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    Coordinate Geometry Weightage In JEE Mains: Weightage, Marks & Important Topics

    Current Density - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • Current Density is considered one of the most asked concept.

    • 14 Questions around this concept.

    Solve by difficulty

    while calculating current passing through a wire which area is taken?

    A charge is flowing uniformly through a cross-section of area A. Then the current density is independent of 

    If current 'i' flowing through a cross-section A makes an angle $30^{\circ}$  with area vector. The current density $J$ is :

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    If 25 A of current passes through a uniform solid cylinder of total surface area $150 \pi \mathrm{~cm}^2$ and height 10 cm. Find the current density

    The electric field through a cross section of area $2 \mathrm{~m}^2$ makes an angle of $60^{\circ}$ with the area vector. The current through cross-section is given by

    current density is

     

     

     

    Concepts Covered - 1

    Current Density
    1.  Current density

    • Current density: The amount of electric current flowing per unit cross-sectional area of a material.

    • It is a vector quantity.

    If a current of $\Delta i$ flows through an area $\Delta A$ the average current density $\bar{j}=\frac{\Delta i}{\Delta A}$ in the direction of current

    At point $P$ :
    $j=\lim _{\Delta A \rightarrow 0} \frac{\Delta i}{\Delta A}$ in the direction of current

    1. If current not Perpendicular to Area

    $
    \begin{aligned}
    J_{a v} & =\frac{d i}{d A \cos \theta} \\
    d i & =J d A \cos \theta=\vec{J} \cdot d \vec{A}
    \end{aligned}
    $

    $\theta$ is the angle between the normal to the area and direction of current
    - If the current density $\vec{J}$ is uniform for a normal cross-section $\vec{A}$ then

    $
    i=\int \vec{J} \cdot d \vec{A}
    $

    - Unit and dimension -

    Unit of current density is $A \mathrm{mp} / \mathrm{m}^2$
    DImension of current density is $\left[L^{-2} A\right]$

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    Current Density

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