Careers360 Logo
ask-icon
share
    JEE Main April Application Form 2026 (Reopened) - Registration Link, Steps to Apply Online

    Integrals of Particular Function - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • Some Special Integration, Application of Special Integral Formula (Part 1) is considered one of the most asked concept.

    • 51 Questions around this concept.

    Solve by difficulty

    $\int \frac{2^{\mathrm{x}}}{\sqrt{1-4^{\mathrm{x}}}} \mathrm{dx}$ equals

    $\int \frac{x+\sin x}{1+\cos x} d x$ is equal to

    $\int \mathrm{c}^2\left(\frac{1-x}{1+x^2}\right)^2 d x_{\text {is equal to }}$

     

    JEE Main 2026: January Question Paper with Solutions

    JEE Main 2026 Tools: College Predictor

    JEE Main 2026: Important Formulas | Foreign Universities in India

    Comprehensive Guide: IIT's | NIT'sIIIT's

    Concepts Covered - 3

    Some Special Integration

    $\begin{aligned} & \text { 1. } \int \frac{\mathrm{dx}}{\mathrm{x}^2+\mathrm{a}^2}=\frac{1}{\mathrm{a}} \tan ^{-1}\left(\frac{\mathrm{x}}{\mathrm{a}}\right)+\mathrm{C} \\ & \text { put } \mathrm{x}=\mathrm{a} \tan \theta, \text { then } \mathrm{dx}=\mathrm{asec}^2 \theta \mathrm{~d} \theta \\ & \begin{aligned} \therefore \int \frac{\mathrm{dx}}{\mathrm{x}^2+\mathrm{a}^2} & =\int \frac{\mathrm{asec}^2 \theta}{\mathrm{a}^2+\mathrm{a}^2 \tan ^2 \theta} \mathrm{~d} \theta \\ & =\int \frac{\mathrm{asec}^2 \theta}{\mathrm{a}^2\left(1+\tan ^2 \theta\right)} \mathrm{d} \theta \\ & =\frac{1}{\mathrm{a}} \int \mathrm{d} \theta=\frac{1}{\mathrm{a}} \theta+\mathrm{C}=\frac{1}{\mathrm{a}} \tan ^{-1}\left(\frac{\mathrm{x}}{\mathrm{a}}\right)+\mathrm{C}\end{aligned}\end{aligned}$

    2. $\int \frac{\mathrm{dx}}{\mathrm{x}^2-\mathrm{a}^2}=\frac{1}{2 \mathrm{a}} \log \left|\frac{\mathrm{x}-\mathrm{a}}{\mathrm{x}+\mathrm{a}}\right|+\mathrm{C}$
    we can rewrite the above integral as
    $
    \begin{aligned}
    \int \frac{d x}{x^2-a^2} & =\frac{1}{2 a} \int\left(\frac{1}{x-a}-\frac{1}{x+a}\right) d x \\
    & =\frac{1}{2 a}(\log |x-a|-\log |x+a|)+c \\
    & =\frac{1}{2 a} \log \left|\frac{x-a}{x+a}\right|+C
    \end{aligned}
    $

    3. $\int \frac{d x}{a^2-x^2}=\frac{1}{2 a} \log \left|\frac{a+x}{a-x}\right|+C$
    4. $\int \frac{d x}{\sqrt{\mathrm{a}^2-\mathrm{x}^2}}=\sin ^{-1}\left(\frac{\mathrm{x}}{\mathrm{a}}\right)+\mathrm{C}$
    5. $\int \frac{d x}{\sqrt{a^2+x^2}}=\log \left|x+\sqrt{x^2+a^2}\right|+C$
    6. $\int \frac{\mathrm{dx}}{\sqrt{\mathrm{x}^2-\mathrm{a}^2}}=\log \left|\mathrm{x}+\sqrt{\mathrm{x}^2-\mathrm{a}^2}\right|+\mathrm{C}$
    7. $\int \sqrt{\mathrm{a}^2-\mathrm{x}^2} \mathrm{dx}=\frac{1}{2} \mathrm{x} \sqrt{\mathrm{a}^2-\mathrm{x}^2}+\frac{1}{2} \mathrm{a}^2 \sin ^{-1}\left(\frac{\mathrm{x}}{\mathrm{a}}\right)+\mathrm{C}$
    8. $\int \sqrt{\mathrm{a}^2+\mathrm{x}^2} \mathrm{dx}=\frac{1}{2} \mathrm{x} \sqrt{\mathrm{a}^2+\mathrm{x}^2}+\frac{1}{2} \mathrm{a}^2 \log \left|\mathrm{x}+\sqrt{\mathrm{a}^2+\mathrm{x}^2}\right|+C$
    9. $\int \sqrt{\mathrm{x}^2-\mathrm{a}^2} \mathrm{dx}=\frac{1}{2} \mathrm{x} \sqrt{\mathrm{x}^2-\mathrm{a}^2}-\frac{1}{2} \mathrm{a}^2 \log \left|\mathrm{x}+\sqrt{\mathrm{x}^2-\mathrm{a}^2}\right|+C$

