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Continuity is considered one of the most asked concept.
278 Questions around this concept.
In which of the following, $\mathrm{x}=1$ is the only point of discontinuity?
If the function.
$
g(x)= \begin{cases}k \sqrt{x+1}, & 0 \leq x \leq 3 \\ \mathrm{~m} x+2, & 3<x \leq 5\end{cases}
$
is differentiable, then the value of $k+m$ is :
Consider the function.
$f(x)= \begin{cases}\frac{a\left(7 x-12-x^2\right)}{b\left|x^2-7 x+12\right|} & , x<3 \\ 2^{\frac{\sin (x-3)}{x-[x]}} & , x>3 \\ b & , x=3\end{cases}$
where $[\mathrm{x}]$ denotes the greatest integer less than or equal to $\mathrm{x}$. If $\mathrm{S}$ denotes the set of all ordered pairs $(\mathrm{a}, \mathrm{b})$ such that $f(x)$ is continuous at $x=3$, then the number of elements in $S$ is:
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f(x) is said to be continuous in (a,b) if it is continuous of -------------- point of the interval (a,b)
Match the following
(i)
(p) Limit exists at $x=a$ but not continuously
(ii)
(q) Continuous at $x=a$
(iii)
(r) Limit doesn't exist at $x=a$
The function $f(x)=\begin{Bmatrix} \frac{1}{4^{x}-1}& ; \: \: x\neq 0 \\ 0 & x=0 \end{Bmatrix}$ is continuous
Let
$
f(x)=\left\{\begin{array}{cc}
\frac{x^3+x^2-16 x+20}{(x-2)^2} & \text { if } x \neq 2 \\
K & \text { if } x=2
\end{array}\right\}
$
If $(x)$ is continuous for all $x$, then $K=$
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If $f(x)=\left\{\begin{array}{cl}(\cos x)^{1 / x} & , x \neq 0 \\ a & , x=0 \\ \text { is continuous at } x=0, \text { then the value of } a \text { is }\end{array}\right.$
Continuity
Many functions have the property that their graphs can be traced with a pen/pencil without lifting the pen/pencil from the page. Such functions are called continuous. Other functions have points at which a break in the graph occurs, but satisfy this property over some intervals contained in their domains. They are continuous on these intervals and are said to have a discontinuity at a point where a break occurs. So continuity can be defined in two ways: Continuity at a point and Continuity over an interval.
Continuity at a point
Let us see different types of conditions to see continuity at point $x=a$
We see that the graph of $f(x)$ has a hole at $x=a$, which means that $f(a)$ is undefined. At the very least, for $f(x)$ to be continuous at $x=a$, we need the following conditions:
(i) $f(a)$ is defined
Next, for the graph given below, although $f(a)$ is defined, the function has a gap at $x=a$. In this graph, the gap exists because $\lim x \rightarrow a f(x)$ does not exist. We must add another condition for continuity at $x=a$, which is
(ii) $\lim _{x \rightarrow a} f(x)$ exists
The above two conditions by themselves do not guarantee continuity at a point. The function in the figure given below satisfies both of our first two conditions but is still not continuous at a. We must add a third condition to our list:
(iii) $\lim _{x \rightarrow a} f(x)=f(a)$
So, a function $f(x)$ is continuous at a point $x=a$ if and only if the following three conditions are satisfied:
1. $f(a)$ is defined
2. $\lim _{x \rightarrow a} f(x)$ exists
3. $\lim _{x \rightarrow a} f(x)=f(a)$
Or
$
\lim _{x \rightarrow a^{-}} f(x)=\lim _{x \rightarrow a^{+}} f(x)=f(a)
$
i.e. L.H.L. $=$ R.H.L. $=$ value of the function at $x=a$
A function is discontinuous at a point a if it fails to be continuous at a.
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