!

You are eligible for JEE Advanced for two consecutive years starting from the year you appear for your Class 12 board exams.

You gave your 12th board exams in 2024 and attempted JEE Advanced in the same year (2024). You then took a drop and didn't appear for JEE Advanced in 2025. Since you haven't exhausted your two attempts yet, you can appear for JEE Advanced in 2026.


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 5 g of Na2SO4 was dissolved in x g of H2O. The change in freezing point was found to be 3.820C.  If Na2SO4 is 81.5% ionised, the value of x (Kf for water=1.860C kg mol−1) is approximately : (molar mass of S=32 g mol−1 and that of Na=23 g mol−1)
Option: 1  15 g
Option: 2  25 g
Option: 3  45 g
Option: 4  65 g  
 

 50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl.  If pKb of ammonia solution is 4.75, the pH of the mixture will be :
Option: 1 3.75
Option: 2 4.75
Option: 3 8.25
Option: 4 9.25
 

CH_3-CH=CH-CH_3+Br_2\overset{CCl_4}{\rightarrow}A

What is A?

Option: 1

CH_3-CH(Br)-CH_2-CH_3


Option: 2

CH_3-CH(Br)-CH(Br)-CH_3


Option: 3

CH_3-CH_2-CH_2-CH_2Br


Option: 4

None


\mathrm{NaNO_{3}} when heated gives a white solid A and two gases B and C. B and C are two important atmospheric gases. What is A, B and C ?

Option: 1

\mathrm{A}: \mathrm{NaNO}_2 \mathrm{~B}: \mathrm{O}_2 \mathrm{C}: \mathrm{N}_2


Option: 2

A: \mathrm{Na}_2 \mathrm{OB}: \mathrm{O}_2 \mathrm{C}: \mathrm{N}_2


Option: 3

A: \mathrm{NaNO}_2 \mathrm{~B}: \mathrm{O}_2 \mathrm{C}: \mathrm{Cl}_2


Option: 4

\mathrm{A}: \mathrm{Na}_2 \mathrm{OB}: \mathrm{O}_2 \mathrm{C}: \mathrm{Cl}_2


C_1+2 C_2+3 C_3+\ldots .n C_n=

Option: 1

2^n


Option: 2

\text { n. } 2^n


Option: 3

\text { n. } 2^{n-1}


Option: 4

n \cdot 2^{n+1}


 

A capacitor is made of two square plates each of side 'a' making a very small angle \alpha between them, as shown in the figure. The capacitance will be close to : 
Option: 1 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{\alpha a }{4 d } \right )

Option: 2 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 + \frac{\alpha a }{4 d } \right )

Option: 3 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{\alpha a }{2 d } \right )

Option: 4 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{3 \alpha a }{2 d } \right )
 

 Among the following compounds, the increasing order of their basic strength is
Option: 1  (I) < (II) < (IV) < (III)
Option: 2  (I) < (II) < (III) < (IV)
Option: 3  (II) < (I) < (IV) < (III)
Option: 4  (II) < (I) < (III) < (IV)
 

 An ideal gas undergoes a quasi static, reversible process in which its molar heat capacity C remains constant.  If during  this process the relation of pressure P and volume V is given by PVn=constant,  then n is given by (Here CP and CV are molar specific heat at constant pressure and constant volume, respectively)
Option: 1  n=\frac{C_{p}}{C_{v}}


Option: 2  n=\frac{C-C_{p}}{C-C_{v}}


Option: 3 n=\frac{C_{p}-C}{C-C_{v}}

Option: 4  n=\frac{C-C_{v}}{C-C_{p}}
 

As shown in the figure, a battery of emf \epsilon is connected to an inductor L and resistance R in series. The switch is closed at t = 0. The total charge that flows from the battery, between t = 0 and t = tc (tc is the time constant of the circuit ) is : 


Option: 1 \frac{\epsilon L }{R^{2}} \left ( 1 - \frac{1}{e} \right )
Option: 2 \frac{\epsilon L }{R^{2}}


Option: 3 \frac{\epsilon R }{eL^{2}}

Option: 4 \frac{\epsilon L }{eR^{2}}
 

As shown in the figure, a particle of mass 10 kg is placed at a point A. When the particle is slightly displaced to its right, it starts moving and reaches the point B. The speed  of the particle at B is x m/s. (Take g = 10 m/s2 ) The value of 'x' to the nearest is ___________.
Option: 1 10
Option: 2 20
Option: 3 40
Option: 4 15

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