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BITSAT 2026 Logical Reasoning Questions - Candidates planning for the BITSAT 2026 exam must see the sample BITSAT logical reasoning questions given here. The logical reasoning section is a highly recommended part of BITSAT, made to assess student's logical and analytical abilities. Candidates often find this section hard due to its diverse range of question types and the requirement for quick thinking. We are providing some important types of BITSAT logical reasoning questions 2025. BITS Pilani will be taking BITSAT 2026 as a computer-based test for admission to undergraduate engineering programs at its campuses in Pilani, Hyderabad, and Goa.
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BITSAT 2026 is planned to be held in two sessions as a computer-based test, Session 1 in May and Session 2 in June, 2026. To get ready for the logical reasoning questions of BITSAT 2026, you will need to understand fundamental concepts and practice BITSAT sample papers. Regular practice of previous years' question papers, BITSAT LR questions and BITSAT 2026 mock tests will help candidates become used to various types of BITSAT LR questions and improve their speed and accuracy.
As per the BITSAT exam pattern, the exam will have a total of 4 sections. One such section is Logical reasoning and English proficiency. The BITSAT logical reasoning section will comprise 20 BITSAT LR questions. Each question will be worth 3 marks, thus making the logical reasoning section a significant component. The BITSAT 2025 logical reasoning questions will test candidates on various aspects of logical reasoning, analytical thinking, and problem-solving skills. Check the BITSAT logical reasoning verbal reasoning questions below.
Q1. In the following question, a matrix of certain characters is given. These characters follow a certain trend, row-wise or column-wise. Find out this trend and choose the missing character accordingly.
18
24
36
58
Solution:
(7 x 3) = 21 and (9 x 3) = 27
and (4 x 9) = 36 and (2 x 9) = 18
Therefore (9 x 6) = 54 and (4 x 6) = 24.
Hence option B is correct.
Q2. In the following question, a matrix of certain characters is given. These characters follow a certain trend, row-wise or column-wise. Find out this trend and choose the missing character accordingly.
6
8
12
10
Solution:
In each column, the fourth value is obtained by taking the cube root of the result of multiplying the first three values of the same column.
3*6*12=216=2161/3=6
2*4*64=512=5121/3=8
Hence option B is correct.
Q3. Select a suitable figure from the four alternatives that would complete the figure matrix.
Solution: In each row, the third figure is the uncommon part of the first two figures.
Hence option D is correct.
Q4. Select a suitable figure from the four alternatives that would complete the figure matrix.
Solution: There are 3 types of faces, 3 types of bodies, 3 types of hands and 3 types of legs, each of which is used only once in a single row. So, the features which have not been used in the first two figures of the third row would combine to produce the missing figure.
Hence option B is correct.
Q5. Find out which of the answer figures (a), (b), (c) and (d) complete the figure matrix.
Solution: In each row, the second figure is obtained from the first figure by reversing the direction of the RHS arrow and the third figure is obtained from the second figure by reversing the direction of both arrows.
Hence option A is correct.
Q6. Count the number of triangles and squares in the given figure.
44 triangles, 10 squares
14 triangles, 16 squares
27 triangles, 6 squares
36 triangles, 9 squares
Solution:
Triangles:
Squares:
Hence option A is correct.
Q7. How many rectangles are there in the given figure?
10
9
8
7
Solution: The simplest rectangles are ABJI, BCKJ, IJFG and JKEF i.e. 4 in number.
The rectangle composed of two components each is ACKI, BCEF, IKEG and ABFG i.e. 4 in number.
The only rectangle composed of four components is ACEG.
Thus, there are 4+4+1=9 rectangles in the given figure.
Hence option B is correct.
Q8. Find the number of triangles in the given figure.
18
20
24
27
Solution: The simplest triangles are IJO, BCJ, CDK, KQL, MLQ, GFM, GHN and NIO i.e. 8 in number.
The triangles composed of two components each are ABO, AHO, NIJ, IGP, ICP, DEQ, FEQ, KLM, LCP and LGP i.e. 10 in number.
The triangles are composed of four components each HAB, DEF, LGI, GIC, ICL and GLC i.e. 6 in number.
Total triangles= 8+10+6= 24
Hence option C is correct.
Q9. Choose the alternative which closely resembles the water image of the given combination.
Solution: In mirror images, the characters and numbers are horizontally inverted. In mirror images right side appears as a left side in the same way the left appears in the right side. The water image is only reversed for all letters. The water image is the anticlockwise reverse of the mirror image. Firstly make a mirror image and then rotate anti-clockwise your notebook. It will be a water image. Hence option D is correct.
Q10. Choose the alternative which closely resembles the water image of the given combination.
Solution: In mirror images, the characters and numbers are horizontally inverted. In mirror images right side appears as a left side in the same way the left appears in the right side. The water image is only reversed for all letters. The water image is the anticlockwise reverse of the mirror image. Firstly make a mirror image and then rotate anti-clockwise your notebook. It will be a water image. Hence option B is correct.
Q 11. Choose the alternative which closely resembles the mirror image of the given combination.
Solution: In mirror images, the characters and numbers are horizontally inverted. In mirror images right side appears as the left side in the same way the left appears in the right side. The water image is only reversed for all letters. The water image is the anticlockwise reverse of the mirror image. Firstly make a mirror image and then rotate anti-clockwise your notebook. It will be a water image. Hence option D is correct.
Q12. Choose the alternative which closely resembles the mirror image of the given combination.
Solution: In mirror images, the characters and numbers are horizontally inverted. In mirror images, the right side appears as the left side in the same way the left appears on the right side. The water image is only reversed for all letters. The water image is the anticlockwise reverse of the mirror image. Firstly make a mirror image and then rotate anti-clockwise your notebook. It will be a water image. Hence option D is correct.
