Vector Algebra VITEEE Quiz 2027 - Practice Questions

VITEEE Vector Algebra Quiz

Questions in VITEEE Vector Algebra will help students practice important topics and check their readiness. Answer the questions given below in order to enhance your proficiency in Vector Algebra.

Question 1. Find the unit vector perpendicular to the plane of $\hat{i}-\hat{j}+2 \hat{k}$ and $\hat{i}+3 \hat{k}$ 

(1) $\frac{2 \hat{i}-\hat{j}+5 \hat{k}}{\sqrt{30}}$ 

(2) $\frac{-3 \hat{i}-\hat{j}+\hat{k}}{\sqrt{11}}$ 

(3) $\frac{-3 \hat{i}-\hat{j}+\hat{k}}{2}$ 

(4) None of these. 

Correct answer: 2

Solution:

Unit vector perpendicular to the plane of vector a and b - $
\frac{\vec{a} \times \vec{b}}{|\vec{a} \times \vec{b}|}
$

Here $\vec{a}$ and $\vec{b}$ are two vectors.

$
\begin{aligned}
& \vec{a} \times \vec{b}=\left|\begin{array}{ccc}
\hat{i} & \hat{j} & \hat{k} \\
1 & -1 & 2 \\
1 & 0 & 3
\end{array}\right|=-3 \hat{i}-\hat{j}+\hat{k} \\
& \frac{\vec{a} \times \vec{b}}{|\vec{a}||\vec{b}|}=\frac{-3 \hat{i}-\hat{j}+\hat{k}}{\sqrt{11}}
\end{aligned}
$

Hence, the correct answer is the option (2)

Question 2. Find $(\vec{a} \times \vec{b})^2$ if $\vec{a} \cdot \vec{b}=2$ and $|\vec{a}|=5$ and $|\vec{b}|=\frac{1}{2}$ 

(1) $\frac{9}{4}$ 

(2) $\frac{1}{4}$ 

(3) $-\frac{9}{4}$ 

(4) $\frac{1}{2}$ 

Correct answer: 1

Solution:
Lagrange's identity -

$
(\vec{a} \times \vec{b})=|\vec{a}|^2|\vec{b}|^2-(\vec{a} \cdot \vec{b})^2
$

- wherein

Here $\vec{a}$ and $\vec{b}$ are two vectors

$
(\vec{a} \times \vec{b})^2=|\vec{a}|^2|\vec{b}|^2-(\vec{a} \cdot \vec{b})^2=\frac{25}{4}-4=\frac{9}{4}
$

Hence, the correct answer is option (1).

Question 3. Find the scalar triple product $[\vec{a} \vec{b} \vec{c}]$, where

$
\vec{a}=\hat{i}-\hat{j}, \quad \vec{b}=2 \hat{i}-2 \hat{j}+\hat{k}, \quad \vec{c}=2 \hat{i}+\hat{j}-3 \hat{k} .
$

(1) -3

(2) 2

(3) 3

(4) 7

Correct answer: 1

Solution:
Scalar Triple Product -
$
\begin{aligned}
& {[\vec{a} \vec{b} \vec{c}]} \\
& =(\vec{a} \times \vec{b}) \cdot \vec{c}=\vec{a} \cdot(\vec{b} \times \vec{c}) \\
& =(\vec{b} \times \vec{c}) \cdot \vec{a}=\vec{b} \cdot(\vec{c} \times \vec{a}) \\
& =(\vec{c} \times \vec{a}) \cdot \vec{b}=\vec{c} \cdot(\vec{a} \times \vec{b})
\end{aligned}
$
- wherein

Scalar Triple Product of three vectors $\hat{a}, \hat{b}, \hat{c}$.

 $\begin{bmatrix} \vec{a} & \vec{b} & \vec{c} \end{bmatrix}=(\vec{a}\times \vec{b})\cdot \vec{c}=\begin{vmatrix} 2 & 1 &-3 \\ 1& -1 &0 \\ 2 & -2 & 1 \end{vmatrix}$

 $=-2-1+0=-3$

Hence, the correct answer is -3.

