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Sandwich Theorem - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

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  • 62 Questions around this concept.

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QuestionMEDIUM

\text { If } \lim _{x \rightarrow 0} \frac{a e^x+b \cos x+c e}{e^{2 x}-2 e^x+1}=4 \text {, then }:

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\text { Evaluate: } \lim _{x \rightarrow 0}\left(\frac{1^x+2^x+3^x+\ldots+n^x}{n}\right)^{a / x}:

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Which of the following is true for the real valued functions f(x),h(x),g(x) 

\lim _{x \rightarrow a} f(x)=L, \lim _{x \rightarrow-a} g(x)=L, \lim _{x \rightarrow-a} f(x)=N, \lim _{x \rightarrow a} g(x)=N?

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The integer \mathrm{n} for which \mathrm{\lim _{x \rightarrow 0}\left\{\frac{(\cos x-1)\left(\cos x-e^2\right)}{x^n}\right\}} is a finite, non-zero real number, is

 

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\mathrm{\lim _{n \rightarrow \infty}\left[\sqrt{\left(n^2+n+1\right)}-\left[\sqrt{\left(n^2+n+1\right)}\right]\right)}
where [ ] denotes the greatest integer function:

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\mathrm{\lim _{n \rightarrow \infty} \sum_{r=1}^n \frac{r}{\left(n^2+n+r\right)} \text { equals : }}

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\mathrm{ Assume\, \, that \lim _{\theta \rightarrow-1} f(\theta) exists and \frac{\theta^2+\theta-2}{\theta+3} \leq \frac{f(\theta)}{\theta^2} \leq \frac{\theta^2+2 \theta-1}{\theta+3} }
\mathrm{ holds\, \, for \, \, certain\, \, interval\, \, containing\, \, the \, \, point \, \, \theta=-1 then \lim _{\theta \rightarrow-1} f(\theta) : }

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\text{ Evaluate :}\mathrm{\lim _{n \rightarrow \infty} \frac{1}{1+n^2}+\frac{2}{2+n^2}+\ldots .+\frac{n}{n+n^2}}.

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\text{ Evaluate :}\mathrm{\lim _{x \rightarrow \infty} \frac{x+7 \sin x}{-2 x+13}}  using Sandwich Theorem.

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\mathrm{\text { If }[x] \text { denotes the integral part of } x \text {, then } \lim _{x \rightarrow \infty} \frac{\log _e[x]}{x}=}.

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Concepts Covered - 1

Sandwich Theorem

Sandwich Theorem

Sandwich theorem is also known as squeeze play theorem. It is typically used to find the limit of a function via comparison with two other functions whose limits are known or are easily calculated.

Sandwich Theorem 

Let f(x), g(x) and h(x) be real functions such that f (x) ≤ g( x) ≤ h(x) for all x in neighbourhood of x = a. If \lim _{x \rightarrow a} f(x)=l=\lim _{x \rightarrow a} h(x), \text { then } \lim _{x \rightarrow a} g(x)=l .

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Sandwich Theorem

Study other Related Concepts

Sandwich Theorem Current Topic

Limit
Left-Hand Limits and Right-Hand Limits
Algebra of Limits
Limit of Indeterminate Form and Algebraic limit
Limit of Algebraic function
Limit Using Expansion
Sandwich Theorem
Limits of Trigonometric Functions
Exponential and Logarithmic Limits
Limits of the form (1 power infinity)

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Sandwich Theorem

Mathematics for Joint Entrance Examination JEE (Advanced) : Calculus

Page No. : 2.7

Line : 6

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