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List of Engineering colleges accepting 98 Percentile in JEE Main 2024

List of Engineering colleges accepting 98 Percentile in JEE Main 2024

Edited By Team Careers360 | Updated on May 22, 2024 11:37 AM IST | #JEE Main

List of Engineering Colleges Accepting 98 Percentile in JEE Main 2024: The scoring percentile of 98 in the Joint Entrance Examination (JEE) Main is a big achievement, which opens the door to admission for many esteemed engineering institutions across India. Finding the right college is always difficult, but students should research properly. According to the below list, most students have chosen B.Tech Computer Science and engineering as their preferred course.

List of Engineering colleges accepting 98 Percentile in JEE Main 2024
List of Engineering colleges accepting 98 Percentile in JEE Main 2024

Students had chosen the Indian Institute of Information Technology as their most preferred. The National Institute of Technology came in at a close second as the preferred institution to pursue their desired courses. In this article, students can check the institution's best courses along with their opening-closing ranks.

List of Engineering Colleges Accepting 98 Percentile in JEE Main 2024

In the below list, we have shortlisted the institutions with their institute names and what their cutoff scores are, along with their opening rank and closing rank. This will give you a brief understanding of the college.

List of Colleges Accepting 98 JEE Main Percentile for B.Tech

College Name

Best Course Name

Best Course cutoff

Opening Rank

Closing Rank




Gender-Neutral

Female only

Gender-Neutral

Female only

Indian Institute of Information Technology, Pune

B.Tech Computer Science and Engineering

98.65573844

4202

8290

14966

21049

Indian Institute of Information Technology, Vadodara

B.Tech Computer Science and Engineering

98.37019738

8180

14659

18145

23183

Indian Institute of Information Technology, Sonipat

B.Tech Computer Science and Engineering

98.15732154

13718


20515


Indian Institute of Information Technology, Kota

B.Tech Computer Science Engineering

98.2758853

12721

18761

19195

25937

Indian Institute of Information Technology, Guwahati

B.Tech Computer Science Engineering

98.3822334

4747

20043

18011

25231

Indian Institute of Information Technology, Surat

B.Tech Computer Science and Engineering

98.35501763

13182

21205

18314

23255

Dr Shyama Prasad Mukherjee International Institute of Information Technology, Naya Raipur

B.Tech Computer Science and Engineering

98.46783284





Indian Institute of Information Technology, Bhopal

B.Tech Computer Science and Engineering

98.04854827

9034


21726


Indian Institute of Information Technology, Nagpur

B.Tech Computer Science Engineering Artificial intelligence and Machine Learning

98.10747086

10066


21070


Indian Institute of Information Technology Tiruchirappalli

B.Tech Computer Science and Engineering

98.03579368

5847

10606

21868

29245

Indian Institute of Information Technology Design and Manufacturing Kancheepuram

B.Tech Computer Engineering

98.68816383

10441

11974

14605

18196

Indian Institute of Information Technology Design and Manufacturing Jabalpur

B.Tech Computer Science and Engineering

98.82334449

8582

14277

13100

20311

National Institute of Technology Patna

B.Tech Computer Science and Engineering

98.6606786

10277

19270

14911

23590

National Institute of Technology Andhra Pradesh

B.Tech Computer Science and Engineering

98.65807379

9262

12616

14940

19909

National Institute of Technology Durgapur

B.Tech Computer Science and Engineering

98.9904116

3070

2136

11240

13052

National Institute of Technology Silchar

B.Tech Computer Science and Engineering

98.05241057

8643

19002

21683

26643

Dr B R Ambedkar National Institute of Technology Jalandhar

B.Tech Computer Science and Engineering

98.73729594

8346

5952

14058

16727

Punjab Engineering College, Chandigarh

BE Computer Science and Engineering

98.61981003

3290


15366


National Institute of Technology Raipur

B.Tech Computer Science Engineering

98.22612445

10067

15044

19749

20935

National Institute of Technology Hamirpur

B.Tech Computer Science and Engineering

98.21938787

9578

22031

19824

32375

National Institute of Technology Goa

B.Tech Computer Science and Engineering

98.40765275

8059

21386

17728

21386

The National Institute of Technology, Durgapur, has the highest cutoff score of 98.9904116 percentile, while the lowest cutoff score belongs to the Indian Institute of Information Technology, Tiruchirappalli, with a score of 98.03579368.

Marks for 98 percentile in JEE mains 2024

To score 98 percentile in the JEE Mains 2024 exam, candidates are required to score a minimum of 149 marks out of 300 in the exam. This score is based on the percentile comparison released by NTA on the official website.

