JEE Mains 2025 Answer Key Release Date for Session 1 - Check NTA Update

Barometer And Manometer - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • 3 Questions around this concept.

Solve by difficulty

Find out the value of $\operatorname{Sin} \theta$ in the given figure where a zig-zag tube open at N having liquids of densities $\rho_1, \rho_2, \rho_3$ and is placed in a vertical plane as shown in the figure. (The pressure at M is equal to atmospheric pressure.)

 

                                                

Concepts Covered - 1

Barometer and Manometer

Barometer-

Mercury Barometer was invented by Torricelli and it is a device used for measuring pressure.

Below is a figure showing the  Mercury Barometer device

From the figure we can say that

At Point C only atmospheric pressure is there.

So $P_C=P_0$
Ans since $B$ and $C$ are at the same horizontal level
So $P_C=P_B=P_A+\rho g h=0+\rho g h=\rho g h=P_0=$ Atmospheric pressure
For mercury barometer $\mathrm{h}=76 \mathrm{~cm}$ and
And using $\rho=13.6 * 10^3 \mathrm{~kg} / \mathrm{m}^3$
We get $P_0=1.013 * 10^5 \mathrm{~N} / \mathrm{m}^2=1 \mathrm{~atm}=76 \mathrm{~cm}$ of Hg

 

Manometer-

Manometers are the devices used for measuring gauge pressure of fluids.

Simple Manometer-

The figure of Simple Manometer is given below

And from the figure we can say that

The gauge pressure at point A in the vessel is 

$P_A=\rho g h$

Where \rho=density of the liquid

U-tube Manometer-

Figure of U-tube manometer is given below

And from the figure we can say that

$
P_A=P_B
$


And The gauge pressure at point A is given by

$
P_A=\rho g h
$
 

Where

\rho=density of the liquid

Study it with Videos

Barometer and Manometer

"Stay in the loop. Receive exam news, study resources, and expert advice!"

Get Answer to all your questions

Back to top