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Tricks To Solve JEE Main Maths MCQs Within Seconds
Edited By Vishal kumar | Updated on Apr 19, 2024 12:43 PM IST | #JEE Main
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We all are familiar with Multiple Choice Questions (MCQs). These are the questions which give us some options, usually 4, out of which one, or sometimes more than one, is correct. The Joint Entrance Examination Main, or JEE Main, has 30 Questions per subject out of which 20 are MCQs with only one correct option. Generally in mathematics for some questions, you will find the options in integer values like chapters trigonometry, sequence and series and others for which you can easily get the answer by using the values given in options directly to solve questions and verify it in less time. In this article, we are going to explain some ticks and trips with the help of examples which you can implement in various questions. Let us understand the trick with the help of some examples.
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Example 1
If A + B = 45°, then find the value of 
equals
a)1
b)0
c)2
d)1
Let us first try to understand the question. It means that if A + B = 45°, then the value of 
is always constant, which is equal to one of the options. So, for all combinations of angles A and B whose sum is 45°, the value of (
will always be the same, which is equal to one of the four options.
So, whether (A = 0° and B = 45°) or (A = 1 ° and B = 44°) or (A = 10° and B = 35°), they all will give the same value of (1+tanA)(1+tanB). So, we can easily replace A and B with some convenient values of angles and get the required value of (1+tanA) * (1+tanB). Let us put A = 0° and B = 45°,
= (1+tan0°)(1+tan45°) = (1 + 0)(1 + 1) = 1*2 = 2
So, option C is correct
Example 2
Now we have to select the option that gives the correct sum for all natural number values of n. So, the correct option has to be true for n = 1, 2, 3, …and all other natural number values of n. So, if any option is giving the wrong sum for n = 1, we can be sure that that option is incorrect.
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Let us try to find the options that are incorrect.
For n = 1, the actual sum of the given series is 
= 
Checking what value option A for n = 1: 
. So, it gives the wrong answer for n = 1, and hence it cannot give the correct answer for all values of n. Hence this option is wrong.
Checking what value option B for n = 1: (
. So, it gives the correct answer for n = 1. But this might give wrong answers for higher values of n. So, we will not mark this as correct right now.
Checking what value option C for n = 1: 
So, it gives the correct answer for n = 1. But this might give wrong answers for higher values of n. So, we will not mark this as correct right now.
Checking what value option D for n = 1: 
So, it gives the wrong answer for n = 1, and hence it cannot give the correct answer for all values of n. Hence this option is wrong.
Now both options A and D are eliminated, and one of option B or C is correct. Let us now see which of these two is giving the correct answer for n = 2.
For n = 2, the actual sum of the given series is
Checking what value option B for n = 2: 
. So, it gives the correct answer for n = 2 as well. But this might give wrong answers for higher values of n. So, we will not mark this as correct right now.
Checking what value option C for n = 2: 
. So, it gives the wrong answer for n = 2, and hence it cannot give the correct answer for all values of n. Hence this option is wrong.
Now we know that 3 out of 4 options are wrong, and only option B is left. So, we can safely mark option B as correct.
Example 3
If the value of the determinant given equals ka3b3c3, then the value of k is
a)1
b)0
c)-1
d)2
This question means that the value of the determinant always equals ka3b3c3 for all sets of values of a, b and c. In such questions, we can substitute some values of a, b and c and check to see the values of the determinant and the value of ka3b3c3. Also try to keep values of a, b and c such that ka3b3c3 does not become 0. So we will keep non-zero values of a, b and c. Let us put a = b = c = 1.
The value of the determinant is
which equals 0 (As two columns are the same) and the value of ka3b3c3 is k. So comparing these, we get k = 0.
Know when to use this trick and when not to. Don't use it for questions with more than one right answer or for multiple-choice questions where 'None of these' or 'All of these' is the only correct option.
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Questions related to JEE Main
Have a question related to JEE Main ?
JEE exam is conducted by NTA for admission to top IITs and NITs for different courses. Based on the previous year trends, for 2025,jee exam, students can expect the cut off between 90-95 percentile for general category students and 80-85 for OBC category and 55-60 for reserved categories. To know more,visit JEE cut off 2025
Annu Kumari 11 January,2025
Ofcourse you can give both the exam JEE and GUJCET as JEE exam give admission to IIT, NIT, and GFTIs for B. Tech courses and GUJCET offers seats in the universities situated in Gujarat.by giving two exams you have more options of colleges to choose from for your b.tech course.
If you see Engineering Admission Process are like this
Josaa: This is JEE counselling process. This would Only admitted students on the basis of JEE Mains marks and would be considered for your rank.
ACPC: This is your state admission process which GUJCET marks along with PCM boards theory marks would be considered. 50% of college seats are given to ACPC.
Since you are interested in both JEE as well as GUJCET, I'd advice you to enroll through both the processes for good colleges and good branches.
Best of luck!!!
sadafreen356 10 January,2025
Hi,
To be eligible for the admission in Thapar University B. Tech programme, candidates must qualify the JEE Main exam, which will be followed by counselling and seat allocation.
The admission in Thapar University is done on the basis of the JEE Main rankings and category-wise cutoffs will be released separately for all the B. Tech courses.
To be eligible for JEE MAINS, candidate must passed 10+2 with minimum of 60% marks from a recognized board. Appearing students are also eligible for JEE MAINS.
Hope this information will help you
Devraj 10 January,2025
Metaphysics is the study of reality of the world and is part of philosophy. It enquires about conceptual framework of human understanding. Admission to metaphysics courses are not done through the JEE exam. JEE exam is conducted for admission to courses related to science and technology. There are various entrance exams for admission to metaphysics courses which are CUET,CUET PG and UGC NET etc.
Annu Kumari 10 January,2025
Hello Greetings
The JEE Main cutoff for Artificial Intelligence (AI) in 2025 hasn't been released yet. However, we can look at the previous year's cutoffs to get an idea of the qualifying marks for NIT and IIT.
For IITs, the cutoff for Artificial Intelligence varies depending on the institute and category. Here are some previous year's cutoffs:
- *IIT Hyderabad*: The general category cutoff for Artificial Intelligence was 685 .
- *IIT Kharagpur*: The opening rank for Artificial Intelligence was 434, and the closing rank was 795 for the general category .
- *IIT Gandhinagar*: The opening rank for Artificial Intelligence was 1424, and the closing rank was 2055 for the general category .
As for NITs, the cutoffs also vary depending on the institute and category. You can check the official websites of the NITs or the Joint Seat Allocation Authority (JoSAA) for the latest cutoff information.
Keep in mind that the cutoffs may fluctuate each year depending on factors like the difficulty level of the exam and the number of candidates appearing. It's essential to stay updated with the latest information and prepare well for the exam to secure a good rank.
Have a great day
Sakshi Badoni 10 January,2025
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