Question 4: If $3 \vec{a} \cdot(\vec{b} \times \vec{c})=17$, then $33\left[\begin{array}{lll}\vec{a} & \vec{b} & \vec{c}\end{array}\right]=$ 

(1) 33

(2) 51

(3) 187

(4) 561

Correct answer: 3

Solution:

Properties of Scalar Triple Product -

$
[K \vec{a} \vec{b} \vec{c}]=K[\vec{a} \vec{b} \vec{c}]
$

wherein
$\vec{a}, \vec{b}$ and $\vec{c}$ are the three vectors.

$
\begin{aligned}
& 3 \vec{a} \cdot(\vec{b} \times \vec{c})=3\left[\begin{array}{lll}
\vec{a} & \vec{b} & \vec{c}
\end{array}\right]=17 \\
& {\left[\begin{array}{lll}
\vec{a} & \vec{b} & \vec{c}
\end{array}\right]=\frac{17}{3}} \\
& 33\left[\begin{array}{lll}
\vec{a} & \vec{b} & \vec{c}
\end{array}\right]=187
\end{aligned}
$

Hence, the answer is the option 3.

Question 5: $\begin{bmatrix} \vec{a}+\vec{b} &\vec{b}+\vec{c} &\vec{c}+\vec{a} \end{bmatrix}=$ 

(1) $\begin{bmatrix} \vec{a} & \vec{b} & \vec{c} \end{bmatrix}$ 

(2) $\begin{bmatrix} \vec{a} & \vec{b} & \vec{c} \end{bmatrix}^{2}$ 

(3) $2\begin{bmatrix} \vec{a} & \vec{b} & \vec{c} \end{bmatrix}$ 

(4) $3\begin{bmatrix} \vec{a} & \vec{b} & \vec{c} \end{bmatrix}$ 

Correct answer: 3

Solution:
Properties of Scalar Triple Product -
$
\begin{bmatrix} \vec{a}+\vec{b} &\vec{b}+\vec{c} &\vec{c}+\vec{a} \end{bmatrix}=2[\vec{a} \vec{b} \vec{c}]
$
- wherein
$\vec{a}, \vec{b}, \vec{c}$ are three vectors

Hence, the correct answer is the option (3).

Question 6. Find the scalar triple product of the vectors $\hat{i}-\hat{j}, 2 \hat{i}+3 \hat{j},-3 \hat{i}-\hat{j} .$ 

(1) 0

(2) 10

(3) 9

(4) 24

Correct answer:1

Solution:
Coplanar vectors -
$
[\vec{a} \vec{b} \vec{c}]=0
$
- wherein
$\vec{a}, \vec{b}$ and $\vec{c}$ are three vectors.
Given that 3 vectors are coplanar ( $x-y$ plane)

Hence, the correct answer is 0.

Question 7: Find volume of parallelepiped having 3 co-terminal edges as $\hat{i}-\hat{j}, \hat{j}+2 \hat{k}, \hat{i}-3 \hat{j}+\hat{k}$. 

(1) 5

(2) 15
(3) 16

(4) 6

Correct answer: 1

Solution:

The volume of a parallelepiped is:

$
V=[\vec{a} \vec{b} \vec{c}]
$

- wherein

Sides are represented by $\vec{a}, \vec{b}, \vec{c}$

$
\left[\begin{array}{lll}
\vec{a} & \vec{b} & \vec{c}
\end{array}\right]=\left|\begin{array}{ccc}
1 & -1 & 0 \\
0 & 1 & 2 \\
1 & -3 & 1
\end{array}\right|=5
$

Hence, the correct answer is option (1).

Question 8: If the angle between $\vec{a}$ and $\vec{b}$ is $\frac{\pi}{3}$, whereas angle between $\vec{a} \times \vec{b}$ and $\vec{c}$ is $\frac{\pi}{6}$. Find the volume of parallelepiped formed by $\vec{a}, \vec{b}$ and $\vec{c}$ where

$|\vec{a}|=|\vec{b}|=2 \text { and }|\vec{c}|=2 \sqrt{3}$ 

(1) $2\sqrt3$ 

(2) $6\sqrt3$ 

(3) $8\sqrt3$ 

(4) $4\sqrt3$ 

Correct option: 2

Solution:

Volume of parallelepiped -

$\vec{a}, \vec{b}$ and $\vec{c}$ are the three edges if Parallelepiped. Volume $=a b c \cos \alpha \sin \theta$
$
\text { Volume }=2 \times 2 \times 2 \sqrt{3} \times \sin \frac{\pi}{3} \times \cos \frac{\pi}{6}=6 \sqrt{3}
$

Hence, the answer is option (2).

