BITSAT 2025 Logical Reasoning Questions with Solutions
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  • BITSAT 2025 Logical Reasoning Questions with Solutions

BITSAT 2025 Logical Reasoning Questions with Solutions

Shivani PooniaUpdated on 16 Dec 2025, 05:19 AM IST

BITSAT 2026 Logical Reasoning Questions - Candidates planning for the BITSAT 2026 exam must see the sample BITSAT logical reasoning questions given in this article. The logical reasoning section is a highly recommended part of BITSAT, made to assess student's logical and analytical abilities. Candidates often find this section hard due to its diverse range of question types and the requirement for quick thinking. We are providing some important types of BITSAT logical reasoning questions 2026. BITS Pilani will be taking BITSAT 2026 as a computer-based test for admission to undergraduate engineering programs at its campuses in Pilani, Hyderabad, and Goa.

This Story also Contains

  1. BITSAT 2026 Logical Reasoning Questions
  2. BITSAT 2026 logical Reasoning Topics (Weightage-wise)
  3. BITSAT 2026 Preparation Tips
BITSAT 2025 Logical Reasoning Questions with Solutions
BITSAT 2025 Logical Reasoning Questions with Solutions

BITSAT 2026 is planned to be held in two sessions as a computer-based test, Session 1 in May and Session 2 in June, 2026. To get ready for the logical reasoning questions of BITSAT 2026, you will need to understand fundamental concepts and practice BITSAT sample papers. Regular practice of previous years' question papers, BITSAT LR questions and BITSAT 2026 mock tests will help candidates become used to various types of BITSAT LR questions and improve their speed and accuracy.

BITSAT 2026 Logical Reasoning Questions


As per the BITSAT exam pattern, the exam will have a total of 4 sections. One such section is Logical reasoning and English proficiency. The BITSAT logical reasoning section will comprise 20 BITSAT LR questions. Each question will be worth 3 marks, thus making the logical reasoning section a significant component. The BITSAT 2025 logical reasoning questions will test candidates on various aspects of logical reasoning, analytical thinking, and problem-solving skills. Check the BITSAT logical reasoning verbal reasoning questions below.

Q1. In the following question, a matrix of certain characters is given. These characters follow a certain trend, row-wise or column-wise. Find out this trend and choose the missing character accordingly.

1715836013187

  1. 18

  2. 24

  3. 36

  4. 58

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Solution:

(7 x 3) = 21 and (9 x 3) = 27

and (4 x 9) = 36 and (2 x 9) = 18

Therefore (9 x 6) = 54 and (4 x 6) = 24.

Hence option B is correct.

Q2. In the following question, a matrix of certain characters is given. These characters follow a certain trend, row-wise or column-wise. Find out this trend and choose the missing character accordingly.

1715836012737

  1. 6

  2. 8

  3. 12

  4. 10

Solution:

In each column, the fourth value is obtained by taking the cube root of the result of multiplying the first three values of the same column.

3*6*12=216=2161/3=6

2*4*64=512=5121/3=8

Hence option B is correct.

Q3. Select a suitable figure from the four alternatives that would complete the figure matrix.

1715836012479

  1. 1715836013794

  2. 1715836011077

  3. 1715836014022

  4. 1715836013123

Solution: In each row, the third figure is the uncommon part of the first two figures.

Hence option D is correct.

Q4. Select a suitable figure from the four alternatives that would complete the figure matrix.

1715836013429

  1. 1715836011213

  2. 1715836012393

  3. 1715836011619

  4. 1715836011503

Solution: There are 3 types of faces, 3 types of bodies, 3 types of hands and 3 types of legs, each of which is used only once in a single row. So, the features which have not been used in the first two figures of the third row would combine to produce the missing figure.

Hence option B is correct.

Q5. Find out which of the answer figures (a), (b), (c) and (d) complete the figure matrix.

1715836013344

  1. 1715836012038

  2. 1715836011736

  3. 1715836010966

  4. 1715836012923

Solution: In each row, the second figure is obtained from the first figure by reversing the direction of the RHS arrow and the third figure is obtained from the second figure by reversing the direction of both arrows.

Hence option A is correct.

Q6. Count the number of triangles and squares in the given figure.

1715836014262

  1. 44 triangles, 10 squares

  2. 14 triangles, 16 squares

  3. 27 triangles, 6 squares

  4. 36 triangles, 9 squares

Solution:

Triangles:

  • The simplest triangles are AEI, EOI, OHI, HAI, EBJ, BFJ, FOJ, OEJ, HOL, OGL, GDL, DHL, OFK, FCK, CGK and GOK i.e. 16 in number.
  • The triangles composed of two components each are HAE, AEO, EOH, OHA, OEB, EBF, BFO, FOE, DHO, HOG, OGD, GDH, GOF, OFC, FCG and CGO i.e. 16 in number.
  • The triangles are composed of four components each HEF, EFG, FGH, GHE, ABO, BGO, CDO and DAO i.e. 8 in number.
  • The triangles are composed of eight components each are DAB, ABC, BCD and CDA i.e. 4 in number.
  • Total number of triangles in the figure = 16 + 16 + 8 + 4 = 44.