Q13. Choose the alternative which closely resembles the mirror image of the given combination.
Solution: In mirror images, the characters and numbers are horizontally inverted. In mirror images right side appears as a left side in the same way the left appears in the right side. The water image is only reversed for all letters. The water image is the anticlockwise reverse of the mirror image. Firstly make a mirror image and then rotate anti-clockwise your notebook. It will be a water image. Hence option B is correct.
Q14. Find out which of the answer figures (a), (b), (c) and (d) complete the figure matrix.
Solution: In each row(as well as column), the figure in the third box is a combination of all the elements of the first and second figures.
Hence option D is correct.
Q14. 3,10,29,66,127,?
164
187
216
218
Solution: The given series is a triangular pattern series.
So we have,
3 10 29 66 127 ?
7 19 37 61
12 18 24
6 6
so missing term is = 127+ (61+24+6)=127+91=218
Q15. Earth is to Venus as Mercury is to
Sun
Pluto
Mars
Moon
Solution: Venus is the planet nearest to the Earth. Likewise, Mercury is the planet nearest to the Sun.
Candidates can check some important topics for the BITSAT 2026 logical reasoning sections along with their expected weightage below.
Important Topics |
Weightage of topics in the exam |
Figure Matrix, Figure Formation and Analysis |
40% |
|
10-20% |
|
5-7% |
Related links:
Here are some preparation tips for BITSAT 2026. Candidates can refer to the following points to ace the exam.
Know the Syllabus- Candidates must understand the BITSAT 2026 syllabus well before starting their preparation. Knowledge of the correct syllabus will help the candidates to study the right topics for the exam.
Make a timetable- Candidates must manage all the available time for preparation in a better way by preparing a timetable and following the BITSAT books. As we have already mentioned the important topics for BITSAT 2026, candidates can also take up the important topics first. The timetable should be made in such a way that the entire syllabus of each section of the exam is covered before time.
Important Books- Candidates must generally start the BITSAT preparations with NCERT books. After this, they should refer to the important reference books mentioned in the article.
Mock tests and sample papers- Candidates must practice more and more mock tests of BITSAT as these are based on the actual pattern of the exam. These also help the candidates to analyze their performance.
Revision- As revision is the key, candidates should give proper time to revision in their BITSAT preparation plan. The candidates must revise whatever they have studied.
On Question asked by student community
Hello Aspirant,
From your BITSAT score of 210, BITS Hyderabad entry supports a very focused choice of integrated M.Sc. (like M.Sc. Physics, Chemistry, Mathematics, Economics or Biology). Generally with this score, admission into the M.Sc. programs at BITS Hyderabad is likely competitive. Based on past trends, the cutoff's for the M.Sc. programs at Hyderabad have ranged 220 to 250. While 210 will typically be below the cutoff marks for most M.Sc. courses, you might still have a small chance / opportunity during the last / spot rounds, provided the cutoff trend is slightly lower that year.
Hello Aspirant,
With a BITSAT score of 172 and SRMJEEE Phase 2 rank of 14,110, securing top branches like CSE at BITS Pilani, Goa, or Hyderabad is unlikely, as their cutoffs are much higher (around 240–270+ for lesser-known branches). Similarly, SRM KTR campus for CSE closes within ~2,000–5,000 rank, so core branches at SRM KTR may not be possible, but Ramapuram or Vadapalani campuses might offer CSE or allied branches.
Now, comparing your other two options:
VIT Bhopal
Part of the reputed VIT group.
Newer campus but decent infrastructure.
Better academic reputation than CU.
Good placements mainly for CSE/IT streams.
Chandigarh University (CU):
Known for aggressive placement marketing.
Good exposure, foreign tie-ups, and more affordable for North Indian students.
Decent placement packages for CSE/AI/ML, but mass placements are often on the lower side.
If you get CSE or CSE-related branches at VIT Bhopal then you take admission at VIT Bhopal.
If not, Chandigarh University is a decent alternative, especially if you’re from North India and want affordability and exposure.
All the best for your admission process.
Hello,
To get admission into B.Tech Cyber Security at BITS , you need to follow these steps:
Fill out the BITSAT application form on the official website.
Prepare for subjects like Physics, Chemistry, Maths, English, and Logical Reasoning.
Appear for the BITSAT exam as per the given schedule.
Try to score well (around 270+ is usually safe for Cyber Security).
After the result, apply for counselling and choose B.Tech Cyber Security as your first preference.
If your score meets the cut-off, you will get a seat.
Keep checking the official website for updates and important dates.
Hope it helps !
Hello,
With a BITSAT score of 263, getting EEE or Electronics and Instrumentation at BITS Hyderabad or Goa may be tough. These branches usually close at a higher score.
Even if the paper was tougher this year, the cut-offs may not drop much. You might have a better chance in later rounds, but it’s still a bit difficult. Keep backup options ready.
Hope it helps !
Pattern of Exam and structure:
Mode : Computer-based test (CBT), English only
Duration : 3 hours (180 minutes), with no sectional time limits
Total Questions : 130 main MCQs (4 options each)
Physics - 30
Chemistry - 30
English Proficiency - 10
Logical Reasoning - 20
Mathematics (or Biology for B.Pharm) - 40
Marks : +3 per correct, -1 per wrong, 0 for unattempted
Extra Questions : If you complete all 130 within time, you can attempt up to 12 additional bonus questions (across core subjects); once attempted, you cannot review earlier answers.
You can download them for free using:
Engineering Careers360 article titled '
BITSAT 2025 Question Paper with Solutions - Download PDF'
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