Hello there,

Yes, TIET (Thapar Institute of Engineering and Technology) accepts NIOS (National Institute of Open Schooling) students for B.Tech CSE as long as the student meets the eligibility criteria.

Admission Process for B.Tech CSE at TIET without JEE Main:

1. Eligibility Criteria :

   • Educational Qualification : You must have completed your 12th or equivalent with a minimum of 60% aggregate in Physics, Chemistry, and Mathematics (for CSE) from a recognized board, including NIOS.
     
     

   • Age Limit : Candidates must be born on or after 1st October 2000 .
     
     

2. Admission Without JEE Main :

   • TIET provides admission to B.Tech courses based on Thapar University’s Entrance Exam (THAPAR Entrance Test) or Direct Admission (based on merit).
     
     

   • For Direct Admission (without JEE Main), students with good academic performance (generally 80% and above) in 12th grade may be eligible. However, this depends on the cutoff for the specific year.
     
     

3. Application Process :

   • Visit the official TIET website and fill out the online application form.
     
     

   • You may have to appear for the Thapar University Entrance Exam (if applicable) . For direct admission, the process is based on merit or marks obtained in 12th.
     
     

4. Important Dates : Keep track of the application dates and exam schedules on the official TIET website.
   
   

5. Admission Fee : After clearing the entrance exam or merit list, the next step will be counseling and document verification , where you'll submit your 12th-grade marks and other relevant documents.
   
   

If you don’t wish to take JEE, direct admission (based on merit) is an option, but it depends on your academic performance and availability of seats.

I hope this answer helps you. If you have more queries, then feel free to share your questions with us, we will be happy to assist you.

Thank you, and I wish you all the best in your bright future.

Hello there,

Yes, Thapar Institute of Engineering and Technology (TIET) accepts students from the National Institute of Open Schooling (NIOS) for admission to its B.Tech Computer Science and Engineering (CSE) program, provided they meet the eligibility criteria.

Eligibility Criteria for B.Tech CSE at TIET:

• Educational Qualification : Completion of 10+2 or equivalent examination with at least 60% aggregate marks (55% for SC/ST candidates) in Physics, Mathematics, and any one of the following subjects: Chemistry, Biology, Biotechnology, or a Technical Vocational subject.
  
  

• Entrance Exam : A valid score in JEE Main 2024 is required for admission to B.Tech CSE at TIET.
  
  

• Age Limit : Candidates must be born on or after 1st October 2000 .
  
  Admission Process for B.Tech CSE without JEE Main:

While JEE Main is the primary entrance exam for B.Tech admissions at TIET, there is an alternative pathway:

• Mode-2 Admission : For candidates who have not appeared in JEE Main, admission is based on the merit of marks secured in 10+2 or equivalent examination in the aggregate of three subjects: Physics, Mathematics, and any one subject out of Chemistry, Biology, Biotechnology, or a Technical Vocational subject.
  
  

• Eligibility for Mode-2 : Candidates must have passed 10+2 or equivalent examination with at least 70% marks (65% for SC/ST candidates) in the aggregate of the specified subjects.

I hope this answer helps you. If you have more queries, then feel free to share your questions with us, we will be happy to assist you.

Thank you, and I wish you all the best in your bright future.

Hello there,

With a 74.82 percentile in JEE Main , getting CS , IT , or AI in top Mumbai colleges might be challenging. However, here are some options:

1. University of Mumbai Colleges :

• VJTI : Highly competitive for top branches, but possible for others.

• SVKM NMIMS (private): May accept JEE Main scores.

• DJ Sanghvi : Competitive for CS/IT, but possible for other branches.
  
  2. Private Colleges :

• L&T Institute of Technology and KJ Somaiya : They accept JEE Main scores but competition is high.
  
  3. Other Considerations :

• MHT CET : As you're from Maharashtra, applying for MHT CET can improve your chances in top colleges.
  
  

• Management Quota : Some private colleges may have lower entry requirements through this route.

You may also consider related branches like Electronics to increase your chances.

I would recommend you to use JEE Mains College Predictor Tool by Careers360 to get the list of possible colleges you can get with your rank or percentile.

I hope this answer helps you. If you have more queries, then feel free to share your questions with us, we will be happy to assist you.

Thank you, and I wish you all the best in your bright future.

Hello there,

With a 94 percentile in JEE Mains, you have several options:

1. NITs : You may get branches like Mechanical, Civil, or Electrical in lower-ranked NITs, especially under the Home State Quota .
   
