JEE Advanced 2013 Eligibility Criteria
Updated on Jun 21, 2014 - 2:50 p.m. IST by Team Careers360
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JEE Advanced 2013 Eligibility Criteria spells out the criteria needed for a candidate to be allowed to appear for the JEE Advanced exam. Students who figure in the top 150000 will have to fulfil additional criteria of figuring in the top 20% of their respective boards to be eligible for admissions to the IITs, IT-BHU and ISM Dhanbad. The students who satisfy JEE Advanced 2013 Eligibility Criteria will be allowed to appear for the JEE Advanced 2013.

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JEE Advanced 2013 Eligibility Criteria:

  • Candidate must have appeared for the JEE Main 2013 Paper 1 exam and scored a rank below 1, 50,000 (including all categories) to be eligible to appear for JEE (Advanced) - 2013.


Admission Criteria for IITs and ISM Dhanbad:

  • The category wise All India Rank (AIR) in JEE (Advanced)  2013 will be the basis for admissions provided the following criterion are met.
  • Candidates must figure in the top 20% of successful students of their respective Boards
  • To qualify, they must have scored a minimum score of 60% in the qualifying exam (Class XII or equivalent) (for students who have passed their Class XII in the first attempt in 2012.


Note:
In case the respective board does not provide the cutoff information regarding  the top twenty percentile of successful candidate Candidates will have to produce a certificate from the board stating the same.

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In case a student is unable to rpoduce a certificate as above, the CBSE percentile will be used as the criteria for deciding minimum percentage of marks in the qualifying examination. 

JEE Advanced 2013  No. Of Attempts: A maximum of two times in consecutive years.

Non eligibility Criteria: students who belong to the following criteria cannot apply for the JEE Advanced

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  • Candidates who have attempted IIT-JEE in 2011 or earlier are NOT ELIGIBLE to appear in JEE (Advanced) - 2013
  • Candidates who have taken /accepted admission at any of the IITs, IT-BHU Varanasi or ISM Dhanbad, are  NOT ELIGIBLE to appear in JEE (Advanced) - 2013.

 

JEE Advance 2013 Rank wise Distribution of top 1, 50,000 candidates as per Category:

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Common Merit List: Top 75750 (50.5 %) 

Other Backward Classes Non creamy layer OBC (NCL): Top 40500 (27%)

 Scheduled Caste (SC) Top 22500 (15 %)

Scheduled Tribe (ST) Top 11250 (7.5 %)

Note: As per GOI norms, 3% in each category is reserved for PD candidates

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More like JEE Advanced

Questions related to JEE Advanced

Showing 10836 out of 10836 Questions
14 Views

I got 88.2032067 percentile in jee main Jan 2020 attempt. Do I qualify for jee advanced with these percentile.? If yes, What rank I should secure in Jee Advanced to get Artificial Intelligence branch at IIT Hyderabad? My category is ST

ayush mishra 27th Jan, 2020
Hey aspirant!
As of now, it is difficult to predict the actual qualifying NTA score for JEE Advanced eligibility. However,going by views of many experts, if you have a percentile above 85-86 then you have a decent enough chance to qualify irrespective of your category. However, you should refer to the previous year JEE Main qualifying cutoff scores by NTA as follows to understand your chances:-
Common Rank List (CRL)

89.7548849

GEN-EWS

78.2174869

Other Backward Classes (OBC-NCL)

74.3166557

Scheduled Caste (SC)

54.0128155

Scheduled Tribe (ST)

44.3345172

PwD

0.11371730

Therefore, looking at previous year's trends it is a big possibility that you would qualify for JEE Advanced. Also, you still have another opportunity to improve your results by performing better in the April attempt and I would advise you to be concentrated on that too and give it your best shot.

As regarding your query about Artificial Intelligence at IIT HYDERABAD, it is a relatively new course and so prediction for cutoff is really tough, however an AIR of 600-700 would be sufficient to qualify for it, however, an AIR of under 500 would probably seal you the seat. Also, note that the previous year opening and closing rank for the course was 657 and 1601 respectively for General category while the opening rank for ST students from ST rank list was 142.
Good luck.
5 Views

For 600rank in st category how much no. And AIR i have to score in jee advanced 2020

Subhodeep Biswas 27th Jan, 2020
Hey there hope you're doing well.
Dear aspirant, see there is no fixed maximum marks for JEE ADVANCED it changes every year and so is the cutoff marks for each subject and category do it's quite difficult to predict at what exact marks you get for much rank. Yes but if you're scoring good marks higher enough that ST cutoff marks you can expect yourself in top ranks in the cat. merit list.
Thank you hope this helps you!
7 Views

Can a student also apply for jee advanced 2020 if he passed his board in 2018

Subhodeep Biswas 27th Jan, 2020
Hey there hope you're doing well.
Dear aspirant, the eligibility criteria for appearing in JEE ADVANCED says that you can appear in the examination in two consecutive years after board appearing year . So if a student appeared 12th board in 2018 he is not eligible for appearing in JEE ADVANCED 2020.
Thank you hope this helps you!
9 Views

i hv scored 72.85 in jee mains 2020 n i belong to obc-ncl, do i hv a chance to get seat in top government colleges n will i b eligible for jee advanced ?

Yashu Shrivastava 27th Jan, 2020

Hello Saumya

Sorry to inform you,but you are not eligible for JEE Advance.Also you will not get any top government colleges like NITs and IIITs because your percentile is very low.However you can give one more attempt and if you want to check the colleges you can get with percentile,you can use college predictor tool https://engineering.careers360.com/jee-main-college-predictor

I Hope This Helps

Best Of Luck!

12 Views

Iam gen pwd .I got 77 percentile in jee main jan 2020 .Can i get cse brach in Nit .what would be my crl pwd and iam i qualified for jee advanced ?

Singampalli sai rahul Student Expert 26th Jan, 2020
Hello aspirant,

You can calculate your rank using the below formula-
100 - your total percentile score is the percentage  of people ahead of you. 869010 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100.

Based on your percentile score your rank will around 2 lac. So, you don't have a chance to gdt a seat in NIT's. Inorder, to get a seat in NIT CS Branch you should get atleast 98.5% percentage.

Top NIT's cutoff ranks
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-top-nits/amp
Top
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