UPES B.Tech Admissions 2025
Ranked #42 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements | Last Date to Apply: 28th April
Series grouping of Resistance is considered one of the most asked concept.
39 Questions around this concept.
In the given circuit, an ideal voltmeter connected across the $10 \Omega$ resistance reads 2 V . The internal resistance r (in $\Omega$ ), of each cell is :
A cell of emf $
90 \mathrm{~V}
$ is connected across series combination of two resistors each of $
100 \Omega
$ resistance. A voltmeter of resistance $
400 \Omega
$ is used to measure the potential difference across each resistor. The reading of the voltmeter will be:
Given below are two statements :
Statement I: The equivalent resistance of resistors in a series combination is smaller than the least resistance used in the combination.
Statement II: The resistivity of the material is independent of temperature.
In the light of the above statements, choose the correct answer from the options given below :
JEE Main 2025: Session 2 Result Out; Direct Link
JEE Main 2025: College Predictor | Marks vs Percentile vs Rank
New: JEE Seat Matrix- IITs, NITs, IIITs and GFTI | NITs Cutoff
Latest: Meet B.Tech expert in your city to shortlist colleges
An infinite sequence of resistance is shown in the figure. The resultant resistance between A and B will be, when R1=1 $ \Omega$ and R2 = 2 $ \Omega$
If n equal resistances are connected in series the equivalent resistance is found to be R. When $(n-3)$ of these resistance are connected in parallel equivalent resistance is found to be $\frac{R}{120}$. Then the value of n is?
In the circuit given, find the currents ${I }, I_1$ and $I_2$ in the circuit.
Two unequal resistors are connected in series across a battery. Then the
Ranked #42 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements | Last Date to Apply: 28th April
Merit Scholarships | NAAC A+ Accredited | Top Recruiters : E&Y, CYENT, Nvidia, CISCO, Genpact, Amazon & many more
A potential divider circuit is shown in figure. The output voltage V0 is :
When the current in the circuit shown in the figure attains a steady value, then:
Series Grouping of resistance
In this case , Potential drop is different across each resistor and Current is the same
.
$
R_{e q}=R_1+R_2+R_3+\cdots+R_n
$
$R_{e q}{ }_{\text {Equivalent Resistance }}$
For nidentical resistance: $R_{e q}=n R$
$
V^{\prime}=\frac{V}{n}
$
"Stay in the loop. Receive exam news, study resources, and expert advice!"