IPU CET Counselling College Predictor 2026

Below are the day-wise JEE Main session 1 questions and answers

https://engineering.careers360.com/download/ebooks/jee-main-2026-analysis-january-session

The complete analysis for JEE Main Jan 29 shift 1 exam 2026 will be updated soon at https://engineering.careers360.com/articles/jee-main-2026-january-29-question-paper-with-solutions-pdf

As of now, January 23 shift 2 is the toughest shift of JEE Mains 2026. Get the difficulty level of all shifts and days here

https://engineering.careers360.com/articles/toughest-shift-of-jee-main-2026-session-1-exam

JEE Main 28 Jan shift 2 exam will end at 6 PM. The complete analysis and memory-based questions will solution will be updated in the below article. Keep checking the page-

https://engineering.careers360.com/articles/jee-main-2026-january-28-shift-2-question-paper-with-solutions-pdf

The JEE Main Jan 28 paper for shift 1 was moderate. Although Chemistry was a bit tricky. As expected, Maths was time consuming. But Physics was on the easier side.

You can find the answers for Jan 28 shift 1 online. They are memory based. I found this article helpful

Hi Lucky,
Please refer to this link and you can download the free pdf.

https://engineering.careers360.com/download/ebooks/jee-main-2026-memory-based-questions-and-analysis-of-21st-january-shift-1

$\begin{array}{rl}& 625=\mathrm{ms}\mathrm{\Delta }\mathrm{T}+\mathrm{mL}\\ & 625=\mathrm{m}[125\times 300+2.5\times {10}^4]\\ & 625=\mathrm{m}[37500+25000]\\ & 625=\mathrm{m}[62500]\\ & \mathrm{m}=\frac{1}{100}\mathrm{kg}\\ & \mathrm{M}=10\text{grams}\end{array}$

HI Manisha Maharana

You can download the JEE Mains 10 Free Mock Test with Detailed solutions. Its a feely downloadable pdf.
https://engineering.careers360.com/download/sample-papers/jee-main-10-full-mock-test-and-explanations-pdf

Also, you can check ad attemp the online mock test on our platform.
https://learn.careers360.com/test-series-jee-main-free-mock-test/

A general equation of a circle is

$
x^2+y^2+2 g x+2 f y+c=0
$

Since it passes through $(0,0)$,

$
c=0
$

So the equation becomes

$
x^2+y^2+2 g x+2 f y=0
$

It cuts the x -axis at ( $a, 0$ ).

Substituting:

$
a^2+2 g a=0
$

g=-a/2

Hi Ritesh
Here is the article for your reference
https://hospitality.careers360.com/articles/best-books-for-nchmct-jee-preparation