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Area Bounded by Two Curves is considered one the most difficult concept.
Area Bounded by Curve and Axes is considered one of the most asked concept.
192 Questions around this concept.
What is the value of $\int_a^b f(x) d x$ ?
The area bounded by the curve $y= x\left | x \right |, \, \,$ x axis and the ordinates x=-1 and x=1 is given by
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$
\text { The area bounded by the curve } \mathrm{f}(\mathrm{x})=\mathrm{x}^2+1 \text { and } \mathrm{x}-\mathrm{a} \text { xis between } \mathrm{x}=1 \text { and } \mathrm{x}=3 \text { is }
$
The area bounded by the curve $\mathrm{y= ln\left ( x \right ),y= 0,x= 1\: and\: x= e\: \: is}$
The area bounded by the curves $y=x^3, y-$ axis, $y=1$ and $y=8$ is
Area Bounded by Curve and Axes
In the previous concept, we learned that if the function $f(x) \geq 0 \forall x \in[a, b]$ then $\int_a^b f(x) d x$ represents the area bounded by $y=f(x), x$-axis and lines $x=a$ and $x=b$.
If the function $f(x) \leq 0 \forall x \in[a, b]$, then the area by bounded $y=f(x), x$-axis and lines $x=a$ and $x=b$ is $\left|\int_a^b f(x) d x\right|$.
Area along Y-axis
The area by bounded $x=g(y)[$ with $g(y)>0], y$-axis and the lines $y=a$ and $y=b$ is $\int_a^b x d y=\int_a^b g(y) d y$
Area of Piecewise Function
If the graph of the function f(x) is of the following form, then.
then $\int_a^b f(x) d x$ will equal $A_1-A_2+A_3-A_4$ and not $A_1+A_2+A_3+A_4$.
If we need to evaluate $A_1+A_2+A_3+A_4$ (the magnitude of the bounded area), we will have to calculate
$
\underbrace{\int_a^x f(x) d x}_{\mathrm{A}_1}+\underbrace{\left|\int_x^y f(x) d x\right|}_{\mathrm{A}_2}+\underbrace{\int_y^z f(x) d x}_{\mathrm{A}_3}+\underbrace{\left|\int_z^b f(x) d x\right|}_{\mathrm{A}_4}
$
The area bounded by the curve when the curve intersects the X-axis
The graph $y=f(x) \forall x \in[a, b]$ intersects the $x$-axis at $x=c$.
If the function $f(x) \geq 0 \forall x \in[a, c]$ and $f(x) \leq 0 \forall x \in[c, b]$ then the area bounded by curve and $x$-axis, between lines $x=a$ and $\mathrm{x}=\mathrm{b}$ is
$\int_a^b|f(x)| d x=\int_a^c f(x) d x-\int_c^b f(x) d x$
The area is bounded by the curves $y=f(x), y=g(x)$, and the lines $x=a$ and $x=b$, and it is given that $f(x) \leq g(x)$.
From the figure, it is clear that,
Area of the shaded region = Area of the region ABEF - Area of the region ABCD
$\int_a^b g(x) d x-\int_a^b f(x) d x=\int_a^b(\underbrace{g(x)}_{\begin{array}{c}\text { upper } \\ \text { curve }\end{array}}-\underbrace{f(x)}_{\begin{array}{c}\text { lower } \\ \text { curve }\end{array}}) d x$
Area bounded by the curves $y=f(x), y=g(x)$ which intersect each other in the interval [a, b]
First find the point of intersection of these curves $y=f(x)$ and $y=g(x)$ by solving the equation $f(x)$ $=g(x)$, let the point of intersection be $x=c$
Area of the shaded region
$=\int_a^c\{f(x)-g(x)\} d x+\int_c^b\{g(x)-f(x)\} d x$
When two curves intersect more than one point
Area bounded by the curves $y=f(x), y=g(x)$ which intersect each other at three points at $x=a, x=$ $b$ and $x=c$.
To find the point of intersection, solve $f(x)=g(x)$.
For $x \in(a, c), f(x)>g(x)$ and for $x \in(c, b), g(x)>f(x)$.
Area bounded by curves,
$\begin{aligned} \mathrm{A} & =\int_a^b|f(x)-g(x)| d x \\ & =\int_a^c(f(x)-g(x)) d x+\int_c^b(g(x)-f(x)) d x\end{aligned}$
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