63 Questions around this concept.
The ratio of thermal energy released in two resistors R and 3R connected in parallel in an electric circuit is :
A 100 V, 40 watt bulb is connected across 220 V DC supply. The power consumption by bulb is:
In the circuit shown in the figure, the heat produced in 5 ohm resistance is 10 calories per second. The heat produced in 4 resistance is
JEE Main: Chapter Wise Weightage | Syllabus
New: CSAB 2026 Counselling CP | Free 1:1 Counselling | Most Scoring Concepts
JEE Main 2026: Last Five Year Analysis (2026-2022) | Inorganic Chemistry
Comprehensive Guide: IIT's | NIT's | IIIT's | Foreign Universities in India | Study Guide
Heat developed in a resistor: When a steady current flows through a resistance R for time $t$, the loss in electric potential energy appears as increased thermal energy(Heat H) of resistor and $H=i^2 R t$
The power developed $=\frac{\text { energy }}{\text { time }}=i^2 R=i R=\frac{V^2}{R} \quad$ (from Ohm's law)
Unit of heat is the joule (J)
Unit of power is watt (W)
"Stay in the loop. Receive exam news, study resources, and expert advice!"