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Resistors In Series And Parallel Combinations - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Series grouping of Resistance is considered one of the most asked concept.

  • 25 Questions around this concept.

Solve by difficulty

In the given circuit, an ideal voltmeter connected across the $10 \Omega$ resistance reads 2 V . The internal resistance r (in $\Omega$ ), of each cell is :

 

A cell of emf $
90 \mathrm{~V}
$ is connected across series combination of two resistors each of $
100 \Omega
$ resistance. A voltmeter of resistance $
400 \Omega
$ is used to measure the potential difference across each resistor. The reading of the voltmeter will be:

Given below are two statements :
Statement I: The equivalent resistance of resistors in a series combination is smaller than the least resistance used in the combination.
Statement II: The resistivity of the material is independent of temperature.

In the light of the above statements, choose the correct answer from the options given below :

An infinite sequence of resistance is shown in the figure. The resultant resistance between A and B will be, when  R1=1 $ \Omega$ and  R2 = 2 $ \Omega$       

                   

If n equal resistances are connected in series the equivalent resistance is found to be R. When $(n-3)$ of these resistance are connected in parallel equivalent resistance is found to be $\frac{R}{120}$. Then the value of n is?

In the circuit given, find the currents ${I }, I_1$ and $I_2$ in the circuit.

Concepts Covered - 1

Series grouping of Resistance
  1. Series Grouping of resistance

 In this case , Potential drop is different across each resistor and Current is the same

.

$
R_{e q}=R_1+R_2+R_3+\cdots+R_n
$

$R_{e q}{ }_{\text {Equivalent Resistance }}$
For nidentical resistance: $R_{e q}=n R$

$
V^{\prime}=\frac{V}{n}
$
 

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Series grouping of Resistance

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