Squares:

  • The squares composed of two components are HIOL, IEJO, JFKO and KGLO i.e. 4 in number.
  • The squares composed of four components are AEOH, EBFO, OFGC and HOGD i.e. 4 in number.
  • There is only one square EFGH which is composed of eight components.
  • There is only one square ABCD which is composed of sixteen components.
  • Total number of squares in the figure = 4 + 4 + 1 + 1 = 10

Hence option A is correct.

Q7. How many rectangles are there in the given figure?

1715836011332

  1. 10

  2. 9

  3. 8

  4. 7

Solution: The simplest rectangles are ABJI, BCKJ, IJFG and JKEF i.e. 4 in number.

The rectangle composed of two components each is ACKI, BCEF, IKEG and ABFG i.e. 4 in number.

The only rectangle composed of four components is ACEG.

Thus, there are 4+4+1=9 rectangles in the given figure.

Hence option B is correct.

Q8. Find the number of triangles in the given figure.

1715836012809

  1. 18

  2. 20

  3. 24

  4. 27

Solution: The simplest triangles are IJO, BCJ, CDK, KQL, MLQ, GFM, GHN and NIO i.e. 8 in number.

The triangles composed of two components each are ABO, AHO, NIJ, IGP, ICP, DEQ, FEQ, KLM, LCP and LGP i.e. 10 in number.

The triangles are composed of four components each HAB, DEF, LGI, GIC, ICL and GLC i.e. 6 in number.

Total triangles= 8+10+6= 24

Hence option C is correct.

Q9. Choose the alternative which closely resembles the water image of the given combination.

1715836012153

  1. 1715836014081

  2. 1715836011681

  3. 1715836011802

  4. 1715836011451

Solution: In mirror images, the characters and numbers are horizontally inverted. In mirror images right side appears as a left side in the same way the left appears in the right side. The water image is only reversed for all letters. The water image is the anticlockwise reverse of the mirror image. Firstly make a mirror image and then rotate anti-clockwise your notebook. It will be a water image. Hence option D is correct.

Q10. Choose the alternative which closely resembles the water image of the given combination.

1715836011271

  1. 1715836013049

  2. 1715836014326

  3. 1715836014202

  4. 1715836014137

Solution: In mirror images, the characters and numbers are horizontally inverted. In mirror images right side appears as a left side in the same way the left appears in the right side. The water image is only reversed for all letters. The water image is the anticlockwise reverse of the mirror image. Firstly make a mirror image and then rotate anti-clockwise your notebook. It will be a water image. Hence option B is correct.

Q 11. Choose the alternative which closely resembles the mirror image of the given combination.

1715836013898

  1. 1715836012215

  2. 1715836011857

  3. 1715836011918

  4. 1715836013962

Solution: In mirror images, the characters and numbers are horizontally inverted. In mirror images right side appears as the left side in the same way the left appears in the right side. The water image is only reversed for all letters. The water image is the anticlockwise reverse of the mirror image. Firstly make a mirror image and then rotate anti-clockwise your notebook. It will be a water image. Hence option D is correct.

Q12. Choose the alternative which closely resembles the mirror image of the given combination.

1715836012541

  1. 1715836011149

  2. 1715836011563

  3. 1715836012096

  4. 1715836012333

Solution: In mirror images, the characters and numbers are horizontally inverted. In mirror images, the right side appears as the left side in the same way the left appears on the right side. The water image is only reversed for all letters. The water image is the anticlockwise reverse of the mirror image. Firstly make a mirror image and then rotate anti-clockwise your notebook. It will be a water image. Hence option D is correct.

Q13. Choose the alternative which closely resembles the mirror image of the given combination.

1715836013716

  1. 1715836013242

  2. 1715836012603

  3. 1715836012667

  4. 1715836012869

Solution: In mirror images, the characters and numbers are horizontally inverted. In mirror images right side appears as a left side in the same way the left appears in the right side. The water image is only reversed for all letters. The water image is the anticlockwise reverse of the mirror image. Firstly make a mirror image and then rotate anti-clockwise your notebook. It will be a water image. Hence option B is correct.

Q14. Find out which of the answer figures (a), (b), (c) and (d) complete the figure matrix.

1715836013514

  1. 1715836011390

  2. 1715836012277

  3. 1715836012992

  4. 1715836011977

Solution: In each row(as well as column), the figure in the third box is a combination of all the elements of the first and second figures.

