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How to calculate JEE Main 2025 rank based on Percentile score? - Many candidates wish to know how to calculate their JEE Main 2025 rank based on the percentile score. This helps them predict their rank before the release of the JEE 2025 result. As we know, NTA has released the JEE Main score in the form of percentile. JEE Main rank is based on the percentile score of both sessions of NTA JEE Mains. So, why would students ask about JEE Main 2025 rank based on the NTA percentile score? Well, the reasons are many and varied like not appearing for JEE Main April session or judging whether a better score would fetch a seat. Check out how to calculate the JEE Main 2025 rank using the percentile score below in this article.
Also Check: JEE Main marks vs percentile table
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NTA will conduct the JEE Main normalisation process session-wise so the percentile score you got would be relative to the others in your session. This score denotes the percentage of candidates who have scored equal to or below (same or lower raw scores) that particular Percentile in that examination. So the 9 toppers are students who have got 100 NTA Scores and have got the highest scores which is 100 percentile after normalisation in their respective sessions. The marks obtained in between the highest and lowest scores will also been converted to appropriate Percentiles.
Note: It may be noted that the formula given for the calculation of percentile in JEE Main is indicative and should not be taken as accurate as the actual ranks will vary on account of many factors. For the actual rank, candiadtes should check the alloted rank on the JEE Main 2025 scorecard.
JEE Main 2025 exam dates will be announced on the official website. Candiadtes can follow the previous year statistics to get an idea of how to calculate the JEE Main rank from the percentile. Below is the process of calculating rank from percentile with last year's example.
As per the previous year NTAJEE Main statistics, 823967 students appeared for JEE Main in the January session. NTA announced that 20 students have scored 100 percentile in the previous year sessions and has declared them as JEE Main Toppers.
To calculate the JEE Main rank, you first need to know the percentage of candidates with higher percentile scores than you. To calculate that, the formula would be 100 (highest score) - your percentile score.
Since the percentile is calculated from 100 to 0 for each session of examinees, the formula applies the total number of students in the January session which is 8,22,000 /100 * percentage of people ahead of you to arrive at the rank.
Therefore, the formula to calculate the JEE Main rank through percentile for January is
JEE Main rank (probable) = (100- NTA percentile score ) X 823967 /100
If the NTA percentile score is 90.70, JEE Main rank will be (100-90.70 ) X 823967/100 = 76628
Consider the NTA score of 80.60 then JEE Main 2023 rank = (100-80.60) X 823967 /100. The rank will be 159849
** This formula would not be for a 100 percentile score as those are the top ranks.
Candidates can also use the JEE Main Rank Predictor to check their rank.
Candidates can take a probable calculation of percentile in JEE Main January 2025 session and check the rank. Based on your performance in the JEE Main January session, you can decide if you want to attempt the April session or not.
According to the previous year statistics, the total number of candidates that appeared for the JEE Main April session are 10,67,959. Using this as a basis, use the NTA score and see what is the JEE Main rank.
Why the January NTA score? The reason is that the authority will consider the better of the two session's scores. So if you perform badly in April, the January NTA score will be counted and if you perform better, then the rank will only be better.
So what will be the April JEE Main rank from the NTA Percentile Score of January?
Using the same formula,
If the NTA percentile score is 90.70, JEE Main rank will be (100-90.70) X 10,67,959/100 = 99320
In this case, you have a good chance of qualifying for JEE Advanced (as 2,50,000 students qualify for it) and can check the JEE Main cutoff from previous years to understand which institute you can apply for admissions.
Consider the NTA score of 80.60 then JEE Main rank = (100-80.60) X 10,67,959 /100. The rank will be 207184 which means may not have a chance of qualifying for JEE Advanced.
The NTA percentile score of 89.7548849 will stand a chance at JEE Advanced if one takes a look at the JEE Main cutoff from last year.
