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    Explain parametric equation of a circle. - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • 23 Questions around this concept.

    Solve by difficulty

    Write the equation of the circle in the following diagram : 

     

     

    The parametric equation of the circle $x^{2}+y^{2}+2x-4y+1= 0$ is

    Concepts Covered - 1

    Parametric Form of circle and Concentric Circle.

    Parametric Form

    To represent any point on a curve in terms of a single variable (parameter), we use parametric form of that curve.
    1. Parametric Form for $x^2+y^2=r^2$
    $P(x, y)$ is a point on the circle $x^2+y^2=r^2$ with centre $O(0,0)$. And $O P$ makes an angle $\theta$ with the positive direction of $X$-axis, then $x=r \cdot \cos \theta, y=r \cdot \sin \theta$ called the parametric equation of the circle.
    Here as $\theta$ varies, the point on the circle also changes, and thus $\theta$ is called the parameter. Here $0 \leq \theta<2 \pi$.
    So any arbitrary point on this circle can be assumed as (r. $\cos \theta, r \cdot \sin \theta)$


    2. Parametric Form for $(x-h)^2+(y-k)^2=r^2$

    Centre of the circle here is $(h, k)$
    Parametric point on it is $(\mathrm{h}+\mathrm{r} \cdot \cos \theta, \mathrm{k}+\mathrm{r} \cdot \sin \theta)$

    Concentric Circles

    Two circles having common centre $\mathrm{C}(\mathrm{h}, \mathrm{k})$ but different radii $r_1$ and $\mathrm{r}_2$ are called concentric circles

    $
    \begin{aligned}
    & S_1=(x-h)^2+(y-k)^2=r_1^2 \\
    & S_2=(x-h)^2+(y-k)^2=r_2^2 \\
    & r_1 \neq r_2 \\
    & \mathrm{~S}_1 \text { and } \mathrm{S}_2 \text { are concentric circle }
    \end{aligned}
    $

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    Parametric Form of circle and Concentric Circle.

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    Books

    Reference Books

    Parametric Form of circle and Concentric Circle.

    Mathematics for Joint Entrance Examination JEE (Advanced) : Coordinate Geometry

    Page No. : 4.10

    Line : 8

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