Amity University-Noida B.Tech Admissions 2026
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
IIT Bombay Fee Structure- Students who have been allotted seats in the institute need to pay IIT Bombay fee to confirm their admission. Fees of IIT Bombay include various charges like admission fees, tuition fees,hostel rent and others. The details about IIT Bombay fee structure is provided below. Students can pay the fees of IIT Bombay by various modes like Debit/ Credit Cards, Net Banking, E-Challan etc. The fees of IIT Bombay is divided into several components, of which a few are paid annually while some are one time payment. The fee structure of IIT Bombay is same for undergraduate and dual degree courses. IIT Bombay fees is different for Indian and foreign students. Students can find below the detailed information about IIT Bombay Fee Structure
For JEE Main 2026 session 2, candidates who passed the Class 12 or equivalent examination in 2023 or earlier are not eligible to appear for JEE Main 2026 session 2. The passing year is counted as the year in which a candidate is declared ‘pass’ for the first time in Class 12. Subsequent attempts, subject additions, or improvement exams will not be considered as a fresh passing year for eligibility purposes.
A | Description (At the time of Admission) | Indian nationals, OCI and PIO card holders (in Rs.) | Foreign nationals (in Rs.) |
1 | Admission Fee | 2200 | 2200 |
2 | Graduate Transcript Fee | 500 | 500 |
3 | Provisional Certificate | 500 | 500 |
4 | Medical Examination | 400 | 400 |
5 | Students’ Welfare Fund | 1000 | 1000 |
6 | Modernisation & Up-gradation | 2500 | 2500 |
7 | Identity Card | 500 | 500 |
| Total (A) | 7600 | 7600 |
B | Per Semester | ||
1 | Tuition Fee | 1,00,000 | 3,00,000 |
2 | Examination Fee | 1000 | 1000 |
3 | Registration Fee | 750 | 750 |
4 | Gymkhana Fee | 1750 | 1750 |
5 | Medical Fee | 1500 | 1500 |
6 | Hostel Rent | 2000 | 2000 |
7 | Electricity & Water Charges | 3000 | 3000 |
8 | Hostel Establishment Charges | 3000 | 3000 |
9 | Mess Establishment Charges | 1550 | 1550 |
10 | Student Benevolent Fund | 500 | 500 |
11 | Student accident insurance fund | 200 | 200 |
| Total (B) | 1,15,250 | 3,15,250 |
| |||
C | Deposits (one time fee only) | ||
1 | Institute Security Deposit | 1000 | 1000 |
2 | Library Security Deposit | 1000 | 1000 |
3 | Mess Security Deposit | 1000 | 1000 |
| Total (C) | 3000 | 3000 |
|
| ||
Grand Total (A+B+C) | 1,25,850 | 3,25,850 | |
1. All SC/ST/PwD students are exempted from payment of Tuition fees (B 1).
2. In addition, every student has to pay per semester mess advance of Rs. 22,000.
Students can find below the step by step procedure to pay the IIT Bombay fees
Students can pay the fees by online transactions through Canara Bank net banking, SBI online banking and PayU payment gateway.
To use Canara Bank net banking SBI online banking students need to have their bank accounts in SBI or Canara Bank. those who do not have an account in either of these banks they can use PayU payment gateway.
Students with bank loans, private or government sponsorship or with foreign nationality are allowed to pay in cash.
After verifying the complete transaction the cash section will issue receipts to the students.
On Question asked by student community
JEE Main 28 Jan shift 2 exam will end at 6 PM. The complete analysis and memory-based questions will solution will be updated in the below article. Keep checking the page-
Math and Chemistry was difficult and Physics was moderate. The complete analysis is available here- https://engineering.careers360.com/articles/jee-main-2026-january-28-shift-1-question-paper-with-solutions-pdf
You can also check the memory-based questions and detailed solutions for JEE Main Jan 28 shift 1 paper.
Hi Lucky,
Please refer to this link and you can download the free pdf.
HI Manisha Maharana
You can download the JEE Mains 10 Free Mock Test with Detailed solutions. Its a feely downloadable pdf.
https://engineering.careers360.com/download/sample-papers/jee-main-10-full-mock-test-and-explanations-pdf
Also, you can check ad attemp the online mock test on our platform.
https://learn.careers360.com/test-series-jee-main-free-mock-test/
A general equation of a circle is
$
x^2+y^2+2 g x+2 f y+c=0
$
Since it passes through $(0,0)$,
$
c=0
$
So the equation becomes
$
x^2+y^2+2 g x+2 f y=0
$
It cuts the x -axis at ( $a, 0$ ).
Substituting:
$
a^2+2 g a=0
$
g=-a/2
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