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JEE Main 2021 Feb 23 & 24 Question Paper and Answer Key

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NTA has released the JEE Main 2021 official question paper and answer key for Feb 23 and 24. Download now.
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Hello Akshat,

Securing 89 marks in JEE Mains 2025 (29th Jan, Shift 2) could place you in a certain percentile and rank based on the exam difficulty and the overall performance of all candidates across shifts.

Since the Maths section was hard , Chemistry was tricky , and Physics was moderate to easy , the overall exam difficulty for your shift might affect the percentile calculation.

Based on historical trends:

  • 89 marks might correspond to a percentile range of 70-80 .

  • Your rank will depend on how well others performed, but it is expected to be around 50,000 to 60,000 in general (approximate).

Please note, the exact percentile and rank will be clearer once the final JEE Mains results and normalization process are announced, as these factors can affect the ranking system.


I would recommend you to use JEE Mains Rank Predictor Tool by Careers360 to get the list of possible colleges you can get with your rank.


I hope this answer helps you. If you have more queries then feel free to share your questions with us we will be happy to assist you.

Thank you and wishing you all the best for your bright future.


Hello there,

For a score of 134 marks in the JEE Mains 2025 exam, January 24th, second shift , the expected percentile range would likely fall between 90 to 95 percentile , assuming the exam difficulty level is moderate.

The actual percentile depends on factors like the number of candidates appearing in that shift, overall performance, and the normalization process used by NTA. However, this is a general estimate based on historical data.

The final and exact percentile will be available once the official results are declared.


I would recommend you to use JEE Mains Rank Predictor Tool by Careers360 to get the list of possible colleges you can get with your rank.


I hope this answer helps you. If you have more queries then feel free to share your questions with us we will be happy to assist you.

Thank you and wishing you all the best for your bright future.


Hello,

The JEE Mains percentile required for DY Patil College of Engineering, Pune varies depending on the branch you are targeting. Based on past trends:

CSE, IT, AI-ML → 85-90+ percentile

ECE, Electrical, Mechanical → 75-85 percentile

Civil, Chemical, and other core branches → 65-75 percentile

With a score of 94 in JEE Main 2025 and your classification as an OBC-NCL-PwD candidate, your estimated percentile is approximately 70–75. This percentile range typically corresponds to an All India Rank (AIR) between 50,000 and 60,000.



Admission Prospects for Computer Science Engineering (CSE):


Securing a seat in the Computer Science Engineering (CSE) branch at top National Institutes of Technology (NITs) with this rank may be challenging, as the cutoffs for CSE are generally higher. For instance, NIT Trichy had a closing rank of 4,178 for OBC-NCL candidates in 2024.

Refer: engineering.careers360.com/articles/nits-cutoff-for-b-tech-computer-science-and-engineering


Alternative Options:


Given the competitive nature of CSE admissions, you might consider the following alternatives:


Other Engineering Branches: Exploring branches with relatively lower cutoffs, such as Civil Engineering, Mechanical Engineering, or Electrical Engineering, could increase your chances of securing a seat.


State Engineering Colleges: Considering reputable state engineering colleges in Tamil Nadu, such as Anna University and its affiliated institutions, may offer more favorable admission prospects.


Private Institutions: Private engineering colleges and universities often have different admission criteria and may provide opportunities in the CSE branch.


Next Steps:


Participate in Counseling: Engage in the Joint Seat Allocation Authority (JoSAA) counseling process to explore available options across various institutes and branches.


Stay Informed: Regularly check official announcements and cutoff trends for the current year, as they can vary based on factors like exam difficulty and the number of applicants.


Consider State Quota: Utilize the home state quota in NITs located in Tamil Nadu, as it can improve your chances of securing a seat in preferred branches.


While the path to securing a seat in CSE at top NITs may be challenging with your current rank, exploring alternative branches and institutions can still lead to a rewarding engineering education.

Hello there,

To get admission to Haldia Institute of Technology (HIT) for B.Tech, you will need to qualify the JEE Mains exam and meet the cutoff percentile specified by the institute. Here's how you can proceed:

1. JEE Mains Percentile:

  • The exact percentile required for admission to HIT may vary each year depending on factors such as the number of applicants, difficulty of the exam, and available seats.

