Amrita Vishwa Vidyapeetham | B.Tech Admissions 2025
ApplyRecognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships | Extended Application Deadline: 30th Jan
3 Questions around this concept.
Find out the value of $\operatorname{Sin} \theta$ in the given figure where a zig-zag tube open at N having liquids of densities $\rho_1, \rho_2, \rho_3$ and is placed in a vertical plane as shown in the figure. (The pressure at M is equal to atmospheric pressure.)
Barometer-
Mercury Barometer was invented by Torricelli and it is a device used for measuring pressure.
Below is a figure showing the Mercury Barometer device
From the figure we can say that
At Point C only atmospheric pressure is there.
So $P_C=P_0$
Ans since $B$ and $C$ are at the same horizontal level
So $P_C=P_B=P_A+\rho g h=0+\rho g h=\rho g h=P_0=$ Atmospheric pressure
For mercury barometer $\mathrm{h}=76 \mathrm{~cm}$ and
And using $\rho=13.6 * 10^3 \mathrm{~kg} / \mathrm{m}^3$
We get $P_0=1.013 * 10^5 \mathrm{~N} / \mathrm{m}^2=1 \mathrm{~atm}=76 \mathrm{~cm}$ of Hg
Manometer-
Manometers are the devices used for measuring gauge pressure of fluids.
Simple Manometer-
The figure of Simple Manometer is given below
And from the figure we can say that
The gauge pressure at point A in the vessel is
$P_A=\rho g h$
Where =density of the liquid
U-tube Manometer-
Figure of U-tube manometer is given below
And from the figure we can say that
$
P_A=P_B
$
And The gauge pressure at point A is given by
$
P_A=\rho g h
$
Where
=density of the liquid
"Stay in the loop. Receive exam news, study resources, and expert advice!"