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Hooke’s law is considered one of the most asked concept.
120 Questions around this concept.
A wire elongates by $l \mathrm{~mm}$ when a load $W$ is hanged from it. If the wire goes over a pulley and two weights $W$ each are hung at the two ends, the elongation of the wire will be (in mm )
A bottle has an opening of radius a and length b. A cork of length b and radius (a + a) where (a<<a) is compressed to fit into the opening completely (See figure). If the bulk modulus of cork is B and frictional coefficient between the bottle and cork is µ then the force needed to push the cork into the bottle is :
A thin steel ring of inner radius r and cross-section area A to be mounted on a wheel of radius $R(R>r)$. If the Young modulus of the metal ring is Y then the tension in the steel ring is
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A rod, of length $L$ at room temperature and uniform area of cross-section $A$, is made of a metal having a coefficient of linear expansion $\alpha /{ }^{\circ} \mathrm{C}$. It is observed that an external compressive force F, is applied on each of its ends, and prevents any change in the length of the rod when its temperature rises by $\Delta T K$. Young's modulus, Y, for this metal, is:
The maximum stretching force of humans is $81 \times 10^4 \mathrm{~V}$, However the Young's modulus for stretch is $36 \times 10^9 \mathrm{~Pa}$. Then what is longitudinal strain $\left(\frac{\Delta_l}{l}=?\right) \longrightarrow \quad\left(A=9 \mathrm{~cm}^2\right)$
According to Hooke's law of elasticity if stress is increased the ratio of stress to strain
The unit of Young's modulus of elasticity is-
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An object of mass 'm' is suspended at the end of a mass-less wire of length L and area of cross-section A. Young's modulus of the maternal of the wire is Y. if the mass is pulled down slightly its freq. of oscillation along the vertical direction is :
There is no change in the volume of a wire due to a change in its length on stretching. The Poisson's ratio of the material of the wire is
Hooke’s law states that if the deformation is small, the stress in a body is proportional to the corresponding strain, i.e.,
$
\begin{gathered}
\text { Stress } \propto \text { Strain } \\
\Rightarrow \text { Stress }=E(\text { Strain }) \\
\Rightarrow E=\frac{\text { Stress }}{\text { Strain }}
\end{gathered}
$
Where E is called as Modulus of elasticity and it depends on the nature of the material and temperature of the body and is independent of the dimensions of the body.
Unit of Modulus of elasticity $=\mathrm{N} / \mathrm{m}^2$
- Modulus of elasticity is of three types:-
a. Young's Modulus(Y):- It is defined as the ratio of longitudinal stress to longitudinal strain.
$
Y=\frac{\text { longitudinal stress }}{\text { longitudinal strain }}=\frac{F / A}{\Delta L / L}=\frac{F l}{A \Delta L}
$
b. Shear Modulus or Modulus of rigidity(G):- It is defined as the ratio of shearing stress to the shearing strain.
$
G=\frac{\text { shearing stress }}{\text { shearing strain }}=\frac{F / A}{x / L}=\frac{F l}{A x}=\frac{F}{A \phi}
$
c. Bulk Modulus(B):- It is defined as the ratio of volume stress to the volume strain.
$
\begin{gathered}
\text { Volumestress }=\frac{F}{A}=\text { Pressure } \\
B=-\frac{P}{\Delta V / V}
\end{gathered}
$
where $\mathrm{P}=$ increase in pressure, $\mathrm{V}=$ original volume, $\Delta V=$ change in volume
The negative sign indicates that with the increase in pressure, volume decreases by $\Delta V$.
- Compressibility(C):- The reciprocal of bulk modulus is called as compressibility.
$
C=\frac{1}{B}=-\frac{\Delta V / V}{P}
$
$\sigma=-\frac{\Delta d / d}{\Delta l / l}$
where negative sign is due to decrease in the transverse length
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