  • Typically, for admission to good private engineering colleges like Haldia Institute of Technology , you may need a percentile in the range of 85-95 or higher, depending on the branch you are applying for.

    2. Counseling Process:

  • HIT accepts JEE Mains scores through WBJEE Counseling (West Bengal Joint Entrance Examination). Once the results are declared, the counseling process will begin, where you can choose HIT based on your rank and available seats.

  • If you have a good rank or percentile, you can get a seat in popular branches like CSE , IT , Electronics , etc.

    3. Application:

  • After the JEE Mains results, check the official website of HIT for the specific admission process.

  • Apply through the WBJEE counseling platform or directly to the college if applicable.

    4. Admission Requirements:

  • Along with the JEE Mains score, the institute may also consider your academic performance in Class 12th .

  • Make sure to check the exact eligibility and cutoff criteria from the official HIT website or WBJEE portal.



    I hope this answer helps you. If you have more queries then feel free to share your questions with us we will be happy to assist you.

    Thank you and wishing you all the best for your bright future.

The National Testing Agency (NTA) has released the provisional answer key for JEE Main 2025 Session 1 on February 4, 2025. You can download the question papers along with the answer keys from the official JEE Main website by logging in with your application number and password or date of birth. The last date to raise objections against the provisional answer key is today, February 6, 2025.

Additionally, several educational platforms have provided the JEE Main 2025 question papers with solutions:


ALLEN Career Institute: Offers free access to download the question papers and solutions organized by shift and subject for the January session.



eSaral: Provides JEE Main 2025 question papers with answer keys and solutions available for download.



Vedantu: Offers free PDF downloads of memory-based JEE Main 2025 question papers with solutions for Physics, Chemistry, and Mathematics.



Aakash Institute: Provides JEE Main 2025 answer keys and solutions for the January sessions.



These resources can assist you in cross-verifying your responses and estimating your scores. Remember to download the official answer key and question papers from the NTA's website and raise any objections before the deadline if necessary.

Hello Raghav,

The percentile corresponding to 96 marks in JEE Mains depends on various factors, including the overall difficulty level of the exam, the performance of candidates, and the normalization process used by NTA.

However, based on historical trends, a score of 96 marks in the January session could roughly correspond to a percentile range between 85 to 90 percentile, but this is an estimate and could vary.

The exact percentile will be calculated based on your score relative to the total number of candidates who appeared in the exam and the overall performance of all students in that particular session.

To get your precise percentile, you will need to wait for the official results, which will include the normalization process.


I would recommend you to use JEE Mains Rank Predictor Tool by Careers360 to get the list of possible colleges you can get with your rank.


I hope this answer helps you. If you have more queries then feel free to share your questions with us we will be happy to assist you.

Thank you and wishing you all the best for your bright future.


Hello there,

Scoring 80 marks in JEE Mains is decent but it depends on various factors, including your category and the difficulty level of the exam that year. Generally, the cutoff for JEE Mains is around 70-90 marks for students in the General category, but it could vary.

For the General category , an 80 mark score might be near the cutoff for qualifying but could be on the lower end for admission into top-tier colleges. For SC, ST, OBC, or other reserved categories , an 80 mark score could be quite competitive.

However, this score alone doesn't guarantee admission to prestigious institutions like IITs or NITs. If you want to get into NITs , your rank will depend on the overall performance, and you might need to perform well in JEE Advanced for admission to IITs.

Improving your score can help you secure better options, so if you're planning for another attempt, consider revising your preparation strategy.


I hope this answer helps you. If you have more queries then feel free to share your questions with us we will be happy to assist you.

Thank you and wishing you all the best for your bright future.


Hi,

If your biometric data in aadhar card  is not updated then it will create problem for you during your exam time because without biometric verification no one is allowed to appear for JEE MAINS exam. Inorder to avoid any problem during online exam you have to first update your biometric data of aadhar at priority basis and then apply for JEE MAINS exams.

Hope this information will help you

Based on analyses of the JEE Main 2025 exam conducted on January 23, Shift 1, scoring 75 marks is expected to place you in the 87.5 to 90.7 percentile range.

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