Question 9: Find volume of tetrahedron formed by vectors $\hat{i}-\hat{j}+2 \hat{k}, 2 \hat{i}+\hat{j}$ and $\hat{j}-2 \hat{k}$ is : 

(1) $\frac{1}{8}$ 

(2) $\frac{1}{3}$ 

(3) $\frac{8}{3}$ 

(4) $\frac{3}{8}$ 

Correct option: 2

Solution:
Volume of tetrahedron -

$
\frac{1}{6}[\vec{a} \vec{b} \vec{c}]
$

- wherein

The vertices of tetrahedron are $\vec{o}, \vec{a}, \vec{b}, \vec{c}$.

$
\mathrm{V}=\frac{1}{6}\left[\begin{array}{lll}
\vec{a} & \vec{b} & \vec{c}
\end{array}\right]=\frac{1}{6}| | \begin{array}{ccc}
1 & -1 & 2 \\
2 & 1 & 0 \\
0 & 1 & -2
\end{array}| |=\frac{1}{6}|(-2-4+4)|=\frac{1}{3}
$

Hence, the correct answer is option (2).

Question 10: Find $(\vec{a})^{\prime},(\vec{b})^{\prime},(\vec{c})^{\prime}$ which are reciprocal system of vectors of $\hat{i}+\hat{j}-\hat{k}, \hat{j}+2 \hat{k}$ and $\hat{i}-\hat{j}$. 

(1) $\frac{1}{5}\hat{i}+\frac{2}{5}\hat{j}-\frac{2}{5}\hat{k}\: ;\: \frac{1}{5}\hat{i}-\frac{1}{5}\hat{j}+\frac{1}{5}\hat{k}\: ;\: \frac{1}{5}\hat{i}-\frac{2}{5}\hat{j}+\frac{1}{5}\hat{k}$ 

(2) $\frac{1}{3}\hat{i}-\frac{1}{3}\hat{j}+\frac{2}{3}\hat{k}\: ;\: \frac{2}{5}\hat{i}+\frac{2}{5}\hat{j}-\frac{1}{5}\hat{k}\: ;\: \frac{3}{5}\hat{i}-\frac{2}{5}\hat{j}+\frac{1}{5}\hat{k}$ 

(3) $\frac{2}{5}\hat{i}+\frac{2}{5}\hat{j}-\frac{1}{5}\hat{k}\: ;\: \frac{1}{5}\hat{i}+\frac{1}{5}\hat{j}+\frac{2}{5}\hat{k}\: ;\: \frac{3}{5}\hat{i}-\frac{2}{5}\hat{j}+\frac{1}{5}\hat{k}$ 

(4) None of these 

Correct option: 3

Solution:
Reciprocal System of Vectors -

$
\begin{aligned}
\vec{a}^{\prime} & =\frac{\vec{b} \times \vec{c}}{[\vec{a} \vec{b} \vec{c}]} \\
\vec{b}^{\prime} & =\frac{\vec{c} \times \vec{a}}{[\vec{a} \vec{b} \vec{c}]} \\
\vec{c}^{\prime} & =\frac{\vec{a} \times \vec{b}}{[\vec{a} \vec{b} \vec{c}]}
\end{aligned}
$

- wherein
$\vec{a}, \vec{b}, \vec{c}$ are three vectors.

$\begin{aligned} & {\left[\begin{array}{lll}\vec{a} & \vec{b} & \vec{c}\end{array}\right]=\left|\begin{array}{ccc}1 & 1 & -1 \\ 0 & 1 & 2 \\ 1 & -1 & 0\end{array}\right|=2+2+1=5} \\ & \vec{b} \times \vec{c}=\left|\begin{array}{ccc}\hat{i} & \hat{j} & \hat{k} \\ 0 & 1 & 2 \\ 1 & -1 & 0\end{array}\right|=2 \hat{i}+2 \hat{j}-\hat{k} \\ & \vec{c} \times \vec{a}=\left|\begin{array}{ccc}\hat{i} & \hat{j} & \hat{k} \\ 1 & -1 & 0 \\ 1 & 1 & -1\end{array}\right|=\hat{i}+\hat{j}+2 \hat{k} \\ & \vec{a} \times \vec{b}=\left|\begin{array}{ccc}\hat{i} & \hat{j} & \hat{k} \\ 1 & 1 & -1 \\ 0 & 1 & 2\end{array}\right|=3 \hat{i}-2 \hat{j}+\hat{k}\end{aligned}$

Hence, the correct answer is option (3).

