25 Questions around this concept.
For the curve $y=3 \sin \theta \cos \theta, \mathrm{x}=e^\theta \sin \theta, 0 \leq \theta \leq \pi$, the tangent is parallel to $x$-axis when $\theta$ is :
If $\mathrm{x^{y}+y^{x}= 2,\, then\, \frac{dy}{dx}\, at\; x= 1\, equals}$
Differentiation of Implicit Function
If variables $x$ and $y$ are connected by a relation of the form $f(x, y)=0$ and it is not possible or convenient to express y as a function of x i.e., in the form $\mathrm{y}=\Phi(\mathrm{x})$, then y is said to be an implicit function.
To find $\frac{d y}{d x}$ in such a case, we differentiate both sides of the given relation concerning x keeping in mind that the derivative of $\Phi(\mathrm{y})$ concerning x is $\frac{d \phi}{d y} \times \frac{d y}{d x}$.
For example
$
\frac{d}{d x}(\sin y)=\cos y \frac{d y}{d x}, \frac{d}{d x}\left(y^2\right)=2 y \frac{d y}{d x}
$
It should be noted that $\frac{d}{d y}(\sin y)=\cos y$ but $\frac{d}{d x}(\sin y)=\cos y \frac{d y}{d x}$
"Stay in the loop. Receive exam news, study resources, and expert advice!"
Mathematics for Joint Entrance Examination JEE (Advanced) : Calculus
Page No. : 3.11
Line : 34
34+ Downloads
24+ Downloads
9+ Downloads
9+ Downloads
6+ Downloads
6+ Downloads
10+ Downloads
6+ Downloads
12+ Downloads
4+ Downloads
2+ Downloads
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Ranked #43 among Engineering colleges in India by NIRF | Get Upto 100% Scholarships | Spot Admissions via CUET
NAAC A++ Grade | Recognized as Category-1 Deemed to be University by UGC | 41,000 + Alumni Imprints Globally
100+ Recruiters | 1200+ Placements of 2026 Batch | NBA & NAAC Accredited | Highest CTC 37 LPA
NAAC A+ Accredited | Highest CTC 45 LPA | Scholarships Available
India's youngest NAAC A++ accredited University | NIRF rank band 151-200 | 2200 Recruiters | 45.98 Lakhs Highest Package
Explore on Careers360
Student Community: Where Questions Find Answers