Hence option D is correct.

Q14. 3,10,29,66,127,?

  1. 164

  2. 187

  3. 216

  4. 218

Solution: The given series is a triangular pattern series.

So we have,

3 10 29 66 127 ?

7 19 37 61

12 18 24

6 6

so missing term is = 127+ (61+24+6)=127+91=218

Q15. Earth is to Venus as Mercury is to

  1. Sun

  2. Pluto

  3. Mars

  4. Moon

Solution: Venus is the planet nearest to the Earth. Likewise, Mercury is the planet nearest to the Sun.

BITSAT 2026 logical Reasoning Topics (Weightage-wise)

Candidates can check some important topics for the BITSAT 2026 logical reasoning sections along with their expected weightage below.

Logical Reasoning Topics

Important Topics

Weightage of topics in the exam

Figure Matrix, Figure Formation and Analysis

40%

  • Logical Deduction

  • Analogy Test

  • Series Test Numerical and Alphabetical

10-20%

  • Paper folding and cutting

  • Detection of the rule

  • Figure Completion Test

5-7%

Related links:

BITSAT 2026 Preparation Tips

Here are some preparation tips for BITSAT 2026. Candidates can refer to the following points to ace the exam.

  • Know the Syllabus- Candidates must understand the BITSAT 2026 syllabus well before starting their preparation. Knowledge of the correct syllabus will help the candidates to study the right topics for the exam.

  • Make a timetable- Candidates must manage all the available time for preparation in a better way by preparing a timetable and following the BITSAT books. As we have already mentioned the important topics for BITSAT 2026, candidates can also take up the important topics first. The timetable should be made in such a way that the entire syllabus of each section of the exam is covered before time.

  • Important Books- Candidates must generally start the BITSAT preparations with NCERT books. After this, they should refer to the important reference books mentioned in the article.

  • Mock tests and sample papers- Candidates must practice more and more mock tests of BITSAT as these are based on the actual pattern of the exam. These also help the candidates to analyze their performance.

  • Revision- As revision is the key, candidates should give proper time to revision in their BITSAT preparation plan. The candidates must revise whatever they have studied.

Frequently Asked Questions (FAQs)

Q: Does BITSAT provide model question papers?
A:

No — the institute does not provide model/question‑papers for BITSAT.

Q: How many sessions/attempts are available for BITSAT in a year?
A:

There are two sessions per year (Session 1 & Session 2). Candidates who opt for both can take the better of the two scores.

Q: What are the session-wise exam dates for BITSAT 2026?
A:

BITSAT 2026 will be conducted multiple times in two sessions. The first session will be held from April 15–17, 2026, followed by the second session from May 24–26, 2026. Candidates can choose to appear in one or both sessions, with admissions based on the best score obtained across the sessions.

Q: Do I need to apply separately for each of the BITS campuses (Pilani, Goa, Hyderabad)?
A:

No — a single online application covers all three campuses.  

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Questions related to BITSAT

On Question asked by student community

Have a question related to BITSAT ?

Since you're from Delhi and have already registered for JEE, BITSAT, VITEEE, and CUET, consider these additional exams: SRMJEEE (SRM Institute of Science and Technology), COMEDK UGET (for Karnataka engineering colleges), WBJEE (West Bengal Joint Entrance Examination), AEEE (Amrita Entrance Examination for Amrita Vishwa Vidyapeetham), KIITEE (Kalinga Institute of Industrial

Hello,
For BITSAT 2026, the approximate weightage across subjects is often given as:
Mathematics: ~ 40 %
Physics: ~ 30 %
Chemistry: ~ 25 %
English + Logical Reasoning: ~ 10 % combined

To know the syllabus and questions Check the follwing link,
https://www.careers360.com/exams/bitsat

Kindly check the below link to

Hello,
If you are looking for colleges with good placements other than through JEE or BITSAT, you can consider private and state-level engineering colleges that conduct their own entrance exams or accept board exam scores. Many of these colleges have strong industry connections and placement cells that help students get

Hello Aspirant,

From your BITSAT score of 210, BITS Hyderabad entry supports a very focused choice of integrated M.Sc. (like M.Sc. Physics, Chemistry, Mathematics, Economics or Biology). Generally with this score, admission into the M.Sc. programs at BITS Hyderabad is likely competitive. Based on past trends, the cutoff's for the

Hello Aspirant,

With a BITSAT score of 172 and SRMJEEE Phase 2 rank of 14,110, securing top branches like CSE at BITS Pilani, Goa, or Hyderabad is unlikely, as their cutoffs are much higher (around 240–270+ for lesser-known branches). Similarly, SRM KTR campus for CSE closes within ~2,000–5,000 rank, so