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    How to Prepare for AP EAMCET with JEE Main 2026 - Detailed Study Plan

    Barometer And Manometer - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • 3 Questions around this concept.

    Solve by difficulty

    Find out the value of $\operatorname{Sin} \theta$ in the given figure where a zig-zag tube open at N having liquids of densities $\rho_1, \rho_2, \rho_3$ and is placed in a vertical plane as shown in the figure. (The pressure at M is equal to atmospheric pressure.)

                             

    Concepts Covered - 1

    Barometer and Manometer

    Barometer-

    Mercury Barometer was invented by Torricelli and it is a device used for measuring pressure.

    Below is a figure showing the  Mercury Barometer device

    From the figure we can say that

    At Point C only atmospheric pressure is there.

    So $P_C=P_0$
    Ans since $B$ and $C$ are at the same horizontal level
    So $P_C=P_B=P_A+\rho g h=0+\rho g h=\rho g h=P_0=$ Atmospheric pressure
    For mercury barometer $\mathrm{h}=76 \mathrm{~cm}$ and
    And using $\rho=13.6 * 10^3 \mathrm{~kg} / \mathrm{m}^3$
    We get $P_0=1.013 * 10^5 \mathrm{~N} / \mathrm{m}^2=1 \mathrm{~atm}=76 \mathrm{~cm}$ of Hg

     

    Manometer-

    Manometers are the devices used for measuring gauge pressure of fluids.

    Simple Manometer-

    The figure of Simple Manometer is given below

    And from the figure we can say that

    The gauge pressure at point A in the vessel is 

    $P_A=\rho g h$

    Where \rho=density of the liquid

    U-tube Manometer-

    Figure of U-tube manometer is given below

    And from the figure we can say that

    $
    P_A=P_B
    $


    And The gauge pressure at point A is given by

    $
    P_A=\rho g h
    $
     

    Where

    \rho=density of the liquid

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    Barometer and Manometer

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