Question 11: Find vector area of $\triangle A B C$, if position vectors of vertices are $\hat{i}+\hat{j}, \hat{j}+\hat{k}, \hat{k}+\hat{i}$. 

(1) $\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$ 

(2) $\frac{1}{2}(\hat{i}+\hat{j})\times\hat{k}$ 

(3) $\frac{1}{2}(\hat{i}+\hat{j}+\hat{k})$ 

(4) $\frac{1}{2}(\hat{i}\times\hat{j}+\hat{j}\times\hat{k})$ 

Correct option: 3

Solution:

Vector Area -
area of $\triangle A B C$

$
=\frac{1}{2}[\vec{a} \times \vec{b}+\vec{b} \times \vec{c}+\vec{c} \times \vec{a}]
$

- wherein
$\vec{a}, \vec{b}$ and $\vec{c}$ are three vectors.
Vector Area -
area of $\triangle A B C$

$
=\frac{1}{2}[\vec{a} \times \vec{b}+\vec{b} \times \vec{c}+\vec{c} \times \vec{a}]
$

- wherein
$\vec{a}, \vec{b}$ and $\vec{c}$ are three vectors.

$\begin{aligned} \ area \ of \ triangle \ A B C & =\frac{1}{2}[(\hat{i}+\hat{j}) \times(\hat{j}+\hat{k})+(\hat{j}+\hat{k}) \times(\hat{k}+\hat{i})+(\hat{k}+\hat{i}) \times(\hat{i}+\hat{j})] \\ & =\frac{1}{2}[(\hat{k}-\hat{j}+\hat{i})+(\hat{i}-\hat{k}+\hat{j})+(\hat{j}-\hat{i}+\hat{k})] \\ & =\frac{1}{2}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

Hence, the correct answer is option (3).

Question 12: If $ A (0,1,3) , B (1,-1,2) , C (1,1,1) and D (0,2,1)$ are four vertices of a tetrahedron , then volume of ABCD is: 

(1) $\frac{1}{3}$ 

(2) $\frac{1}{2}$ 

(3) 2

(4) 7

Correct option: 2

Solution:

 $1=\frac{1}{6}\left ( A\vec{B} \times A\vec{C}\right )\cdot A\vec{D}=\frac{1}{6}1\begin{vmatrix} 1 &-2 &-1 \\ 1&0 &-2 \\ 0&1 &-2 \end{vmatrix}1=\frac{1}{6}\times 3=\frac{1}{2}$

Hence, the answer is option (2).

Question 13: What is moment of force, $\vec{F}=\hat{i}-2 \hat{j}+\hat{k}$ about O , where radius vector is $\vec{r}=2 \hat{i}+2 \hat{j}-3 \hat{k}$ ? 

(1) $\frac{2}{5}\hat{i}-\frac{1}{5}\hat{j}+\frac{3}{5}\hat{k}$ 

(2) $2\hat{i}+3\hat{j}+2\hat{k}$ 

(3) $4\hat{i}+6\hat{j}+5\hat{k}$ 

(4) $-4\hat{i}-5\hat{j}-6\hat{k}$ 

Correct option: 4

Solution:

Applications of Vectors -

$
\vec{M}=\vec{r} \times \vec{F}
$

- wherein
$\vec{r}$ is position vector of P part M is moment of $\vec{F}$ about O . Direction of $\vec{M}$ is along the normal to the plane OPN .

$
\vec{M}=\left|\begin{array}{ccc}
\hat{i} & \hat{j} & \hat{k} \\
2 & 2 & -3 \\
1 & -2 & 1
\end{array}\right|=-4 \hat{i}-5 \hat{j}-6 \hat{k}
$
Hence, the correct answer is Option (4).

Question 14: What is work done by a force, $\vec{F}=2 \hat{i}-\hat{j}+3 \hat{k}$ when displacement is $\vec{d}=\hat{i}+\hat{k}_?$ 

(1) 5

(2) 3

(3) 6

(4) 10

Correct option: 1

Solution:

$\hat{W}=\hat{c} \cdot \hat{a}=2-0+3=5$ units

Hence, the correct answer is 5. 