   

2. IIITs : You could secure a seat in newer IIITs like IIIT Pune or IIIT Vadodara .
   
   

3. State Government Colleges : Apply through state counseling for good chances, especially in non-circuit branches .
   
   

4. Private Colleges : Institutions like VIT , SRM , and Manipal may offer opportunities based on your JEE score.
   
   Suggestion: Participate in JoSAA counseling and explore state and private universities for better chances of admission. Focus on branches like Mechanical , Civil , and Electrical .
   
   
   

   I hope this answer helps you. If you have more queries, then feel free to share your questions with us, we will be happy to assist you.

   Thank you, and I wish you all the best in your bright future.

   
   
   
   
   

Hello there,

With an 82.63 percentile in JEE Mains 2025 under the OBC-NCL category, you are not eligible to appear for JEE Advanced 2025 .

Eligibility Criteria for JEE Advanced 2025

To qualify for JEE Advanced, candidates must be among the top 2,50,000 performers in JEE Mains. The distribution is as follows:

• OBC-NCL : 27% of 2,50,000 = 67,500 candidates

Your percentile of 82.63 suggests that your rank is beyond the cutoff for the OBC-NCL category. Therefore, you are not among the top 67,500 candidates in your category and thus do not qualify for JEE Advanced.

Next Steps

• Focus on NITs and IIITs : With your percentile, you can aim for admission to NITs and IIITs through JoSAA counseling .
  
  

• Consider State Engineering Colleges : Explore admission opportunities in state government engineering colleges .
  
  

• Explore Private Universities : Institutions like VIT Vellore , SRM Chennai , and Manipal University may also be viable options.

I hope this answer helps you. If you have more queries, then feel free to share your questions with us, we will be happy to assist you.

Thank you, and I wish you all the best in your bright future.

Hello there,

With 157 marks in JEE Mains under the OBC-NCL female category, it's a bit challenging to predict a seat in CSE at an NIT , as CSE is a highly competitive branch.

Based on Previous Trends:

• The closing ranks for CSE in NITs are typically very high, especially for top NITs (like NIT Trichy, NIT Warangal, and NIT Surathkal), and for the OBC-NCL female category, the cutoffs tend to be higher than other categories.
  
  

• With 157 marks , you may fall around the rank range of 20,000-30,000 (approximate estimate). However, this can vary based on the specific NIT and the competition in that particular year.
  
  What You Can Expect:

• You may not be able to get CSE in top NITs with your marks, but there are chances for other branches of CSE (such as IT or ECE ) or CSE in newer NITs .
  
  

• Consider lower NITs or other branches in better NITs like NIT Puducherry , NIT Goa , etc.
  
  Next Steps:

• Participate in JoSAA Counseling : Ensure to participate in JoSAA counseling , as the exact cutoffs will be declared after the results.
  
  

• Consider Other Engineering Institutes : Explore private universities like VIT Vellore , SRM Chennai , and Manipal University , which offer CSE and have relatively flexible cutoffs.

I hope this answer helps you. If you have more queries, then feel free to share your questions with us, we will be happy to assist you.

Thank you, and I wish you all the best in your bright future.

Hello,

Scoring 92 out of 300 in JEE Main 7th April 2025 Shift 2 would likely give you a predicted percentile between 83 and 86 , based on past trends and difficulty levels.

How This Estimate Is Calculated:

• 92 marks is above average, but not among the top scoring range.

• For most sessions in previous years:

80–90 marks → ~80 to 85 percentile

90–100 marks → ~83 to 87 percentile

So, your estimated percentile is ~84.5 ±1.5 , depending on how difficult your shift was.

What This Means:

If you belong to any reservation category (OBC, SC, ST, EWS, etc.) , you may qualify for JEE Advanced .

If you're a General (Open) category student, the cutoff for JEE Advanced is usually around 88–90 percentile , so you may fall just short — unless the cutoff is lower this year.

Hello,

Ryan International School, Kundalahalli, follows the ICSE/ISC curriculum and provides a strong academic foundation that aligns with competitive exams like JEE and NEET. However, there is no specific information available on their official platforms regarding dedicated in-school coaching programs exclusively for JEE preparation.

The school's curriculum is designed to cover core subjects comprehensively, which can be beneficial for students preparing for competitive exams. For specialized coaching, students often consider enrolling in external coaching centers.

For the most accurate and updated information, it's advisable to contact the school directly. You can reach them at:

• Phone : 080-28476963 / 28525439 / 28475080

• Email : ris.blr1@ryangroup.org (mailto:ris.blr1@ryangroup.org)

They can provide detailed information about any additional support or programs they may offer for competitive exam preparation.

Hi. Rohit

No. You cannot get btech cse from iit patna without qualifying jee mains and advance.

Thanks.