    Following are some important substitutions useful in evaluating integrals.

    \begin{array}{c||c|}
    \text { Expression } & \text { Substitution } \\
    \hline a^2+x^2 & x=a \tan \theta \text { or } x=a \cot \theta \\
    \hline a^2-x^2 & x=a \sin \theta \text { or } x=a \cos \theta \\
    \hline x^2-a^2 & x=a \sec \theta \text { or } x=a \csc \theta \\
    \hline \sqrt{\frac{a-x}{a+x}} \text { or } \sqrt{\frac{a+x}{a-x}} & x=a \cos 2 \theta \\
    \hline
    \end{array}

    Application of Special Integral Formula (Part 1)

    Integration of the type 

    (i) $\int \frac{(p x+q) d x}{a x^2+b x+c}$
    (ii) $\int \frac{(p x+q)}{\sqrt{a x^2+b x+c}} d x$
    (iii) $\int(p x+q) \sqrt{a x^2+b x+c} d x$

    Express the linear factor $p x+q$ in terms of the derivative of quadratic factor $a x^2+b x+c$
    i.e.
    $
    \begin{aligned}
    \mathrm{px}+\mathrm{q} & =\lambda \cdot \frac{\mathrm{d}}{\mathrm{dx}}\left(\mathrm{ax}^2+\mathrm{bx}+\mathrm{c}\right)+\mu \\
    \Rightarrow \quad \mathrm{px}+\mathrm{q} & =\lambda(2 \mathrm{ax}+\mathrm{b})+\mu
    \end{aligned}
    $

    Find $\lambda$ and $\mu$ and replace $(p x+q)$ by $\lambda(2 a x+b)+\mu$

     

    Application of Special Integral Formula (Part 2)

    Integration of the type

    1. $\int \frac{a x^2+b x+c}{\left(p x^2+q x+r\right)} d x$
    2. $\int \frac{\left(a x^2+b x+c\right)}{\sqrt{\mathrm{px}^2+\mathrm{qx}+\mathrm{r}}} \mathrm{dx}$
    3. $\int\left(\mathrm{ax}^2+\mathrm{bx}+\mathrm{c}\right) \sqrt{\mathrm{px}^2+\mathrm{qx}+\mathrm{r}} \mathrm{dx}$

    Substitute,
    $
    \mathrm{ax}^2+\mathrm{bx}+\mathrm{c}=\lambda\left(\mathrm{px}^2+\mathrm{qx}+\mathrm{r}\right)+\mu\left\{\frac{\mathrm{d}}{\mathrm{dx}}\left(\mathrm{px}^2+\mathrm{qx}+\mathrm{r}\right)\right\}+\gamma
    $

    Find λ, μ, and γ. These integrations reduce to integration of three independent functions.

    Integration of the form $\int \frac{\mathrm{k}(\mathrm{x})}{\mathrm{ax}^2+\mathrm{bx}+\mathrm{c}} \mathrm{dx}$

    (here, k(x) is a polynomial of degree greater than 2)

    To solve this type of integration, divide the numerator by the denominator and express the integral as 

    $\mathrm{Q}(\mathrm{x})+\frac{\mathrm{R}(\mathrm{x})}{\mathrm{ax}+\mathrm{bx}+\mathrm{c}}$ 

    Here, R(x) is a linear function of x.

    Study it with Videos

    Some Special Integration
    Application of Special Integral Formula (Part 1)
    Application of Special Integral Formula (Part 2)

    "Stay in the loop. Receive exam news, study resources, and expert advice!"

    Books

    Reference Books

    Some Special Integration

    Mathematics for Joint Entrance Examination JEE (Advanced) : Calculus

    Page No. : 7.14

    Line : 1

    Application of Special Integral Formula (Part 1)

    Mathematics for Joint Entrance Examination JEE (Advanced) : Calculus

    Page No. : 7.19

    Line : 1

    E-books & Sample Papers

    Get Answer to all your questions