Question 15: $\vec{a} \times(\vec{b} \times \vec{c})$ is in plane of: 

(1) $\vec{b}$ and $\vec{c}$ 

(2) $\vec{a}$ and $\vec{b}$ 

(3) $\vec{a}$ and $\vec{c}$ 

(4) $\vec{a} \times \vec{b}$ and $\vec{c}$ 

Correct option: 1

Solution:

For three vectors $\overrightarrow{\mathbf{a}}, \overrightarrow{\mathbf{b}}$ and $\overrightarrow{\mathbf{c}}$ vector triple product is defined as $\overrightarrow{\mathbf{a}} \times(\overrightarrow{\mathbf{b}} \times \overrightarrow{\mathbf{c}})$. $\vec{a} \times(\vec{b} \times \vec{c})=(\vec{a} \cdot \vec{c}) \cdot \vec{b}-(\vec{a} \cdot \vec{b}) \cdot \vec{c}$

$\vec{a} \times(\vec{b} \times \vec{c})=x \vec{b}+y \vec{c}$

x and y are scalars.

Hence, the answer is the option 1.

Question 16: $\hat{i}\times (2\hat{i}\times \hat{j})$  is along which axis : 

(1) X-axis 

(2) Y-axis 

(3) Z-axis 

(4) None of these 

Correct option: 2 

Solution

Vector Triple Product -

$\vec{a} \times(\vec{b} \times \vec{c})$ is a vector perpendicular to $\vec{a}$ and $(\vec{b} \times \vec{c})$ 

Perpendicular to $\hat{i}$ and $2 \hat{i} \times \hat{j}$, $\hat{i}$ and $\hat{k} \rightarrow \hat{j}($ or $Y-$ axis $)$

Hence, the correct answer is option (2).

Question 17: $\vec{a} \times(\vec{b} \times \vec{c})$ is called : 

(1) Vector product 

(2) Vector triple product 

(3) Cross product 

(4) Cross triple product 

Correct option: 2

Solution:

For three vectors $\overrightarrow{\mathbf{a}}, \overrightarrow{\mathbf{b}}$ and $\overrightarrow{\mathbf{c}}$ vector triple product is defined as $\overrightarrow{\mathbf{a}} \times(\overrightarrow{\mathbf{b}} \times \overrightarrow{\mathbf{c}})$. $\vec{a} \times(\vec{b} \times \vec{c})=(\vec{a} \cdot \vec{c}) \cdot \vec{b}-(\vec{a} \cdot \vec{b}) \cdot \vec{c}$

Hence, the answer is the option 2.

Question 18: $\vec{a} \times(\vec{b}+\vec{c})=(\vec{a} \times \vec{b})+(\vec{a} \times \vec{c})$ Which property is it? 

(1) Commutative 

(2) Associative 

(3) Distributive 

(4) Equivalence 

Correct option: 3

Solution:

$\vec{a} \times(\vec{b}+\vec{c})=(\vec{a} \times \vec{b})+(\vec{a} \times \vec{c})$

Vector product is distributive

Hence, the answer is the option 3.

Question 19: $\vec{a} \times \vec{b}=\vec{c}$, then $\vec{a} \cdot \vec{c}=$ 

(1) 0

(2) 1

(3) $|\vec{b}|$ 

(4) $\vec{b}$ 

Correct option: 1

Solution

$\vec{a} \times \vec{b}$ is perpendicular to $\vec{a}$ and $\vec{b}$
wherein

$
\begin{aligned}
& \text { If } \vec{a} \times \vec{b}=\vec{c} \\
& \vec{c} \cdot \vec{a}=\vec{c} \cdot \vec{b}=0
\end{aligned}
$
Hence, the answer is the option 1

Question 20: If $\vec{a} \times \vec{b}=\hat{i}-\hat{j}+2 \hat{k}$, then $\vec{b} \times \vec{a}=$ 

(1) $\hat{i}-\hat{j}+2 \hat{k}$ 

(2) $\frac{\hat{i}-\hat{j}+2 \hat{k}}{\sqrt{6}}$ 

(3) $\hat{i}+\hat{j}+2 \hat{k}$ 

(4) None of these 

Correct option: 4

Solution:

The vector cross product satisfies the anti-commutative property:

$
\vec{a} \times \vec{b}=-(\vec{b} \times \vec{a})
$
Given:

$
\vec{a} \times \vec{b}=\hat{i}-\hat{j}+2 \hat{k},
$

we have:

$
\vec{b} \times \vec{a}=-(\hat{i}-\hat{j}+2 \hat{k})=-\hat{i}+\hat{j}-2 \hat{k}
$

Final Answer:

$
\vec{b} \times \vec{a}=-\hat{i}+\hat{j}-2 \hat{k}
$

Hence, the answer is the option 4

VITEEE Vector Algebra Important Topics 2027

Vector Algebra carries 11% of the weightage of all maths chapters. While preparing for VITEEE, students must cover the following topics in Vector Algebra:

• Different types of vectors

• Magnitude of a vector

• Unit vectors

• Direction cosines/ratios

• Addition/ Subtraction of vectors

• Multiplication by scalars

• Dot product of vectors

• Angle between two vectors

• Cross product of vectors

• Scalar triple product

• Vector equations

• Applications of vectors

Also Check: Most Scoring Topics in VITEEE| VITEEE Chapter-Wise Weightage 

Important VITEEE Vector Algebra Formulas

Before you solve VITEEE Vector Algebra Important Questions, it’s important to learn the basic vector formulas. These formulae are used quite often in numericals.

1. For vector $\vec{A}=a \hat{i}+b \hat{j}+c \hat{k}$, the magnitude $|\vec{A}|=\sqrt{a^2+b^2+c^2}$

2. Unit Vector: $\hat{A}=\frac{\vec{A}}{|\vec{A}|}$

3. The position vector of $P(x, y, z)$, is $\overrightarrow{O P}=x \hat{i}+y \hat{j}+z \hat{k}$

4. $\vec{A}+\vec{B}=\left(a_1+b_1\right) \hat{i}+\left(a_2+b_2\right) \hat{j}+\left(a_3+b_3\right) \hat{k}$

5. $\vec{A}-\vec{B}=\left(a_1-b_1\right) \hat{i}+\left(a_2-b_2\right) \hat{j}+\left(a_3-b_3\right) \hat{k}$

6. Distance between 2 vectors 

$A B=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2+\left(z_2-z_1\right)^2}$

7. Dot products: $\vec{A} \cdot \vec{B}=|\vec{A}||\vec{B}| \cos \theta$

8. Angle between 2 vectors: $\cos \theta=\frac{\vec{A} \cdot \vec{B}}{|\vec{A}||\vec{B}|}$

9. Cross product: $|\vec{A} \times \vec{B}|=|\vec{A}||\vec{B}| \sin \theta$

10. Projection of One Vector on Another

• Scaler: $\frac{\vec{A} \cdot \vec{B}}{|\vec{B}|}$

• Vector: $\frac{\vec{A} \cdot \vec{B}}{|\vec{B}|^2} \vec{B}$

11. Vector Triple Product:  $\vec{A} \times(\vec{B} \times \vec{C})=\vec{B}(\vec{A} \cdot \vec{C})-\vec{C}(\vec{A} \cdot \vec{B})$

Also Check: VITEEE 2027 Important Formulas

Preparation Tips for Vector Algebra in VITEEE

Students need to be clear about the basics and formulae of Vector Algebra to prepare for VITEEE. Practice is the key to improving calculation ability and speed. Here are some easy tips that can help you prepare better:

1. Learn basic concepts like vectors, magnitude, unit vectors, direction ratios and cosines.

2. Go through the important formulas like dot product, cross product, angle between vectors and scalar triple product.

3. Practice VITEEE Vector Algebra questions to get acquainted with various question formats.

4. Practice calculations properly since calculation errors might give you the wrong answer.

5. Do not forget to include Vector Algebra in your VITEEE mock test practice.

Also Check: VITEEE 2027 Preparation Tips 

Best Books for VITEEE Vector Questions

While preparing vector questions for VITEEE, it is very important to follow the best books because they help properly cover all the concepts. 

Why Practice VITEEE Vector Algebra MCQs

There are various advantages of practising vector algebra problems:

1. VITEEE Vector Algebra Questions will enhance your knowledge about various aspects of vectors.

2. It will enable you to acquaint yourself with different types of questions.

3. VITEEE Vector Algebra Practice Questions will increase your speed of calculations.

4. It will assist in identifying areas that require further practice.