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Minimum Marks in JEE Advanced 2025 to get IIT for general: IIT Kanpur has declared the JEE Advanced result 2025 on its official website jeeadv.ac.in. Candidates who attempted the exam will be curious about the minimum marks in JEE Advanced 2025 to get IIT for the general category. Getting admission into the prestigious IIT institutes through the JEE Advanced exam is a dream for many candidates. The minimum marks required to get admission into the JEE Advanced 2025 are 35% for the general category. 31.5% is for OBC-NCL/EWS, and SC/ST/PwD candidates are 17.5%. The JEE Advanced 2025 exam date is May 18, 2025.
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All JEE Advanced 2025 admissions are based on the JoSAA cutoff marks. All candidates who score more than the JoSAA cutoff will be offered admission to the IIT institutes. Read the article below to know the complete details regarding the Minimum marks in JEE Advanced 2025 to get into IIT for the general category.
Rank List | Minimum percentage of marks in each subject | Minimum percentage of aggregate marks |
Common rank list (CRL) | 7 | 74 |
GEN-EWS rank list | 6 | 66 |
OBC-NCL rank list | 6 | 66 |
SC Rank list | 3 | 37 |
ST Rank List | 3 | 37 |
Common-PwD rank list (CRL-PwD) | 3 | 37 |
GEN-EWS-PwD rank list | 3 | 37 |
OBC-NCL-PwD rank list | 3 | 37 |
SC-PwD rank list | 3 | 37 |
ST-PwD Rank List | 3 | 37 |
Preparatory Course (PC) Rank List | 1 | 18 |
The minimum marks that are required to get qualified in JEE Advanced 2025 are 35%, and the marks for each subject are 10. The total aggregate marks of JEE Advanced 2025 exam are 360. Physics & Chemistry carries 180 marks and Mathematics carries 180 marks.
Category/Rank List | Minimum Marks per Subject | Minimum Total Marks (in Percentage) | Total Aggregate Marks |
General | 10 | 35% | 360 |
GEN/EWS | 9 | 31.5% | 360 |
OBC/NCL | 9 | 31.5% | 360 |
SC | 5 | 17.5% | 360 |
ST | 5 | 17.5% | 360 |
Common/PwD | 5 | 17.5% | 360 |
GEN/EWS/PwD | 5 | 17.5% | 360 |
OBC/NCL/PwD | 5 | 17.5% | 360 |
SC/PwD | 5 | 17.5% | 360 |
ST/PwD | 5 | 17.5% | 360 |
Preparatory Course List | 5 | 17.5% | 360 |
Below are the expected minimum qualifying marks for JEE Advanced 2025 to be eligible for admission into IITs under the general category.
Criteria | Minimum Marks per Subject | Minimum Aggregate Marks | Total Marks in Exam |
General Qualification | 10% of the total marks | 35% of the total marks | 360 |
Minimum qualifying marks in the general rank list for JEE Advanced in 2024 were 97, and for each subject minimum marks for the general were 8. Below is the table in which the minimum marks and rank list for JEE Advanced 2024 cutoff for the general category are given.
Rank List / Category | Minimum Marks per Subject | Minimum Aggregate Marks |
Common | 9 | 97 |
GEN-EWS | 8 | 88 |
OBC-NCL | 8 | 88 |
SC Rank | 5 | 56 |
ST Rank | 5 | 56 |
(CRL-PwD) | 5 | 56 |
GEN-EWS-PwD | 5 | 56 |
OBC-NCL-PwD | 5 | 56 |
SC-PwD | 5 | 56 |
ST-PwD | 5 | 56 |
Preparatory Course | 3 | 31 |
Candidates have to secure a minimum mark in JEE Mains to qualify for the JEE Advanced 2025 exam. Below are the factors given. JEE aspirants need to focus on the following factors to secure good marks and a rank to qualify for the JEE Advanced exam and to get a seat in prestigious IITs.
Number of Applicants
Difficulty Level of the JEE Advanced Exam
Previous Years Cutoff Trends
Number of Seats Available
Candidates Performance
Frequently Asked Questions (FAQs)
There are a number of factors like number of applicants, exam difficulty level, previous cutoff trends, availability of seats and candidates performance.
Admissions are based on JoSAA counselling Cutoffs.
It is 31.5 % of the total marks.
On Question asked by student community
Hello,
If you appeared for the NIOS October 2024 exam, your passing year will be 2024 (because NIOS counts the year in which the exam is held).
For
JEE Advanced eligibility
:
You can appear in
JEE Advanced only in the year you pass Class 12 and the following year
.
So, since your passing year is 2024 , you are eligible for:
JEE Advanced 2024
JEE Advanced 2025
You will not be eligible for JEE Advanced 2026 , as it will be your third attempt after passing Class 12.
Hope it helps !
Hey,
If you take an additional exam in mathematics from an open board, as you want to pursue engineering, you will have two mark sheets which is not acceptable for JEE Mains or Advanced or JOSSA. NTA and IIT require single 10+2 certificate with the subjects Physics, Chemistry and Maths.
Hi,
JEE Advanced me qualify karne ke liye JEE Main me kisi fixed percentage ki requirement nahi hoti. Percentile aur rank ke basis par cutoff decide hoti hai. JEE Advanced ke liye eligible hone ke liye aapko JEE Main ke Top 2,50,000 rank holders ke andar aane chahiye, sab category mila kar.
Har saal cutoff percentile thoda alag hota hai, par approximate range general (UR) ke liye hoti hai 90–92 percentile tak, EWS ke liye 78–80 percentile tak, OBC-NCL ke liye 73-75 percentile tak, SC ke liye 55-60 percentile tak aur ST ke liye 45-50 percentile tak.
Iska matlab hai ki agar aap SC category se hai, to lagbhag 55 se 60 percentile JEE Main me lana par aap JEE Advanced ke liye qualify kar sakte hai.
Hope it helps!!!
You can find the syllabus and past years papers here on careers360
for the syllabus
https://engineering.careers360.com/hi/articles/jee-main-syllabus
for the previous years question papers
https://engineering.careers360.com/hi/articles/jee-main-question-paper-hindi-medium
Hello,
Yes, you can start now and prepare for the January attempt of JEE Main . It will be challenging, but with focus and proper planning, it is possible.
Here’s what you can do:
Make a study plan : Divide topics into daily and weekly targets. Focus more on important and high-weightage topics.
Start with basics : Make sure your concepts in Physics, Chemistry, and Math are clear.
Practice regularly : Solve previous year papers and mock tests to understand the exam pattern.
Revise often : Keep revising formulas, important concepts, and tricky problems.
Stay consistent : Even small daily progress is better than irregular study.
If you stay dedicated and follow a strict plan, you can be ready for January.
Hope it helps !
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