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Charging Of Battery And Discharging Of Battery - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

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Emf of a cell when the cell is charging and discharging and Open circuit and Short circuit is considered one of the most asked concept.
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MEDIUM

The length of a wire of a potentiometer is 100 cm and the e.m.f. of its standard cell is E volt. It is employed to measure the e.m.f. of a battery whose internal resistance is 0.5 $\Omega$ If the balance point is obtained at $l=30$ cm from the positive end, the e.m.f. of the battery is :

$\frac{30E}{100.5}$

$\frac{30E}{100-0.5}$

$\frac{30E}{100}-0.5 i$

where i is the current in the potentiometer wire

$\frac{30E}{100}$

View Solution

A dry cell delivering 2 A has a terminal voltage 1.14V. What is the internal resistance of the cell if its open–circuit voltage is 1.59 V?

$5.09\; \Omega$

$6.09\; \Omega$

$7.09\; \Omega$

$0.09\; \Omega$

View Solution

Concepts Covered - 1

Emf of a cell when the cell is charging and discharging and Open circuit and Short circuit

Emf of a cell when the cell is charging and discharging and Open circuit and Short circuit

Open circuit:

no current is taken from the cell. $i=0$
The potential difference between A and B $V_{AB}=E$
The potential difference between C and D $V_{CD}=0$

Short circuit

Two terminals of a cell are joined together by a thick conducting wire
Maximum current $i=\frac{E}{r}$
$V=0$

Equation of cell

When supplying the current: $E=V+iR$
When the cell is being charged: $E=V-iR$

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Emf of a cell when the cell is charging and discharging and Open circuit and Short circuit

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