Candidates can check the percentile conversions for various scores from the table below

Expected JEE Main 2024 Marks vs Rank vs Percentile

Marks out of 300

Rank

Percentile

286- 292

19-12

99.99826992- 99.99890732

280-284

42-23

99.99617561 - 99.99790569

268- 279

106-64

99.99034797 - 99.99417236

250- 267

524-108

99.95228621- 99.99016586

231-249

1385-546

99.87388626-99.95028296

215-230

2798-1421

99.74522293-99.87060821

200-214

4667-2863

99.57503767- 99.73930423

189-199

6664- 4830

99.39319714- 99.56019541

175-188

10746-7152

99.02150308 - 99.3487614

160-174

16163-11018

98.52824811-98.99673561

149-159

21145-16495

98.07460288-98.49801724

132-148

32826-22238

97.0109678-97.97507774

120-131

43174-33636

96.0687115-96.93721175

110-119

54293-44115

95.05625037-95.983027

102-109

65758-55269

94.01228357-94.96737888

95-101

76260-66999

93.05600452 -93.89928202

89-94

87219-78111

92.05811248 -92.88745828

79-88

109329-90144

90.0448455 -91.79177119

62-87

169542-92303

84.56203931-91.59517945

41-61

326517-173239

70.26839007-84.22540213

1-40

1025009-334080

6.66590786-69.5797271

Frequently Asked Question (FAQs)

1. Which colleges accept the 98 percentile?

There are many colleges to choose from if you have obtained 98 percentile in the JEE Main exam some of them are NIT Raipur, NIT Hamirpur, NIT Goa,

2. What are the best colleges for the 98 percentile?

Many best colleges accept the 98 percentile. IIITs and NITs also accept 98 percentile. Many colleges accept the 98 percentile including IIITs and NITs. 

3. Which NIT is best for the 98 percentile?

Some of the best NITs that accept the 98 percentile are NIT Raipur, NIT Hamirpur, NIT Goa, NIT Andhra Pradesh etc.,

4. What are the marks for the 98 percentile in JEE Main?

It is very difficult to predict the marks as it keeps changing every year depending on various factors such as the number of students who appear in the exam and the toughness level of the examination.

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Questions related to JEE Main

Have a question related to JEE Main ?

There is no requirement to have Physics, Chemistry, and Math (PCM) in 12th to appear for JEE Mains 2025. You must have passed the class 12 exam in 2023, 2024, or 2025 .You need to have studied at least five subjects in your qualifying exam, with Physics, Chemistry, and Mathematics being mandatory. This means your PCB combination fulfills the Physics and Chemistry requirement.

Since you haven't studied Math in 12th, you need to put in extra effort to build a strong foundation in Mathematics, which is a crucial subject for JEE Mains.Qualifying for JEE Advanced, which allows admission to IITs, requires Mathematics at the 12th-grade level.

https://engineering.careers360.com/download/ebooks/jee-main-2022-preparation-tips

I hope it helps!


Alliance University Bangalore doesn't specify a single entrance exam for this program on their official website. Here are the possibilities:

  • Alliance University Scholastic Aptitude Test (AUSAT): This is the university's own entrance exam. It's a possibility for admission to various undergraduate programs, including engineering.

  • JEE Main/Advanced: These national-level engineering entrance exams are widely accepted by many universities in India. While not explicitly mentioned, Alliance might consider JEE scores for B.Tech. programs.

  • Other State or National Level Engineering Entrance Exams: Some states might have their own engineering entrance exams, and Alliance could potentially accept scores from those as well.

  • Merit-Based Admission: In some cases, Alliance might grant admission based solely on your Class 12th marks (depending on availability of seats).

    https://www.careers360.com/university/alliance-university-bangalore

    I hope it helps!

A simple refresh of the page can sometimes resolve temporary glitches causing the session to expire. Try refreshing the webpage and see if you can regain access.

Sometimes, accumulated cache and cookies in your browser can interfere with website functionality. Try clearing your browser's cache and cookies, then restarting your browser and logging back in to the JoSAA portal.

If refreshing and clearing cache don't work, you can try logging out completely and then logging back in with your JoSAA credentials. This can sometimes reset your session and allow you to continue.


Occasionally, the JoSAA portal might undergo scheduled maintenance, which could cause temporary inaccessibility. Check the JoSAA website for any announcements about maintenance periods.

If none of the above solutions work immediately, there might be a temporary technical issue with the JoSAA portal. Wait for a while (maybe an hour or two) and try logging in again later.

https://engineering.careers360.com/download/ebooks/josaa-what-you-need-to-know

I hope it helps!

No, directly floating your choices to get a higher preference in subsequent JoSAA counselling rounds isn't guaranteed.

JoSAA uses a demand-filling process. In each round, it allocates seats based on candidate preferences, institute/branch choices, and candidate ranks.

If you don't get any of your higher choices (including your 1st choice) in a round, and a seat is available in one of your lower choices (like your 4th choice), JoSAA might allocate that seat to you.

However, there is no guarantee that your 1st choice will become available in later rounds.

During the second round (or any subsequent round), you'll have the option to either freeze your allocated seat (4th choice) or float it. Floating means you're willing to give up your current seat for a chance at a higher preference in the next round.