It is a fact that IITs are dream institutions for most engineering aspirants. So a student who has done exceptionally well in January session of JEE Main may wish to skip the JEE Main April session to concentrate on JEE Advanced preparation. Another student may have scored well enough and feels that another session is too strenuous so may wish to skip it if only he/she has a fair chance of a seat in one good NIT or IIIT. Others may wish to know if they have the chance for any admissions based on their January JEE Main percentile scores or if should they appear for the April exam to better this.
We hope that the decision to write or skip can be made a bit easier using the calculation methods mentioned in this article.
JEE Main 2025 normalisation process is done by the authority to ensure all candidates scores are at an equal level regardless of the difficulty level of the session.
Application Date:03 September,2024 - 31 December,2024
Application Date:16 September,2024 - 04 December,2024
Hello Ronish,
If you belong to OBC-NCL (Non-Creamy Layer) but currently do not have an updated NCL certificate for the JEE 2025 form, you can still proceed as follows:
Select OBC-NCL During Form Filling
: Mark your category as
OBC-NCL
in the JEE 2025 form if that is your eligible category. Even if you don’t have the NCL certificate at the time of form submission, selecting this category initially is allowed.
Obtain the NCL Certificate
: Ensure you acquire the
OBC-NCL certificate
by the time of
JEE counseling
. Generally, this certificate should be issued within the same financial year as the counseling period, so applying for it as soon as possible is ideal.
Documentation During Counseling
: The certificate is typically required at the
counseling stage
for seat allocation under the OBC-NCL category. If you don’t present a valid NCL certificate at that point, you may be treated as a
general candidate
for admissions.
Contact Authorities if Needed : If you have any specific concerns or delays, you may contact the JEE helpline for guidance.
So, complete the form with your intended category and work on getting your NCL certificate before counseling to ensure eligibility for reserved category benefits.
For more details about JEE Mains exam you can check out an article by Careers360 whose link is given below:
Link: https://engineering.careers360.com/exams/jee-main
I hope this answer helps you. If you have more queries then feel free to share your questions with us we will be happy to assist you.
Thank you and wishing you all the best for your bright future.
No, jee mains 2025 eligibility criteria says that candidates who have passed their class 12th exams in 2023, 2024 or appearing  in 2025 are eligible. And candidates  must score above 75% marks in class 12th to be eligible to get admission to IITs, NITs or IIIT. Those who have completed in year 2022 are not eligible  for exam .
For more information regarding jee mains 2025 eligibility criteria, you can visit career 360 website
https://www.careers360.com/question-jee-main-2025-registration-form-is-out
Yes, you are eligible for JEE Main 2025.
Eligibility for JEE Main is just passing of Class 12 or equivalent examination in the immediately preceding two years. However, you have passed Class 12 in 2022 and therefore, fulfill that eligibility.
Note, however, that there could be year-to-year variance in the above eligibility criteria.
The most authentic and recent information can be fetched from the official notification by National Testing Agency for conducting JEE Main 2025. This notice contains information related to eligibility criteria, all important dates, and also contains application criteria.
The official notification is available on the NTA website .
If you consult the eligibility criteria and then follow the application process properly, you will get an easy process of smooth processing of your application.
Yes, you must choose "Appearing" for your 12th status in the JEE Main registration form.
Since you are going to reappear in your Class 12th board exams in the session 2024-25, therefore, you'll have the status of an "Appearing" candidate for JEE Main 2025 as your final results for Class 12th will be considered for eligibility and seat allotment.
When you select "Appearing", then you would be saying that you are still appearing for the class 12th and will appear in the respective year to sit for the board exams.
Always keep your admission ticket, along with other documents; this may also be needed at the time of counseling for JEE Main
All such queries or concerns you can mail or contact the National Testing Agency (NTA).
Hello,
The JEE Main cutoff varies yearly and depends on factors like the number of applicants, exam difficulty, and seat availability. For 2024, general category cutoffs are expected around the 85-90 percentile, while reserved categories (OBC, SC, ST, etc.) typically have lower cutoffs. For top NITs or CFTIs, candidates generally need higher percentiles, around 95-98+. Official cutoffs are announced by NTA post-exam, so check for updates on the official JEE website.
Hope this helps you,
Thank you
https://engineering.careers360.com/exams/jee-main
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