If you are happy with your allocated seat (4th choice) and don't mind attending that college/branch, you can lock it (freeze). Consider how likely it is for your 1st choice to become available in the next rounds. If the seats for your 1st choice are filling quickly, floating might be a gamble. You might end up with no seat at all in the next round. Floating involves some risk. You might lose your current seat (4th choice) and not get your 1st choice either. Locking secures your current seat but eliminates the possibility of getting your 1st choice.

I hope it helps!

You are eligible for JEE Advanced for two consecutive years starting from the year you appear for your Class 12 board exams.

You gave your 12th board exams in 2024 and attempted JEE Advanced in the same year (2024). You then took a drop and didn't appear for JEE Advanced in 2025. Since you haven't exhausted your two attempts yet, you can appear for JEE Advanced in 2026.


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 5 g of Na2SO4 was dissolved in x g of H2O. The change in freezing point was found to be 3.820C.  If Na2SO4 is 81.5% ionised, the value of x (Kf for water=1.860C kg mol−1) is approximately : (molar mass of S=32 g mol−1 and that of Na=23 g mol−1)
Option: 1  15 g
Option: 2  25 g
Option: 3  45 g
Option: 4  65 g  
 

 50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl.  If pKb of ammonia solution is 4.75, the pH of the mixture will be :
Option: 1 3.75
Option: 2 4.75
Option: 3 8.25
Option: 4 9.25
 

CH_3-CH=CH-CH_3+Br_2\overset{CCl_4}{\rightarrow}A

What is A?

Option: 1

CH_3-CH(Br)-CH_2-CH_3


Option: 2

CH_3-CH(Br)-CH(Br)-CH_3


Option: 3

CH_3-CH_2-CH_2-CH_2Br


Option: 4

None


\mathrm{NaNO_{3}} when heated gives a white solid A and two gases B and C. B and C are two important atmospheric gases. What is A, B and C ?

Option: 1

\mathrm{A}: \mathrm{NaNO}_2 \mathrm{~B}: \mathrm{O}_2 \mathrm{C}: \mathrm{N}_2


Option: 2

A: \mathrm{Na}_2 \mathrm{OB}: \mathrm{O}_2 \mathrm{C}: \mathrm{N}_2


Option: 3

A: \mathrm{NaNO}_2 \mathrm{~B}: \mathrm{O}_2 \mathrm{C}: \mathrm{Cl}_2


Option: 4

\mathrm{A}: \mathrm{Na}_2 \mathrm{OB}: \mathrm{O}_2 \mathrm{C}: \mathrm{Cl}_2


C_1+2 C_2+3 C_3+\ldots .n C_n=

Option: 1

2^n


Option: 2

\text { n. } 2^n


Option: 3

\text { n. } 2^{n-1}


Option: 4

n \cdot 2^{n+1}


 

A capacitor is made of two square plates each of side 'a' making a very small angle \alpha between them, as shown in the figure. The capacitance will be close to : 
Option: 1 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{\alpha a }{4 d } \right )

Option: 2 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 + \frac{\alpha a }{4 d } \right )

Option: 3 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{\alpha a }{2 d } \right )

Option: 4 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{3 \alpha a }{2 d } \right )
 

 Among the following compounds, the increasing order of their basic strength is
Option: 1  (I) < (II) < (IV) < (III)
Option: 2  (I) < (II) < (III) < (IV)
Option: 3  (II) < (I) < (IV) < (III)
Option: 4  (II) < (I) < (III) < (IV)
 

 An ideal gas undergoes a quasi static, reversible process in which its molar heat capacity C remains constant.  If during  this process the relation of pressure P and volume V is given by PVn=constant,  then n is given by (Here CP and CV are molar specific heat at constant pressure and constant volume, respectively)
Option: 1  n=\frac{C_{p}}{C_{v}}


Option: 2  n=\frac{C-C_{p}}{C-C_{v}}


Option: 3 n=\frac{C_{p}-C}{C-C_{v}}

Option: 4  n=\frac{C-C_{v}}{C-C_{p}}
 

As shown in the figure, a battery of emf \epsilon is connected to an inductor L and resistance R in series. The switch is closed at t = 0. The total charge that flows from the battery, between t = 0 and t = tc (tc is the time constant of the circuit ) is : 


Option: 1 \frac{\epsilon L }{R^{2}} \left ( 1 - \frac{1}{e} \right )
Option: 2 \frac{\epsilon L }{R^{2}}


Option: 3 \frac{\epsilon R }{eL^{2}}

Option: 4 \frac{\epsilon L }{eR^{2}}
 

As shown in the figure, a particle of mass 10 kg is placed at a point A. When the particle is slightly displaced to its right, it starts moving and reaches the point B. The speed  of the particle at B is x m/s. (Take g = 10 m/s2 ) The value of 'x' to the nearest is ___________.
Option: 1 10
Option: 2 20
Option: 3 40
Option: 4 15

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